This is my homework question:
Write a program that simulates rolling a set of six-sided dice multiple times. The program should use a dictionary to record the results and then display the results.
Input: The program should prompt for the number of dice to roll and the number of times to roll the dice.
Output:
The program is to display how many times each possible value was rolled. The format of the output must be as shown below:
The first column is the number shown on the dice when they are rolled. The brackets are only as wide as needed and the number inside the brackets is right justified. Note the minimum and maximum values in the sample runs below.
The second column is the number of times that value was rolled. This column is right justified.
The last column is the percent of times that the number was rolled. The percentages are displayed with an accuracy of one decimal place.
This is the code I have so far:
import random
from math import floor, ceil
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
rand = float(0)
rolltotal = int(input("How many times do you want to roll? "))
q = 0
while q < rolltotal:
q = q + 1
rand = ceil(6*(random.random()))
if rand == 1:
one = one + 1
elif rand == 2:
two = two + 1
elif rand == 3:
three = three + 1
elif rand == 4:
four = four + 1
elif rand == 5:
five = five + 1
else:
six = six + 1
total = one + two + three + four + five + six
print("[1]", one, " ",round(100*one/total, 1),"%")
print("[2]", two, " ",round(100*two/total, 1),"%")
print("[3]", three, " ",round(100*three/total, 1),"%")
print("[4]", four, " ",round(100*four/total, 1),"%")
print("[5]", five, " ",round(100*five/total, 1),"%")
print("[6]", six, " ",round(100*six/total, 1),"%")
My question is: I just know how to roll one dice. how can i get more than one .
from collections import defaultdict
import random
dice = int(input("How many dice do you want to roll? "))
rolls = int(input("How many times do you want to roll them? "))
irange = xrange
sides = [1,2,3,4,5,6]
d = defaultdict(int)
for r in irange(rolls):
d[sum( random.choice(sides) for d in irange(dice) )] += 1
total = float(rolls)
for k in sorted(d.keys()):
print "[%d] %d %.1f%%" % (k, d[k], 100.0*d[k]/total)
You would rather do the following:-
loop=True
import random #This allows python to import built in "random" function.
while loop is True:
dice=input("Which sided dice would you like to roll? (You can only choose 4,6 or 12) \n") # "\n" allows python to add a new line.
if dice=="4":
print("You have chosen to roll dice 4\nYour score is... \n", random.randint(1,4)) #This allows python to generate a random number from 1 to 4.
elif dice=="6":
print("You have chosen to roll dice 6\nYour score is...\n", random.randint(1,6)) #This allows python to generate a random number from 1 to 6.
elif dice=="12":
print("You have chosen to roll dice 12\nYour score is...\n", random.randint(1,12)) #This allows python to generate a random number from 1 to 12.
else: print("Invalid option! Please try again!")
loop2=input("Do you want to roll again? (Yes or No) \n")
if loop2=="yes" or loop2=="Yes": # "or" funtion allows python to accept any of the two answers input by the user.
loop=True
else: break # This function allows program to close.
Related
Im trying to make a loop where I start with 5 random dice rolls. the values 1,3,4, and 6 are added up for your score, while 2s and 5s are not counted and subtract the combined amount of dice rolled with 2s and 5s from the amount of dice rolled the next turn. I can't quite figure out how to get the sum of only the dice that rolled 1,3,4,6 and roll a lesser amount of dice the next turn based off ho many dice were 2 or 5
#Stuck in the Mud Dice Game
Exit = 0
Rolls = int(5)
score = 0
def RollDice():
totalsum = 0
for die in range(0, Rolls):
number = random.randint(1,6)
print("die", die + 1, ":", number)
totalsum += number
print("score: ", totalsum)
def Menu():
print("1. Roll Dice")
print("2. Exit Program")
print()
choice = int(input("Enter option here: "))
if(choice == 1):
RollDice()
if(choice == 2):
Exit()
Menu()
In the for-loop, use an if statement:
if number==2 or number==5:
Rolls -= 1
else:
totalsum += number
I suppose that you also need to start your function RollDice like this:
def RollDice():
global Rolls
...
otherwise, it might only locally (i.e., within the function) assign a new value to the variable.
Or do you mean the number of Rolls should be different when you re-start the program? This can only be done by writing the value to a file.
