I want to make my function trigger at 0 second,30second every minute.
Rather than use time.sleep(30) because the script will run for months and have some blocking system call,
I want to make it happens on specific time like 12:00:00, 12:00:30, 12:01:00
How could I do it on Python 2.7
Not sure how your function works but if there is any sort of a loop you could use an if statement.
t = time.time()
while/for loop:
...
if time.time() > t + 30:
yourFunction()
t = time.time()
...
EDIT:
My fault, misread that. Similar method but you can use date time, probably better off looking into chrontab though. This method is a little hacky and if your script is small and can cycle every second this will work, otherwise go chrontab.
import datetime
t = datetime.datetime
run = True
while/for loop:
...
if t.now().second % 30 == 0 and run == True:
yourFunction()
run = False
if t.now().second % 30 == 1:
run = True
...
Related
Complete newbie here so bare with me. I've got a number of devices that report status updates to a singular location, and as more sites have been added, drift with time.sleep(x) is becoming more noticeable, and with as many sites connected now it has completely doubles the sleep time between iterations.
import time
...
def client_list():
sites=pandas.read_csv('sites')
return sites['Site']
def logs(site):
time.sleep(x)
if os.path.isfile(os.path.join(f'{site}/target/', 'hit')):
stamp = time.strftime('%Y-%m-%d,%H:%M:%S')
log = open(f"{site}/log", 'a')
log.write(f",{stamp},{site},hit\n")
log.close()
os.remove(f"{site}/target/hit")
else:
stamp = time.strftime('%Y-%m-%d,%H:%M:%S')
log = open(f"{site}/log", 'a')
log.write(f",{stamp},{site},miss\n")
log.close()
...
if __name__ == '__main__':
while True:
try:
client_list()
with concurrent.futures.ThreadPoolExecutor() as executor:
executor.map(logs, client_list())
...
I did try adding calculations for drift with this:
from datetime import datetime, timedelta
def logs(site):
first_called=datetime.now()
num_calls=1
drift=timedelta()
time_period=timedelta(seconds=5)
while 1:
time.sleep(n-drift.microseconds/1000000.0)
current_time = datetime.now()
num_calls += 1
difference = current_time - first_called
drift = difference - time_period* num_calls
if os.path.isfile(os.path.join(f'{site}/target/', 'hit')):
...
It ends up with a duplicate entries in the log, and the process still drifts.
Is there a better way to schedule the function to run every x seconds and account for the drift in start times?
Create a variable equal to the desired system time at the next interval. Increment that variable by 5 seconds each time through the loop. Calculate the sleep time so that the sleep will end at the desired time. The timings will not be perfect because sleep intervals are not super precise, but errors will not accumulate. Your logs function will look something like this:
def logs(site):
next_time = time.time() + 5.0
while 1:
time.sleep(time.time() - next_time)
next_time += 5.0
if os.path.isfile(os.path.join(f'{site}/target/', 'hit')):
# do something that takes a while
So I managed to find another route that doesn't drift. The other method still drifted over time. By capturing the current time and seeing if it is divisible by x (5 in the example below) I was able to keep the time from deviating.
def timer(t1,t2)
return True if t1 % t2 == 0 else False
def logs(site):
while 1:
try:
if timer(round(time.time(), 0), 5.0):
if os.path.isfile(os.path.join(f'{site}/target/', 'hit')):
# do something that takes a while
time.sleep(1) ''' this kept it from running again immediately if the process was shorter than 1 second. '''
...
I am trying to make a python script that works in a loop mode with iteration through a text file to run for periods of one hour and make 30minute pauses between each hour loop .
After some searching I found this piece of code :
import datetime
import time
delta_hour = 0
while:
now_hour = datetime.datetime.now().hour
if delta_hour != now_hour:
# run your code
delta_hour = now_hour
time.sleep(1800) # 1800 seconds sleep
# add some way to exit the infinite loop
This code has a few issues though :
It does not consider one hour periods since the script starts running
It does not seem to work continuously for periods over one hour
Considering what I am trying to achieve (running script 1hour before each time it pauses for 30mins) what is the best approach to this ? Cron is not an option here .
For clarification :
1hour run -- 30min pause -- repeat
Thanks
Here is a so simple code, I have written for teaching purposes, which is very clear
from datetime import datetime
class control_process():
def __init__(self, woking_period, sleeping_period):
self.woking_period = woking_period # working period in minutes
self.sleeping_period = sleeping_period # sleeping period in minutes
self.reset()
def reset(self):
self.start_time = datetime.utcnow() # set starting point
def manage(self):
m = (datetime.utcnow() - self.start_time).seconds / 60 # how long since starting point
if m >= self.woking_period: # if exceeded the working period
time.sleep(self.sleeping_period * 60) # time to sleep in seconds
self.reset() # then reset time again
return # go to continue working
cp = control_process(60, 30) # release for 60 minutes and sleep for 30 minutes
while True: # you code loop
cp.manage()
'''
your code
'''
in which 'control_processobject - I calledcp- callscp.manage()` inside your executing loop.
you reset time via cp.reset() before going in the loop or whenever you want
Based on Comments
The simplicity I mean is to add this class to your general library so you can use it whenever you want by instantiation of cp then one or two controlling functions 'cp.manage()` which control the working cycles, and cp.reset() if you want to use it in another location of the code. I believe that use a function is better than a long condition statement.
