replace "Variables config" with "Variables /path/CLOUD234/__init__.py" in robot framework .Cloud instance is defined at run time .In each run the value changes ,so I have created a python file initpath.py as follows with fun() keyword .It will return the required path .How can I call it in Variables section of robot framework ? Thank you in advance.
import socket
import re
import os
def fun():
name = socket.gethostname()
pattern = ".*CLOUD[0-9]*"
hname = re.findall(pattern,name)
cloud_instance = hname[0].replace("-","_")
init_file = "/path/{}/__init__.py".format(cloud_instance)
return init_file
Variables section do not execute any code.
I suggest you run the python under testcase/suite up and use Set Test Variable to set the variable.
Try following: Here, you are not required to use any variables/section to call py file.
Under *** Settings *** section add
Library initpath.py
I've trying to decode qr or aztec code data by Python-zxing. Everytime I get empty data without any error in python Shell. What I do wrong?
import zxing
image = "aztec.png"
rd = zxing.BarCodeReader()
rs = rd.decode(image)
print rs.data
print rs
Output:
''
<zxing.BarCode instance at 0x0312A260>
Python ver. 2.7.11 (Windows)
P.S.
When I run script from cmd I've message:
Exception in thread "main" java.lang.NoClassDefFoundError: com/google/zxing/client/j2se/CommandLineRunner
Assuming the mvn installation of Zxing is correct,add the path of the Zxing folder while creating an instance of reader (in this case 'rd')
rd = zxing.BarCodeReader("/path/to/zxing")
FYI: Am running it on Raspbian, not windows, but had the same error.
You forgot class inheritance. See below. Answer made compatible for python 3; but seriously... this is not the pep-way to do it. For long-term compatibility you should check by versioning and use an if-statement.
image = "aztec.png"
zxing = zxing() # notice zxhing()
rd = zxing.BarCodeReader()
rs = rd.decode(image)
try:
print (rs.data)
print (rs)
except:
print (rs.data)
print (rs)
print(rs.raw) # This returns the decoded text.
You can also use rs.parsed.
print(rs.format) # This returns the Format like the detected one is DataMatrix. QR Code etc.
print(rs.points) # This returns the boundary of points where its detected.
So, I am passing a environment variable from bash to python;
#!/usr/bin/env python2
import os
#connect("weblogic", "weblogic", url=xxx.xxx.xxx.xxx:xxxx)
os.environ['bash_variable']
via wlst.sh I can print exported bash_variable, but how do I execute stored variable? Basically, I am trying to remove the original connect statement and pass a variable that has said information. Thanks
Question though, why wouldn't you called the script with the variable as an argument and use sys.argv[] ?
By example something like this.
import os
import sys
import traceback
from java.io import *
from java.lang import *
wlDomain = sys.argv[1]
wlDomPath = sys.argv[2]
wlNMHost = sys.argv[3]
wlNMPort = sys.argv[4]
wlDPath="%s/%s" %(wlDomPath,wlDomain)
wlNMprop="/apps/bea/wls/scripts/.shadow/NM.prop"
try:
print "Connection to Node Manager"
print ""
loadProperties(wlNMprop)
nmConnect(username=NMuser,password=NMpass,host=wlNMHost,port=wlNMPort,domainName=wlDomain,domainDir=wlDPath,mType='ssl',verbose='true')
except:
print "Fatal Error : No Connection to Node Manager"
exit()
print "Connected to Node Manager"
The NM.prop file is a 600 file with the username/password for the NM.
EDIT :
So from what I understand you want to do something like this :
URLS = ['t3s://Host1:Port1','t3s://Host2:Port2','t3s://Host3:Port3']
for urls in URLS:
connect('somebody','password',urls)
{bunch of commands}
disconnect()
And the values of the list URLS would be define by the environment.
The way I see it you have 3 choices :
Have 1 script per environment, more or less identical save for the URLS list
Have 1 script but with a conditionnal branching on sys.argv[1] (the environment as a parameter) and create the list there.
