Catch any error in Python [duplicate] - python

This question already has answers here:
How can I write a `try`/`except` block that catches all exceptions?
(10 answers)
Closed 1 year ago.
Is it possible to catch any error in Python? I don't care what the specific exceptions will be, because all of them will have the same fallback.

Using except by itself will catch any exception short of a segfault.
try:
something()
except:
fallback()
You might want to handle KeyboardInterrupt separately in case you need to use it to exit your script:
try:
something()
except KeyboardInterrupt:
return
except:
fallback()
There's a nice list of basic exceptions you can catch here. I also quite like the traceback module for retrieving a call stack from the exception. Try traceback.format_exc() or traceback.print_exc() in an exception handler.

try:
# do something
except Exception, e:
# handle it
For Python 3.x:
try:
# do something
except Exception as e:
# handle it

You might want also to look at sys.excepthook:
When an exception is raised and uncaught, the interpreter calls
sys.excepthook with three arguments, the exception class, exception
instance, and a traceback object. In an interactive session this
happens just before control is returned to the prompt; in a Python
program this happens just before the program exits. The handling of
such top-level exceptions can be customized by assigning another
three-argument function to sys.excepthook.
Example:
def except_hook(type, value, tback):
# manage unhandled exception here
sys.__excepthook__(type, value, tback) # then call the default handler
sys.excepthook = except_hook

Quoting the bounty text:
I want to be able to capture ANY exception even weird ones like
keyboard interrupt or even system exit (e.g. if my HPC manger throws
an error) and get a handle to the exception object e, whatever it
might be. I want to process e and custom print it or even send it by
email
Look at the exception hierarchy, you need to catch BaseException:
BaseException
+-- SystemExit
+-- KeyboardInterrupt
+-- GeneratorExit
+-- Exception
This will capture KeyboardInterrupt, SystemExit, and GeneratorExit, which all inherit from BaseException but not from Exception, e.g.
try:
raise SystemExit
except BaseException as e:
print(e.with_traceback)

Not mentioning the type of exception you want to handle itself does the job.
Try this:
try:
#code in which you expect an exception
except:
#prints the exception occured
if you want to know the type of exception that occurred:
try:
# code in which you expect an exception
except Exception as e:
print(e)
# for any exception to be catched
print(type(e))
# to know the type of exception.
for detailed explanation go trough this
https://www.tutorialspoint.com/python/python_exceptions.htm

# in python 3
# if you want the error
try:
func()
except Exception as e:
exceptionFunc(e)
# if you simply want to know an error occurs
try:
func()
except:
exceptionFunc()
# if you don't even wanna do anything
try:
func()
except:
pass

The following only worked for me (both in PY2 and PY3):
try:
# (Anything that produces any kind of error)
except:
ertype = sys.exc_info()[0] # E.g. <class 'PermissionError'>
description = sys.exc_info()[1] # E.g. [Errno 13] Permission denied: ...
# (Handle as needed )

Built-In Exceptions in Python
Built-In exception classes are divided into Base error classes from which the error classes are defined and Concrete error classes which define exceptions which you are more likely to see time to time.
The more detailed document about the buit-In exception can be found in [https://docs.python.org/3/library/exceptions.html]
Custom Exceptions
It is used to fit your specific application situation. For example, you can create your own exception as RecipeNotValidError as the recipe is not valid in your class for developing a cooking app.
Implementation
class RecipeNotValidError(Exception):
def __init__(self):
self.message = "Your recipe is not valid"
try:
raise RecipeNotValidError
except RecipeNotValidError as e:
print(e.message)
These are custom exceptions that are not defined in the standard library. The steps you can follow to create custom classes are :
Subclass the Exception class.
Create a new Exception class of your choice.
Write your code and use the try...except flow to capture and handle your custom exception.

Related

How to catch PyGetWindowException when using pygetwindow in Python?

