Python: PyQt Popup Window - python

So I've been creating my GUI with Qt for my Python application. I've now come to a situation where after a button has been pushed the appropriate deferred gets executed, we perform some tasks then I need to open up a separate window that contains one or two things. But I can't seem to figure out how to create this new separate window. Could anyone give me an example of how to create one?

A common error that can drive you crazy is forgetting to store the handle of the popup window you create in some python variable that will remain alive (e.g. in a data member of the main window).
The following is a simple program that creates a main window with a button where pressing the button opens a popup
#!/usr/bin/env python
#-*- coding: utf-8 -*-
import sys
from PyQt4.Qt import *
class MyPopup(QWidget):
def __init__(self):
QWidget.__init__(self)
def paintEvent(self, e):
dc = QPainter(self)
dc.drawLine(0, 0, 100, 100)
dc.drawLine(100, 0, 0, 100)
class MainWindow(QMainWindow):
def __init__(self, *args):
QMainWindow.__init__(self, *args)
self.cw = QWidget(self)
self.setCentralWidget(self.cw)
self.btn1 = QPushButton("Click me", self.cw)
self.btn1.setGeometry(QRect(0, 0, 100, 30))
self.connect(self.btn1, SIGNAL("clicked()"), self.doit)
self.w = None
def doit(self):
print "Opening a new popup window..."
self.w = MyPopup()
self.w.setGeometry(QRect(100, 100, 400, 200))
self.w.show()
class App(QApplication):
def __init__(self, *args):
QApplication.__init__(self, *args)
self.main = MainWindow()
self.connect(self, SIGNAL("lastWindowClosed()"), self.byebye )
self.main.show()
def byebye( self ):
self.exit(0)
def main(args):
global app
app = App(args)
app.exec_()
if __name__ == "__main__":
main(sys.argv)
What I think can be surprising for Python users and may be is the problem you are facing is the fact that if you don't store a reference to the new widget in the main e.g. by using w = MyPopup(...) instead of self.w = MyPopup(...) the window apparently doesn't appear (actually it's created and it's immediately destroyed).
The reason is that when the local variable w goes out of scope as no one is explicitly referencing the widget the widget gets deleted. This can be seen clearly because if you press again the button you'll see that as the second popup appears the first one is closed.
This also means that if you need to create several popups you have for example to put them in a python list and you should remove them from this list once the popups are closed by the user. The equivalent in the example could be changing to self.w = [] in constructor and then doing self.w.append(MyPopup(...)). Doing that would allow you to open several popups.

Generally, you just show multiple parentless windows with someQWidget.show(), like:
w1 = QLabel("Window 1")
w2 = QLabel("Window 2")
w1.show()
w2.show()
But most likely, you want a modal standard Dialog like this. Also be sure to understand modal dialogs.

Related

QPushButton.clicked.connect doesn't seem to work

I am trying to decouple entirely my GUI from my controller class, and for some reason I can't seem to manage to connect my buttons from outside of my GUI class itself.
Here's a small example of what I mean :
import sys
from PySide6 import QtWidgets
class Gui(QtWidgets.QWidget):
def __init__(self, parent=None):
super(Gui, self).__init__(parent)
layout = QtWidgets.QHBoxLayout(self)
self.button = QtWidgets.QPushButton("Do stuff")
layout.addWidget(self.button)
class Controller(object):
def do_stuff(self):
print("something")
def startup(parent):
ctrl = Controller()
gui = Gui(parent)
gui.button.clicked.connect(ctrl.do_stuff)
return gui
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
dialog = QtWidgets.QDialog()
gui = startup(dialog)
dialog.show()
sys.exit(app.exec_())
I would expect this code, when run, to display a GUI with one push button (which it does), and when pressing the push button, I'd expect the word "something" to get printed. However this doesn't seem to be the case.
I might just be too tired, but I can't find the solution.
What am I missing?
Thanks a lot in advance!
ctrl = None
gui = None
def startup(parent):
global ctrl
global gui
ctrl = Controller()
gui = Gui(parent)
gui.button.clicked.connect(ctrl.do_stuff)
return gui
try this, and it does work. when the variable is in the function, it will be destroyed before the function is finished. the global variable is not a good coding style but is a simple way to figure out your confusion.

