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I have a file and some substitution is needed: replace "，" with "," and all other characters not in rule2 with a whitespace, how can I do that？
What about this?
text = text.replace("，", ",")
You can use the regular expressions module:
text = re.sub('，', ',', text)
text = re.sub(negated_rule2, ' ', text)
where your negation of "rule2" is formatted using the regular expressions syntax (see link above).
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I have strings of this form:
FPLBX(2x3)ZE(53x13)(4x7)ZGQO
I want to find the blocks in parenthesis but only when they're not preceded by another group.
The other way around works perfectly fine but I can't make it work with preceding.
current regex:
(\(\d*x\d*\))(?<!\))
You simply need to put the so-called negative lookbehind assertion, i.e. the (?<!\))-part, in front of your search re:
>>> import re
>>> txt = "FPLBX(2x3)ZE(53x13)(4x7)ZGQO"
>>> re.findall(r"(?<!\))(\(\d*x\d*\))", txt)
['(2x3)', '(53x13)']
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I am trying to remove a " ' " character from a python string .
Below code gives a syntax error, How to achieve this task
final = string.replace(old_str, '\'', '')
To replace single quotes
final = old_str.replace("'", "")
str = "this is string example....wow!!! this is really string"
print(str.replace("is", "was"))
Here's an example of how to correctly use the replace function. This replaces all the is's with was's. It's hard to see what you're trying to do but use this as a guide.
You can do this
string = "some ' string"
final = string.replace('\'','')
print(final)
output
some string
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I want to reverse and split a string in Python. Please suggest how?
'this is Xing Min' should return ['niM', 'gniX', 'si', 'siht'].
You can do it as:
my_str[::-1].split()
Example
>>> s = 'Hello World'
>>> print s[::-1].split()
['dlroW'. 'olleH']
>>> s = 'this is Xing Min'
>>> print s[::-1].split()
['niM', 'gniX', 'si', 'siht']
Here, the [::-1] gets the whole string in reverse order. This is the syntax [start:end:step]. When you don't specify a start and end, it will deal with the whole string. When you do [::-1], the step value is -1 which means that the string is read in reverse.
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I need to parse a string from this:
CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt
To this:
ES1-HER / ES1-Seura
Any easy way to do this with regex?
>>> import re
>>> s = 'CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt'
>>> re.findall('OU=([^,]+)', s)
['Computers', 'ES1-HER', 'ES1-Seura', 'RES-ES1']
>>> re.findall('OU=([^,]+)', s)[1:3]
['ES1-HER', 'ES1-Seura']
>>> ' / '.join(re.findall('OU=([^,]+)', s)[1:3])
'ES1-HER / ES1-Seura'
Don't use str as a variable name. It shadows builtin function str.
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What regex would I use to get urls that follow this pattern:
'https://www.facebook.com/' + 'some text' + 'browser'
Meaning that it starts with the facebook url, has some text which varies, and then has the word 'browser' at the end?
Thanks!
r'https://www\.facebook\.com/.*browser'
. is a regex metacharacter meaning "any single character", so the literal periods have to be escaped with backslashes. * means "any number of matches for the previous thing", so .* means "any number of arbitrary characters". The r in front of the string marks it as a raw string literal, so backslashes are processed by the regex engine instead of the Python parser.
I think it is r'https://www\.facebook\.com/.*browser$' , because the word 'browser' is at the end.