Have 1 script which use a parameter file for each environment according to the environment. Each parameter file containing the list in question.
Something like that :
propENV = sys.argv[1]
propPath = "/path1/path2"
propFile = "%s/%s" %(propPath,propENV)
loadProperties(propFile)
I would probably use the properties file option myself as it is more flexible from an operational standpoint...at least IMHO.
I've been looking around for an answer to my original issue.. how do i determine (programmatically) that my win32api.ShellExecute statement executed successfully, and if a successful execution occurs, execute an os.remove() statement.
Researching I found out that the ShellExecute() call returns the HINSTANCE. Further digging I found that ShellExecute() will return an HINSTANCE > 32 if it was successful. My problem/question now is, how do i use it to control the rest of my program's flow? I tried using an if HINSTANCE> 32: statement to control the next part, but I get a NameError: name 'hinstance' is not defined message. Normally this wouldn't confuse me because it means i need to define the variable 'hinstance' before referencing it; however, because i thought ShellExecute is supposed to return HINSTANCE, i thought that makes it available for use?
Here is my full code where i am trying to implement this. Note that in my print_file() def i am assigning hinstance to the full win32api.ShellExecute() command in attempt to capture the hinstance along with explicitly returning it at the end of the function.. this isn't working either.
import win32print
import win32api
from os.path import isfile, join
import glob
import os
import time
source_path = "c:\\temp\\source\\"
def main():
printer_name = win32print.GetDefaultPrinter()
while True:
file_queue = [f for f in glob.glob("%s\\*.txt" % source_path) if isfile(f)]
if len(file_queue) > 0:
for i in file_queue:
print_file(i, printer_name)
if hinstance > 32:
time.sleep(.25)
delete_file(i)
print "Filename: %r has printed" % i
print
time.sleep(.25)
print
else:
print "No files to print. Will retry in 15 seconds"
time.sleep(15)
def print_file(pfile, printer):
hinstance = win32api.ShellExecute(
0,
"print",
'%s' % pfile,
'/d:"%s"' % printer,
".",
0
)
return hinstance
def delete_file(f):
os.remove(f)
print f, "was deleted!"
def alert(email):
pass
main()
With ShellExecute, you will never know when the printing is complete, it depends on the size of the file and whether the printer driver buffers the contents (the printer might be waiting for you to fill the paper tray, for example).
According to this SO answer, it looks like subprocess.call() is a better solution, since it waits for the command to complete, only in this case you would need to read the registry to obtain the exe associated with the file.
ShellExecuteEx is available from pywin32, you can do something like:
import win32com.shell.shell as shell
param = '/d:"%s"' % printer
shell.ShellExecuteEx(fmask = win32com.shell.shellcon.SEE_MASK_NOASYNC, lpVerb='print', lpFile=pfile, lpParameters=param)
EDIT: code for waiting on the handle from ShellExecuteEx()
import win32com.shell.shell as shell
import win32event
#fMask = SEE_MASK_NOASYNC(0x00000100) = 256 + SEE_MASK_NOCLOSEPROCESS(0x00000040) = 64
dict = shell.ShellExecuteEx(fMask = 256 + 64, lpFile='Notepad.exe', lpParameters='Notes.txt')
hh = dict['hProcess']
print hh
ret = win32event.WaitForSingleObject(hh, -1)
print ret
The return value of ShellExecute is what you need to test. You return that from print_file, but you then ignore it. You need to capture it and check that.
hinstance = print_file(i, printer_name)
if hinstance > 32:
....
However, having your print_file function leak implementation detail like an HINSTANCE seems bad. I think you would be better to check the return value of ShellExecute directly at the point of use. So try to move the > 32 check inside print_file.
Note that ShellExecute has very weak error reporting. If you want proper error reporting then you should use ShellExecuteEx instead.