I have a script which uses pygetwindow module to do some operations on a specific window. While the script runs, I get the following exception:
File "C:\Program Files (x86)\Python38-32\lib\site-packages\pygetwindow\_pygetwindow_win.py", line 237, in activate
_raiseWithLastError()
File "C:\Program Files (x86)\Python38-32\lib\site-packages\pygetwindow\_pygetwindow_win.py", line 97, in _raiseWithLastError
raise PyGetWindowException('Error code from Windows: %s - %s' % (errorCode, _formatMessage(errorCode)))
pygetwindow.PyGetWindowException: Error code from Windows: 0 - The operation completed successfully.
I'm okay with the exception occurring but I want to catch this exception explicitly. I have done the following to try and catch this exception:
try:
#implementation
except pygetwindow.PyGetWindowException:
#handle exception
and
try:
#implementation
except PyGetWindowException:
#handle exception
Neither of the above catches the exception. If I use either of the above, I get another exception:
NameError: name 'PyGetWindowException' is not defined
or
NameError: name 'pygetwindow' is not defined
I don't want to catch the general Exception and then handle it since in case of other exceptions, I want to handle it differently. Is there something wrong in how I'm trying to catch this exception or is there a way to avoid this exception altogether?
EDIT: To be very clear, I have already imported pygetwindow.
You should have import pygetwindow at the begging of your script. It complains about not knowing what pygetwindow is.
Update
From the source file, it was clear that in order to use PyGetWindowException, you need to import the exception specifically (and not just import pygetwindow). Therefore, in order to catch the exception, one will have to do:
from pygetwindow import PyGetWindowException
After this import, you can use the exception in the normal way:
try:
#implementation
except PyGetWindowException:
#handle exception
Update 2
Another general way to do this would be to get the exception name from general exception and compare.
try:
try:
#implementation
except Exception as e:
if e.__class__.__name__ == 'PyGetWindowException':
#handle exception
else:
raise e
except Exception as e:
#handle other exceptions except pygetwindow exception
Original answer (not recommended)
Found a way to solve this question in this answer.
From the source of pygetwindow, it was clear that, whenever PyGetWindowException is raised, it is accompanied by the text:
"Error code from Windows:"
which indicates the error code given by Windows.
Based on this information, I did the following:
try:
try:
#Implementation
except Exception as e:
if "Error code from Windows" in str(e)
# Handle pygetwindow exception
else:
raise e
except Exception as e:
#handle other exceptions
This is another way (although the first one and second one are the correct and straightforward solutions) to solve the problem.

Count exception thrown in Python [duplicate]