In PyQt, how does one get a shared menu and toolbar to talk to the currently active subwindow?

I have an application which has a main window, which can have multiple subwindows. I would like to have one set of QActions in the main window that interact with the currently selected window. For example, the application might be a text editor, and clicking file->save should save the text file the user is currently working on. Additionally, some QActions are checkable, so their checked state should reflect the state of the currently active window.
Here is a minimum working example that has the basic functionality I want, but I suspect there is a better way to do it (further discussion below the code).
import sys
import PyQt4.QtGui as QtGui
class DisplayWindow(QtGui.QWidget):
def __init__(self, parent=None, name="Main Window"):
# run the initializer of the class inherited from
super(DisplayWindow, self).__init__()
self.myLayout = QtGui.QFormLayout()
self.FooLabel = QtGui.QLabel(self)
self.FooLabel.setText(name)
self.myLayout.addWidget(self.FooLabel)
self.setLayout(self.myLayout)
self.is_foo = False
def toggle_foo(self):
self.is_foo = not self.is_foo
if self.is_foo:
self.FooLabel.setText('foo')
else:
self.FooLabel.setText('bar')
class WindowActionMain(QtGui.QMainWindow):
def __init__(self):
super(WindowActionMain, self).__init__()
self.fooAction = QtGui.QAction('Foo', self)
self.fooAction.triggered.connect(self.set_foo)
self.fooAction.setCheckable(True)
menubar = self.menuBar()
fileMenu = menubar.addMenu('&File')
fileMenu.addAction(self.fooAction)
self.toolbar = self.addToolBar('File')
self.toolbar.addAction(self.fooAction)
self.centralZone = QtGui.QMdiArea()
self.centralZone.subWindowActivated.connect(
self.update_current_window)
self.setCentralWidget(self.centralZone)
self.create_dw("Window 1")
self.create_dw("Window 2")
def create_dw(self, name):
dw = DisplayWindow(name=name)
self.centralZone.addSubWindow(dw)
dw.show()
def update_current_window(self):
""" redirect future actions to affect the newly selected window,
and update checked statuses to reflect state of selected window"""
current_window = self.centralZone.activeSubWindow()
if current_window:
self.current_dw = self.centralZone.activeSubWindow().widget()
self.fooAction.setChecked(self.current_dw.is_foo)
def set_foo(self):
self.current_dw.toggle_foo()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
ex = WindowActionMain()
ex.show()
sys.exit(app.exec_())
My actual version of DisplayWindow could be useful in many different projects, and I want to package it up so that you don't have to add a lot of code to the main window to use it. Therefore, DisplayWindow, all of its functionality and a list of available actions should be in one module, which would be imported in WindowActionMain's module. I should then be able to add more actions for DisplayWindow without changing any code in WindowActionMain. In particular, I don't want to have to write a little function like WindowActionMain.set_foo(self) just to redirect each action to the right place.
Yes, this is possible by handling the QMenu's aboutToShow signal
and considering the QGuiApplication's focusWindow (or however you get that in Qt4).
Example below shows a generic 'Window' menu acting on the frontmost window.
http://doc.qt.io/qt-4.8/qmenu.html#aboutToShow
http://doc.qt.io/qt-5/qguiapplication.html#focusWindow
def on_windowMenu_aboutToShow(self):
self.windowMenu.clear()
self.newWindowAction = QtWidgets.QAction(self)
self.newWindowAction.setShortcut("Ctrl+n")
self.newWindowAction.triggered.connect(self.on_newWindowAction)
self.newWindowAction.setText("New Window")
self.windowMenu.addAction(self.newWindowAction)
self.windowMenu.addSeparator()
playerWindows = [w for w in self.topLevelWindows() if w.type()==QtCore.Qt.Window and w.isVisible()]
for i, w in enumerate(playerWindows):
def action(i,w):
a = QtWidgets.QAction(self)
a.setText("Show Window {num} - {title}".format(num=i+1, title=w.title()))
a.triggered.connect(lambda : w.requestActivate())
a.triggered.connect(lambda : w.raise_())
self.windowMenu.addAction(a)
action(i,w)
self.windowMenu.addSeparator()
self.closeWindowAction = QtWidgets.QAction(self)
self.closeWindowAction.setShortcut("Ctrl+w")
self.closeWindowAction.triggered.connect(lambda : self.focusWindow().close())
self.closeWindowAction.setText("Close")
self.windowMenu.addAction(self.closeWindowAction)

