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number guessing function in python using tkinter

So ive been trying to create a program of number guessing using tkinter but it isn't working proper like after first attempt it shows 0 attempts while ive declared 3 im attaching the source code here for better understanding the problem i feel is that its not taking attemptsas a global scope so its not being accessed by the other functions
import random
from tkinter import *
random_number = random.randint(0, 999)
root = Tk()
root.geometry('500x500')
root.title("Number guessing game")
label_0 = Label(root, text="Number guessing game", width=20, font=("bold", 20))
label_0.place(x=90, y=53)
label_1 = Label(root, text="Enter number", width=20, font=("bold", 10))
label_1.place(x=80, y=150)
entry_1 = Entry(root)
entry_1.place(x=240, y=150)
def printAttempts(_attempts):
attempt_string = "Attempt left: " + str(_attempts)
label_attempt = Label(root,
text=attempt_string,
width=20,
font=("bold", 20))
label_attempt.place(x=90, y=100)
printAttempts(3)
def printMessage(msg):
_message = Label(root, text=msg, width=50, font=("bold", 10))
_message.place(x=80, y=200)
def onSubmit():
attempts = 3
guessed_number = entry_1.get()
guessed_number = int(guessed_number)
while attempts != 0:
if (guessed_number == random_number):
printMessage("Horray you just got it Right!")
attempts = 0
break
else:
attempts -= 1
printMessage("You got it wrong :(")
if (guessed_number > random_number):
printMessage("Your guess number is greater than lucky number")
else:
printMessage("Your guess number is less than lucky number")
printAttempts(attempts)
continue
if (attempts == 0):
printMessage("No attempts left, try again later")
break
Button(root, text='Submit', width=20, bg='brown', fg='white',
command=onSubmit).place(x=180, y=380)
root.mainloop()

Removing the while loop fixes the problem.
Also have to make the attempts variable global.
Also have to modify the if statements.
Added some print statements for debugging.
comment:
prefer an alias import tkinter as tk to the wildcard from tkinter import *. it is easier to see where functions come from.
This works:
import random
from tkinter import *
attempts = 3
random_number = random.randint(0, 999)
root = Tk()
root.geometry('500x500')
root.title("Number guessing game")
label_0 = Label(root, text="Number guessing game", width=20, font=("bold", 20))
label_0.place(x=90, y=53)
label_1 = Label(root, text="Enter number", width=20, font=("bold", 10))
label_1.place(x=80, y=150)
entry_1 = Entry(root)
entry_1.place(x=240, y=150)
def printAttempts(_attempts):
attempt_string = "Attempt left: " + str(_attempts)
label_attempt = Label(root,
text=attempt_string,
width=20,
font=("bold", 20))
label_attempt.place(x=90, y=100)
printAttempts(3)
def printMessage(msg):
_message = Label(root, text=msg, width=50, font=("bold", 10))
_message.place(x=80, y=200)
def onSubmit():
global attempts
print('attempts', attempts)
guessed_number = entry_1.get()
guessed_number = int(guessed_number)
if attempts != 0:
print('the guess', guessed_number)
print('the random', random_number)
if (guessed_number == random_number):
printMessage("Horray you just got it Right!")
attempts = 0
print(attempts)
else:
print('removing one attempt')
attempts = attempts - 1
printMessage("You got it wrong :(")
if (guessed_number > random_number):
printMessage("Your guess number is greater than lucky number")
print('too high', attempts)
else:
printMessage("Your guess number is less than lucky number")
print('too low', attempts)
if (attempts == 0):
printMessage("No attempts left, try again later")
print('run out', attempts)
printAttempts(attempts)
Button(root, text='Submit', width=20, bg='brown', fg='white',
command=onSubmit).place(x=180, y=380)
root.mainloop()
result:

Tkinter while loop guess game

# Tkinter guessing game
from tkinter import *
import random
window = Tk()
# Bot Generator
bot = random.randint(1, 20+1)
print(bot)
def submit():
tries = 5
while tries >= 0:
e1 = (int(guessE.get()))
if e1 == bot:
print("You win")
break
elif e1 != bot:
print("Try again")
tries -= 1
break
def clear():
guessE.delete(0, "end")
# Guess Label
guessL = Label(window, text="Guess a number (between 1 and 20}")
guessL.place(x=75, y=50)
# Guess Entry
guessE = Entry(window, width=25, bg="lightgrey")
guessE.place(x=95, y= 80)
# Submit Button
submitBtn = Button(window, width=10, height=2, text="Submit", command=submit)
submitBtn.place(x=85, y=115)
# Clear Button
clearBtn = Button(window, width=10, height=2, text="Clear", command=clear)
clearBtn.place(x=175, y=115)
window.geometry("350x350")
window.resizable(0, 0)
window.attributes("-topmost", True)
window.mainloop()
I am trying to create a guessing game with Tkinter, I have created all the entries and labels, the clear button is working. I am struggling with creating a while loop, I need the program to stop accepting submitted entries once 5 tries have been used. Any ideas on how I can solve this?

