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Reverse and split string: Python [closed]

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I want to reverse and split a string in Python. Please suggest how?
'this is Xing Min' should return ['niM', 'gniX', 'si', 'siht'].

You can do it as:
my_str[::-1].split()
Example
>>> s = 'Hello World'
>>> print s[::-1].split()
['dlroW'. 'olleH']
>>> s = 'this is Xing Min'
>>> print s[::-1].split()
['niM', 'gniX', 'si', 'siht']
Here, the [::-1] gets the whole string in reverse order. This is the syntax [start:end:step]. When you don't specify a start and end, it will deal with the whole string. When you do [::-1], the step value is -1 which means that the string is read in reverse.

Check if part of text is in tuple [closed]

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How to check if part of text is in tuple?
For example:
my_data = ((1234L,), (23456L,), (3333L,))
And we need to find if 123 or 1234 is in tuple.
I didn't worked lot with tuples before.
In array we use:
if variable in array
But its not working for tuples like my_data
PS. 1st answer solved problem.

def findIt(data, num):
num = str(num)
return any(num in str(i) for item in data for i in item)
data = ((1234L,), (23456L,), (3333L,))
print findIt(data, 123)
Output
True

How to find every item of the list in a string [closed]

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strSpecialChars=['%', 'dBu', 'dB', 'kHz', 'Hz']
str = "-20.0dB"
I need to get True here as it checks for each item of the list - strSpecialChars in the string str.

Use the any() function to test each value:
>>> strSpecialChars=['%', 'dBu', 'dB', 'kHz', 'Hz']
>>> yourstr = "-20.0dB"
>>> any(s in yourstr for s in strSpecialChars)
True
where I renamed str to yourstr to avoid masking the built-in type.
any() will only advance the generator expression passed to it until a True value is returned; this means only the first 3 options are tested for your example.
You could use str.endswith() here:
any(yourstr.endswith(s) for s in strSpecialChars)
to limit matches to only those that end with any of the special characters.

map(lambda s: s in "-20.0dB", strSpecialChars)
You may need to convert the output through list to actually see it.

how to replace specific characters with different rules with python? [closed]

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I have a file and some substitution is needed: replace "，" with "," and all other characters not in rule2 with a whitespace, how can I do that？

What about this?
text = text.replace("，", ",")

You can use the regular expressions module:
text = re.sub('，', ',', text)
text = re.sub(negated_rule2, ' ', text)
where your negation of "rule2" is formatted using the regular expressions syntax (see link above).

how to convert timecode into seconds:fractions_of_a_second? [closed]

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Given timecode in this format
00:00:00,0
What is the best way to convert this into seconds.fractions_of_a_second?

Here's a link for some python code to handle SMPTE timecodes http://code.google.com/p/pytimecode/
Hope it helps...

The datetime module is your friend in this case
import datetime
time_string = "17:48:12,98"
t = datetime.datetime.strptime(time_string, "%H:%M:%S,%f")
seconds = 60 * t.minute * t.hour
print (seconds, t.microsecond)