I have this error when running this code with Python:
TypeError: "NoneType" object is unsubscriptable".
Code:
number = 0
with open('playlist.txt') as read_number_lines:
for line in read_number_lines:
if line.strip():
number += 1
number = number - 1
print 'number: ', number
for i in range(number):
author_ = raw_input('author: ')
line = input('line: ')
file = open('playlist.txt','a').writelines(' - ' + author_)[line]
How do I fix it?
You've got a few problems in
file = open('playlist.txt','a').writelines(' - ' + author_)[line]
The immediate source of your error is that .writelines() doesn't return anything (so it returns None) which you're trying to index using [line]. That produces your error.
Also, you shouldn't be calling that method on the open() call directly.
The entire second for loop is mysterious to me. You're opening that file again during each iteration of the loop (which you don't want to do; it probably wouldn't even work).
Perhaps you wanted to do something like
with open('playlist.txt','a') as file:
for i in range(number):
author_ = raw_input('author: ')
line = raw_input('line: ')
file.write(author + " - " + line)
but it's still hard to see the point of this...
Related
Problem solved! was newfilename[0,3] instead of newfilename[0: 3]
I know this question has been asked before and I have look around on all the answers and the types of problems people have been having related to this error message, but was unable to find anyone with the same type of problem.
I am sowing the whole method just in case. So here is my problem;
When I am trying to get is a substring of "newfilename" using newfilename[int, int] and the compiler keeps thinking I don't have an integer there when I do, at least from my checking I do.
What I'm doing with this code: I am cutting of the end of a filename such as 'foo.txt' to get 'foo' that is saved as newfilename. Then I am adding the number (converted to a string) to the end of it to get 'foo 1' and after that adding back the '.txt' to get the final result of 'foo 1.txt'. The problem occurs when I try to get the substring out and delete the last four characters of the filename to get just 'foo'. After that, I do another check to see if there is a file like that still in the folder and if so I do another set of cutting and pasting to add 1 to the previous file. To be honest, I have not tested of the while loop will work I just thought it should work technically, but my code does not reach that far because of this error lol.
My error:
File "C:/Users/Reaper/IdeaProjects/Curch Rec Managment/Setup.py", line 243, in moveFiles
print(newfilename[0, 3])
TypeError: string indices must be integers
NOTE this error is from when I tried to hard code the numbers it to see if it would work
Here is the current error with the hard code commented out:
newfilename = newfilename[0, int(newfilename.__len__() - 4)] + " 1.m4a"
TypeError: string indices must be integers
What I have tried: I have tried hard coding the numbers is by literally typing in newfilename[0, 7] and still got the same error. I have tried doing this in a separate python file and it seems to work there fine. Also, what is really confusing me is that it works in another part of my program just fine as shown here:
nyear = str(input("Enter new Year: "))
if nyear[0:2] != "20" or nyear.__len__() > 4:
print("Sorry incorrect year. Please try again")
So I have been at it for a while now trying to figure out what in the world is going on and can't get there. Decided I would sleep on it but would post the question just in case. If someone could point out what may be wrong that would be awesome! Or tell me the compilers are just being stupid, well I guess that will do as well.
My function code
def moveFiles(pathList, source, filenameList):
# moves files to new location
# counter keeps track of file name position in list
cnter = 0
for x in pathList:
filename = filenameList[cnter]
#print(x + "\\" + filename)
# new filename
if filename.find("PR") == 0:
newfilename = filename[3:filename.__len__()]
else:
newfilename = filename[2:filename.__len__()]
# checking if file exists and adding numbers to the end if it does
if os.path.isfile(x + "\\" + newfilename):
print("File Name exists!!")
# adding a 1 to the end
print(newfilename)
# PROBLEM ON NEXT TWO LINES, also prob. on any line with the following calls
print(newfilename[0, 3])
newfilename = newfilename[0, int(newfilename.__len__() - 4)] + " 1.m4a"
print("Adding 1:", newfilename)
# once again check if the file exists and adding 1 to the last number
while os.path.isfile(x + "\\" + newfilename):
# me testing if maybe i just can't have math operations withing the substring call
print("File exists again!!")
num = newfilename.__len__() - 6
num2 = newfilename.__len__() - 4
num3 = int(newfilename[num, num2])
num = newfilename.__len__() - 5
newfilename = newfilename[0, num] + str(num3 + 1)
print("Adding 1:", newfilename)
# moving file and deleting prefix
if not os.path.isdir(x):
os.makedirs(x)
os.rename(source + "\\" + filename, x + "\\" + newfilename)
cnter += 1
I think you need this:
print(newfilename[0:3])
My problem is that I have a many functions that essentially do the same thing depending on a given error code. How can I develop a loop to simplify these functions into one algorithm that checks the error code from a list or table of error codes. As well as detecting the error code string, I would like to count occurrences for each unique error code.
