I'm teaching myself python with the aid of Head First Programming.
I thought I might tweak their example more to my liking, but I think I'm missing something about time.sleep.
My code is
print("Welcome to SuperBeans!")
time.sleep(3)
answer = input("Do you need a price now? y/n: ")
But rather than pausing for three seconds after the welcome message, it waits 3 minutes, then displays both the message and the input request. What am I missing?
Additionally, the program seems to hang indefinitely when running the "poll" function I defined, without ever displaying the "polling..." notice. I know get_price() is working because it prints it in another section ...
def poll():
price = 99.99
print(price)
while price > 4.74:
print("Polling...")
price = get_price()
time.sleep(5)
print("Buy!")
So why is the welcome pausing before I think it should be, and why is the poll() function hanging?
As discussed in comments above, Python output is being buffered, so the programs run (and sleeps for the right time etc) but you don't see the output for a while.
If you're running Python from a nonstandard console, you need to pass the "-u" option to Python to disable the buffering. I.e.:
python -u foo.py
About why is poll() function hanging, this may be because it stays in the while loop.
So question: is get_price() ever returning something strictly greater than 4.74 ? (hint: print the value returned)
Related
I have a python script driving me crazy.
Right now i have a infinite loop that checks a data and get into a function in a specific situation.
while true:
time.sleep(1)
peso = getPeso()
if peso > 900:
processo = multiprocessing.Process(target=processo_automatico)
processo.start()
processo.join()
andare() #this is where it should go after the process.
The function works a lot of times but nondeterministically it hangs at the end of the process (literally finish and hangs there forever. How do i know this? i tried with logs).
So at the beginning I tried to terminate it with exit codes:
processo.join(timeout=10)
if processo.exitcode is None:
errore_cicalino() #this is just a warning for me
processo.kill()
elif processo.exitcode != 0:
errore_cicalino()
processo.kill()
but this never worked. NEVER.
So i tried without the join(). Tried with is_alive().
time.sleep(10)
if processo.is_alive():
processo.terminate()
errore_cicalino()
and even like this, it never entered this if.
This is driving me crazy, i accept the fact that the process could fail but, after the timeout, i should be able to terminate it and carry on with the script.
The script is running on a Raspberry Pi 4 2 GB.
Any idea?
Minimal example:
while True:
time.sleep(10)
processo = multiprocessing.Process(target=processo_automatico)
processo.start()
processo.join()
code randomly hangs at the end of the started process and cannot terminate in any way.
processo_automatico() is a function where the script get a picture from a camera and upload it in a DB thanks to another module.
def processo_automatico():
now = str(datetime.now())
now = now.replace(":", "-")
foto = CAMERA.read_camera()
cv2.imwrite("/var/www/html/" + now + ".png", foto)
DB.insert("/var/www/html/" + now + ".png", peso)
They don't create exceptions and i already tried to add to the end of the function a log info(executed even when the code hangs)
Solved.
What was that?
Well, my focus was on the end of the process while the issue was right at the start.
See the function getPeso()? That one just gets values from the serial.
After a few hours of getting those values the raspberry py just starts to see random values and you gotta reboot to fix it.
I wasn't prepared for that. My function just became a recursive infinite function with no break.
My tip, do not use infinite cycles except if you really need to or at least think if it could get stuck somewhere and check it.
Is there an easy way to execute time delay (like time.sleep(3)) between every statement of Python code without having to explicitly write between every statement?
Like in the below Python Script which performs certain action on SAP GUI window. Sometimes, the script continues to the next statement before the previous statement is complete. So, I had to add a time delay between every statement so that it executes correctly. It is working with time delay, but I end up adding time.sleep(3) between every line. Just wondering if there is a better way?
import win32com.client
import time
sapgui = win32com.client.GetObject("SAPGUI").GetScriptingEngine
session = sapgui.FindById("ses[0]")
def add_record(employee_num, start_date, comp_code):
try:
time.sleep(3)
session.findById("wnd[0]/tbar[0]/okcd").text = "/npa40"
time.sleep(3)
session.findById("wnd[0]").sendVKey(0)
time.sleep(3)
session.findById("wnd[0]/usr/ctxtRP50G-PERNR").text = employee_num
time.sleep(3)
session.findById("wnd[0]").sendVKey(0)
time.sleep(3)
session.findById("wnd[0]/usr/ctxtRP50G-EINDA").text = start_date
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-WERKS[1,0]").text = comp_code
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-PERSG[2,0]").text = "1"
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT/ctxtRP50G-PERSK[3,0]").text = "U1"
time.sleep(3)
session.findById("wnd[0]/usr/tblSAPMP50ATC_MENU_EVENT").getAbsoluteRow(0).selected = True
time.sleep(3)
return "Pass"
except:
return "failed"
The right way to do what you asked for is almost certainly to use the debugger, pdb.
