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Count of different numbers in one long number [closed]

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How can I count how many different numbers there are in one long number?
For example: this number 1122334455 has 5 different numbers.
How can I do that in Python?

You can do that as:
print len(set(str(s)))
The str() casts the int as a string
The set() takes the unique elements of the string and creates a set of it
The len() returns the length of the set
Examples
>>> print len(set(str(s)))
5
s = 1324082304
>>> print len(set(str(s)))
6

Check if part of text is in tuple [closed]

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How to check if part of text is in tuple?
For example:
my_data = ((1234L,), (23456L,), (3333L,))
And we need to find if 123 or 1234 is in tuple.
I didn't worked lot with tuples before.
In array we use:
if variable in array
But its not working for tuples like my_data
PS. 1st answer solved problem.

def findIt(data, num):
num = str(num)
return any(num in str(i) for item in data for i in item)
data = ((1234L,), (23456L,), (3333L,))
print findIt(data, 123)
Output
True

python parsing string using regex [closed]

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I need to parse a string from this:
CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt
To this:
ES1-HER / ES1-Seura
Any easy way to do this with regex?

>>> import re
>>> s = 'CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt'
>>> re.findall('OU=([^,]+)', s)
['Computers', 'ES1-HER', 'ES1-Seura', 'RES-ES1']
>>> re.findall('OU=([^,]+)', s)[1:3]
['ES1-HER', 'ES1-Seura']
>>> ' / '.join(re.findall('OU=([^,]+)', s)[1:3])
'ES1-HER / ES1-Seura'
Don't use str as a variable name. It shadows builtin function str.

Python List sorting by columns [closed]

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If I had a list
['xxxx', 'oooo', 'xxxx', 'oooo'......etc]
which looks like
(xxxx)
(oooo)
(xxxx)
(oooo)
and the list could be as long as the user inputs,
how would I make a new list sorted by each column which would look like:
['xoxo', 'xoxo', 'xoxo', 'xoxo']
which would be
(xoxo)
(xoxo)
(xoxo)
(xoxo)

myList=['xxxx', 'oooo', 'xxxx', 'oooo']
print [''.join(element) for element in zip(*myList)]
Output
['xoxo', 'xoxo', 'xoxo', 'xoxo']
What you are looking for, is called, transposing an array. That can be achieved with zip function.

how to replace specific characters with different rules with python? [closed]

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I have a file and some substitution is needed: replace "，" with "," and all other characters not in rule2 with a whitespace, how can I do that？

What about this?
text = text.replace("，", ",")

You can use the regular expressions module:
text = re.sub('，', ',', text)
text = re.sub(negated_rule2, ' ', text)
where your negation of "rule2" is formatted using the regular expressions syntax (see link above).