Like already mentioned by #Paul Rooney, i also think that a while loop is a bad design for this. However, here is a working example with a global variable and some minor changes (disabling entry and button when 0 tries are reached):
# Tkinter guessing game
from tkinter import *
import random
window = Tk()
# Bot Generator
bot = random.randint(1, 20+1)
print(bot)
# define outside of function to not overwrite each time
tries = 5
def submit():
global tries # to make tries a global variable
while tries > 0: # this matches your tries amount correctly
e1 = (int(guessE.get()))
if e1 == bot:
print("You win")
break
elif e1 != bot:
print("Try again")
tries -= 1
break
# print status, disable the widgets
if tries == 0:
print("No more tries left")
guessE.configure(state="disabled")
submitBtn.configure(state="disabled")
def clear():
guessE.delete(0, "end")
# Guess Label
guessL = Label(window, text="Guess a number (between 1 and 20}")
guessL.place(x=75, y=50)
# Guess Entry
guessE = Entry(window, width=25, bg="lightgrey")
guessE.place(x=95, y= 80)
# Submit Button
submitBtn = Button(window, width=10, height=2, text="Submit", command=submit)
submitBtn.place(x=85, y=115)
# Clear Button
clearBtn = Button(window, width=10, height=2, text="Clear", command=clear)
clearBtn.place(x=175, y=115)
window.geometry("350x350")
window.resizable(0, 0)
window.attributes("-topmost", True)
window.mainloop()

Python Question. Need an answer from Python Random In my script (beginner)

I'm a beginner in Python, I need help. How to make the robot to choose 1, 2 or 3 and display it.
Here Is my Script.
from tkinter import *
from time import time
import random
window = Tk()
window.geometry('400x300')
sticks = 20
def computer():
global sticks
delete_sticks = random.randint(1, 3)
sticks = delete_sticks
def player():
global sticks
delete_sticks = int(entry_sticks.get())
if delete_sticks in [1,2,3]:
sticks -= delete_sticks
label_sticks.config(text="|"*sticks)
status.config(text=sticks)
if sticks == 1:
status.config(text='YOU WON!', fg='Green')
else:
window.after(200, computer)
Label_move.config(text='Computers turn, please wait.')
Label_move = Label(text='Type in a number from 1 to 3', font=('Arial', 15,'bold'))
Label_move.pack()
emptyspace1 = Label()
emptyspace1.pack()
entry_sticks = Entry(font=('Arial', 15,'bold'))
entry_sticks.pack()
emptyspace2 = Label()
emptyspace2.pack()
label_sticks = Label(text = sticks*'|', font = ('Arial', 30,'bold'))
label_sticks.pack()
emptyspace3 = Label()
emptyspace3.pack()
status = Label(text = '0', font=('Arial', 30, 'bold'))
status.pack()
button = Button(text = 'Take sticks', font=('Arial', 15, 'bold'), command = player)
button.pack()
window.mainloop()
Also for ones who did not understand the script...
def computer():
global sticks
delete_sticks = random.randint(1, 3)
sticks = delete_sticks
this is the def for the computer to answer

Use random.choice() so as to make the choice
import random
l=[1,2,3]
value=random.choice(l)
print(value)
You can even use random.randint(start,stop) which will choose any number between the limits,'both inclusive'
value=random.randint(1,3)
print(value)

You have already used random.randint(1, 3) to generate computer choice, but need to update the remaining sticks.
Suggest to put the update of remaining sticks in a function which can be called after player or computer choice:
from tkinter import *
import random
window = Tk()
window.geometry('400x300')
sticks = 20
def update_sticks(delete_sticks):
global sticks
sticks -= delete_sticks
label_sticks.config(text="|"*sticks)
status.config(text=sticks)
return sticks == 1
def computer():
# you can put some logic to make computer more intelligence
delete_sticks = random.randint(1, min(3, sticks-1))
computer_choice.config(text=f"computer last take: {delete_sticks}")
if update_sticks(delete_sticks):
status.config(text="Computer Won!", fg="red")
else:
Label_move.config(text="Type in a number from 1 to 3")
def player():
try:
delete_sticks = int(entry_sticks.get())
if delete_sticks in (1,2,3) and delete_sticks < sticks:
if update_sticks(delete_sticks):
status.config(text="You Won!", fg="green")
else:
Label_move.config(text="Computer's turn, please wait ...")
window.after(200, computer)
else:
# user input invalid number of sticks
raise
except:
Label_move.config(text="Invalid input")
Label_move = Label(window, text='Type in a number from 1 to 3', font=('Arial', 15,'bold'))
Label_move.pack(pady=5)
entry_sticks = Entry(window, font=('Arial', 15,'bold'))
entry_sticks.pack(pady=5)
label_sticks = Label(window, text=sticks*'|', font=('Arial', 30,'bold'))
label_sticks.pack(pady=5)
status = Label(window, text=sticks, font=('Arial', 30, 'bold'))
status.pack(pady=5)
button = Button(window, text='Take sticks', font=('Arial', 15, 'bold'), command=player)
button.pack(pady=5)
# show computer's last choice
computer_choice = Label(window)
computer_choice.pack(pady=5)
window.mainloop()