The right way to do what you want is probably something completely different: find some signal that tells you that the step is done, and wait for that signal. With problems like this, almost any time you pick will be way, way too long 99% of the time, but still too short 1% of the time. That signal may be joining a thread, or waiting on a (threading or multiprocessing) Condition, or getting from a queue, or awaiting a coroutine or future, or setting the sync flag on an AppleEvent, or… It really depends on what you're doing.
But if you really want to do this, you can use settrace:
def sleeper(frame, event, arg):
if event == 'line':
time.sleep(2)
return sleeper
sys.settrace(sleeper)
One small problem is that the notion of line used by the interpreter may well not be what you want. Briefly, a 'line' trace event is triggered whenever the ceval loop jumps to a different lnotab entry (see lnotab_notes.txt in the source to understand what that means—and you'll probably need at least a passing understanding of how bytecode is interpreted, at least from reading over the dis docs, to understand that). So, for example, a multiline expression is a single line; the line of a with statement may appear twice, etc.1
And there's probably an even bigger problem.
Sometimes, the script continues to next step before the previous step is fully complete.
I don't know what those steps are, but if you put the whole thread to sleep for 2 seconds, there's a good chance the step you're waiting for won't make any progress, because the thread is asleep. (For example, you're not looping through any async or GUI event loops, because you're doing nothing at all.) If so, then after 2 seconds, it'll still be just as incomplete as it was before, and you'll have wasted 2 seconds for nothing.
1. If your notion of "line" is closer to what's described in the reference docs on lexing and parsing Python, you could create an import hook that walks the AST and adds an expression statement with a Call to time.sleep(2) after each list element in each body with a module, definition, or compound statement (and then compiles and execs the result as usual).
Anything you want to happen in a program has to be explicitly stated - this is the nature of programming. This is like asking if you can print hello world without calling print("hello world").
I think the best advice to give you here is: don't think in terms of "lines", but think in term of functions.
use debugging mode and watch each and every line executing line by line.
So the question is how to have an input function or stdin.readline function waiting for an input, while having an updating prompt i.e. The prompt contains the time in format HH:MM:SS and is refreshing every second like:
while 1:
sys.stdout.write('\r' + time.strftime(TIME_FORMAT) + ' :>')
time.sleep(1.0)
But as soon as you add an input there, of course the program waits until you write some input. The version of python I am using is 3.5.
I know I should use curses, but I am planing to write a cross-platform program and the only module I have found is clint, but it didn't have anything in the documentation on the updating prompt.
I have found something that got pretty close but has different problems:
def input_thread(L):
x = input()
L.append(x)
L = []
thread = threading.Thread(target=input_thread, args=(L,))
thread.start()
while 1:
sys.stdout.write('\r' + time.strftime(TIME_FORMAT) + '>:')
time.sleep(1.0)
sys.stdout.flush()
Now the problem remains is that when you type the input but do not press ENTER, the input on the next iteration remains but when you write something, the previous input gets replaced by the current one. Of course the previous inputs are still there in the argument L, so there is no lost input. I hope I didn't describe this to confusing.
If there is no easy way of doing this as it could be done with curses, I'm open to similar cross open tools. Thanks for your time and answers!
So, I figured out what I wanted, a few months ago but didn't answered my own quesiton.
To have a prompt with updating time, you need a separate threads that:
Updates the prompt with additional input
Catches your key strokes
The second thread handles every key-stroke and you can program it how to handle the pressed keys.
When pressing a key, the thread that updates the prompt adds the pressed keys. Also you have to configure some shortcuts for Return, Backspace, etc... to work as expected
I've got it to work and unfortunately... I don't like it. If anyone would like to see the code I will happily provide.
