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How can I use Python to print a line of my choosing from a file?
E.g. a file 10 lines long and I use sys.argv to provide a value for the line that I wish to print.
f = open('put_your_text_file.csv', 'r')
num = sys.argv[2]
for i, line in enumerate(f.readlines()):
if i == num:
print(line)
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I want to print out 3 of the same words on the same line after reading it from a file. So say the word is Test. I want it to print TestTestTest. Here is the code I came up with, but it prints each as a separate line. How do I fix this?
import os
file = open('rockyou.txt', 'r')
for line in file:
output = line.title()
print(output+output+output)
It must have newlines:
for line in file:
output = line.strip().title()
print(output + output + output)
Instead of output + output + output, just do multiplication:
for line in file:
output = line.strip().title()
print(output * 3)
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Please help.
I have data in text file with 2 long columns tab spaced
I have to extract first and second columns separately
Can it be done with Python ?
If you need the columns as two separate lists:
first_column = []
second_column = []
data_file = open('your_file.txt')
for line in data_file.readlines():
first_column.append(line.split('\t')[0])
second_column.append(line.split('\t')[1])
data_file.close()
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I'm new to Python and need to remove lines from text file in Python that contain a certain letter. i.e. a text file containing the months of the year and I want to remove the months containing an r. I'm completely lost.
How about this? (Reads from stdin, writes to stdout.)
import sys
for line in sys.stdin:
if 'r' not in line:
print(line)
Sample usage:
$ python program.py < months_file > months_without_r_file
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Users are prompted for the location of a file that contains multiple sets of some information: the product number, the price of the product, the day, the month, the year.
eg.
12345678,200,1,1,2014
23456789,150,1,1,2014
12345678,180,1,2,2014
I need to get the total number of prices (ie 200,150,180). How do I do so?
Open your file, iterate over its lines with a for loop, split each line by commas and print second field.
This should work:
filepath = raw_input('Input file path:\n')
with open(filepath) as f:
for line in f:
print line.split(',')[1]
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How can I find a string in a text file and then print which line that string was found on?
I am using Python 2.7.
In Python, enumerate is handy for this sort of thing:
with open(myfile) as f:
for index, line in enumerate(f, 1):
if s in line:
print("'{0}' found on line {1}".format(s, index))