I have following string of date "2018-05-08" and I would like to convert it into the datetime format of python like: "2018-05-08T00:00:00.0000000". I understand I can combine the string like:
> date = "2018-05-08"
> time = "T00:00:00.0000000"
> date+time
'2018-05-08T00:00:00.0000000'
But is there pythonic way of doing it where I can use libraries like datetime?
You can use datetime module like this example:
import datetime
date = "2018-05-08"
final = datetime.datetime.strptime(date, '%Y-%m-%d').strftime('%Y-%m-%dT%H:%M:%S.%f')
print(final)
Output:
2018-05-08T00:00:00.000000
For more details visit datetime's documentation
Use this code
from datetime import date
from datetime import datetime
d = date.today()
datetime.combine(d, datetime.min.time())
from datetime import datetime
datetime.strftime(datetime.strptime('2018-05-08','%Y-%m-%d'),'%Y-%m-%dT%H:%M:%S.%f')
OUTPUT:
'2018-05-08T00:00:00.000000'
from datetime import datetime
date_as_datetime = datetime.strptime("2018-05-08", '%Y-%m-%d')
date_as_string = date_as_datetime.strftime('%Y-%m-%dT%H:%M:%S')
print(date_as_string)
Out:
'2018-05-08T00:00:00'
See strptime/strftime options here: https://docs.python.org/2/library/datetime.html#strftime-and-strptime-behavior
Yes, you can use the datetime module and the strftime method from that module. Here is an example below if we want to format the current time.
import datetime
current_time = datetime.datetime.now()
formatted_time = datetime.datetime.strftime(current_time, "%Y-%h-%d %H:%m:%S")
print(formatted_time)
Here is the output:
2018-May-08 13:05:16
Related
I have a timestamp that was created with datetime module and now I need to convert '2020-10-08T14:52:49.387077+00:00' into 08/OCT/2020?
Can datetime do this? I have tried strptime but I think the +00:00 at the end is causing errors.
Use fromisoformat and strftime method from datetime package in Python 3.7:
from datetime import datetime
time = '2020-10-08T14:52:49.387077+00:00'
new_time = datetime.fromisoformat(time).strftime("%d/%b/%Y")
print(new_time)
Or with strptime:
from datetime import datetime
time = '2020-10-08T14:52:49.387077+00:00'
new_time = datetime.strptime(time.split('T')[0], "%Y-%m-%d").strftime("%d/%b/%Y")
print(new_time)
Output:
08/Oct/2020
I'a m trying to extract only time (Hour:Minute) from datetime field
Example:
today_with_hour = fields.Datetime(
string=u'hora',
default=fields.Datetime.now,
)
I would like to know how get only hour from today_with_hour in format
17:10:20
This is one way to extract:
from datetime import datetime
now = datetime.now()
print(str(now.hour)+':'+str(now.minute)+':'+str(now.second))
This may be better way to do it
You can use strftime
Example:
from datetime import datetime
datetime.now().strftime("%H:%M:%S")
In your case you can follow like this:
from datetime import datetime
datetime.strptime('20/06/2019 17:28:52', "%d/%m/%Y %H:%M:%S").time()
Output will be:
17:28:52
Better way to do is by using strftime().
dt = datetime.strptime('20/06/2019 17:28:52', "%d/%m/%Y %H:%M:%S")
dt.strftime("%H:%M:%S")
output:
17:28:52
To get the current time from the datetime.now()
datetime.datetime.now().time().strftime("%H:%M:%S")
O/P:
'11:16:17'
if you want to get the time with milliseconds also, use isoformat()
datetime.datetime.now().time().isoformat()
O/P:
'11:20:34.978272'
I what to change standard time output to "%Y-%m-%dT%H:%M:%S.%f+00:00" format, how can I do it?
Here is what i have now.
import datetime
start_date = datetime.datetime.now()
print(start_date,"+00:00")
#output: 2019-04-19 06:57:47.563791 +00:00
#what to be: 2019-04-19T06:57:47.563791+00:00
Use exactly that format string with datetime.strftime:
datetime.now().strftime("%Y-%m-%dT%H:%M:%S.%f+00:00")
Use datetime.strftime to convert your datetime object to the required format
import datetime
start_date = datetime.datetime.now()
print(start_date.strftime("%Y-%m-%dT%H:%M:%S.%f+00:00"))
#2019-04-26T12:50:45.219062+00:00
I have this string '2015-04-08T07:52:00Z' and I wanna to convert it to '08/04/2015', how can I do this?
You can use the datetime.datetime.strptime() function to create a datetime object, then datetime.datetime.strftime() to return your correctly formatted date like so:
from datetime import datetime
dt = datetime.strptime('2015-04-08T07:52:00Z', '%Y-%m-%dT%H:%M:%SZ')
print dt.strftime('%d/%m/%Y')
You can use easy_date to make it easy:
import date_converter
converted_date = date_converter.string_to_string('2015-04-08T07:52:00Z', '%Y-%m-%dT%H:%M:%SZ', '%d/%m/%Y')
I am using the date time lib to get the current date. After obtaining the current date I need to convert the obtained date to in to a string format. Any help is appriciated
from datetime import date
today=date.today()
print today
You can use today.strftime(format). format will be a string as described here http://docs.python.org/library/time.html#time.strftime . Example:
from datetime import date
today = date.today()
today.strftime("%x")
#>>> '01/31/11'
datetime.strftime allows you to format a datetime however you want
stringDate = str(today)
If that's what you want.
In Python3, you can use f-string formatting:
from datetime import date
today=date.today()
today_str = f"{today:%m/%d/%y}"
today_str
#>>>'06/24/22'