How to get all text between [CODE][/CODE]? [closed] - python

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I have text with tags [CODE]something here[/CODE].
How can I take only part between this tags, using re module.


Using the re.findall function we can use a regular expression with a capture group which will return a list of all the matches.
import re
regex = r"\[CODE\](.+?)\[\/CODE\]"
test_str = "[CODE]Noob[/CODE] Nb[CODE]something here[/CODE]"
matches = re.findall(regex, test_str)
for match in matches:
print(match)

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find the word before specific string in python [closed]

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Suppose I have string
exp='"\"OLS\".\"ORDER_ITEMS\".\"QUANTITY\" <50 and \"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston''
How can I find word before string \"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston' that is and in my case
result should be and

Here's one way (after fixing your string literal):
import re
exp='"OLS"."ORDER_ITEMS"."QUANTITY" <50 and "OLS"."PRODUCTS"."PRODUCT_NAME" = \'Kingston\''
search_for = '"OLS"."PRODUCTS"."PRODUCT_NAME"'
m = re.search(r'(\w+)\s+' + search_for, exp)
print(m.group(1))
Result:
and
Note that there's no reason to escape the double quote characters in your string, since you're defining the string with single quotes. For the same reason, you do have to escape the single quotes around Kingston.

This?
key = "\"OLS\".\"PRODUCTS\".\"PRODUCT_NAME\" = 'Kingston'"
exp[:exp.index(key)].split()[-1]

Extract Data Enclosed between three asterisks in python [closed]

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I want the data enclosed between three asterisks.And the Word should start with description.
For eg:I have data like
description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;
I want only
tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568

You may use re.findall here:
inp = "description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;"
matches = re.findall(r'\bdescription\s+\*{3}(.*?)\*{3}', inp, flags=re.DOTALL)
print(matches)
This prints:
['tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568']
Note that I use dot all mode in the regex, in case your expected matches might span across more than one line.

Regex in python to catch a string like MMS-2839 [closed]

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How can I catch some string like these with a regex in python?
M1Sxs-2839
McS-28S9213
Both the first and the second part (divided by the -) can contains letters and numbers (case insensitive).

You may try the below re.match function.
re.match(r"(?i)[A-Z0-9]+-[A-Z0-9]+$", st)
(?i) helps to do case-insensitive match. Since re.match scans the input from start, you don't need to add start of the line anchor ^ explicitly.

Regular Expressions(extraction values) [closed]

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I want to extract content, between a certain text.
For example:
<html><title>lol</title></html>
I want to extract what is located between the <title> </ title>, which regular expression do I need ?

You can use better tools than regular expressions.
Read about HTMLParser
EDIT:
But if you want use regular expressions:
import re
def get_tag_body(tagname, text):
regexp = r'<%s>(.*?)</%s>' % (tagname, tagname)
rx_obj = re.search(regexp, text, re.IGNORECASE|re.DOTALL)
return rx_obj.groups()

grep with python to match string inside quotes in html files [closed]

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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks

That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]

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