Is it possible to tell if there was an exception once you're in the finally clause? Something like:
try:
funky code
finally:
if ???:
print('the funky code raised')
I'm looking to make something like this more DRY:
try:
funky code
except HandleThis:
# handle it
raised = True
except DontHandleThis:
raised = True
raise
else:
raised = False
finally:
logger.info('funky code raised %s', raised)
I don't like that it requires to catch an exception, which you don't intend to handle, just to set a flag.
Since some comments are asking for less "M" in the MCVE, here is some more background on the use-case. The actual problem is about escalation of logging levels.
The funky code is third party and can't be changed.
The failure exception and stack trace does not contain any useful diagnostic information, so using logger.exception in an except block is not helpful here.
If the funky code raised then some information which I need to see has already been logged, at level DEBUG. We do not and can not handle the error, but want to escalate the DEBUG logging because the information needed is in there.
The funky code does not raise, most of the time. I don't want to escalate logging levels for the general case, because it is too verbose.
Hence, the code runs under a log capture context (which sets up custom handlers to intercept log records) and some debug info gets re-logged retrospectively:
try:
with LogCapture() as log:
funky_code() # <-- third party badness
finally:
# log events are buffered in memory. if there was an exception,
# emit everything that was captured at a WARNING level
for record in log.captured:
if <there was an exception>:
log_fn = mylogger.warning
else:
log_fn = getattr(mylogger, record.levelname.lower())
log_fn(record.msg, record.args)
Using a contextmanager
You could use a custom contextmanager, for example:
class DidWeRaise:
__slots__ = ('exception_happened', ) # instances will take less memory
def __enter__(self):
return self
def __exit__(self, exc_type, exc_val, exc_tb):
# If no exception happened the `exc_type` is None
self.exception_happened = exc_type is not None
And then use that inside the try:
try:
with DidWeRaise() as error_state:
# funky code
finally:
if error_state.exception_happened:
print('the funky code raised')
It's still an additional variable but it's probably a lot easier to reuse if you want to use it in multiple places. And you don't need to toggle it yourself.
Using a variable
In case you don't want the contextmanager I would reverse the logic of the trigger and toggle it only in case no exception has happened. That way you don't need an except case for exceptions that you don't want to handle. The most appropriate place would be the else clause that is entered in case the try didn't threw an exception:
exception_happened = True
try:
# funky code
except HandleThis:
# handle this kind of exception
else:
exception_happened = False
finally:
if exception_happened:
print('the funky code raised')
And as already pointed out instead of having a "toggle" variable you could replace it (in this case) with the desired logging function:
mylog = mylogger.WARNING
try:
with LogCapture() as log:
funky_code()
except HandleThis:
# handle this kind of exception
else:
# In case absolutely no exception was thrown in the try we can log on debug level
mylog = mylogger.DEBUG
finally:
for record in log.captured:
mylog(record.msg, record.args)
Of course it would also work if you put it at the end of your try (as other answers here suggested) but I prefer the else clause because it has more meaning ("that code is meant to be executed only if there was no exception in the try block") and may be easier to maintain in the long run. Although it's still more to maintain than the context manager because the variable is set and toggled in different places.
Using sys.exc_info (works only for unhandled exceptions)
The last approach I want to mention is probably not useful for you but maybe useful for future readers who only want to know if there's an unhandled exception (an exception that was not caught in any except block or has been raised inside an except block). In that case you can use sys.exc_info:
import sys
try:
# funky code
except HandleThis:
pass
finally:
if sys.exc_info()[0] is not None:
# only entered if there's an *unhandled* exception, e.g. NOT a HandleThis exception
print('funky code raised')
raised = True
try:
funky code
raised = False
except HandleThis:
# handle it
finally:
logger.info('funky code raised %s', raised)
Given the additional background information added to the question about selecting a log level, this seems very easily adapted to the intended use-case:
mylog = WARNING
try:
funky code
mylog = DEBUG
except HandleThis:
# handle it
finally:
mylog(...)
You can easily assign your caught exception to a variable and use it in the finally block, eg:
>>> x = 1
>>> error = None
>>> try:
... x.foo()
... except Exception as e:
... error = e
... finally:
... if error is not None:
... print(error)
...
'int' object has no attribute 'foo'
Okay, so what it sounds like you actually just want to either modify your existing context manager, or use a similar approach: logbook actually has something called a FingersCrossedHandler that would do exactly what you want. But you could do it yourself, like:
#contextmanager
def LogCapture():
# your existing buffer code here
level = logging.WARN
try:
yield
except UselessException:
level = logging.DEBUG
raise # Or don't, if you just want it to go away
finally:
# emit logs here
Original Response
You're thinking about this a bit sideways.
You do intend to handle the exception - you're handling it by setting a flag. Maybe you don't care about anything else (which seems like a bad idea), but if you care about doing something when an exception is raised, then you want to be explicit about it.
The fact that you're setting a variable, but you want the exception to continue on means that what you really want is to raise your own specific exception, from the exception that was raised:
class MyPkgException(Exception): pass
class MyError(PyPkgException): pass # If there's another exception type, you can also inherit from that
def do_the_badness():
try:
raise FileNotFoundError('Or some other code that raises an error')
except FileNotFoundError as e:
raise MyError('File was not found, doh!') from e
finally:
do_some_cleanup()
try:
do_the_badness()
except MyError as e:
print('The error? Yeah, it happened')
This solves:
Explicitly handling the exception(s) that you're looking to handle
Making the stack traces and original exceptions available
Allowing your code that's going to handle the original exception somewhere else to handle your exception that's thrown
Allowing some top-level exception handling code to just catch MyPkgException to catch all of your exceptions so it can log something and exit with a nice status instead of an ugly stack trace
If it was me, I'd do a little re-ordering of your code.
raised = False
try:
# funky code
except HandleThis:
# handle it
raised = True
except Exception as ex:
# Don't Handle This
raise ex
finally:
if raised:
logger.info('funky code was raised')
I've placed the raised boolean assignment outside of the try statement to ensure scope and made the final except statement a general exception handler for exceptions that you don't want to handle.
This style determines if your code failed. Another approach might me to determine when your code succeeds.
success = False
try:
# funky code
success = True
except HandleThis:
# handle it
pass
except Exception as ex:
# Don't Handle This
raise ex
finally:
if success:
logger.info('funky code was successful')
else:
logger.info('funky code was raised')
If exception happened --> Put this logic in the exception block(s).
If exception did not happen --> Put this logic in the try block after the point in code where the exception can occur.
Finally blocks should be reserved for "cleanup actions," according to the Python language reference. When finally is specified the interpreter proceeds in the except case as follows: Exception is saved, then the finally block is executed first, then lastly the Exception is raised.

