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Create dictionary values automatically? [closed] - python

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So i have a list with strings for path of images:
["folder1/_D7327", "folder1/_D7527", "folder2/_D7455", "folder3/_D1237"]
I want to automatically create a dictionary to store each photo:
{"folder1": ["_D7327", "_D7527"], "folder2": ["_D7455"], "folder3": ["_D1237"]}
How can I achieve something like this automatically?

You can use dict.setdefault. For example:
lst = ["folder1/_D7327", "folder1/_D7527", "folder2/_D7455", "folder3/_D1237"]
out = {}
for path in lst:
folder, file = path.split("/")
out.setdefault(folder, []).append(file)
print(out)
Prints:
{'folder1': ['_D7327', '_D7527'], 'folder2': ['_D7455'], 'folder3': ['_D1237']}

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use python 3.6
this json： [["10000000000"], ["12000000000"]]
i want get like result like
"data": {"calleeInfo": [{"phone": "10000000000",},{"phone": "12000000000",}]}

By list generation
temp = [["10000000000"], ["12000000000"]]
value = [{"phone": i[0]} for i in temp]
result = {"data": {"calleeInfo": value}}
print(result)
Output
{'data': {'calleeInfo': [{'phone': '10000000000'}, {'phone': '12000000000'}]}}

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Input_data=[{​​​'filename':'file_A','start_page':1,'end_page':3,'angle':90}​​​,{'filename':'file_A','start_page':6,'end_page':8,'angle':270}​​​,{'filename':'file_B','start_page':2,'end_page':3,'angle':90}​​​,{'filename':'file_B','start_page':5,'end_page':5,'angle':270}​​​]
output=[{​​​'filename':'file_A','page':1,'angle':90}​​​,
{​​​'filename':'file_A','page':2,'angle':90}​​​,{​​​'filename':'file_A','page':3,'angle':90}​​​,{​​​'filename':'file_A','page':6,'angle':270}​​​,{​​​'filename':'file_A','page':7,'angle':270}​​​,
{​​​'filename':'file_A','page':8,'angle':270}​​​,{​​​'filename':'file_B','page':2,'angle':90}​​​,
{​​​'filename':'file_B','page':3,'angle':90}​​​,{​​​'filename':'file_B','page':5,'angle':270}​​​]
}

If I understood correctly, you want to do:
output = []
for d in Input_data:
for i in range(d["start_page"], d["end_page"] + 1):
output.append({'filename':d["filename"], 'page':i, 'angle':d["angle"]})
print(output)

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I tried to append these values in the list but it appends only else part.
I want to store these values i printed in a list. How can i achieve this??
for i in d["Cabin new"]:
if i=="nan":
print ("na")
else:
print (i[1:])

Append in both places:
res = []
for i in d["Cabin new"]:
if i=="nan":
res.append('na')
else:
res.append(i[1:])

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these items are in a list
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
AHU-02-17-019-DPS03,
AHU-T3-01-PL-TS01,
EF-03-32-108-MD01,
AHU-02-16-019-MD01,
AHU-T3-01-003-MD01,
SF-04-08-010-MD01,
AHU-VVIP-02-003-MD03,
so i want a new list which should be like
SF-04-08
AHU-VVIP
AHU-02-17
AHU-T3-01
EF-03-32
AHU-02-16
AHU-T3-01
SF-04-08
AHU-VVIP-02
using python??

you can use strip like:
data = ['SF-04-08-010-MD01',
'AHU-VVIP-02-003-MD03',
'AHU-02-17-019-DPS03'
]
for item in data:
print ('-'.join(item.split('-')[:3]))
output:
SF-04-08
AHU-VVIP-02
AHU-02-17

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I have the following list stored in a variable:
names = ['a.lastname1', 'b.lastname2']
I would like to parse out the '.' in each string and return a string so it reads each last name on two lines without the 'a.' and 'b.'

Simple solution using str.split() function:
names = ['a.lastname1', 'b.lastname2']
l1, l2 = (lname.split('.')[1] for lname in names)
print(l1, l2)
The output:
lastname1 lastname2