Your delete/sleep loop is very brittle indeed. I'm not quite sure I can recommend anything better since I'm not sure what you are trying to achieve. However, expect to run into trouble with that part of your program.
I am trying to obtain the current NoteBook name when running the IPython notebook. I know I can see it at the top of the notebook. What I am after something like
currentNotebook = IPython.foo.bar.notebookname()
I need to get the name in a variable.
adding to previous answers,
to get the notebook name run the following in a cell:
%%javascript
IPython.notebook.kernel.execute('nb_name = "' + IPython.notebook.notebook_name + '"')
this gets you the file name in nb_name
then to get the full path you may use the following in a separate cell:
import os
nb_full_path = os.path.join(os.getcwd(), nb_name)
I have the following which works with IPython 2.0. I observed that the name of the notebook is stored as the value of the attribute 'data-notebook-name' in the <body> tag of the page. Thus the idea is first to ask Javascript to retrieve the attribute --javascripts can be invoked from a codecell thanks to the %%javascript magic. Then it is possible to access to the Javascript variable through a call to the Python Kernel, with a command which sets a Python variable. Since this last variable is known from the kernel, it can be accessed in other cells as well.
%%javascript
var kernel = IPython.notebook.kernel;
var body = document.body,
attribs = body.attributes;
var command = "theNotebook = " + "'"+attribs['data-notebook-name'].value+"'";
kernel.execute(command);
From a Python code cell
print(theNotebook)
Out[ ]: HowToGetTheNameOfTheNoteBook.ipynb
A defect in this solution is that when one changes the title (name) of a notebook, then this name seems to not be updated immediately (there is probably some kind of cache) and it is necessary to reload the notebook to get access to the new name.
[Edit] On reflection, a more efficient solution is to look for the input field for notebook's name instead of the <body> tag. Looking into the source, it appears that this field has id "notebook_name". It is then possible to catch this value by a document.getElementById() and then follow the same approach as above. The code becomes, still using the javascript magic
%%javascript
var kernel = IPython.notebook.kernel;
var thename = window.document.getElementById("notebook_name").innerHTML;
var command = "theNotebook = " + "'"+thename+"'";
kernel.execute(command);
Then, from a ipython cell,
In [11]: print(theNotebook)
Out [11]: HowToGetTheNameOfTheNoteBookSolBis
Contrary to the first solution, modifications of notebook's name are updated immediately and there is no need to refresh the notebook.
As already mentioned you probably aren't really supposed to be able to do this, but I did find a way. It's a flaming hack though so don't rely on this at all:
import json
import os
import urllib2
import IPython
from IPython.lib import kernel
connection_file_path = kernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
# Updated answer with semi-solutions for both IPython 2.x and IPython < 2.x
if IPython.version_info[0] < 2:
## Not sure if it's even possible to get the port for the
## notebook app; so just using the default...
notebooks = json.load(urllib2.urlopen('http://127.0.0.1:8888/notebooks'))
for nb in notebooks:
if nb['kernel_id'] == kernel_id:
print nb['name']
break
else:
sessions = json.load(urllib2.urlopen('http://127.0.0.1:8888/api/sessions'))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
print sess['notebook']['name']
break
I updated my answer to include a solution that "works" in IPython 2.0 at least with a simple test. It probably isn't guaranteed to give the correct answer if there are multiple notebooks connected to the same kernel, etc.
It seems I cannot comment, so I have to post this as an answer.
The accepted solution by #iguananaut and the update by #mbdevpl appear not to be working with recent versions of the Notebook.
