So I had to make code that roll a die fairly and counted how many 4's I got. With the help of people on here I got it to work. Well now I have to created another die and roll them and then add they products together. This is the instructions I've been given.
"Then write another function that simulates rolling two fair dice. The easy way is to call the function you just wrote, twice, and add the numbers you get.
This should return a number between 2 and 12."
I've added rolling the dice a second time but how do I add the sums of the two rolls together is my question?
And this is my code.
from random import randrange
def roll():
rolled = randrange(1,7)
if rolled == 1:
return "1"
if rolled == 2:
return "2"
if rolled == 3:
return "3"
if rolled == 4:
return "4"
if rolled == 5:
return "5"
if rolled == 6:
return "6"
def rollManyCountTwo(n):
twoCount = 0
for i in range (n):
if roll() == "2":
twoCount += 1
if roll() == "2":
twoCount +=1
print ("In", n,"rolls of a pair of dice, there were",twoCount,"twos.")
rollManyCountTwo(6000)
You shouldn't have to deal with strings at all, this could be done entirely using int values
from random import randint
def roll():
return randint(1,6)
def roll_twice():
total = 0
for turn in range(2):
total += roll()
return total
For example
>>> roll_twice()
10
>>> roll_twice()
7
>>> roll_twice()
8
And for your function that is supposed to count the number of 2s that were rolled, again you can do integer comparison
def rollManyCountTwo(n):
twos = 0
for turn in range(n):
if roll() == 2:
twos += 1
print('In {} rolls of a pair of dice there were {} twos'.format(n, twos))
return twos
>>> rollManyCountTwo(600)
In 600 rolls of a pair of dice there were 85 twos
85
from random import randint
def roll():
return randint(1,6)
def rollManyCountTwo(n):
twoCount = 0
for _n in xrange(n*2):
if roll() == 2:
twoCount += 1
print "In {n} rolls of a pair of dice, there were {cnt} twos.".format(n=n, cnt=twoCount)
Since you roll two dices for n times and count every single two rolled, just loop for n*2 and check if the dice result is two.
Related
Im trying to make a loop where I start with 5 random dice rolls. the values 1,3,4, and 6 are added up for your score, while 2s and 5s are not counted and subtract the combined amount of dice rolled with 2s and 5s from the amount of dice rolled the next turn. I can't quite figure out how to get the sum of only the dice that rolled 1,3,4,6 and roll a lesser amount of dice the next turn based off ho many dice were 2 or 5
#Stuck in the Mud Dice Game
Exit = 0
Rolls = int(5)
score = 0
def RollDice():
totalsum = 0
for die in range(0, Rolls):
number = random.randint(1,6)
print("die", die + 1, ":", number)
totalsum += number
print("score: ", totalsum)
def Menu():
print("1. Roll Dice")
print("2. Exit Program")
print()
choice = int(input("Enter option here: "))
if(choice == 1):
RollDice()
if(choice == 2):
Exit()
Menu()
In the for-loop, use an if statement:
if number==2 or number==5:
Rolls -= 1
else:
totalsum += number
I suppose that you also need to start your function RollDice like this:
def RollDice():
global Rolls
...
otherwise, it might only locally (i.e., within the function) assign a new value to the variable.
Or do you mean the number of Rolls should be different when you re-start the program? This can only be done by writing the value to a file.
I need help condensing my Yahtzee code. I'm familiar with loops, but I can't seem to figure out how to do it without wiping my roll each turn. It's set up to roll 5 random dice and then you choose which you want to keep. It will then roll what's left for three total rolls. I thought of making a placeholder list, but I can't make it work that way either.
Dice = [‘⚀ ’,‘⚁ ‘,’ ⚂ ‘,’ ⚃ ‘,’ ⚄ ‘,’ ⚅ ‘]
turns = 3
#first roll
first_roll = []
for _ in range(5):
roll = random.choice(dice)
first_roll.append(roll)
print(first_roll)
turns -= 1
print(f'You have {turns} turns left.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#second roll
second_roll = []
for i in keep:
x = int(i)
j = first_roll[x-1]
second_roll.append(j)
remainder = 5 - len(second_roll)
for _ in range(remainder):
roll = random.choice(dice)
second_roll.append(roll)
print(second_roll)
turns -= 1
print(f'This is your last turn.')
keep = input("Which dice would you like to keep? 1 - 5: ").split()
clear()
#third roll
third_roll = []
for i in keep:
x = int(i)
j = second_roll[x-1]
third_roll.append(j)
remainder = 5 - len(third_roll)
for _ in range(remainder):
roll = random.choice(dice)
third_roll.append(roll)
print(third_roll)
So I'm not sure if this is exactly what you're looking for, but I created a function that lets you continuously roll for X turns and the dice pool gets progressively smaller like your code shows. I thoroughly commented the code to hopefully give you a good explanation to what I'm doing.
import random
#Dice characters
dice = ['1','2','3','4','5','6']
#Number of turns player has
turns = 3
#This is the group of dice kept by the player
kept_dice = []
def roll():
#This is the group of dice randomly chosen
rolled_dice = []
#Generate up to 5 random dice based on how many have been kept so far
for _ in range(5 - len(kept_dice)):
#Append random dice value to rolled_dice array
rolled_dice.append(random.choice(dice))
#Print roll group
print(rolled_dice)
dice_to_keep = int(input("Which dice would you like to keep? 1 - 5: "))
kept_dice.append(rolled_dice[dice_to_keep-1])
while turns != 0:
#Let the user know how many turns they have left
print(f'You have {turns} turns left.')
