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Users are prompted for the location of a file that contains multiple sets of some information: the product number, the price of the product, the day, the month, the year.
eg.
12345678,200,1,1,2014
23456789,150,1,1,2014
12345678,180,1,2,2014
I need to get the total number of prices (ie 200,150,180). How do I do so?
Open your file, iterate over its lines with a for loop, split each line by commas and print second field.
This should work:
filepath = raw_input('Input file path:\n')
with open(filepath) as f:
for line in f:
print line.split(',')[1]
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Could you advise what would be the best way to extract an element from JSON when I have multiple JSONs in a CSV file?
The data structure is like this
Line1: {"CreationTime":"2018-10-29T13:40:13","Id":"35127aae-a888-4665-6514-08d63da40e14","Operation":....,"IPaddress":"x.x.x.x"...}
Line 2: {"CreationTime":"2018-10-29T13:41:13","Id":"35127aae-a888-4665-6514-08d63da40e14","Operation":....,"IPAddress":"x.x.x.x"...}
.....
LineYY:...
My goal is to extract the IPAddress value from every line, that means from every json array. What would be the best way to do it?
Thanks a lot!
You can use json to load each line into a dictionary and then access IPAddress
import json
ips = []
for line in data.readlines():
row = json.loads(line)
ips.append(row['IPAddress'])
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consider below the output of my subprocess module of python. Now from here I want to grab the very first username only like root ,daemon and continuew. I tried but not able to write the exact regex to fetch the users only .
root:x:0:0:root:/root:/bin/bash
daemon:x:1:1:daemon:/usr/sbin:/usr/sbin/nologin
bin:x:2:2:bin:/bin:/usr/sbin/nologin
You do not a regex in the first place, as per your comments. So, you may iterate over the output line by line (str.splitlines()), split the line with : (str.split(':')) and take the first result (result[0]). This expects the output to be consistent, else it will fail.
Use split instead of regex
for line in output.split('\n'):
print line.split(':')[0]
>>>root
>>>daemon
....
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Please help.
I have data in text file with 2 long columns tab spaced
I have to extract first and second columns separately
Can it be done with Python ?
If you need the columns as two separate lists:
first_column = []
second_column = []
data_file = open('your_file.txt')
for line in data_file.readlines():
first_column.append(line.split('\t')[0])
second_column.append(line.split('\t')[1])
data_file.close()
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I'm new to Python and need to remove lines from text file in Python that contain a certain letter. i.e. a text file containing the months of the year and I want to remove the months containing an r. I'm completely lost.
How about this? (Reads from stdin, writes to stdout.)
import sys
for line in sys.stdin:
if 'r' not in line:
print(line)
Sample usage:
$ python program.py < months_file > months_without_r_file
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How can I use Python to print a line of my choosing from a file?
E.g. a file 10 lines long and I use sys.argv to provide a value for the line that I wish to print.
f = open('put_your_text_file.csv', 'r')
num = sys.argv[2]
for i, line in enumerate(f.readlines()):
if i == num:
print(line)