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SO I have this code:
Chars = maketrans(" ABCDEFGHIJKLMNOPQRSTUVWXYZ-.,"," ABCDEFGHIJKLMNOPQRSTUVWXYZ-.,");
input = input.split(" ");
length = len(input);
charLength = len(Chars);
for x in range(1,length):
for y in range(1,charLength):
for z in range(MinInt,MaxInt):
if Transform(z + x.translate(Chars) + Key)[:5] == input[x]
print x.translate(Chars)
The function receives blocks of 5 characters separated by spaces. When attempting to run it, I get the following error:
File "SH25.py", line 21
if Transform(z + x.translate(Chars) + Key) == input[x]
^
SyntaxError: invalid syntax
I'm admittedly a newbie at Python, but could anyone help? Thanks.
The error message is pretty precise: you need a : after if
if Transform(z + x.translate(Chars) + Key)[:5] == input[x]:
Related
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def ShowData(data = (x)):
for r in data:
print (“{:}, {:.2f}”.format(x, x))
keep getting this error:
File "<ipython-input-10-9963f96f39ca>", line 8
print (“{:}, {:.2f}”.format(x, x))
^
SyntaxError: invalid character in identifier
Replace the “ charachter with this " ?
# data is a list of lists
def ShowData(data = (x)):
for r in data:
print ("{:}, {:.2f}".format(x, x))
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I'm trying to run a simple program in Python3, but I keep getting this error message after typing into the terminal python3 mario.py:
File "mario.py", line 10
^
SyntaxError: unexpected EOF while parsing
I'm not sure why this is happening. Here is my code:
#from cs50 import get_int
height = int(input("Height: "))
if height < 1 or height > 8:
height = get_int("Height: ")
for i in range(height):
print(f"{"#" * i} {"#" * i}\n", end="")
I believe it has something to do with the way I'm formatting my print function. I'm not sure which one of these to use: ' or "
I would love if you could help!
You have to alternate between " and '. Try this:
print(f'{" # " * i} {"#" * i}\n', end="")
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Here's a function I'm writing:
def addError(test,range_min,range_max,result):
err = abs(log(range_max/max(range_min,epsylon))
if test >= range_min and test <= range_max:
result.append(err)
else:
e1=abs(log(test/max(range_min,epsylon)))
e2=abs(log(test/max(range_max,epsylon)))
result.append( min(e1,e2) / max(err,epsylon) *100 + err)
When I try to run this, it fails with error:
File "<ipython-input-26-8b4b5ae453e4>", line 12
if (test >= range_min and test <= range_max):
^
SyntaxError: invalid syntax
Why am I getting this?
You forgot to close all the brackets in the previous line, this should fix the problem:
err = abs(log(range_max/max(range_min,epsylon)))
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I'm trying to make a simple console game in Python 2.7, where the user gets a dilemma and makes a decision by typing the number correlating to the option he wants to choose. This question is the main menu.
s = raw_input("Enter a number in the range 1 to %s\n> " % v
if (is_number(s) and s in q):
return s
I'm getting a "SyntaxError: Invalid syntax" from the if (is_number(s) and s in q) statemet when trying to run the program. It was working fine before i added the question.
This is my first real program.
You're missing a parentheses on the previous line:
s = raw_input("Enter a number in the range 1 to %s\n> " % v
# here--^
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Issue occurred right after I added the and x= "J1234": I don't know what's going on.
original = ""
if len(original) > 0 and x = "J123":
raw_input("Enter a word:")
original = raw_input('word')
print "original"
else:
print "empty"
x.isalpha()
So, you're getting a SyntaxError. To fix this, change:
x = "J123":
to...
x == "J123":
In Python the former is for setting values and the latter is for checking them. Therefore when you use this the wrong way round the syntax is incorrect.