convert a list of dictionary in given format [closed] - python

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
Input_data=[{​​​'filename':'file_A','start_page':1,'end_page':3,'angle':90}​​​,{'filename':'file_A','start_page':6,'end_page':8,'angle':270}​​​,{'filename':'file_B','start_page':2,'end_page':3,'angle':90}​​​,{'filename':'file_B','start_page':5,'end_page':5,'angle':270}​​​]
output=[{​​​'filename':'file_A','page':1,'angle':90}​​​,
{​​​'filename':'file_A','page':2,'angle':90}​​​,{​​​'filename':'file_A','page':3,'angle':90}​​​,{​​​'filename':'file_A','page':6,'angle':270}​​​,{​​​'filename':'file_A','page':7,'angle':270}​​​,
{​​​'filename':'file_A','page':8,'angle':270}​​​,{​​​'filename':'file_B','page':2,'angle':90}​​​,
{​​​'filename':'file_B','page':3,'angle':90}​​​,{​​​'filename':'file_B','page':5,'angle':270}​​​]
}


If I understood correctly, you want to do:
output = []
for d in Input_data:
for i in range(d["start_page"], d["end_page"] + 1):
output.append({'filename':d["filename"], 'page':i, 'angle':d["angle"]})
print(output)

Related

How to select only last record in ddata base [NEED FAST] python [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 days ago.
Improve this question
The problem in picture
kaka=dayData['Name']
date=datetime.strptime(kaka, '%d-%m-%Y')
date=date.strftime('%Y-%m-%d ')
#print(date)
sSplit = row['StartTime'].split("T")
eSplit = row['EndTime'].split("T")
sSplit[0]=date
eSplit[0]=date
#print(sSplit)
#print(eSplit)
start_str=' '.join(map(str,sSplit))
end_str=' '.join(map(str,eSplit))
I need to change the date of the last record in database as shown in picture.
..................................................

How do I write a Python program to print the pattern? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 months ago.
Improve this question
How do I write a Python program to print the pattern?
543210
432105
321054
210543
054321
543210

You can do it by something like this:
a = "543210"
print(a)
for i in range(6):
a = a + (a[0])
a = a[1:]
print(a)

python handle json list format to array list [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 11 months ago.
Improve this question
use python 3.6
this json： [["10000000000"], ["12000000000"]]
i want get like result like
"data": {"calleeInfo": [{"phone": "10000000000",},{"phone": "12000000000",}]}

By list generation
temp = [["10000000000"], ["12000000000"]]
value = [{"phone": i[0]} for i in temp]
result = {"data": {"calleeInfo": value}}
print(result)
Output
{'data': {'calleeInfo': [{'phone': '10000000000'}, {'phone': '12000000000'}]}}

string concatination at specificv value [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 3 years ago.
Improve this question
these items are in a list
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
AHU-02-17-019-DPS03,
AHU-T3-01-PL-TS01,
EF-03-32-108-MD01,
AHU-02-16-019-MD01,
AHU-T3-01-003-MD01,
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
so i want a new list which should be like
SF-04-08
AHU-VVIP
AHU-02-17
AHU-T3-01
EF-03-32
AHU-02-16
AHU-T3-01
SF-04-08
AHU-VVIP-02
using python??

you can use strip like:
data = ['SF-04-08-010-MD01',
'AHU-VVIP-02-003-MD03',
'AHU-02-17-019-DPS03'
]
for item in data:
print ('-'.join(item.split('-')[:3]))
output:
SF-04-08
AHU-VVIP-02
AHU-02-17

how to get projectID value from dictionary in python? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
need to extract projectID and my final output is to be 1868117666669.
'{
"code":"ok",
"job":{
"config":{
"progress":{
"message":"Reading 2014-03-03__12-57-01-PM.xml",
"percent":107,
"maxmemory":954,
"memory":667
},
"projectID":1868117666669,
# other stuff
}
}
}'

You can try
>>> a = '{"code":"ok","job":{"config":{"progress":{"message":"Reading 2014-03-03__12-57-01-PM.xml","percent":107, "maxmemory":954,"memory":667},"projectID":1868117666669}}}'
>>> json.loads(a)['job']['config']['projectID']
1868117666669

Categories

Resources