#Roll dice
roll()
#Subtract 1 turn
turns -= 1
#After all turns, show the kept dice:
print("Kept dice:")
print(kept_dice)
I made a simple Yahtzee game in as few of lines as I could think. Currently, the user must press Enter (with any value) to continue. I would like to use a loop statement so that the dice continue to roll until Yahtzee (all rolled numbers are the same). I would also like a 10 second timer. What is the best way to add a loop statement to this code? P.S. This is not homework, I wanted to make this game for my Yahtzee nights. My daughter wakes easil...haha
import random
while True:
dice1 = random.randint(1,6)
dice2 = random.randint(1,6)
dice3 = random.randint(1,6)
dice4 = random.randint(1,6)
dice5 = random.randint(1,6)
numbers = (dice1, dice2, dice3, dice4, dice5)
sum1 = sum(numbers)
if sum1 == ("5" or "10" or "15" or "20" or "25"):
print("Winner, winner, chicken dinner!", dice1, dice2, dice3, dice4, dice5)
else:
print("Your rolls are: ", dice1, dice2, dice3, dice4, dice5)
input("Press return key to roll again.")
EDIT: This is my final product. Thank you for all the help guys!!
import random
import time
input("Press return key to roll.")
for x in range(0,10000):
numbers = [random.randint(1,6) for _ in range(5)]
if all(x == numbers[0] for x in numbers):
print("Winner, winner, chicken dinner!", numbers)
input("Press return key to play again.")
else:
print("Your rolls are: ", numbers)
print("Next roll in one second.")
time.sleep(1)
If you would like to check if all the dice numbers are the same it is as simple as.
allDice = [dice1, dice2, dice3, dice4, dice5] #List of dice variables
if all(x == allDice[0] for x in allDice): # If all dice are the same
print("Yahtzee")
break # Break out of while loop
The most simple way of having a "timer" could be adding a time.sleep(). You have to import time otherwise it won't work.
So replace
input("Press return key to roll again.")
with
time.sleep(10)
This means every 10 seconds the dice will roll until all dice are the same number, if they are then it prints Yahtzee and stops the loop.
Replace the while True:... with a while boolean_variable: ... and set the value of that boolean_variable to True before the while loop and to False when you achieved Yahtzee => in the if condition.
What do you mean by 10 second timer, however? A sleep time of ten seconds can be implemented by a time.sleep(10) at the end of the inner while loop.
EDIT boolean_variable EXAMPLE
import time
...
not_yahtzee = True
while not_yathzee:
....
if sum == 5 or sum == 10 or ... :
...
not_yahtzee = False
else:
...
time.sleep(10)
The ... represent the code you already have. As commented on your question, the if condition should look more like this one. There are other ways on how to check all the elements in a list are the same.
import random
total = [0]
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
dice=True
while dice:
a = random.randrange(1,7)
if a == 1:
one = one + 1
elif a == 2:
two = two + 1
elif a == 3:
three = three + 1
elif a == 4:
four = four + 1
elif a == 5:
five = five + 1
elif a == 6:
six = six + 1
b = len(total)
print ("Roll:", b,)
print ("The dice has rolled:",a,)
total.append (a)
dice =input("Roll again? (y,n):")
if dice == "n":
print ("Thank-You!")
print ("One rolled",one,"times")
print ("Two rolled",two,"times")
print ("Three rolled",three,"times")
print ("Four rolled",four,"times")
print ("Five rolled",five,"times")
print ("Six rolled",six,"times")
break
How can I make it so that if "one" has only been rolled "once" it says "one has been rolled time" instead of "one has been rolled 1 times"?
Thanks. An explanation would also be good so that I can learn
Make a function called printTimesRolled or something similar. Then pass a string, and an int. Like this:
def printTimesRolled(numberWord, timesRolled):
if (timesRolled == 1):
print(numberWord, "rolled 1 time.")
else:
print(numberWord, "rolled", timesRolled, "times.")
Then, to print them all, just do this:
printTimesRolled("One", one)
printTimesRolled("Two", two)
...
You can use str.format and a check whether the number has been rolled exactly one time. Demo:
>>> one = 1
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 1 time'
>>> one = 0
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 0 times'
>>> one = 3
>>> 'One rolled {} time{}'.format(one, 's' if one!=1 else '')
'One rolled 3 times'
This would be a good way to handle the dice rolling. I am not sure if you have started exploring classes yet, but by making the DiceRoller class you make it slightly more organized. Besides, you avoid tons of global variables.
