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I want the data enclosed between three asterisks.And the Word should start with description.
For eg:I have data like
description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;
I want only
tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568
You may use re.findall here:
inp = "description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;"
matches = re.findall(r'\bdescription\s+\*{3}(.*?)\*{3}', inp, flags=re.DOTALL)
print(matches)
This prints:
['tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568']
Note that I use dot all mode in the regex, in case your expected matches might span across more than one line.
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This is my string
word = " Saturday Fortune 08-09-2022 (4872) Draw Numbers "
But I only want to print the date in the string like this
'08-09-2022'
So how can I achieve this?
Should use a regular expression to find that part in the string. Something like:
import re
match = re.search(r'\d{2}-\d{2}-\d{4}', word)
This already seems to be answered as a subproblem in this thread.
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I need help, in a long string, I want to know the the 2 characters after a number
example = "gz15gr123da1az4gr1sd23f168zgre4r6z"
if in example after 1 number == "gr":
so delete "gr"
If I understand your question correctly, what you need is regex:
import re
example = "gz15gr123da1az4gr1sd23f168zgre4r6z"
re.sub("(\d)gr", r"\1", example)
Output
gz15123da1az41sd23f168zgre4r6z
Explnatation
The re.sub function takes three arguments: the first argument is a patter, the second one the replacement, and the last of is the string itself. (\d)gr selects the parts that contain a number followed by gr, then replaces it with the number (\d) itself(removing the gr part).
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I have text with tags [CODE]something here[/CODE].
How can I take only part between this tags, using re module.
Using the re.findall function we can use a regular expression with a capture group which will return a list of all the matches.
import re
regex = r"\[CODE\](.+?)\[\/CODE\]"
test_str = "[CODE]Noob[/CODE] Nb[CODE]something here[/CODE]"
matches = re.findall(regex, test_str)
for match in matches:
print(match)
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Why is not filter the df like in the screenshot
Show the function of str.contain("|") that's didn't work
You need to set the regex parameter of contains to False. In your code now, the string "|" is parsed as a regular expression, but you want to match the literal pipe character.
movies_with_more_dir = movies_df[movies_df['director'].str.contains("|", regex=False)]
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How can I catch some string like these with a regex in python?
M1Sxs-2839
McS-28S9213
Both the first and the second part (divided by the -) can contains letters and numbers (case insensitive).
You may try the below re.match function.
re.match(r"(?i)[A-Z0-9]+-[A-Z0-9]+$", st)
(?i) helps to do case-insensitive match. Since re.match scans the input from start, you don't need to add start of the line anchor ^ explicitly.