How can I kill a thread with python

I am making a random number guessing game with GUI (Tkinter) and this comes up RuntimeError: threads can only be started once. I'm trying to kill the thread but I can't find any way. Here's the code:
def main(c):
global max_num, number, guess_num, enter, l1, t1
if c <= 5:
messagebox.showerror(title='Import error', message='Please add a bigger number than 5')
max_num.delete(0, END)
else:
number = random.randrange(1, c+1)
print(number)
t1 = threading.Thread(target=lambda: process(int(guess_num.get())))
l1 = Label(root, text='Whats the number?')
guess_num = Entry(root, bd=3)
enter = Button(root, text='Enter', command=t1.start)
l1.grid(row=2)
guess_num.grid(row=3)
enter.grid(row=3, column=1)
def process(answer):
global number
if number == answer:
result = Label(root, text='Correct Answer!')
result.grid(row=4)
guess_num.destroy()
enter.destroy()
l1.destroy()
else:
if answer > number:
wrong_result = Label(root, text='Wrong Answer! Your answer is bigger than the random number', fg='red')
elif answer < number:
wrong_result = Label(root, text='Wrong Answer! Your answer is smaller than the random number', fg='red')
wrong_result.grid(row=4)
time.sleep(3)
wrong_result.destroy()
In the first function (main) is where I call the Thread and in the second function (process) is where I want to kill the Thread.

The error is trying to tell you that passing command=t1.start will result in calling start() on the same t1 instance every time the button is pressed. In Python, you cannot call thread.start() multiple times on the same thread instance. Change the following lines:
...
print(number)
t1 = threading.Thread(target=lambda: process(int(guess_num.get())))
l1 = Label(root, text='Whats the number?')
guess_num = Entry(root, bd=3)
enter = Button(root, text='Enter', command=t1.start)
...
To
...
print(number)
def process_in_thread():
t1 = threading.Thread(target=lambda: process(int(guess_num.get())))
t1.start()
l1 = Label(root, text='Whats the number?')
guess_num = Entry(root, bd=3)
enter = Button(root, text='Enter', command=process_in_thread)
...

Get input in Python tkinter Entry when Button pressed

I am trying to make a 'guess the number' game with Pyhon tkinter but so far I have not been able to retrieve the input from the user.
How can I get the input in entry when b1 is pressed?
I also want to display a lower or higher message as a clue to the player but I am not sure if what I have is right:
import time
import random
import decimal
import tkinter as tk
root = tk.Tk()
randomnum = float(decimal.Decimal(random.randrange(100,10000))/100)
guess = 0
def get(entry):
guess = entry.get()
return guess
def main():
b1 = tk.Button(root, text="Guess", command=get)
entry = tk.Entry()
b1.grid(column=1, row=0)
entry.grid(column=0, row=0)
root.mainloop()
print(guess)
if guess < randomnum:
l2 = tk.Label(root, text="Higher!")
l2.grid(column=0, row=2)
elif guess > randomnum:
l3 = tk.Label(root, text="Lower!")
l3.grid(column=0, row=2)
while guess != randomnum:
main()
l4 = tk.Label(root, text="Well guessed")
time.sleep(10)

You could define get inside main, so that you can access the entry widget you created beforehand, like this:
entry = tk.Entry()
def get():
guess = entry.get()
return guess # Replace this with the actual processing.
b1 = tk.Button(root, text="Guess", command=get)

