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need to extract projectID and my final output is to be 1868117666669.
'{
"code":"ok",
"job":{
"config":{
"progress":{
"message":"Reading 2014-03-03__12-57-01-PM.xml",
"percent":107,
"maxmemory":954,
"memory":667
},
"projectID":1868117666669,
# other stuff
}
}
}'
You can try
>>> a = '{"code":"ok","job":{"config":{"progress":{"message":"Reading 2014-03-03__12-57-01-PM.xml","percent":107, "maxmemory":954,"memory":667},"projectID":1868117666669}}}'
>>> json.loads(a)['job']['config']['projectID']
1868117666669
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use python 3.6
this json： [["10000000000"], ["12000000000"]]
i want get like result like
"data": {"calleeInfo": [{"phone": "10000000000",},{"phone": "12000000000",}]}
By list generation
temp = [["10000000000"], ["12000000000"]]
value = [{"phone": i[0]} for i in temp]
result = {"data": {"calleeInfo": value}}
print(result)
Output
{'data': {'calleeInfo': [{'phone': '10000000000'}, {'phone': '12000000000'}]}}
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Input_data=[{'filename':'file_A','start_page':1,'end_page':3,'angle':90},{'filename':'file_A','start_page':6,'end_page':8,'angle':270},{'filename':'file_B','start_page':2,'end_page':3,'angle':90},{'filename':'file_B','start_page':5,'end_page':5,'angle':270}]
output=[{'filename':'file_A','page':1,'angle':90},
{'filename':'file_A','page':2,'angle':90},{'filename':'file_A','page':3,'angle':90},{'filename':'file_A','page':6,'angle':270},{'filename':'file_A','page':7,'angle':270},
{'filename':'file_A','page':8,'angle':270},{'filename':'file_B','page':2,'angle':90},
{'filename':'file_B','page':3,'angle':90},{'filename':'file_B','page':5,'angle':270}]
}
If I understood correctly, you want to do:
output = []
for d in Input_data:
for i in range(d["start_page"], d["end_page"] + 1):
output.append({'filename':d["filename"], 'page':i, 'angle':d["angle"]})
print(output)
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these items are in a list
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
AHU-02-17-019-DPS03,
AHU-T3-01-PL-TS01,
EF-03-32-108-MD01,
AHU-02-16-019-MD01,
AHU-T3-01-003-MD01,
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
so i want a new list which should be like
SF-04-08
AHU-VVIP
AHU-02-17
AHU-T3-01
EF-03-32
AHU-02-16
AHU-T3-01
SF-04-08
AHU-VVIP-02
using python??
you can use strip like:
data = ['SF-04-08-010-MD01',
'AHU-VVIP-02-003-MD03',
'AHU-02-17-019-DPS03'
]
for item in data:
print ('-'.join(item.split('-')[:3]))
output:
SF-04-08
AHU-VVIP-02
AHU-02-17
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I have this type of string given by my lambda function
aws-internal/3 aws-sdk-java/1.11.432
Linux/4.9.124-0.1.ac.198.71.329.metal1.x86_64
OpenJDK_64-Bit_Server_VM/25.181-b13 java/1.8.0_181
Now i want to convert this string into Json like
{
aws-internal:3,
aws-sdk-java:1.11.432,
Linux:/4.9.124-0.1.ac.198.71.329.metal1.x86_64
}
Please Give me a suggestion i search many website and library
You can do that with something like:
items = dict(a.split('/') for a in a_string.split())
Test Code:
a_string='aws-internal/3 aws-sdk-java/1.11.432 Linux/4.9.124-0.1.ac.198.71.329.metal1.x86_64 OpenJDK_64-Bit_Server_VM/25.181-b13 java/1.8.0_181'
items = dict(a.split('/') for a in a_string.split())
print(items)
Results
{
'aws-internal': '3',
'aws-sdk-java': '1.11.432',
'Linux': '4.9.124-0.1.ac.198.71.329.metal1.x86_64',
'OpenJDK_64-Bit_Server_VM': '25.181-b13',
'java': '1.8.0_181'
}
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Example:
var = "string"
and I want an xml output file: string.xml
Thank you!
It seams to be too easy... maybe i did not get the question right:
var = "String"
fileName = var + ".xml"
print fileName
this will print
String.xml