How many exceptions are possible when reading a json in Python/django?

I have:
MY_PATH_DIR = 'path/to/my/json/file.json'
try:
with open(MY_PATH_DIR, 'r') as f:
MY_PATH_DIR = json.load(f)
except IOError, RuntimeError, ValueError:
pass
except PermissionDenied:
pass
And I want to catch all possible errors. With
IOError - I am catching errors when the file doesn't exist or has a
syntax error (non valid JSON).
RuntimeError - couldn't test it but I think that makes sense from the
documentation in case of an unexpected error
ValueError - I got from here in case nothing got returned
PermissionDenied - is a specific Django error
Are there any other Exceptions that would make sense? I'm not sure if OSError makes sense here. I think that would be raised earlier, right?
The purpose of capturing exceptions is to control the program's behavior when something bad happened, but in an expected way. If you are not even sure what would cause that exception happen, capturing it would only swallow the underlying programming errors you might have.
I wouldn't add as many kinds of exception as possible to that single block of code, you should only add what you care about. To take it to extreme, each line of code would yield certain exceptions but for obvious reason you couldn't do try except for all of them.
Edit:
For the sake of correctness, since you mentioned I don't want my code to break in any case, you could simply do:
try:
# json.load
except Exception as e:
print "Let's just ignore all exceptions, like this one: %s" % str(e)
This is would give you what exception happens as output.
import random
import sys
def main():
"""Demonstrate the handling of various kinds of exceptions."""
# This is like what you are doing in your code.
exceptions = IOError, RuntimeError, ValueError
try:
raise random.choice(exceptions)()
except exceptions as error:
print('Currently handling:', repr(error))
# The following is not much different from Shang Wang's answer.
try:
raise random.choice(exceptions)()
except Exception as error:
print('Currently handling:', repr(error))
# However, the following code will sometimes not handle the exception.
exceptions += SystemExit, KeyboardInterrupt, GeneratorExit
try:
raise random.choice(exceptions)()
except Exception as error:
print('Currently handling:', repr(error))
# The code can be slightly altered to take the new errors into account.
try:
raise random.choice(exceptions)()
except BaseException as error:
print('Currently handling:', repr(error))
# This does not take into account classes not in the exception hierarchy.
class Death:
pass
try:
raise Death()
except BaseException as error:
print('Currently handling:', repr(error))
# If your version of Python does not consider raising an exception from an
# instance of a class not derived from the BaseException class, the way to
# get around this problem would be with the following code instead.
try:
raise Death()
except:
error = sys.exc_info()[1]
print('Currently handling:', repr(error))
if __name__ == '__main__':
main()

