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"while True" intermediate solutions [closed]

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I'm working with big multidimensional arrays. I want to know after x loops the values S,S2,E,E2
I want to find all the solutions of a loop.
I have a code that iterates with a greedy. My output is a list of numers. I want to save the arrays that generate those numbers. My code:
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
print f2-f
else:
break
If i run this code I have a list of f2-f but I need also to save the f,S,S2,f2,E,E2 created in each passage of the while.. Thank you

results = []
while True:
if f2<f:
f,S,S2=f2,E,E2 # f is a value and S and E are arrays
......
results.append((f,S,S2,E,E2))
print f2-f
print "intermediate result:", results[-1]
else:
break

Check if part of text is in tuple [closed]

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How to check if part of text is in tuple?
For example:
my_data = ((1234L,), (23456L,), (3333L,))
And we need to find if 123 or 1234 is in tuple.
I didn't worked lot with tuples before.
In array we use:
if variable in array
But its not working for tuples like my_data
PS. 1st answer solved problem.

def findIt(data, num):
num = str(num)
return any(num in str(i) for item in data for i in item)
data = ((1234L,), (23456L,), (3333L,))
print findIt(data, 123)
Output
True

python parsing string using regex [closed]

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I need to parse a string from this:
CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt
To this:
ES1-HER / ES1-Seura
Any easy way to do this with regex?

>>> import re
>>> s = 'CN=ERT234,OU=Computers,OU=ES1-HER,OU=ES1-Seura,OU=RES-ES1,DC=resu,DC=kt,DC=elt'
>>> re.findall('OU=([^,]+)', s)
['Computers', 'ES1-HER', 'ES1-Seura', 'RES-ES1']
>>> re.findall('OU=([^,]+)', s)[1:3]
['ES1-HER', 'ES1-Seura']
>>> ' / '.join(re.findall('OU=([^,]+)', s)[1:3])
'ES1-HER / ES1-Seura'
Don't use str as a variable name. It shadows builtin function str.

Python List sorting by columns [closed]

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If I had a list
['xxxx', 'oooo', 'xxxx', 'oooo'......etc]
which looks like
(xxxx)
(oooo)
(xxxx)
(oooo)
and the list could be as long as the user inputs,
how would I make a new list sorted by each column which would look like:
['xoxo', 'xoxo', 'xoxo', 'xoxo']
which would be
(xoxo)
(xoxo)
(xoxo)
(xoxo)

myList=['xxxx', 'oooo', 'xxxx', 'oooo']
print [''.join(element) for element in zip(*myList)]
Output
['xoxo', 'xoxo', 'xoxo', 'xoxo']
What you are looking for, is called, transposing an array. That can be achieved with zip function.

how to convert timecode into seconds:fractions_of_a_second? [closed]

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Given timecode in this format
00:00:00,0
What is the best way to convert this into seconds.fractions_of_a_second?

Here's a link for some python code to handle SMPTE timecodes http://code.google.com/p/pytimecode/
Hope it helps...

The datetime module is your friend in this case
import datetime
time_string = "17:48:12,98"
t = datetime.datetime.strptime(time_string, "%H:%M:%S,%f")
seconds = 60 * t.minute * t.hour
print (seconds, t.microsecond)