I'm new to programming. I''ve successfully wrote everybody's first program , however , it executes right before closing itself. How can I add a pause to the program?
Modify the code to be like this, you will learn about the below function soon enough:
print('Hello world!')
input()
Now at the end of the program it won't exit until you press Return.
Or better still, run the code in a shell like IDLE so you don't have to worry about all that.
You need to put a call to input at the bottom of your script:
print("Hello World!")
input("Press 'Enter' to exit.") # Use raw_input in Python 2.x
Doing so will keep the output window open until you press Enter.
If you literally want to add a fixed pause, use the sleep function in the time module. The is discussed in detail in the answer to How can I make a time delay in Python? . Your program then becomes:
import time
print("Hello world")
time.sleep(1)
The first line tells python that time means the module time, while the last line says to wait for 1 second. (If you wanted to wait for 2.5 seconds, then change the last line to time.sleep(2.5), etc...)
Okay, so I'm writing a very simplistic password cracker in python that brute forces a password with alphanumeric characters. Currently this code only supports 1 character passwords and a password file with a md5 hashed password inside. It will eventually include the option to specify your own character limits (how many characters the cracker tries until it fails). Right now I cannot kill this code when I want it to die. I have included a try and except snippit, however it's not working. What did I do wrong?
Code: http://pastebin.com/MkJGmmDU
import linecache, hashlib
alphaNumeric = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z",1,2,3,4,5,6,7,8,9,0]
class main:
def checker():
try:
while 1:
if hashlib.md5(alphaNumeric[num1]) == passwordHash:
print "Success! Your password is: " + str(alphaNumeric[num1])
break
except KeyboardInterrupt:
print "Keyboard Interrupt."
global num1, passwordHash, fileToCrack, numOfChars
print "What file do you want to crack?"
fileToCrack = raw_input("> ")
print "How many characters do you want to try?"
numOfChars = raw_input("> ")
print "Scanning file..."
passwordHash = linecache.getline(fileToCrack, 1)[0:32]
num1 = 0
checker()
main
The way to allow a KeyboardInterrupt to end your program is to do nothing. They work by depending on nothing catching them in an except block; when an exception bubbles all the way out of a program (or thread), it terminates.
What you have done is to trap the KeyboardInterrupts and handle them by printing a message and then continuing.
As for why the program gets stuck, there is nothing that ever causes num1 to change, so the md5 calculation is the same calculation every time. If you wanted to iterate over the symbols in alphaNumeric, then do that: for symbol in alphaNumeric: # do something with 'symbol'.
Of course, that will still only consider every possible one-character password. You're going to have to try harder than that... :)
I think you're also confused about the use of classes. Python does not require you to wrap everything inside a class. The main at the end of your program does nothing useful; your code runs because it is evaluated when the compiler tries to figure out what a main class is. This is an abuse of syntax. What you want to do is put this code in a main function, and call the function (the same way you call checker currently).
Besides printing, you need to actually exit your program when capturin KeyboardInterrupt, you're only printing a message.
This is what worked for me...
import sys
try:
....code that hangs....
except KeyboardInterrupt:
print "interupt"
sys.exit()
Well, when you use that try and except block, the error is raised when that error occurs. In your case, KeyboardInterrupt is your error here. But when KeyboardInterrupt is activated, nothing happens. This due to having nothing in the except part. You could do this after importing sys:
try:
#Your code#
except KeyboardInterrupt:
print 'Put Text Here'
sys.exit()
sys.exit() is an easy way to safely exit the program. This can be used for making programs with passwords to end the program if the password is wrong or something like that. That should fix the except part. Now to the try part:
If you have break as the end of the try part, nothing is going to happen. Why? Because break only works on loops, most people tend to do it for while loops. Let's make some examples. Here's one:
while 1:
print 'djfgerj'
break
The break statement will stop and end the loop immediately unlike its brother continue, which continues the loop. That's just extra information. Now if you have break in a something like this:
if liners == 0:
break
That's going to depend where that if statement is. If it is in a loop, it is going to stop the loop. If not, nothing is going to happen. I am assuming you made an attempt to exit the function which didn't work. It looks like the program should end, so use sys.exit() like I showed you above. Also, you should group that last piece of code (in the class) into a seperate function. I hope this helps you!