Using a dictionary for comparisons will allow you to run a for loop to compare it, rahter than having 6 elif statements, making the code more efficient.
Finally, when the user types "n" to quit and check on his rolls, we compare to again.lower() to failsafe it in case the user types "N" instead.
Then it loops through the dictionary and prints 'time / roll' or 'times / rolls' based on a simple if statement.
I hope this makes sense to you, if not just ask!
import random
# DEFINING THE CLASS
class DiceRoller(object):
def __init__(self):
self.sides = {1:0,
2:0,
3:0,
4:0,
5:0,
6:0}
# WILL ROLL THE DICE AND ADD 1 TO THE SIDE COUNTER WHEN A SIDE IS ROLLED
def rollTheDice(self):
roll = random.randint(1,6)
for side in (self.sides):
if roll == side:
self.sides[side] += 1
print('Rolled a %s' % (roll))
# WILL PRINT TOTAL ROLLS WHEN CALLED
def getTotals(self):
for i, side in enumerate(self.sides):
if self.sides[side] == 1:
print('Side %s: %s roll' % (i + 1, self.sides[side]))
else:
print('Side %s: %s rolls' % (i + 1, self.sides[side]))
# THIS CODE IS EXECUTED
Dice = DiceRoller()
while True:
Dice.rollTheDice()
again = input('Roll again [y/n]: ')
if again.lower() == 'n':
break
Dice.getTotals()
This code outputs the following when run a couple of times:
Rolled a 2
Roll again [y/n]: y
Rolled a 4
Roll again [y/n]: y
Rolled a 3
Roll again [y/n]: y
Rolled a 1
Roll again [y/n]: y
Rolled a 4
Roll again [y/n]: y
Rolled a 2
Roll again [y/n]: n
Side 1: 1 roll
Side 2: 2 rolls
Side 3: 1 roll
Side 4: 2 rolls
Side 5: 0 rolls
Side 6: 0 rolls
Process finished with exit code 0
This is my homework question:
Write a program that simulates rolling a set of six-sided dice multiple times. The program should use a dictionary to record the results and then display the results.
Input: The program should prompt for the number of dice to roll and the number of times to roll the dice.
Output:
The program is to display how many times each possible value was rolled. The format of the output must be as shown below:
The first column is the number shown on the dice when they are rolled. The brackets are only as wide as needed and the number inside the brackets is right justified. Note the minimum and maximum values in the sample runs below.
The second column is the number of times that value was rolled. This column is right justified.
The last column is the percent of times that the number was rolled. The percentages are displayed with an accuracy of one decimal place.
This is the code I have so far:
import random
from math import floor, ceil
one = 0
two = 0
three = 0
four = 0
five = 0
six = 0
rand = float(0)
rolltotal = int(input("How many times do you want to roll? "))
q = 0
while q < rolltotal:
q = q + 1
rand = ceil(6*(random.random()))
if rand == 1:
one = one + 1
elif rand == 2:
two = two + 1
elif rand == 3:
three = three + 1
elif rand == 4:
four = four + 1
elif rand == 5:
five = five + 1
else:
six = six + 1
total = one + two + three + four + five + six
print("[1]", one, " ",round(100*one/total, 1),"%")
print("[2]", two, " ",round(100*two/total, 1),"%")
print("[3]", three, " ",round(100*three/total, 1),"%")
print("[4]", four, " ",round(100*four/total, 1),"%")
print("[5]", five, " ",round(100*five/total, 1),"%")
print("[6]", six, " ",round(100*six/total, 1),"%")
My question is: I just know how to roll one dice. how can i get more than one .
from collections import defaultdict
import random
dice = int(input("How many dice do you want to roll? "))
rolls = int(input("How many times do you want to roll them? "))
irange = xrange
sides = [1,2,3,4,5,6]
d = defaultdict(int)
for r in irange(rolls):
d[sum( random.choice(sides) for d in irange(dice) )] += 1
total = float(rolls)
for k in sorted(d.keys()):
print "[%d] %d %.1f%%" % (k, d[k], 100.0*d[k]/total)
You would rather do the following:-
loop=True
import random #This allows python to import built in "random" function.
while loop is True:
dice=input("Which sided dice would you like to roll? (You can only choose 4,6 or 12) \n") # "\n" allows python to add a new line.
if dice=="4":
print("You have chosen to roll dice 4\nYour score is... \n", random.randint(1,4)) #This allows python to generate a random number from 1 to 4.
elif dice=="6":
print("You have chosen to roll dice 6\nYour score is...\n", random.randint(1,6)) #This allows python to generate a random number from 1 to 6.
elif dice=="12":
print("You have chosen to roll dice 12\nYour score is...\n", random.randint(1,12)) #This allows python to generate a random number from 1 to 12.
else: print("Invalid option! Please try again!")
loop2=input("Do you want to roll again? (Yes or No) \n")
if loop2=="yes" or loop2=="Yes": # "or" funtion allows python to accept any of the two answers input by the user.
loop=True
else: break # This function allows program to close.