Python - how to change directory - python

I am doing a school assignment where I have to take input from a user and save it to a text file.
My file structure will be something like:
- Customer register
- Customer ID
- .txt files 1-5
It can be saved in the python folder and I can make the folders like this:
os.makedirs("Customer register/Customer ID")
My question is, how do I set the path the text files are to be stored in, in the directory when I don't know the directory? So that no matter where the program is run it is saved in the "Customer ID" folder I create (but on the computer the program is run on)?
Also, how do I make this work on both windows and mac?
I also want to program to be able to be executed several times, and check if the folder is there and save to the "Customer ID" folder if it already exists. Is there a way to do that?
EDIT:
This is the code I am trying to use:
try:
dirs = os.makedirs("Folder")
path = os.getcwd()
os.chdir(path + "/Folder")
print (os.getcwd())
except:
if os.path.exists:
path = os.getcwd()
unique_filename = str(uuid.uuid4())
customerpath = os.getcwd()
os.chdir(customerpath + "/Folder/" + unique_filename)
I am able to create a folder and change the directory (everything in "try" works as I want).
When this folder is created I want to create a second folder with a random generated folder name (used for saving customer files). I can't get this to work in the same way.
Error:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'C:\Users\48736\PycharmProjects\tina/Folder/979b9026-b2f6-4526-a17a-3b53384f60c4'
EDIT 2:
try:
os.makedirs("Folder")
path = os.getcwd()
os.chdir(path + "/Folder")
print (os.getcwd())
except:
if os.path.exists:
path = os.getcwd()
os.chdir(os.path.join(path, 'Folder'))
print(os.getcwd())
def userId(folderid):
try:
if not os.path.exists(folderid):
os.makedirs(folderid)
except:
if os.path.exists(folderid):
os.chdir(path + "/Folder/" + folderid)
userId(str(uuid.uuid4()))
print(os.getcwd())
So I can now create a folder, change directory to the folder I have created and create a new folder with a unique filename within that folder.
But I can't change the directory again to the folder with the unique filename.
Any suggestions?
I have tried:
os.chdir(path + "/Folder/" + folderid)
os.chdir(path, 'Folder', folderid)
os.chdir(os.path.join(path, 'Folder', folderid))
But is still just stays in: C:\Users\47896\PycharmProjects\tina\Folder

You can use relative paths in your create directory command, i.e.
os.makedirs("./Customer register/Customer ID")
to create folder in project root (=where the primary caller is located) or
os.makedirs("../Customer register/Customer ID") in parent directory.
You can, of course, traverse the files tree as you need.
For specific options mentioned in your question, please, see makedirs documentation at Python 3 docs

here is solution
import os
import shutil
import uuid
path_on_system = os.getcwd() # directory where you want to save data
path = r'Folder' # your working directory
dir_path = os.path.join(path_on_system, path)
if not os.path.exists(dir_path):
os.makedirs(dir_path)
file_name = str(uuid.uuid4()) # file which you have created
if os.path.exists(file_name) and os.path.exists(dir_path):
shutil.move(file_name,os.path.join(dir_path,file_name))
else:
print(" {} does not exist".format(file_name))

Related

For loop with files with Python

I have this code:
import os
directory = "JeuDeDonnees"
for filename in os.listdir(directory):
print("File is: "+filename)
This code run and prints files name in a VSCode/Python environment.
However, when I run it in Sikuli-IDE I got this error:
[error] SyntaxError ( "no viable alternative at input 'for'", )
How can I make this for loop run or is there an alternative that can work?
Answer found ;
Basically, in my Sikuli-IDE environnement, there's layers of Python, Java, Jython... interlocking each other so the Path finding was tedious.
src_file_path = inspect.getfile(lambda: None) #The files we're in
folder = os.path.dirname(src_file_path) # The folder we're in
directory = folder + "\JeuDeDonnees" # Where we wanna go
for filename in os.listdir(directory) # Get the files
print(filename)
We're telling the Path where we are with the current file, get the folder we're in, then moving to "\JeuDeDonnees" and the files.

