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How to select only last record in ddata base [NEED FAST] python [closed]

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The problem in picture
kaka=dayData['Name']
date=datetime.strptime(kaka, '%d-%m-%Y')
date=date.strftime('%Y-%m-%d ')
#print(date)
sSplit = row['StartTime'].split("T")
eSplit = row['EndTime'].split("T")
sSplit[0]=date
eSplit[0]=date
#print(sSplit)
#print(eSplit)
start_str=' '.join(map(str,sSplit))
end_str=' '.join(map(str,eSplit))
I need to change the date of the last record in database as shown in picture.
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BeautifulSoup - how to select separate values? [closed]

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In my scrapper I use .select("div.class-name") method but have a trouble: it returns non-separated values.
Structure of my html:
<div class="class-name">
<div>Text1</div>
<div>Text2</div>
<div>Text3</div>
</div>
And as a result it gives me a list ["Text1Text2Text3"]. Is there any way to separate it as in html?

You mean like this?
from bs4 import BeautifulSoup
sample_html = '''<div class="class-name">
<div>Text1</div>
<div>Text2</div>
<div>Text3</div>
</div>'''
print(BeautifulSoup(sample_html, "lxml").select("div.class-name div"))
Output:
[<div>Text1</div>, <div>Text2</div>, <div>Text3</div>]

convert a list of dictionary in given format [closed]

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Input_data=[{​​​'filename':'file_A','start_page':1,'end_page':3,'angle':90}​​​,{'filename':'file_A','start_page':6,'end_page':8,'angle':270}​​​,{'filename':'file_B','start_page':2,'end_page':3,'angle':90}​​​,{'filename':'file_B','start_page':5,'end_page':5,'angle':270}​​​]
output=[{​​​'filename':'file_A','page':1,'angle':90}​​​,
{​​​'filename':'file_A','page':2,'angle':90}​​​,{​​​'filename':'file_A','page':3,'angle':90}​​​,{​​​'filename':'file_A','page':6,'angle':270}​​​,{​​​'filename':'file_A','page':7,'angle':270}​​​,
{​​​'filename':'file_A','page':8,'angle':270}​​​,{​​​'filename':'file_B','page':2,'angle':90}​​​,
{​​​'filename':'file_B','page':3,'angle':90}​​​,{​​​'filename':'file_B','page':5,'angle':270}​​​]
}

If I understood correctly, you want to do:
output = []
for d in Input_data:
for i in range(d["start_page"], d["end_page"] + 1):
output.append({'filename':d["filename"], 'page':i, 'angle':d["angle"]})
print(output)

string concatination at specificv value [closed]

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these items are in a list
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
AHU-02-17-019-DPS03,
AHU-T3-01-PL-TS01,
EF-03-32-108-MD01,
AHU-02-16-019-MD01,
AHU-T3-01-003-MD01,
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
so i want a new list which should be like
SF-04-08
AHU-VVIP
AHU-02-17
AHU-T3-01
EF-03-32
AHU-02-16
AHU-T3-01
SF-04-08
AHU-VVIP-02
using python??

you can use strip like:
data = ['SF-04-08-010-MD01',
'AHU-VVIP-02-003-MD03',
'AHU-02-17-019-DPS03'
]
for item in data:
print ('-'.join(item.split('-')[:3]))
output:
SF-04-08
AHU-VVIP-02
AHU-02-17

grep with python to match string inside quotes in html files [closed]

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I am newbie in grep and I'm familiar with Python. My problem is to find and replace every string inside the quote like "text" by < em >text< /em >
The source file has the html form
Thanks

That'll do the trick
import re
s = '"text" "some"'
res = re.subn('"([^"]*)"', '<em>\\1</em>', s)[0]