Using the default library you could do something like call the script itself using subprocess. By checking whether conditions are met the process could do a task and call itself. Extending the logic with a kill pill would make it stop (I leave that up to you).
import argparse, time
from subprocess import call
DELAY = 60 * 30 # minutes
WORK_TIME = 60 * 60 # minutes
parser = argparse.ArgumentParser()
parser.add_argument("-s",
help = "interval start time",
type = float,
default = time.time())
parser.add_argument("-t",
help = "interval stop time",
type = float,
default = time.time() + WORK_TIME)
def do_task():
# implement task
print("working..")
return
if __name__ == "__main__":
args = parser.parse_args()
start = args.s
stop = args.t
# work
if start < time.time() < stop:
do_task()
# shift target
else:
start = time.time() + DELAY
stop = start + WORK_TIME
call(f"python test.py -t {stop} -s {start}".split())
The simplest solution I could come up with was the following piece of code, which I added inside my main thread :
start_time = int(time())
... #main thread code
#main thread code end
if int(time() - start_time >= 60 * 60):
print("pausing time")
sleep(30 * 60)
start_time = int(time())
From the moment the script starts this will pause every hour for 30mins and resume afterwards .
Simple yet effective !
I'm trying to get a for loop to print the value of 'i' every 5 minutes
import threading
def f(i):
print(i)
threading.Timer(600, f).start()
for i in range(1,1000000000000):
f(i=i)
However, this method results in the code printing the value of i instantly since it calls 'f' as soon as it finds 'i'.
I know this is not the first time someone will ask, nor the last, but I can't get it to work on a for loop nested within a function.
I'm fairly new to Python and I'd appreciate any help.
How about just keeping track of how long has passed in the loop?
from timeit import default_timer as timer
start = timer()
freq = 5 * 60 # Time in seconds
last_time = 0.0
for i in range(int(1e8)):
ctime = timer()
if ctime - last_time > freq:
print(i)
last_time = ctime
I imagine you can make this more efficient by only checking the time every N iterations rather than every time. You may also want to look into using progressbar2 for a ready-made solution.
I prefer using datetime, as I think it's more intuitive and looks a bit cleaner. Otherwise, using more or less the same approach as Paul:
from datetime import datetime, timedelta
print_interval = timedelta(minutes=5)
# Initialize the next print time. Using now() will print the first
# iteration and then every interval. To avoid printing the first
# time, just add print_interval here (i.e. uncomment).
next_print = datetime.now() # + print_interval
for i in range(int(1e8)):
now = datetime.now()
if now >= next_print:
next_print = now + print_interval
print(i)
Also note that before python 3.x xrange would be preferable over range.
I'm wondering how I can play a .wav file after some time has passed without using the sleep function. Essentially, I was wondering if there is a way to keep track of time in Python, so that, after say 15 seconds has elapsed, I can play a sound without pausing my code.
# checks if I should play the sound or not and, sets the variable
def Tyler(self):
if self.started == 1:
if self.isTaiwan == 0:
if self.myListNames[self.current_player_id / 3].lower() == "tyler":
self.isTyler = 1
else:
self.isTyler = 0
self.Tyler()
if self.isTyler == 1:
time.sleep(6)
winsound.PlaySound("tyler.wav", winsound.SND_ASYNC)
# This is where I would want to check to see
# if some time has passed and the conditions haven't changed.
from time import time
def delay(secs):
init_time = time()
while time() < init_time+secs: pass
This won't use sleep but it is similar. Still uses time module
matches = []
done = []
for item in matches:
dofunctioneveryloop()
done.extent(item)
dofunctiononce5min()
How can I execute dofunctiononce5min() inside this loop once 5 minute? This is backup to file function is this possible?
Not sure I understood the question. I'll assume that you want this function to be executed only once every five minutes, no matter how often it is really called.
This might be overkill, but why not use a decorator? This will create a new function for the 'decorated' function that will execute the original function if X seconds have passed since the last execution. This will make sure the function is not executed more than once every 5 minutes (or whateer time interval in seconds you pass to the decorator), no matter whether it's called in that loop or elsewhere.
import time
def onceEveryXSeconds(seconds): # this creates the decorator
def wrapper(f): # decorator for given 'seconds'
f.last_execution = 0 # memorize last execution time
def decorated(*args, **kwargs): # the 'decorated' function
if f.last_execution < time.time() - seconds:
f.last_execution = time.time()
return f(*args, **kwargs)
return decorated
return wrapper
Usage:
#onceEveryXSeconds(3)
def function(foo):
print foo
while True:
print "loop"
function("Hello again")
time.sleep(1)
Output, with #onceEveryXSeconds(3)
loop
Hello again
loop
loop
loop
Hello again
loop
...
Assuming the loop takes longer than five minutes, you could use time.time() to determine when 5 minutes has been up.
import time
matches = []
done = []
starttime = time.time()
for item in matches:
dofunctioneveryloop()
done.extent(item)
if time.time() - starttime > 300:
dofunctiononce5min()
starttime = time.time()
It is not recommended that you do this way. Perhaps the best approach could be to schedule it on operation system, and it run it task periodically.
Anyway, if want to run a statement every x time, here is an example
import time
for i in range(5):
print i
time.sleep(3) # seconds
Time as parameter should be fractioned like 0.5 seconds.