Develop Reference

How to modify this script so that all of my files are not deleted when trying to delete files that do not have XML files with them?

I am trying to delete all .JPG files that do not have .xml files with the same name attached to them. However, when I run this script, all of my files are deleted in my directory and not just the desired images. How can I change this script so that I can just delete the images without corresponding .xml files?
Note: The only files I have in the directory are .JPG and .XML
import os
from tqdm import tqdm
path = 'C:\\users\\my_username\\path_to_directory_with_xml_and_jpg_images'
files = os.listdir(path)
for file in tqdm(files):
filename, filetype = file.split('.')
if filetype == 'xml':
continue
imgfile = os.path.join(path, file)
xmlfile = os.path.join(path, filename + '.xml')
if not os.path.exists(xmlfile):
print('{} deleted.'.format(imgfile))
os.remove(imgfile)

It's hard to tell why your code doesn't work as we don't know the exact contents of the directory. But a simpler way to do what you want could be to use the amazing pathlib library (Python >= 3.4). The method Path.with_suffix() will make the task quite easy, together with Path.glob():
from pathlib import Path
path = Path('C:\\users\\my_username\\path_to_directory_with_xml_and_jpg_images')
for imgfile in path.glob("*.jpg"):
xmlfile = imgfile.with_suffix(".xml")
if not xmlfile.exists():
imgfile.unlink()
print(imgfile, 'deleted.')

Read all files in project folder with variable path - Python

Looking for thoughts on how to read all csv files inside a folder in a project.
As an example, the following code is a part of my present working code, where my 'ProjectFolder' is on Desktop, and I am hardcoding the path. Inside the project folder, I have 'csvfolder' where I have all my csv files
However if I move the "ProjectFolder" to a different Hard drive, or other location, my path fails and I have to provide a new path. Is there an smart way to not worry about location of the project folder?
path = r'C:\Users\XXX\Desktop\ProjectFolder\csvFolder' # use your path
all_files = glob.glob(path + "/*.csv")
df_mm = pd.concat((pd.read_csv(f, usecols=["[mm]"]) for f in all_files),
axis = 1, ignore_index = True)

We have dynamic and absolute path concepts, just search on google "absolute vs relative path"; in your case if your python file is in the ProjectFolder you can simply try this:
from os import listdir
from os.path import dirname, realpath, join
def main():
# This is your project directory
current_directory_path = dirname(realpath(__file__))
# This is your csv directory
csv_files_directory_path = join(current_directory_path, "csvFolder")
for each_file_name in listdir(csv_files_directory_path):
if each_file_name.endswith(".csv"):
each_csv_file_full_path = join(csv_files_directory_path, each_file_name)
# Do whatever you want with each_csv_file_full_path
if __name__ == '__main__':
main()

Accessing CSV File in Different Directory (Python)

I have my data in the file 'Climate\Data\Raw_Flooding\CSV\input\addresses.csv'
My code which needs to access the file, however, is in the folder 'Climate\Code\Flooding\python_code\code.py'
How do I access the data subdirectory when I am in the code subdirectory?

import os
cwd = os.getcwd()
print(cwd)
path = cwd.split('\\')
new_path = ''
for i in range(path.index('Climate')):
new_path += path[i]+'\\'
new_path+='Data\Raw_Flooding\CSV\input\\address.csv'
print(new_path)
This will give you the path to the csv file.

Python - how to change directory

I am doing a school assignment where I have to take input from a user and save it to a text file.
My file structure will be something like:
- Customer register
- Customer ID
- .txt files 1-5
It can be saved in the python folder and I can make the folders like this:
os.makedirs("Customer register/Customer ID")
My question is, how do I set the path the text files are to be stored in, in the directory when I don't know the directory? So that no matter where the program is run it is saved in the "Customer ID" folder I create (but on the computer the program is run on)?
Also, how do I make this work on both windows and mac?
I also want to program to be able to be executed several times, and check if the folder is there and save to the "Customer ID" folder if it already exists. Is there a way to do that?
EDIT:
This is the code I am trying to use:
try:
dirs = os.makedirs("Folder")
path = os.getcwd()
os.chdir(path + "/Folder")
print (os.getcwd())
except:
if os.path.exists:
path = os.getcwd()
unique_filename = str(uuid.uuid4())
customerpath = os.getcwd()
os.chdir(customerpath + "/Folder/" + unique_filename)
I am able to create a folder and change the directory (everything in "try" works as I want).
When this folder is created I want to create a second folder with a random generated folder name (used for saving customer files). I can't get this to work in the same way.
Error:
FileNotFoundError: [WinError 2] The system cannot find the file specified: 'C:\Users\48736\PycharmProjects\tina/Folder/979b9026-b2f6-4526-a17a-3b53384f60c4'
EDIT 2:
try:
os.makedirs("Folder")
path = os.getcwd()
os.chdir(path + "/Folder")
print (os.getcwd())
except:
if os.path.exists:
path = os.getcwd()
os.chdir(os.path.join(path, 'Folder'))
print(os.getcwd())
def userId(folderid):
try:
if not os.path.exists(folderid):
os.makedirs(folderid)
except:
if os.path.exists(folderid):
os.chdir(path + "/Folder/" + folderid)
userId(str(uuid.uuid4()))
print(os.getcwd())
So I can now create a folder, change directory to the folder I have created and create a new folder with a unique filename within that folder.
But I can't change the directory again to the folder with the unique filename.
Any suggestions?
I have tried:
os.chdir(path + "/Folder/" + folderid)
os.chdir(path, 'Folder', folderid)
os.chdir(os.path.join(path, 'Folder', folderid))
But is still just stays in: C:\Users\47896\PycharmProjects\tina\Folder

You can use relative paths in your create directory command, i.e.
os.makedirs("./Customer register/Customer ID")
to create folder in project root (=where the primary caller is located) or
os.makedirs("../Customer register/Customer ID") in parent directory.
You can, of course, traverse the files tree as you need.
For specific options mentioned in your question, please, see makedirs documentation at Python 3 docs

here is solution
import os
import shutil
import uuid
path_on_system = os.getcwd() # directory where you want to save data
path = r'Folder' # your working directory
dir_path = os.path.join(path_on_system, path)
if not os.path.exists(dir_path):
os.makedirs(dir_path)
file_name = str(uuid.uuid4()) # file which you have created
if os.path.exists(file_name) and os.path.exists(dir_path):
shutil.move(file_name,os.path.join(dir_path,file_name))
else:
print(" {} does not exist".format(file_name))

How can I scrape file names and create directories for each filename in Python?

I'm trying to scrape filenames inside a folder and then make directories for each filename inside another folder. This is what I've got so far but when I run it, it doesn't create the new folders in the destination folder. When I run it in the terminal it doesn't return any errors.
import os
import shutil
folder = "/home/ro/Downloads/uglybettyfanfiction.net/"
destination = "/home/ro/A Python Scripts/dest_test/"
# get each files path name
def ensure_dir(f):
d = os.path.dirname(f)
if not os.path.exists(d):
os.makedirs(d)
for files in os.listdir(folder):
new_path = folder + files
ensure_dir(new_path)

You've got a few mistakes. No need to use dirname and you should write to your destination, not the same folder:
def ensure_dir(f):
if not os.path.exists(f):
os.mkdir(f)
for files in os.listdir(folder):
new_path = destination + files
ensure_dir(new_path)