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I'm trying to make a simple console game in Python 2.7, where the user gets a dilemma and makes a decision by typing the number correlating to the option he wants to choose. This question is the main menu.
s = raw_input("Enter a number in the range 1 to %s\n> " % v
if (is_number(s) and s in q):
return s
I'm getting a "SyntaxError: Invalid syntax" from the if (is_number(s) and s in q) statemet when trying to run the program. It was working fine before i added the question.
This is my first real program.
You're missing a parentheses on the previous line:
s = raw_input("Enter a number in the range 1 to %s\n> " % v
# here--^
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I am currently trying to create team selection code for my python video game.
Unfortunately, it keeps highliting the ":" of my if statement and saying that it is invalid syntax, even if i change the if statement for another. I tried everything, but after all, it IS an if statement, and i can't do much.
Heres my minimal recreation of the problem. The structure is important as there is netwroking code there;
team1=[]
team2=[]
if (len(team1)+len(team2)):
if team1==team2:
rand = (random.choice([team1, team2])
if rand == "team1":
team1.append(username)
else:
team2.append(username)
else:
if team1>=team2:
team1.append(username)
else:
team2.append(username)
else:
team1.append(username)
The problem is the stray '(' you have before random.choice([team1, team2]). Delete it so it becomes:
rand = random.choice([team1, team2])
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I am new to python and trying to execute my code. Below is my code.
def evod(number):
if number % 2 == 0:
print("The number is even")
return"The number is odd"
print(evod(60))
Output is:
The number is even
The number is odd
if I run this function it prints both lines. It should print a single one of those. Right? Why is this happening?
if c=="July":
print("7/1/2017")
else:
print("sorry")
Indentation matters in python!
if c == "July":
print ("7/1/2017")
else:
print ("sorry")
Correct your indentation
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I tried to make a power calculator program in Python 2.7. It worked but I tried to write the values into a file and the /n didn't work. Here is the program:
import math
file = open("numbers.txt" , 'w')
c = 0
a = int(raw_input("A number: "))
b = int(raw_input("To the power "))
h = range(b)
h.append(b)
print 1
file.write('1')
for c in range(b):
print int((math.pow(a, h[c+1])))
k = (int((math.pow(a, h[c+1]))))
file.write((str(k)+"/n") `
You're using a normal slash (/). But you need to use a Backslash (\).
So, \n will add a new line.
\ is used for escape sequence.
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Issue occurred right after I added the and x= "J1234": I don't know what's going on.
original = ""
if len(original) > 0 and x = "J123":
raw_input("Enter a word:")
original = raw_input('word')
print "original"
else:
print "empty"
x.isalpha()
So, you're getting a SyntaxError. To fix this, change:
x = "J123":
to...
x == "J123":
In Python the former is for setting values and the latter is for checking them. Therefore when you use this the wrong way round the syntax is incorrect.
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Closed 9 years ago.
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I am new to this and am receiving an error that says print (line 5) is an invalid syntax
from random import randint
r=randint
while True:
s=int(input('How many sides would you like on your die')
print (r(1,s))
The problem is not actually on line 5, but on line 4. You have two ( brackets but only one ). In search of the final ) the Python interpreter checks the following line, and only at that point does it raise the error.
s=int(input('How many sides would you like on your die')
^
There is a closing parenthesis missing.