I need help condensing my Yahtzee code. I'm familiar with loops, but I can't seem to figure out how to do it without wiping my roll each turn. It's set up to roll 5 random dice and then you choose which you want to keep. It will then roll what's left for three total rolls. I thought of making a placeholder list, but I can't make it work that way either.
Dice = [‘⚀ ’,‘⚁ ‘,’ ⚂ ‘,’ ⚃ ‘,’ ⚄ ‘,’ ⚅ ‘]
turns = 3
#first roll
first_roll = []
for _ in range(5):
roll = random.choice(dice)
first_roll.append(roll)
print(first_roll)
turns -= 1
print(f'You have {turns} turns left.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#second roll
second_roll = []
for i in keep:
x = int(i)
j = first_roll[x-1]
second_roll.append(j)
remainder = 5 - len(second_roll)
for _ in range(remainder):
roll = random.choice(dice)
second_roll.append(roll)
print(second_roll)
turns -= 1
print(f'This is your last turn.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#third roll
third_roll = []
for i in keep:
x = int(i)
j = second_roll[x-1]
third_roll.append(j)
remainder = 5 - len(third_roll)
for _ in range(remainder):
roll = random.choice(dice)
third_roll.append(roll)
print(third_roll)
So I'm not sure if this is exactly what you're looking for, but I created a function that lets you continuously roll for X turns and the dice pool gets progressively smaller like your code shows. I thoroughly commented the code to hopefully give you a good explanation to what I'm doing.
import random
#Dice characters
dice = ['1','2','3','4','5','6']
#Number of turns player has
turns = 3
#This is the group of dice kept by the player
kept_dice = []
def roll():
#This is the group of dice randomly chosen
rolled_dice = []
#Generate up to 5 random dice based on how many have been kept so far
for _ in range(5 - len(kept_dice)):
#Append random dice value to rolled_dice array
rolled_dice.append(random.choice(dice))
#Print roll group
print(rolled_dice)
dice_to_keep = int(input("Which dice would you like to keep? 1 - 5: "))
kept_dice.append(rolled_dice[dice_to_keep-1])
while turns != 0:
#Let the user know how many turns they have left
print(f'You have {turns} turns left.')
#Roll dice
roll()
#Subtract 1 turn
turns -= 1
#After all turns, show the kept dice:
print("Kept dice:")
print(kept_dice)
So i'm stuck with this problem, how can i add something within a function and print it from out of the function
import random
def dieRoll():
sum = 0
for i in range (die-1):
dieThrow = random.randrange( 1, sides+1)
sum += dieThrow
print(dieThrow)
print("That totals: ", sum)
return i
players = int(input("How many players are rolling dice? "))
die = int(input("How many dice does each player roll? "))
sides = int(input("How many sides does each die have? "))
for a in range(1, players+1):
print("Player",a, "rolled: ")
print(dieRoll())
it's supposed to look something like:
Player 1 rolled:
5
4
9
that totals: 18
but i'm getting something like:
Player 1 rolled:
5
4
that totals: 9
9
i feel like the answer is right in front of me but i just can't see it
it's because you print what the function return in the end, if you want such output you have two choices :
print(i)
return("That totals: ", sum)
or the other choice :
print(i)
print("That totals: ", sum)
#replace print(dieRoll())
dieRoll()
The problem is the line
for i in range (die-1):
Try this instead:
for i in range(0, die):
The thing is, the range function by default starts at 0 and "stops" when it gets to the last number (does not execute it), meaning you are not geting to do that last dice roll you expected.
Hope it helps.
import random
#Making sure all values are = to 0
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
#Loop for rolling the die 100 times
for r in range(0, 100):
roll = random.randint(1, 6)
if roll == 1:
one += 1
elif roll == 2:
two += 1
elif roll == 3:
three += 1
elif roll == 4:
four += 1
elif roll == 5:
five += 1
elif roll == 6:
six += 1
#print how many times each number was rolled
print(one)
print(two)
print(three)
print(four)
print(five)
print(six)
#How many times the 3 was rolled
print("The 3 was rolled", three, "times!")
#Average roll between all of them
print("The average roll was", (one * 1 + two * 2 + three * 3 + 4 * four + 5 * five + 6 * six)/100)
I am trying to make it so it prints out
"number is the most common roll." for whichever the roll is.