Python3 PyQt4 Calling function from QPushButton

I try to achieve a very simple thing in PyQT4 (python 3.3) :
Calling a new window from a button.
So far I have a 2nd Class (my second window, empty for now)...:
class Window2(QtGui.QWidget):
def __init__(self):
super(Window2, self).__init__()
self.initUI2()
def initUI2(self):
self.vbox2 = QtGui.QVBoxLayout()
self.setLayout(self.vbox2)
self.setGeometry(300, 300, 200, 120)
self.setWindowTitle('Image Bits')
self.show()
def main2():
w2 = QtGui.QWidget()
w2.resize(150, 150)
w2.move(300, 300)
w2.setWindowTitle('Window2')
w2.show()
which is called byt this function in my main class:
def FN_OpenWindow2(self):
win2 = Window2()
#Display it
win2.show()
Function which is called by this button in the same class :
self.NextButton = QtGui.QPushButton("Next")
self.NextButton.setCheckable(True)
self.NextButton.clicked[bool].connect(self.FN_OpenWindow2)
I must not be totally wrong because I have indeed my second window called and opening... a fraction of seconds... I guess only the time the button is "pushed".
So here's my question, how do I keep a reference to the instance of class Window2 ? so once called it stay here (and if I hit again the same button I will just destroy/create to refresh, that's my plan).
Hope I am clear enough, apologize if not I am fairly new to Python.
Thanks !
As you say, you just have to keep reference to the new window alive.
E.g. by simply storing it inside your main class:
def FN_OpenWindow2(self):
self.win2 = Window2()
#Display it
self.win2.show()
Or, if you could have multiple of those, make it a list:
def __init__(self,...):
# initialize an empty list in you main class' init function
self.secondaryWindows = []
def FN_OpenWindow2(self):
win2 = Window2()
#Display it
win2.show()
# append the window to the list
self.secondaryWindows.append(win2)
Mind though, that the references will remain when you close those widgets again.
So it maybe necessary to add additional logic that clears the references at that point.

