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Is there a way to compress this whole operation into one line?
# a string containing comma separated key value pairs
long_string = "value1=hello,value2=world"
# split string into pairs
kv_pairs = long_string.split(',')
# split into actual key value dictionary
my_dict = dict(i.split('=') for i in kv_pairs)
print(my_dict)
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So i have a list with strings for path of images:
["folder1/_D7327", "folder1/_D7527", "folder2/_D7455", "folder3/_D1237"]
I want to automatically create a dictionary to store each photo:
{"folder1": ["_D7327", "_D7527"], "folder2": ["_D7455"], "folder3": ["_D1237"]}
How can I achieve something like this automatically?
You can use dict.setdefault. For example:
lst = ["folder1/_D7327", "folder1/_D7527", "folder2/_D7455", "folder3/_D1237"]
out = {}
for path in lst:
folder, file = path.split("/")
out.setdefault(folder, []).append(file)
print(out)
Prints:
{'folder1': ['_D7327', '_D7527'], 'folder2': ['_D7455'], 'folder3': ['_D1237']}
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I have a dictionary with names as keys and the phone numbers as values
dictionary = {"ABCD":12345 , "EFGH":6789}
I want to enter a substring say AB and print all keys which start with that substring
I also want to return there respective values seperately
Matching keys and values could be assigned to separate variables using zip on the filtered dictionary items:
matching = lambda kv:kv[0].startswith("AB")
keys,values = zip(*filter(matching,dictionary.items()))
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I tried to append these values in the list but it appends only else part.
I want to store these values i printed in a list. How can i achieve this??
for i in d["Cabin new"]:
if i=="nan":
print ("na")
else:
print (i[1:])
Append in both places:
res = []
for i in d["Cabin new"]:
if i=="nan":
res.append('na')
else:
res.append(i[1:])
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The string i needed to format is,
string = "How are you? abcdef"
I need to remove the "abcdef" from the string.
string = string.split(' ')[0]
Edit: Explanation. The line of code above will split the single string into a list of strings wherever there is a double space. It is important to note that whatever is split upon, will be removed. [0] then retrieves the first element in this newly formed list.
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I have the following list stored in a variable:
names = ['a.lastname1', 'b.lastname2']
I would like to parse out the '.' in each string and return a string so it reads each last name on two lines without the 'a.' and 'b.'
Simple solution using str.split() function:
names = ['a.lastname1', 'b.lastname2']
l1, l2 = (lname.split('.')[1] for lname in names)
print(l1, l2)
The output:
lastname1 lastname2