I am trying to decouple entirely my GUI from my controller class, and for some reason I can't seem to manage to connect my buttons from outside of my GUI class itself.
Here's a small example of what I mean :
import sys
from PySide6 import QtWidgets
class Gui(QtWidgets.QWidget):
def __init__(self, parent=None):
super(Gui, self).__init__(parent)
layout = QtWidgets.QHBoxLayout(self)
self.button = QtWidgets.QPushButton("Do stuff")
layout.addWidget(self.button)
class Controller(object):
def do_stuff(self):
print("something")
def startup(parent):
ctrl = Controller()
gui = Gui(parent)
gui.button.clicked.connect(ctrl.do_stuff)
return gui
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
dialog = QtWidgets.QDialog()
gui = startup(dialog)
dialog.show()
sys.exit(app.exec_())
I would expect this code, when run, to display a GUI with one push button (which it does), and when pressing the push button, I'd expect the word "something" to get printed. However this doesn't seem to be the case.
I might just be too tired, but I can't find the solution.
What am I missing?
Thanks a lot in advance!
ctrl = None
gui = None
def startup(parent):
global ctrl
global gui
ctrl = Controller()
gui = Gui(parent)
gui.button.clicked.connect(ctrl.do_stuff)
return gui
try this, and it does work. when the variable is in the function, it will be destroyed before the function is finished. the global variable is not a good coding style but is a simple way to figure out your confusion.
Related
Normally in Qt applications you would use this at the start and end of your code:
app = QtWidgets.QApplication(sys.argv)
...
app.exec_()
But in Maya, you don't use this because Qt runs on the Maya application it self. I'm sure this works the same for many other applications as well if you don't know what Maya is. That said, my code looks like this:
import sys
from PySide2 import QtWidgets, QtGui, QtCore
class Test():
def __init__(self):
self.open_qt()
def open_qt(self):
# app = QtWidgets.QApplication(sys.argv) # Don't need this in Maya
self.window = QtWidgets.QWidget() # I tried QDialog also
btn = QtWidgets.QPushButton("press me")
btn.clicked.connect(self.login)
lay = QtWidgets.QVBoxLayout()
lay.addWidget(btn)
self.window.setLayout(lay)
self.window.show()
# app.exec_() # Don't need this in Maya
def login(self):
print("logged in!")
print("before")
temp = Test()
print("after")
But running this in Maya I get this result:
before
after
logged in!
But I need it to be:
before
logged in!
after
If you run this code outside of Maya (and you use those two commented out lines) then you get the correct result (block above here).
How can I get the Maya Qt to also wait correctly like it would if you used QtWidgets.QApplication(sys.argv)?
A QDialog might be more well suited for your needs, as it runs its own event loop that won't block the program, while waiting for the dialog to be completed.
The important thing to do is to call of its exec_() and call accept() when needed.
from PySide2 import QtWidgets, QtGui, QtCore
class Test(QtWidgets.QDialog):
def __init__(self, parent=None):
super(Test, self).__init__(parent)
layout = QtWidgets.QVBoxLayout(self)
self.spinBox = QtWidgets.QSpinBox()
layout.addWidget(self.spinBox)
btn = QtWidgets.QPushButton("press me")
layout.addWidget(btn)
btn.clicked.connect(self.login)
def login(self):
print("logged in!")
self.accept()
dialog = Test()
if dialog.exec_():
print(dialog.spinBox.value())
I don't have Maya, but according to this answer you can get its main window using the maya.OpenMayaUI module and shiboken's wrapInstance().
I'm trying to write a simple code which will change existing text widget to another one when user clicks a button.