How to pop out a separate window from a tabWidget in PySide Qt

I have an extended main window with a QtGui.QTabWidget added to it. I am creating several widgets extended from QtGui.QWidget which I can add and remove to the tab widget.
What I would like to do is have a "pop-out" button that causes the child widget to be removed from the tab widget and come up as it's own independent window (and a "pop-in" button to put it back into the main window). The same sort of idea as Gtalk-in-Gmail has.
Note that if I close the main window, the other "tabs" or "windows" should also close, and I should be able to put all the windows side-by-side and have them all visible and updating at the same time. (I will be displaying near-realtime data).
I am new to Qt, but if I'm not mistaken, if a Widget has no parent it comes up independently. This works, but I then have no idea how I could "pop" the window back in.
class TCWindow(QtGui.QMainWindow):
.
.
.
def popOutWidget(self, child):
i = self.tabHolder.indexOf(child)
if not i == -1:
self.tabCloseRequested(i)
self.widgets[i].setParent(None)
self.widgets[i].show()
My gut says that there should still be a parent/child relationship between the two.
Is there a way to keep the parent but still have the window come up independently, or am I misunderstanding Qt's style?
Otherwise, would creating a variable in the child to hold a link to the main window (like self.parentalUnit = self.parent()) be a good idea or a hackish/kludgy idea?
Leave the parent as is. If you remove the parent, then closing main window won't close 'floating' tabs, since they are now top-level windows. windowFlags defines if a widget is window or a child widget. Basically, you need to alternate between QtCore.Qt.Window and QtCore.Qt.Widget
Below is a small but complete example:
#!/usr/bin/env python
# -.- coding: utf-8 -.-
import sys
from PySide import QtGui, QtCore
class Tab(QtGui.QWidget):
popOut = QtCore.Signal(QtGui.QWidget)
popIn = QtCore.Signal(QtGui.QWidget)
def __init__(self, parent=None):
super(Tab, self).__init__(parent)
popOutButton = QtGui.QPushButton('Pop Out')
popOutButton.clicked.connect(lambda: self.popOut.emit(self))
popInButton = QtGui.QPushButton('Pop In')
popInButton.clicked.connect(lambda: self.popIn.emit(self))
layout = QtGui.QHBoxLayout(self)
layout.addWidget(popOutButton)
layout.addWidget(popInButton)
class Window(QtGui.QWidget):
def __init__(self, parent=None):
super(Window, self).__init__()
self.button = QtGui.QPushButton('Add Tab')
self.button.clicked.connect(self.createTab)
self._count = 0
self.tab = QtGui.QTabWidget()
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.button)
layout.addWidget(self.tab)
def createTab(self):
tab = Tab()
tab.setWindowTitle('%d' % self._count)
tab.popIn.connect(self.addTab)
tab.popOut.connect(self.removeTab)
self.tab.addTab(tab, '%d' % self._count)
self._count += 1
def addTab(self, widget):
if self.tab.indexOf(widget) == -1:
widget.setWindowFlags(QtCore.Qt.Widget)
self.tab.addTab(widget, widget.windowTitle())
def removeTab(self, widget):
index = self.tab.indexOf(widget)
if index != -1:
self.tab.removeTab(index)
widget.setWindowFlags(QtCore.Qt.Window)
widget.show()
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
w = Window()
w.show()
sys.exit(app.exec_())
In Qt, layout takes ownership over the widgets that are added to layout, so let it handle parentship.
You can create another widget (with no parent) which will be hidden until you press pop-out button and when it is pressed, you remove "pop-out widget" from its original layout and add it to layout of the hidden widget. And when pop-in button pressed - return widget to it's original layout.
To close this hidden window, when closing main window, you will need to redefine closeEvent(QCloseEvent* ev) to something like this (sorry for c++, but i bet, in python it's all the same):
void MainWindow::closeEvent(QCloseEvent* ev)
{
dw->setVisible(false); // independent of mainwindow widget
sw->setVisible(false); // independent of mainwindow widget
QWidget::closeEvent(ev); //invoking close event after all the other windows are hidden
}

