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Python List to Float conversion [closed]

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The result of one of my web scrapes produces the following:
price = ['$1049.98']
which is type list, and I am trying to convert this to float.

Take the first and only element in the list, strip off the $ sign and convert it to a float:
parsed_price = float(price[0].lstrip('$'))

import re
price = ['$1049.98']
get_values = [float(re.search(r'(\d+\.\d+)+',cost).group()) for cost in price]
print(get_values)
>>>[1049.98]

Here is my simple solution. Hope that helps.
price = ['$1049.98']
result = [float(i[1:]) for i in price][0]
print(result)
You can change the index(I mean, replace 0 with other numbers) or loop though the list(result).

"while True" intermediate solutions [closed]

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I'm working with big multidimensional arrays. I want to know after x loops the values S,S2,E,E2
I want to find all the solutions of a loop.
I have a code that iterates with a greedy. My output is a list of numers. I want to save the arrays that generate those numbers. My code:
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
print f2-f
else:
break
If i run this code I have a list of f2-f but I need also to save the f,S,S2,f2,E,E2 created in each passage of the while.. Thank you

results = []
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
results.append((f,S,S2,E,E2))
print f2-f
print "intermediate result:", results[-1]
else:
break

Please help me understand this - Python [closed]

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Closed 9 years ago.
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Can someone please explain how this works? Like, how does it count?
for a in range(2,5):
for b in range(1,2):
print (a+b,end=" ")
print("---",end=" ")
the output is: 3 --- 4 --- 5 ---

It just adds 2, 3, 4 with 1 and prints the result.
In Python-3.x, print() is a function and the argument end in it means
string appended after the last value, default a newline
Values returned by range(x, y) are [x, y-1]
If you don't know the usage of a function, you could open ipython and type something like the following:
help(print)
help(range)

Check if part of text is in tuple [closed]

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How to check if part of text is in tuple?
For example:
my_data = ((1234L,), (23456L,), (3333L,))
And we need to find if 123 or 1234 is in tuple.
I didn't worked lot with tuples before.
In array we use:
if variable in array
But its not working for tuples like my_data
PS. 1st answer solved problem.

def findIt(data, num):
num = str(num)
return any(num in str(i) for item in data for i in item)
data = ((1234L,), (23456L,), (3333L,))
print findIt(data, 123)
Output
True

Python List sorting by columns [closed]

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If I had a list
['xxxx', 'oooo', 'xxxx', 'oooo'......etc]
which looks like
(xxxx)
(oooo)
(xxxx)
(oooo)
and the list could be as long as the user inputs,
how would I make a new list sorted by each column which would look like:
['xoxo', 'xoxo', 'xoxo', 'xoxo']
which would be
(xoxo)
(xoxo)
(xoxo)
(xoxo)

myList=['xxxx', 'oooo', 'xxxx', 'oooo']
print [''.join(element) for element in zip(*myList)]
Output
['xoxo', 'xoxo', 'xoxo', 'xoxo']
What you are looking for, is called, transposing an array. That can be achieved with zip function.