So I have
title1=QtGui.QLabel('Hello')
title2=QtGui.QLabel('bye')
abutton=QtGui.QPushButton('Click me')
grid.addWidget(title1,1,5)
grid.addWidget(abutton,3,5)
and I have a function:
def myfunc(self):
self.grid.removeWidget(self.title1)
self.grid.addWidget(title2,1,5)
which I expect to change my "hello" to "bye" after I do this:
abutton.clicked.connect(self.myfunc)
but apparently that doesn't work. And I've checked: removeWidged works perfectly outside the function (my first thought was, maybe, i was doing something wrong in the function), and also the function does work itself(i checked it by making in print stuff and it did once I clicked the button, but the widget was still there)
what might I be doing wrong? thanks.
You had typo and you trying local vars like so many issues in your code. Here is a working example
from PyQt4 import QtGui, QtCore
import sys
class BASEGUICLS(QtGui.QDialog):
def __init__(self,parent=None):
super(BASEGUICLS, self).__init__(parent)
self.gridLayout = QtGui.QGridLayout()
self.title1=QtGui.QLabel('Hello')
self.title2=QtGui.QLabel('bye')
abutton=QtGui.QPushButton('Click me')
self.gridLayout.addWidget(self.title1,1,5)
self.gridLayout.addWidget(abutton,3,5)
self.setLayout(self.gridLayout)
abutton.clicked.connect(self.myfunc)
def myfunc(self):
self.gridLayout.removeWidget(self.title1)
self.title1.deleteLater()
self.gridLayout.addWidget(self.title2,1,5)
def main():
app = QtGui.QApplication(sys.argv)
ex = BASEGUICLS(None)
ex.show()
sys.exit(app.exec_())
if __name__ == "__main__":
main()
I need to implement a top-level widget (fixed position on screen) that hides whenever the user clicks somewhere else in the desktop, but it should hide gradually, so the widget should still be visible when it happens. To simplify, I want something like the Windows 8 right sidebar, when the user pushes a button, like the Super key it comes up, when clicking somewhere else it fades away, but is still visible in the process.
This is, I want to have an always-on-top window that hides when it loses focus. I have implemented this in pyqt4 but it is not working.
import sys
from PyQt4 import QtGui, QtCore
class Signals(QtCore.QObject):
close = QtCore.pyqtSignal()
class Menu(QtGui.QWidget):
def __init__(self, signals):
super(Menu, self).__init__()
self.signals = signals
def mousePressEvent(self, event):
# Just simplificating the gradual hiding effect for the moment
self.signals.close.emit()
def focusOutEvent(self, event):
print "FocusOut"
self.signals.close.emit()
def main():
app = QtGui.QApplication(sys.argv)
signals = Signals()
signals.close.connect(app.quit)
w = Menu(signals)
w.setWindowFlags( QtCore.Qt.SplashScreen )
w.resize(200, 200)
w.move(0, 0)
w.setWindowTitle('Test')
w.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
However, this is not working. When I click somewhere else the widget won't enter the focusOutEvent. I've also tried installing an eventFilter but since the window is a SplashScreen it won't work.
Any ideas on how to tackle this?
I have a login screen dialog written using pyqt and python and it shows a dialog pup up when it runs and you can type in a certin username and password to unlock it basicly. It's just something simple I made in learning pyqt. I'm trying to take and use it somewhere else but need to know if there is a way to prevent someone from using the x button and closing it i would like to also have it stay on top of all windows so it cant be moved out of the way? Is this possible? I did some research and couldn't find anything that could help me.
Edit:
as requested here is the code:
from PyQt4 import QtGui
class Test(QtGui.QDialog):
def __init__(self):
QtGui.QDialog.__init__(self)
self.textUsername = QtGui.QLineEdit(self)
self.textPassword = QtGui.QLineEdit(self)
self.loginbuton = QtGui.QPushButton('Test Login', self)
self.loginbuton.clicked.connect(self.Login)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.textUsername)
layout.addWidget(self.textPassword)
layout.addWidget(self.loginbuton)
def Login(self):
if (self.textUsername.text() == 'Test' and
self.textPassword.text() == 'Password'):
self.accept()
else:
QtGui.QMessageBox.warning(
self, 'Wrong', 'Incorrect user or password')
class Window(QtGui.QMainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
if Test().exec_() == QtGui.QDialog.Accepted:
window = Window()
window.show()
sys.exit(app.exec_())
Bad news first, it is not possible to remove the close button from the window, based on the Riverbank mailing system
You can't remove/disable close button because its handled by the
window manager, Qt can't do anything there.
