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I want to extract content, between a certain text.
For example:
<html><title>lol</title></html>
I want to extract what is located between the <title> </ title>, which regular expression do I need ?
You can use better tools than regular expressions.
Read about HTMLParser
EDIT:
But if you want use regular expressions:
import re
def get_tag_body(tagname, text):
regexp = r'<%s>(.*?)</%s>' % (tagname, tagname)
rx_obj = re.search(regexp, text, re.IGNORECASE|re.DOTALL)
return rx_obj.groups()
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I have text with tags [CODE]something here[/CODE].
How can I take only part between this tags, using re module.
Using the re.findall function we can use a regular expression with a capture group which will return a list of all the matches.
import re
regex = r"\[CODE\](.+?)\[\/CODE\]"
test_str = "[CODE]Noob[/CODE] Nb[CODE]something here[/CODE]"
matches = re.findall(regex, test_str)
for match in matches:
print(match)
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How can I grab the invite code from this string?
{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}
The expected output would be "111A111A".
Any help is appreciated
I tried it in a simple way, You could give more details for further improvement.
s = "{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}"
print(s[-11: -3])
This will do it with ReGex
import re
def findInvite(s):
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
assert findInvite("{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}") == "111A111A"
And if this isn't a string but a dict, then change the function to:
def findInvite(d):
s = d["inviteURL"]
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
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I want the data enclosed between three asterisks.And the Word should start with description.
For eg:I have data like
description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;
I want only
tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568
You may use re.findall here:
inp = "description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;"
matches = re.findall(r'\bdescription\s+\*{3}(.*?)\*{3}', inp, flags=re.DOTALL)
print(matches)
This prints:
['tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568']
Note that I use dot all mode in the regex, in case your expected matches might span across more than one line.
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How can I catch some string like these with a regex in python?
M1Sxs-2839
McS-28S9213
Both the first and the second part (divided by the -) can contains letters and numbers (case insensitive).
You may try the below re.match function.
re.match(r"(?i)[A-Z0-9]+-[A-Z0-9]+$", st)
(?i) helps to do case-insensitive match. Since re.match scans the input from start, you don't need to add start of the line anchor ^ explicitly.
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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks
That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]