How to create child window and communicate with parent in TkInter

I'm creating some dialogs using TkInter and need to be able to open a child sub-window (modal or modeless) on clicking a button in the parent. The child would then allow a data record to be created and this data (either the record or if the operation was cancelled) needs to be communicated back to the parent window. So far I have:
import sel_company_dlg
from Tkinter import Tk
def main():
root = Tk()
myCmp = sel_company_dlg.SelCompanyDlg(root)
root.mainloop()
if __name__ == '__main__':
main()
This invokes the top level dialog which allows the user to select a company. The company selection dialog looks like this:
class SelCompanyDlg(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
self.parent_ = parent
self.frame_ = Frame( self.parent_ )
// .. more init stuff ..
self.btNew_ = Button( self.frame_, text="New ...", command=self.onNew )
def onNew(self):
root = Toplevel()
myCmp = company_dlg.CompanyDlg(root)
On clicking the New ... button, a Create Company dialog is displayed which allows the user to fill in company details and click on create or cancel. Here's the opening bit of that:
class CompanyDlg(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
// etc.
I'm struggling with the best way of invoking the child dialog in onNew() - what I have works but I'm not convinced it's the best approach and also, I can't see how to communicate the details to and from the child dialog.
I've tried looking at online tutorials / references but what I've found is either too simplistic or focuses on things like tkMessageBox.showinfo() which iss not what I want.
There are at least a couple ways to solve your problem. Either your dialog can directly send information to the main application, or your dialog can generate an event that tells the main application that data is really to be pulled from the dialog. If the dialog simply changes the appearance of something (for example, a font dialog) I usually generate an event. If the dialog creates or deletes data I typically have it push information back to the application.
I typically have an application object that acts as the controller for the GUI as a whole. Often this is the same class as the main window, or it can be a separate class or even defined as a mixin. This application object has methods that dialogs can call to feed data to the application.
For example:
class ChildDialog(tk.Toplevel):
def __init__(self, parent, app, ...)
self.app = app
...
self.ok_button = tk.Button(parent, ..., command=self.on_ok)
...
def on_ok(self):
# send the data to the parent
self.app.new_data(... data from this dialog ...)
class MainApplication(tk.Tk):
...
def on_show_dialog(self):
dialog = ChildDialog(self)
dialog.show()
def new_data(self, data):
... process data that was passed in from a dialog ...
When creating the dialog, you pass in a reference to the application object. The dialog then knows to call a specific method on this object to send data back to the application.
If you're not into the whole model/view/controller thing you can just as easily pass in a function rather than an object, effectively telling the dialog "call this function when you want to give me data".
In one of my projects I was trying to check within a child tk.Toplevel window (child1) of my root window (self), if a tk.Toplevel window (child2) was created by the user from within the root window, and if this window (child2) is present at the users screen at the moment.
If this wouldn't be the case, the new tk.Toplevel window should gets created by the child window (child1) of the root window, instead of the root window itself. And if it was already created by the root window and is currently present at the users screen, it should get focus() instead of getting reinitialized by "child1".
The root window was wrapped inside a class called App() and both "children" windows were created by methods inside the root class App().
I had to initialize "child2" in a quiet mode if an argument given to the method was True. I suppose that was the entangled mistake. The problem occurred on Windows 7 64 bit, if that's significant.
I tried this (example):
import tkinter as tk
from tkinter import ttk
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
top = self.winfo_toplevel()
self.menuBar = tk.Menu(top)
top['menu'] = self.menuBar
self.menuBar.add_command(label='Child1', command=self.__create_child1)
self.menuBar.add_command(label='Child2', command=lambda: self.__create_child2(True))
self.TestLabel = ttk.Label(self, text='Use the buttons from the toplevel menu.')
self.TestLabel.pack()
self.__create_child2(False)
def __create_child1(self):
self.Child1Window = tk.Toplevel(master=self, width=100, height=100)
self.Child1WindowButton = ttk.Button(self.Child1Window, text='Focus Child2 window else create Child2 window', command=self.CheckForChild2)
self.Child1WindowButton.pack()
def __create_child2(self, givenarg):
self.Child2Window = tk.Toplevel(master=self, width=100, height=100)
if givenarg == False:
self.Child2Window.withdraw()
# Init some vars or widgets
self.Child2Window = None
else:
self.Child2Window.TestLabel = ttk.Label(self.Child2Window, text='This is Child 2')
self.Child2Window.TestLabel.pack()
def CheckForChild2(self):
if self.Child2Window:
if self.Child2Window.winfo_exists():
self.Child2Window.focus()
else:
self.__create_child2(True)
else:
self.__create_child2(True)
if __name__ == '__main__':
App().mainloop()
Here comes the problem:
I wasn't able to check if "child2" is already present. Got error: _tkinter.TclError: bad window path name
Solution:
The only way to get the right 'window path name' was, instead of calling the winfo_exists() method directly onto the "child2" window, calling the master of the "child1" window and adding the according attributes followed by the attributes of the master window you want to use.
Example (edit of the method CheckForChild2):
def CheckForChild2(self):
if self.Child2Window:
if self.Child1Window.master.Child2Window.winfo_exists():
self.Child1Window.master.Child2Window.focus()
else:
self.__create_child2(True)
else:
self.__create_child2(True)

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