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How can I grab the invite code from this string?
{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}
The expected output would be "111A111A".
Any help is appreciated
I tried it in a simple way, You could give more details for further improvement.
s = "{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}"
print(s[-11: -3])
This will do it with ReGex
import re
def findInvite(s):
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
assert findInvite("{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}") == "111A111A"
And if this isn't a string but a dict, then change the function to:
def findInvite(d):
s = d["inviteURL"]
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
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This is my string
word = " Saturday Fortune 08-09-2022 (4872) Draw Numbers "
But I only want to print the date in the string like this
'08-09-2022'
So how can I achieve this?
Should use a regular expression to find that part in the string. Something like:
import re
match = re.search(r'\d{2}-\d{2}-\d{4}', word)
This already seems to be answered as a subproblem in this thread.
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I have this:
a = ['a','b','c','d','e','f']
And I want to make it into this:
a = ['ab','cd','ef']
I tried this:
for i in range(len(a)):
if round(i/2) > len(a):
break
c = (a[(i*2)-1])+(a[i*2])
c_list.append(c)
But it didn't work, and I felt it wasn't the best way to approach it.
def pair_up(a):
return [a[i]+a[i+1] for i in range(0,len(a),2)]
print(pair_up(a))
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Hi I need to remove the duplicates in python but only when they are in a row. For example:
Input: AAABBCCDDAA
Output:ABCDA
Could you please help me? thnks.
To learn more about text processing in Python3 I recommend training on codingame.com.
def removeDuplicates(inp):
output =""
lastCharacter=""
for character in inp:
output+=character*(character!=lastCharacter)
lastCharacter=character
return output
inpTest ="AAABBCCDDAA"
print(removeDuplicates(inpTest))
ABCDA
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these items are in a list
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
AHU-02-17-019-DPS03,
AHU-T3-01-PL-TS01,
EF-03-32-108-MD01,
AHU-02-16-019-MD01,
AHU-T3-01-003-MD01,
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
so i want a new list which should be like
SF-04-08
AHU-VVIP
AHU-02-17
AHU-T3-01
EF-03-32
AHU-02-16
AHU-T3-01
SF-04-08
AHU-VVIP-02
using python??
you can use strip like:
data = ['SF-04-08-010-MD01',
'AHU-VVIP-02-003-MD03',
'AHU-02-17-019-DPS03'
]
for item in data:
print ('-'.join(item.split('-')[:3]))
output:
SF-04-08
AHU-VVIP-02
AHU-02-17
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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks
That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]