I've tried to make a table that includes column such as error and description. I am confused how I can match the error with the description
file_path = ('/Users/.../error.txt')
def check_error1():
count = 0
fault = ':error1'
with open(file_path) as f:
for line in f.readlines():
if fault in line:
count += fault.count(fault)
return count != 0
if check_error1():
print 'error 1 occurred ' , count, ' times || WARNING, Bot failed to read data'
print 'error 1 occurred ' , count, ' times || WARNING, Bot failed to read data'
You could find all faulty lines in the file and then take the length of that:
def check_error1():
with open(file_path) as f:
return len(line for line in f if ':error1' in line)
I'm new to Python and I'm trying to output the length of a list as a single integer, eg:
l1 = ['a', 'b', 'c']
len(l1) = 3
However, it is printing on cmdline with 1s down the page, eg:
1
1
1
1
1
1
etc
How can I get it to just output the number rather than a list of 1s?
(Here's the code:)
def Q3():
from datetime import datetime, timedelta
inputauth = open("auth.log", "r")
authStrings = inputauth.readlines()
failedPass = 'Failed password for'
for line in authStrings:
time = line[7:15]
dateHour = line[0:9]
countAttack1 = []
if time in line and failedPass in line:
if dateHour == 'Feb 3 08':
countAttack1.append(time)
length1 = len(countAttack1)
print(length1)
Ideally, I'd like it to output the number in a print so that I could format it, aka:
print("Attack 1: " + length1)
I think you are looping and ifs are inside a loop. If so, just print the length outside loop scope.
Please share the complete code for a better answer
Well as Syed Abdul Wahab said, the problem is that the "list" is getting recreated each loop. This makes so that the print reports "1", as it is the actual length of the list.
The other problem, repetition of the printng is similar - you are actually printing "each time in the loop".
The solution is then simple: you initialize the list outside the loop; and also report outside the loop.
def Q3():
from datetime import datetime, timedelta
inputauth = open("auth.log", "r")
authStrings = inputauth.readlines()
failedPass = 'Failed password for'
countAttack1 = [] # after this line the countAttack will be empty
for line in authStrings:
time = line[7:15]
dateHour = line[0:9]
if time in line and failedPass in line:
if dateHour == 'Feb 3 08':
countAttack1.append(time)
length1 = len(countAttack1)
print("Attack 1: " + str(length1))
I'd also like to take a bit of time to link you to string formatting While the documentation is complex it will make printing much easier, above print is trnasformed into:
print("Attack 1: {0}".format(length1))
Further analysing the code gives some peculiarities, you check if time is in the line string. - However just a few codelines above you create time from a slice of line - so it will always be inside line. (Except for the edge case where line is not of correct length, but that'll error anyways). So that if statement should be simplified to:
if failedPass in line:
Here is the function that prints the the length:
def print_length():
if time in line and failedPass in line:
if dateHour == 'Feb 3 08':
countAttack1.append(time)
length1 = len(countAttack1)
print(length1)
print_length()
>>>Print length of the List.
I wrote a programme to generate a string of number, consisting of 0,1,2,and 3 with the length s and write the output in decode.txt file. Below is the code :
import numpy as np
n_one =int(input('Insert the amount of 1: '))
n_two =int(input('Insert the amount of 2: '))
n_three = int(input('Insert the amount of 3: '))
l = n_one+n_two+n_three
n_zero = l+1
s = (2*(n_zero))-1
data = [0]*n_zero + [1]*n_one + [2]*n_two + [3]*n_three
print ("Data string length is %d" % len(data))
while data[0] == 0 and data[s-1]!=0:
np.random.shuffle(data)
datastring = ''.join(map(str, data))
datastring = str(int(datastring))
files = open('decode.txt', 'w')
files.write(datastring)
files.close()
print("Data string is : %s " % datastring)
The problem occur when I try to read the file from another program, the program don't call the last value of the string.
For example, if the string generated is 30112030000 , the other program will only call 3011203000, means the last 0 is not called.
But if I key in 30112030000 directly to the .txt file, all value is read. I can't figure out where is wrong in my code.
Thank you
Some programs might not like the fact that the file doesn't end with a newline. Try adding files.write('\n') before you close it.
I'm trying to read the last line from a text file. Each line starts with a number, so the next time something is inserted, the new number will be incremented by 1.
For example, this would be a typical file
1. Something here date
2. Something else here date
#next entry would be "3. something date"
If the file is blank I can enter an entry with no problem. However, when there are already entries I get the following error
LastItemNum = lineList[-1][0:1] +1 #finds the last item's number
TypeError: cannon concatenate 'str' and 'int objects
Here's my code for the function
def AddToDo(self):
FILE = open(ToDo.filename,"a+") #open file for appending and reading
FileLines = FILE.readlines() #read the lines in the file
if os.path.getsize("EnteredInfo.dat") == 0: #if there is nothing, set the number to 1
LastItemNum = "1"
else:
LastItemNum = FileLines[-1][0:1] + 1 #finds the last items number
FILE.writelines(LastItemNum + ". " + self.Info + " " + str(datetime.datetime.now()) + '\n')
FILE.close()
I tried to convert LastItemNum to a string but I get the same "cannot concatenate" error.
LastItemNum = int(lineList[-1][0:1]) +1
then you've to convert LastItemNum back to string before writing to file, using :
LastItemNum=str(LastItemNum) or instead of this you can use string formatting.