You've assembled random lines of code out of order. For example, the root.mainloop() should only be called once after setting up the code but you're calling it in the middle of main() such that anything after won't execute until Tk is torn down. And the while guess != randomnum: loop has no place in event-driven code. And this, whatever it is, really should be preceded by a comment:
randomnum = float(decimal.Decimal(random.randrange(100,10000))/100)
Let's take a simpler, cleaner approach. Rather than holding onto pointers to the the various widgets, let's use their textvariable and command properties to run the show and ignore the widgets once setup. We'll use StringVar and IntVar to handle input and output. And instead of using sleep() which throws off our events, we'll use the after() feature:
import tkinter as tk
from random import randint
def get():
number = guess.get()
if number < random_number:
hint.set("Higher!")
root.after(1000, clear_hint)
elif number > random_number:
hint.set("Lower!")
root.after(1000, clear_hint)
else:
hint.set("Well guessed!")
root.after(5000, setup)
def setup():
global random_number
random_number = randint(1, 100)
guess.set(0)
hint.set("Start Guessing!")
root.after(2000, clear_hint)
def clear_hint():
hint.set("")
root = tk.Tk()
hint = tk.StringVar()
guess = tk.IntVar()
random_number = 0
tk.Entry(textvariable=guess).grid(column=0, row=0)
tk.Button(root, text="Guess", command=get).grid(column=1, row=0)
tk.Label(root, textvariable=hint).grid(column=0, row=1)
setup()
root.mainloop()

Here is a tkinter version on the number guessing game.
while or after are not used!
Program checks for illegal input (empty str or words) and reports error message. It also keeps track of the number of tries required to guess the number and reports success with a big red banner.
I've given more meaningful names to widgets and used pack manager instead of grid.
You can use the button to enter your guess or simply press Return key.
import time
import random
import tkinter as tk
root = tk.Tk()
root.title( "The Number Guessing Game" )
count = guess = 0
label = tk.Label(root, text = "The Number Guessing Game", font = "Helvetica 20 italic")
label.pack(fill = tk.BOTH, expand = True)
def pick_number():
global randomnum
label.config( text = "I am tkinking of a Number", fg = "black" )
randomnum = random.choice( range( 10000 ) )/100
entry.focus_force()
def main_game(guess):
global count
count = count + 1
entry.delete("0", "end")
if guess < randomnum:
label[ "text" ] = "Higher!"
elif guess > randomnum:
label[ "text" ] = "Lower!"
else:
label.config( text = f"CORRECT! You got it in {count} tries", fg = "red" )
root.update()
time.sleep( 4 )
pick_number()
count = 0
def get( ev = None ):
guess = entry.get()
if len( guess ) > 0 and guess.lower() == guess.upper():
guess = float( guess )
main_game( guess )
else:
label[ "text" ] = "MUST be A NUMBER"
entry.delete("0", "end")
entry = tk.Entry(root, font = "Helvetica 15 normal")
entry.pack(fill = tk.BOTH, expand = True)
entry.bind("<Return>", get)
b1 = tk.Button(root, text = "Guess", command = get)
b1.pack(fill = tk.BOTH, expand = True)
pick_number()
root.geometry( "470x110" )
root.minsize( 470, 110 )
root.mainloop()

Correct way to write guess number.
I write a small script for number guessing game in Python in
get_number() function.
Used one widget to update Label instead of duplicating.
I added some extra for number of turns that you entered.
Code modified:
import time
import random
import decimal
import tkinter as tk
root = tk.Tk()
randomnum = float(decimal.Decimal(random.randrange(100,10000))/100)
print(randomnum)
WIN = False
GUESS = 0
TURNS = 0
Vars = tk.StringVar(root)
def get_number():
global TURNS
while WIN == False:
Your_guess = entry.get()
if randomnum == float(Your_guess):
guess_message = f"You won!"
l3.configure(text=guess_message)
number_of_turns = f"Number of turns you have used: {TURNS}"
l4.configure(text=number_of_turns)
l4.grid(column=0, row=3, columnspan=3, pady=5)
WIN == True
break
else:
if randomnum > float(Your_guess):
guess_message = f"Your Guess was low, Please enter a higher number"
else:
guess_message = f"your guess was high, please enter a lower number"
l3.configure(text=guess_message)
l3.grid(column=0, row=2, columnspan=3, pady=5)
TURNS +=1
return Your_guess
label = tk.Label(root, text="The Number Guessing Game", font="Helvetica 12 italic")
label.grid(column=0, row=0, columnspan=3, sticky='we')
l2 = tk.Label(root, text='Enter a number between 1 and 100',
fg='white', bg='blue')
l2.grid(row=1, column=0, sticky='we')
entry = tk.Entry(root, width=10, textvariable=Vars)
entry.grid(column=1, row=1, padx=5,sticky='w')
b1 = tk.Button(root, text="Guess", command=get_number)
b1.grid(column=1, row=1, sticky='e', padx=75)
l3 = tk.Label(root, width=40, fg='white', bg='red' )
l4 = tk.Label(root, width=40, fg='white', bg='black' )
root.mainloop()
while guess:
time.sleep(10)
Output for enter floating numbers:
Output after the guess was high:
Output after the guess was low:
Output You won and number of turns: