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Does someone know how to convert this result: u'001' to 001 to put it in a variable path: Z:\ProjectPath\001\
In advance, thanks a lot for your help!
you can use format to achieve you purpose
>>> IN = u'001'
>>> OUT = "Z:\\ProjectPath\\{}\\".format(IN)
>>> print(OUT)
Z:\ProjectPath\001\
According to #hop's suggestion, you can use os.path to compose your path.
>>> OUT = os.path.join("Z:", os.sep, "ProjectPath", "{}".format(IN))
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How do I write a Python program to print the pattern?
543210
432105
321054
210543
054321
543210
You can do it by something like this:
a = "543210"
print(a)
for i in range(6):
a = a + (a[0])
a = a[1:]
print(a)
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Hi I need to remove the duplicates in python but only when they are in a row. For example:
Input: AAABBCCDDAA
Output:ABCDA
Could you please help me? thnks.
To learn more about text processing in Python3 I recommend training on codingame.com.
def removeDuplicates(inp):
output =""
lastCharacter=""
for character in inp:
output+=character*(character!=lastCharacter)
lastCharacter=character
return output
inpTest ="AAABBCCDDAA"
print(removeDuplicates(inpTest))
ABCDA
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How can I grab the invite code from this string?
{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}
The expected output would be "111A111A".
Any help is appreciated
I tried it in a simple way, You could give more details for further improvement.
s = "{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}"
print(s[-11: -3])
This will do it with ReGex
import re
def findInvite(s):
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
assert findInvite("{awarded:1,inviteURL:https:\/\/www.example.com\/refer\/invite\/111A111A\/}") == "111A111A"
And if this isn't a string but a dict, then change the function to:
def findInvite(d):
s = d["inviteURL"]
return re.search(r"(?<=/invite\\/).*(?=\\/)",s).group()
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Example:
var = "string"
and I want an xml output file: string.xml
Thank you!
It seams to be too easy... maybe i did not get the question right:
var = "String"
fileName = var + ".xml"
print fileName
this will print
String.xml
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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks
That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]