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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks
That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]
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This is my string
word = " Saturday Fortune 08-09-2022 (4872) Draw Numbers "
But I only want to print the date in the string like this
'08-09-2022'
So how can I achieve this?
Should use a regular expression to find that part in the string. Something like:
import re
match = re.search(r'\d{2}-\d{2}-\d{4}', word)
This already seems to be answered as a subproblem in this thread.
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Hi I need to remove the duplicates in python but only when they are in a row. For example:
Input: AAABBCCDDAA
Output:ABCDA
Could you please help me? thnks.
To learn more about text processing in Python3 I recommend training on codingame.com.
def removeDuplicates(inp):
output =""
lastCharacter=""
for character in inp:
output+=character*(character!=lastCharacter)
lastCharacter=character
return output
inpTest ="AAABBCCDDAA"
print(removeDuplicates(inpTest))
ABCDA
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How can I grab the invite code from this string?
{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}
The expected output would be "111A111A".
Any help is appreciated
I tried it in a simple way, You could give more details for further improvement.
s = "{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}"
print(s[-11: -3])
This will do it with ReGex
import re
def findInvite(s):
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
assert findInvite("{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}") == "111A111A"
And if this isn't a string but a dict, then change the function to:
def findInvite(d):
s = d["inviteURL"]
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
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I want the data enclosed between three asterisks.And the Word should start with description.
For eg:I have data like
description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;
I want only
tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568
You may use re.findall here:
inp = "description ***tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568***;"
matches = re.findall(r'\bdescription\s+\*{3}(.*?)\*{3}', inp, flags=re.DOTALL)
print(matches)
This prints:
['tCore-DFON_P.17-18>dPLUC80115_S19P1>>><<<dPDCL80121_S17P1<100G.IPT.NTTA.SEA.ASE+PC1.LUC/PLD-SEA/PLD_100GEL064.263568']
Note that I use dot all mode in the regex, in case your expected matches might span across more than one line.
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I've an issue here. I have a string and I want to extract parts of it using regex. Here is the string
{{name}} I love me some work {{hero}}
I want to extract
[{{name}}, {{hero}}]
also in a case where the string exist as
{{name} I love me some work {{hero, come in {here, this is right}
I still want to get
[{{name}, {{name, {here, right}]
I hope this makes sense. I am working with Python.
If you want ['{{name}}', '{{hero}}', '{{hero, come in {here, this is right}'] use #Avinash's regex.
If you want ['{{name}}', '{{hero}}', '{{hero', {here', 'right}'] use the following:
re.findall(r'{+\w+}*|{*\w+}+', s)
RegEX DEMO
Have you tried the following?
import re
s = '{{name} I love me some work {{hero, come in {here, this is right}'
print re.findall(r'\{.*?\}', s)