Just trying to do this is the most simple way, and I'm confused on how to do it. I tried to do like if one > two > three etc etc. but that did not work.
Choosing an appropriate data structure to gain maximum leverage of a language’s core features is one of the most valuable skills a programmer can develop.
For this particular use case, it’s best to use an iterable data type that facilitates operations (e.g. sort, obtain the maximum) on the collection of numbers. As we want to associate a number (1-6) with the number of times that number was rolled, a dictionary seems like the simplest data structure to choose.
I’ve re-written the program to show how its existing functionality could be re-implemented using a dictionary as its data structure. With the comments, the code should be fairly self-explanatory.
The tricky part is what this question is actually asking: determining the number rolled most often. Instead of manually implementing a sorting algorithm, we can use the Python built-in max function. It can accept an optional key argument which specifies the function that should be applied to each item in the iterable object before carrying out the comparison. In this case, I chose the dict.get() method which returns the value corresponding to a key. This is how the dictionary of roll results is compared by the number of rolls for each result for determining the number rolled most often. Note that max() only returns one item so in the case of a tie, only one of the results will be printed (see Which maximum does Python pick in the case of a tie?).
See also: How do I sort a dictionary by value?
import random
NUM_ROLLS = 100
DIE_SIDES = 6
# Create the dictionary to store the results of each roll of the die.
rolls = {}
#Loop for rolling the die NUM_ROLLS times
for r in range(NUM_ROLLS):
roll_result = random.randint(1, DIE_SIDES)
if roll_result in rolls:
# Add to the count for this number.
rolls[roll_result] += 1
else:
# Record the first roll result for this number.
rolls[roll_result] = 1
# Print how many times each number was rolled
for roll_result in range(1, 7):
print("The number", str(roll_result), "was rolled", str(rolls[roll_result]), "times.")
#How many times the 3 was rolled
print("The number three was rolled", str(rolls[3]), "times.")
#Average roll between all of them
sum = 0
for roll_result in rolls:
sum += roll_result * rolls[roll_result]
print("The average roll result was", str(sum/NUM_ROLLS))
# The number rolled most often.
print(str(max(rolls, key=rolls.get)), "is the most common roll result.")
So I had to make code that roll a die fairly and counted how many 4's I got. With the help of people on here I got it to work. Well now I have to created another die and roll them and then add they products together. This is the instructions I've been given.
"Then write another function that simulates rolling two fair dice. The easy way is to call the function you just wrote, twice, and add the numbers you get.
This should return a number between 2 and 12."
I've added rolling the dice a second time but how do I add the sums of the two rolls together is my question?
And this is my code.
from random import randrange
def roll():
rolled = randrange(1,7)
if rolled == 1:
return "1"
if rolled == 2:
return "2"
if rolled == 3:
return "3"
if rolled == 4:
return "4"
if rolled == 5:
return "5"
if rolled == 6:
return "6"
def rollManyCountTwo(n):
twoCount = 0
for i in range (n):
if roll() == "2":
twoCount += 1
if roll() == "2":
twoCount +=1
print ("In", n,"rolls of a pair of dice, there were",twoCount,"twos.")
rollManyCountTwo(6000)
You shouldn't have to deal with strings at all, this could be done entirely using int values
from random import randint
def roll():
return randint(1,6)
def roll_twice():
total = 0
for turn in range(2):
total += roll()
return total
For example
>>> roll_twice()
10
>>> roll_twice()
7
>>> roll_twice()
8
And for your function that is supposed to count the number of 2s that were rolled, again you can do integer comparison
def rollManyCountTwo(n):
twos = 0
for turn in range(n):
if roll() == 2:
twos += 1
print('In {} rolls of a pair of dice there were {} twos'.format(n, twos))
return twos
>>> rollManyCountTwo(600)
In 600 rolls of a pair of dice there were 85 twos
85
from random import randint
def roll():
return randint(1,6)
def rollManyCountTwo(n):
twoCount = 0
for _n in xrange(n*2):
if roll() == 2:
twoCount += 1
print "In {n} rolls of a pair of dice, there were {cnt} twos.".format(n=n, cnt=twoCount)
Since you roll two dices for n times and count every single two rolled, just loop for n*2 and check if the dice result is two.