I fixed it as shown below. I checked it on Python v3.6.1 + Notebook v5.0.0 and on Python v3.6.5 and Notebook v5.5.0.
import jupyterlab
if jupyterlab.__version__.split(".")[0] == "3":
from jupyter_server import serverapp as app
key_srv_directory = 'root_dir'
else :
from notebook import notebookapp as app
key_srv_directory = 'notebook_dir'
import urllib
import json
import os
import ipykernel
def notebook_path(key_srv_directory, ):
"""Returns the absolute path of the Notebook or None if it cannot be determined
NOTE: works only when the security is token-based or there is also no password
"""
connection_file = os.path.basename(ipykernel.get_connection_file())
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
for srv in app.list_running_servers():
try:
if srv['token']=='' and not srv['password']: # No token and no password, ahem...
req = urllib.request.urlopen(srv['url']+'api/sessions')
else:
req = urllib.request.urlopen(srv['url']+'api/sessions?token='+srv['token'])
sessions = json.load(req)
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
return os.path.join(srv[key_srv_directory],sess['notebook']['path'])
except:
pass # There may be stale entries in the runtime directory
return None
As stated in the docstring, this works only when either there is no authentication or the authentication is token-based.
Note that, as also reported by others, the Javascript-based method does not seem to work when executing a "Run all cells" (but works when executing cells "manually"), which was a deal-breaker for me.
The ipyparams package can do this pretty easily.
import ipyparams
currentNotebook = ipyparams.notebook_name
On Jupyter 3.0 the following works. Here I'm showing the entire path on the Jupyter server, not just the notebook name:
To store the NOTEBOOK_FULL_PATH on the current notebook front end:
%%javascript
var nb = IPython.notebook;
var kernel = IPython.notebook.kernel;
var command = "NOTEBOOK_FULL_PATH = '" + nb.base_url + nb.notebook_path + "'";
kernel.execute(command);
To then display it:
print("NOTEBOOK_FULL_PATH:\n", NOTEBOOK_FULL_PATH)
Running the first Javascript cell produces no output.
Running the second Python cell produces something like:
NOTEBOOK_FULL_PATH:
/user/zeph/GetNotebookName.ipynb
Yet another hacky solution since my notebook server can change. Basically you print a random string, save it and then search for a file containing that string in the working directory. The while is needed because save_checkpoint is asynchronous.
from time import sleep
from IPython.display import display, Javascript
import subprocess
import os
import uuid
def get_notebook_path_and_save():
magic = str(uuid.uuid1()).replace('-', '')
print(magic)
# saves it (ctrl+S)
display(Javascript('IPython.notebook.save_checkpoint();'))
nb_name = None
while nb_name is None:
try:
sleep(0.1)
nb_name = subprocess.check_output(f'grep -l {magic} *.ipynb', shell=True).decode().strip()
except:
pass
return os.path.join(os.getcwd(), nb_name)
There is no real way yet to do this in Jupyterlab. But there is an official way that's now under active discussion/development as of August 2021:
https://github.com/jupyter/jupyter_client/pull/656
In the meantime, hitting the api/sessions REST endpoint of jupyter_server seems like the best bet. Here's a cleaned-up version of that approach:
from jupyter_server import serverapp
from jupyter_server.utils import url_path_join
from pathlib import Path
import re
import requests
kernelIdRegex = re.compile(r"(?<=kernel-)[\w\d\-]+(?=\.json)")
def getNotebookPath():
kernelId = kernelIdRegex.search(get_ipython().config["IPKernelApp"]["connection_file"])[0]
for jupServ in serverapp.list_running_servers():
for session in requests.get(url_path_join(jupServ["url"], "api/sessions"), params={"token": jupServ["token"]}).json():
if kernelId == session["kernel"]["id"]:
return Path(jupServ["root_dir"]) / session["notebook"]['path']
Tested working with
python==3.9
jupyter_server==1.8.0
jupyterlab==4.0.0a7
Modifying #jfb method, gives the function below which worked fine on ipykernel-5.3.4.
def getNotebookName():
display(Javascript('IPython.notebook.kernel.execute("NotebookName = " + "\'"+window.document.getElementById("notebook_name").innerHTML+"\'");'))
try:
_ = type(NotebookName)
return NotebookName
except:
return None
Note that the display javascript will take some time to reach the browser, and it will take some time to execute the JS and get back to the kernel. I know it may sound stupid, but it's better to run the function in two cells, like this:
nb_name = getNotebookName()
and in the following cell:
for i in range(10):
nb_name = getNotebookName()
if nb_name is not None:
break
However, if you don't need to define a function, the wise method is to run display(Javascript(..)) in one cell, and check the notebook name in another cell. In this way, the browser has enough time to execute the code and return the notebook name.