Good news, you can override and ignore, so that when the user sends the event, you can ignore or put a message or something.
Read this article for ignoring the QCloseEvent
Also, take a look at this question, How do I catch a pyqt closeEvent and minimize the dialog instead of exiting?
Which uses this:
class MyDialog(QtGui.QDialog):
# ...
def __init__(self, parent=None):
super(MyDialog, self).__init__(parent)
# when you want to destroy the dialog set this to True
self._want_to_close = False
def closeEvent(self, evnt):
if self._want_to_close:
super(MyDialog, self).closeEvent(evnt)
else:
evnt.ignore()
self.setWindowState(QtCore.Qt.WindowMinimized)
You can disable the window buttons in PyQt5.
The key is to combine it with "CustomizeWindowHint",
and exclude the ones you want to be disabled.
Example:
#exclude "QtCore.Qt.WindowCloseButtonHint" or any other window button
self.setWindowFlags(
QtCore.Qt.Window |
QtCore.Qt.CustomizeWindowHint |
QtCore.Qt.WindowTitleHint |
QtCore.Qt.WindowMinimizeButtonHint
)
Result with QDialog:
Reference: https://doc.qt.io/qt-5/qt.html#WindowType-enum
Tip: if you want to change flags of the current window, use window.show()
after window.setWindowFlags,
because it needs to refresh it, so it calls window.hide().
Tested with QtWidgets.QDialog on:
Windows 10 x32,
Python 3.7.9,
PyQt5 5.15.1
.
I don't know if you want to do this but you can also make your window frameless. To make window frameless you can set the window flag equal to QtCore.Qt.FramelessWindowHint
I'm trying to minimize a window to the tray, but it seems it refuses to hide from the taskbar. I've spent a little time and distilled the problem code down to this. It's not mcuh so I'm wondering if I need something else to hide my app to tray in Windows 7.
import sys, os
from PyQt4 import uic
from PyQt4.QtGui import QMainWindow, QApplication
class MyClass(QMainWindow):
def __init__(self, parent = None):
QMainWindow.__init__(self, parent)
self.ui = uic.loadUi(os.path.join("gui", "timeTrackerClientGUI.ui"), self)
def hideEvent(self, event):
self.hide()
def showEvent(self, event):
self.show()
if __name__ == '__main__':
app = QApplication(sys.argv)
wnd = MyClass()
wnd.show()
app.exec_()
It seems the application icon does hide but then another one pops up, If I click the taskbar icon multiple times I can get these two icons flickering, looks kind of like this for a splitsecond before the first one hides:
It took a quite ugly hack to get it working but here's the final code if anybody is interested, ph is my platform-specific module, you can use platform.name or similar function instead:
def hideEvent(self, event):
self.hide()
if ph.is_windows():
self.hidden = True
self.setWindowFlags(Qt.ToolTip)
def showEvent(self, event):
if ph.is_windows() and self.hidden:
self.setWindowFlags(Qt.Window)
self.hidden = False
self.show()
calling show/hide in showEvent()/hideEvent() doesn't make sense - those events are the result of show()/hide() calls (and the like), not the trigger. If you want to toggle the window visiblity by clicking the tray icon, try setVisible(!isVisible()) on the widget, if you want to hide the window when the user clicks the window close button try reimplementing closeEvent():
MyMainWindow::closeEvent( QCloseEvent* e ) {
hide();
e->accept();
}
In Python, that is
def closeEvent(self, event):
self.hide()
event.accept()