Catching an exceptions in __enter__ in the calling code in Python

Is there a way I can catch exceptions in the __enter__ method of a context manager without wrapping the whole with block inside a try?
class TstContx(object):
def __enter__(self):
raise Exception("I'd like to catch this exception")
def __exit__(self, e_typ, e_val, trcbak):
pass
with TstContx():
raise Exception("I don't want to catch this exception")
pass
I know that I can catch the exception within __enter__() itself, but can I access that error from the function that contains the with statement?
On the surface the question Catching exception in context manager __enter__() seems to be the same thing but that question is actually about making sure that __exit__ gets called, not with treating the __enter__ code differently from the block that the with statement encloses.
...evidently the motivation should be clearer. The with statement is setting up some logging for a fully automated process. If the program fails before the logging is set up, then I can't rely on the logging to notify me, so I have to do something special. And I'd rather achieve the effect without having to add more indentation, like this:
try:
with TstContx():
try:
print "Do something"
except Exception:
print "Here's where I would handle exception generated within the body of the with statement"
except Exception:
print "Here's where I'd handle an exception that occurs in __enter__ (and I suppose also __exit__)"
Another downside to using two try blocks is that the code that handles the exception in __enter__ comes after the code that handles exception in the subsequent body of the with block.
You can catch the exception using try/except inside of __enter__, then save the exception instance as an instance variable of the TstContx class, allowing you to access it inside of the with block:
class TstContx(object):
def __enter__(self):
self.exc = None
try:
raise Exception("I'd like to catch this exception")
except Exception as e:
self.exc = e
return self
def __exit__(self, e_typ, e_val, trcbak):
pass
with TstContx() as tst:
if tst.exc:
print("We caught an exception: '%s'" % tst.exc)
raise Exception("I don't want to catch this exception")
Output:
We caught an exception: 'I'd like to catch this exception'.
Traceback (most recent call last):
File "./torn.py", line 20, in <module>
raise Exception("I don't want to catch this exception")
Exception: I don't want to catch this exception
Not sure why you'd want to do this, though....
You can use contextlib.ExitStack as outlined in this doc example in order to check for __enter__ errors separately:
from contextlib import ExitStack
stack = ExitStack()
try:
stack.enter_context(TstContx())
except Exception: # `__enter__` produced an exception.
pass
else:
with stack:
... # Here goes the body of the `with`.

Python exception logging, correct syntax?

I'm adding logging to some python code that deals with exceptions, in the example below what's the correct syntax for wanting to log exception details (e.g. via logger.exception()) when a TypeError or AttributeError occurs?
try:
...
except (TypeError, AttributeError):
# want to do a logger.exception(x) here but not sure what to use for x
...
raise CustomError("Unable to parse column status)
exception(...) is just a convenience method which takes a message just like the other methods:
def exception(self, msg, *args):
"""
Convenience method for logging an ERROR with exception information.
"""
self.error(msg, exc_info=1, *args)
So you would just use it like
logger.exception("Some error message")
and the logging handler will automatically add the exception information from the current exception. Only use this in an exception handler (i.e. in a except: block)!
If you want the exception details, you need to bind the exception itself to a local variable, like this:
except (TypeError, AttributeError), e:
# e is the Exception object
logger.exception(e)
If you need to do different things based on the type of the exception, then you can catch them separately:
except TypeError, e:
logger.exception('There was a Type Error; details are %s' % e)
# Do something, or raise another exception
except AttributeError, e:
logger.exception('There was an Attribute Error; details are %s' % e)
# Do something, or raise another exception
And if you need more information about the context of the exception itself, look into the sys.exc_info() function; it can get you the traceback, and the details about exactly where the exception occurred.

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