How to Copy Sub Folders and files into New folder using Python

Very new to iterating over folder structures in python (and python!)
All the answers I've found on this site seem very confusing to implement to my situation. Hoping someone can assist.
I have a folder called Downloads. ( 1st level )
This folder is stored at "C:\Users\myusername\Desktop\downloads"
Within this folder I have the following subfolders. (2nd level)
Folder path example: C:\Users\myusername\Desktop\downloads\2020-03-13
2020-03-13
2020-03-13
2020-03-15... etc
Within each of these 2nd level folders I have another level of folders with pdf files.
So if I take 2020-03-13 it has a number of folders below: - 3rd level
22105853
22108288
22182889
Example path for third level:
C:\Users\myusername\Desktop\downloads\2020-03-13\22105853
All I am trying to do is create a new folder at the Downloads (1st)level and copy all the folders at the third level into it. Eliminating the second level structure basically.
Desired result.
C:\Users\myusername\Desktop\r3\downloads\NEWFOLDER\22105853
C:\Users\myusername\Desktop\r3\downloads\NEWFOLDER\22108288
C:\Users\myusername\Desktop\r3\downloads\NEWFOLDER\22182889
I started the code below and managed to recreate the file structure within a new file called Downloads: But stuck now and hoping someone can help me.
save_dir='C:\\Users\\myusername\\Desktop\\downloads\\'
localpath = os.path.join(save_dir, 'Repository')
if not os.path.exists(localpath):
try:
os.mkdir(localpath, mode=777)
print('MAKE_DIR: ' + localpath)
except OSError:
print("directory error occurred")
for root, dirs, files in os.walk(save_dir):
for dir in dirs:
path = os.path.join(localpath, dir)
if '-' not in path and not os.path.exists(path):
#(Checking for '-' to not create folders at sceond level)
os.mkdir(path, mode=777)
print(path)
This code snippet should work:
import os
from distutils.dir_util import copy_tree
root_dir = 'path/to/your/rootdir'
try:
os.mkdir('path/to/your/rootdir/dirname')
except:
pass
for folder_name in os.listdir(root_dir):
path = root_dir + folder_name
for folder_name in os.listdir(path):
copy_tree(path + folder_name, 'path/to/your/rootdir/dirname')
just replace the directory names with the names you need
Using copy_tree is probably the best way to do it, however I prefer check if there are strange files or folders in wrong place and then create folders or copy the files.
Here is another way to do that.
However be careful if you will create the repository folder inside the root folder and than you will iterate over the root folder, in listdir you will have also the Repository folder.
import os
import shutil
def main_copy():
save_dir='C:\\Users\\myusername\\Desktop\\downloads'
localpath = os.path.join(save_dir, 'Repository')
if not os.path.exists(localpath):
try:
os.mkdir(localpath, mode=777)
print('MAKE_DIR: ' + localpath)
except OSError:
print("directory error occurred")
return
for first_level in os.listdir(save_dir):
subffirstlevel = os.path.join(save_dir, first_level)
# skip repository folder
if subffirstlevel == localpath: continue
# skip eventually files
if os.path.isfile(subffirstlevel): continue
for folder_name in os.listdir(subffirstlevel):
subf = os.path.join(subffirstlevel, folder_name)
# skip eventually files
if os.path.isfile(subf): continue
newsubf = os.path.join(localpath, folder_name)
if not os.path.exists(newsubf):
try:
os.mkdir(newsubf, mode=777)
print('MAKE_DIR: ' + newsubf)
except OSError:
print("directory error occurred")
continue
for file_name in os.listdir(subf):
filename = os.path.join(subf, file_name)
if os.path.isfile(filename):
shutil.copy(filename, os.path.join(newsubf, file_name))
print("copy ", file_name)

removing substrings from subdirectory names using values held in list

I have a parent directory that contains a lot of subdirectories. I want to create a script that loops through all of the subdirectories and removes any key words that I have specified in the list variable.
I am not entirely sure how to acheive this.
Currently I have this:
import os
directory = next(os.walk('.'))[1]
stringstoremove = ['string1','string2','string3','string4','string5']
for folders in directory:
os.rename
And maybe this type of logic to check to see if the string exists within the subdirectory name:
if any(words in inputstring for words in stringstoremove):
print ("TRUE")
else:
print ("FALSE")
Trying my best to to deconstruct the task, but I'm going round in circles now
Thanks guys
Startng from your existing code:
import os
directory = next(os.walk('.'))[1]
stringstoremove = ['string1','string2','string3','string4','string5']
for folder in directory :
new_folder = folder
for r in stringstoremove :
new_folder = new_folder.replace( r, '')
if folder != new_folder : # don't rename if it's the same
os.rename( folder, new_folder )
If you want to rename those sub directories which match in your stringstoremove list then following script will be helpful.
import os
import re
path = "./" # parent directory path
sub_dirs = os.listdir(path)
stringstoremove = ['string1','string2','string3','string4','string5']
for directory_name in sub_dirs:
if os.path.isdir(path + directory):
for string in stringstoremove:
if string in directory_name:
try:
new_name = re.sub(string, "", directory_name)
os.rename(path + directory, path + new_name) # rename this directory
except Exception as e:
print (e)

Specifying a partial path for os.path.join

I have a python script that creates a PDF and saves it in a subfoler of the folder where the script is saved. I have the following that saves the file to the subfolder:
outfilename = "Test" + ".pdf" #in real code there is a var that holds the name of the file
outfiledir = 'C:/Users/JohnDoe/Desktop/dev/PARENTFOLDER/SUBFOLDER/' #parent folder is where the script is - subfolder is where the PDFs get saved to
outfilepath = os.path.join(outfiledir, outfilename)
Is there a way I can save the PDFs to the subfolder without having to specify the full path? Lets say I wanted yto make this script an exe that multiple computers could use, how would I display the path so that the PDFs are just saved in the subfoler?
Thanks!
Try it:
import os
dir_name = os.path.dirname(os.path.abspath(__file__)) + '/subdir'
path = os.path.join(dir_name, 'filename')

How to use the current folder the program is in?

When I open a file, I have to specify the directory that it is in. Is there a way to specify using the current directory instead of writing out the path name? I'm using:
source = os.listdir("../mydirectory")
But the program will only work if it is placed in a directory called "mydirectory". I want the program to work in the directory it is in, no matter what the name is.
def copyfiles(servername):
source = os.listdir("../mydirectory") # directory where original configs are located
destination = '//' + servername + r'/c$/remotedir/' # destination server directory
for files in source:
if files.endswith("myfile.config"):
try:
os.makedirs(destination, exist_ok=True)
shutil.copy(files,destination)
except:
this is a pathlib version:
from pathlib import Path
HERE = Path(__file__).parent
source = list((HERE / "../mydirectory").iterdir())
if you prefer os.path:
import os.path
HERE = os.path.dirname(__file__)
source = os.listdir(os.path.join(HERE, "../mydirectory"))
note: this will often be different from the current working directory
os.getcwd() # or '.'
__file__ is the filename of your current python file. HERE is now the path of the directory where your python file lives.
'.' stands for the current directory.
try:
os.listdir('./')
or:
os.listdir(os.getcwd())

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