If you don't mind to use a library, the most robust way is:
import ipynbname
nb_name = ipynbname.name()
If you are using Visual Studio Code:
import IPython ; IPython.extract_module_locals()[1]['__vsc_ipynb_file__']
Assuming you have the Jupyter Notebook server's host, port, and authentication token, this should work for you. It's based off of this answer.
import os
import json
import posixpath
import subprocess
import urllib.request
import psutil
def get_notebook_path(host, port, token):
process_id = os.getpid();
notebooks = get_running_notebooks(host, port, token)
for notebook in notebooks:
if process_id in notebook['process_ids']:
return notebook['path']
def get_running_notebooks(host, port, token):
sessions_url = posixpath.join('http://%s:%d' % (host, port), 'api', 'sessions')
sessions_url += f'?token={token}'
response = urllib.request.urlopen(sessions_url).read()
res = json.loads(response)
notebooks = [{'kernel_id': notebook['kernel']['id'],
'path': notebook['notebook']['path'],
'process_ids': get_process_ids(notebook['kernel']['id'])} for notebook in res]
return notebooks
def get_process_ids(name):
child = subprocess.Popen(['pgrep', '-f', name], stdout=subprocess.PIPE, shell=False)
response = child.communicate()[0]
return [int(pid) for pid in response.split()]
Example usage:
get_notebook_path('127.0.0.1', 17004, '344eb91bee5742a8501cc8ee84043d0af07d42e7135bed90')
To realize why you can't get notebook name using these JS-based solutions, run this code and notice the delay it takes for the message box to appear after python has finished execution of the cell / entire notebook:
%%javascript
function sayHello() {
alert('Hello world!');
}
setTimeout(sayHello, 1000);
More info
Javascript calls are async and hence not guaranteed to complete before python starts running another cell containing the code expecting this notebook name variable to be already created... resulting in NameError when trying to access non-existing variables that should contain notebook name.
I suspect some upvotes on this page became locked before voters could discover that all %%javascript-based solutions ultimately don't work... when the producer and consumer notebook cells are executed together (or in a quick succession).
All Json based solutions fail if we execute more than one cell at a time
because the result will not be ready until after the end of the execution
(its not a matter of using sleep or waiting any time, check it yourself but remember to restart kernel and run all every test)
Based on previous solutions, this avoids using the %% magic in case you need to put it in the middle of some other code:
from IPython.display import display, Javascript
# can have comments here :)
js_cmd = 'IPython.notebook.kernel.execute(\'nb_name = "\' + IPython.notebook.notebook_name + \'"\')'
display(Javascript(js_cmd))
For python 3, the following based on the answer by #Iguananaut and updated for latest python and possibly multiple servers will work:
import os
import json
try:
from urllib2 import urlopen
except:
from urllib.request import urlopen
import ipykernel
connection_file_path = ipykernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
running_servers = !jupyter notebook list
running_servers = [s.split('::')[0].strip() for s in running_servers[1:]]
nb_name = '???'
for serv in running_servers:
uri_parts = serv.split('?')
uri_parts[0] += 'api/sessions'
sessions = json.load(urlopen('?'.join(uri_parts)))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
nb_name = os.path.basename(sess['notebook']['path'])
break
if nb_name != '???':
break
print (f'[{nb_name}]')
just use ipynbname , which is practical
import ipynbname
nb_fname = ipynbname.name()
nb_path = ipynbname.path()
print(f"{nb_fname=}")
print(f"{nb_path=}")
I found this in https://stackoverflow.com/a/65907473/15497427