Develop Reference

Python: convert date format YYYY-mm-dd to dd-MON-yyyy with abbreviated month

I have a date that is a string in this format:
'2021-01-16'
And need to convert it to a string in this format:
'16-JAN-2021'
I am able to get most of it like this:
x = datetime.strptime('2021-01-16', '%Y-%m-%d')
x.strftime('%d-%b-%Y')
But the month is not fully capitalized:
'16-Jan-2021'

Just use upper() to capitalize the output string:
from datetime import datetime
x = datetime.strptime('2021-01-16', '%Y-%m-%d')
print(x.strftime('%d-%b-%Y').upper())
# 16-JAN-2021

You were almost there. Simply use upper().
>>> from datetime import datetime
>>> datetime.strptime('2021-01-16', '%Y-%m-%d').strftime('%d-%b-%Y').upper()
'16-JAN-2021'

x.strftime('%d-%b-%Y').upper()

I read answers with upper() function, here is another way using %^b
from datetime import datetime
date = datetime.strptime('2011-01-16', '%Y-%m-%d')
formatted_date = date.strftime('%d-%^b-%Y')
print(formatted_date)
Goodluck!

Convert Timestamp to ISO Date

I am extracting Data from Mongodb using some date filter. In mongo my date is in ISO format . As i am dynamically adding date from some variable which is in timestamp format(2019-07-15 14:54:53).Getting Empty Result
curs = col1.aggregate([{'$match':{update_col: {'$gte': last_updt }}},{'$project':json_acceptable_string}])
I am expecting Rows after filtering but acual its giving empty dataset

you can use datetime.strptime to parse the original string to a datetime object, then use datetime.isoformat to get it in ISO format.
try this:
import datetime
original_date = '2019-07-15 14:54:53'
date_obj = datetime.datetime.strptime(original_date, "%Y-%m-%d %H:%M:%S")
iso_date = date_obj.isoformat()
print(iso_date)

try this
from dateutil import parser as date_parser
dt_obj = date_parser.parse('2019-07-15 14:54:53')
where dt_obj is an object of standard datetime.datetime class

You can use fromisoformat.
Try
from datetime import datetime
iso_string = '2019-07-15 14:54:53'
you_date_obj = datetime.fromisoformat(iso_string)

Extract only time (HH:MM) from datetime field - Odoo 10

I'a m trying to extract only time (Hour:Minute) from datetime field
Example:
today_with_hour = fields.Datetime(
string=u'hora',
default=fields.Datetime.now,
)
I would like to know how get only hour from today_with_hour in format
17:10:20

This is one way to extract:
from datetime import datetime
now = datetime.now()
print(str(now.hour)+':'+str(now.minute)+':'+str(now.second))

This may be better way to do it
You can use strftime
Example:
from datetime import datetime
datetime.now().strftime("%H:%M:%S")
In your case you can follow like this:
from datetime import datetime
datetime.strptime('20/06/2019 17:28:52', "%d/%m/%Y %H:%M:%S").time()
Output will be:
17:28:52

Better way to do is by using strftime().
dt = datetime.strptime('20/06/2019 17:28:52', "%d/%m/%Y %H:%M:%S")
dt.strftime("%H:%M:%S")
output:
17:28:52
To get the current time from the datetime.now()
datetime.datetime.now().time().strftime("%H:%M:%S")
O/P:
'11:16:17'
if you want to get the time with milliseconds also, use isoformat()
datetime.datetime.now().time().isoformat()
O/P:
'11:20:34.978272'

Modify datetime.now() standard output

I what to change standard time output to "%Y-%m-%dT%H:%M:%S.%f+00:00" format, how can I do it?
Here is what i have now.
import datetime
start_date = datetime.datetime.now()
print(start_date,"+00:00")
#output: 2019-04-19 06:57:47.563791 +00:00
#what to be: 2019-04-19T06:57:47.563791+00:00

Use exactly that format string with datetime.strftime:
datetime.now().strftime("%Y-%m-%dT%H:%M:%S.%f+00:00")

Use datetime.strftime to convert your datetime object to the required format
import datetime
start_date = datetime.datetime.now()
print(start_date.strftime("%Y-%m-%dT%H:%M:%S.%f+00:00"))
#2019-04-26T12:50:45.219062+00:00

Python convert date to datetime

I have following string of date "2018-05-08" and I would like to convert it into the datetime format of python like: "2018-05-08T00:00:00.0000000". I understand I can combine the string like:
> date = "2018-05-08"
> time = "T00:00:00.0000000"
> date+time
'2018-05-08T00:00:00.0000000'
But is there pythonic way of doing it where I can use libraries like datetime?

You can use datetime module like this example:
import datetime
date = "2018-05-08"
final = datetime.datetime.strptime(date, '%Y-%m-%d').strftime('%Y-%m-%dT%H:%M:%S.%f')
print(final)
Output:
2018-05-08T00:00:00.000000
For more details visit datetime's documentation

Use this code
from datetime import date
from datetime import datetime
d = date.today()
datetime.combine(d, datetime.min.time())

from datetime import datetime
datetime.strftime(datetime.strptime('2018-05-08','%Y-%m-%d'),'%Y-%m-%dT%H:%M:%S.%f')
OUTPUT:
'2018-05-08T00:00:00.000000'

from datetime import datetime
date_as_datetime = datetime.strptime("2018-05-08", '%Y-%m-%d')
date_as_string = date_as_datetime.strftime('%Y-%m-%dT%H:%M:%S')
print(date_as_string)
Out:
'2018-05-08T00:00:00'
See strptime/strftime options here: https://docs.python.org/2/library/datetime.html#strftime-and-strptime-behavior

Yes, you can use the datetime module and the strftime method from that module. Here is an example below if we want to format the current time.
import datetime
current_time = datetime.datetime.now()
formatted_time = datetime.datetime.strftime(current_time, "%Y-%h-%d %H:%m:%S")
print(formatted_time)
Here is the output:
2018-May-08 13:05:16