I have two foreign keys in an entity refering to another entity.
Here is how it looks
class Review(db.Model):
__tablename__ = 'Review'
id = db.Column(db.Integer, primary_key = True)
user_id = db.Column(db.Integer, db.ForeignKey('User.id'), nullable=False)
business_user_id = db.Column(db.Integer, db.ForeignKey('User.id'), nullable=False)
user = db.relationship('User', foreign_keys=[user_id])
business_user = db.relationship('User', foreign_keys=[business_user_id])
and
class User(db.Model):
__tablename__ = 'User'
id = db.Column(db.Integer, primary_key = True)
reviews = db.relationship('Review', backref='user',
lazy='dynamic')
However, it still shows me an error saying
there are multiple foreign key paths linking the tables. Specify the
'foreign_keys' argument, providing a list of those columns which
should be counted as containing a foreign key reference to the parent
table
The above workaround is what I get from some other posts. I have checked and changed many times, and still no luck. I wonder if it's already correct or there is something I miss. Need help
Finally, I got the workaround after trying to figure out. In my case, I don't have to put backref in Review class. Instead, I should put the User backref in User class itself. So, it should look like below
class Review(db.Model):
__tablename__ = 'Review'
id = db.Column(db.Integer, primary_key = True)
user_id = db.Column(db.Integer, db.ForeignKey('User.id'), nullable=False)
business_user_id = db.Column(db.Integer, db.ForeignKey('User.id'), nullable=False)
user = relationship('User', backref='user_reviews', foreign_keys=user_id)
business_user = relationship("User", backref='business_user_reviews', foreign_keys=[business_user_id])
class User(db.Model):
__tablename__ = 'User'
id = db.Column(db.Integer, primary_key = True)
Here, both types of User have many Reviews. Then, when I need to get the list of reviews of both User, what I can do is
user = User.query.get(id)
user_reviews = User.user_reviews
business_user_reviews = user.business_user_reviews
And I am no longer running across this error.
Related
I'm learning flask and i'm looking to implement a many to many realtionship. I searched on internet but there are different ways,
this is what i have tried so far
class Group(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
class Course(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
class Group_Course(db.Model):
id = db.Column(db.Integer, primary_key=True)
group_id = db.Column(db.Integer, db.ForeignKey(Group.id))
theory_id = db.Column(db.Integer, db.ForeignKey(Course.id))
I'm not sure this is the right way to do it. I'm having issues with delete endpoint. I think that i should add on delete cascade but i don't know how to do it.
there are some sites that add relationships to the table association, so the association table looks like that.
class Group_Course(db.Model):
id = db.Column(db.Integer, primary_key=True)
group_id = db.Column(db.Integer, db.ForeignKey(Group.id))
course_id = db.Column(db.Integer, db.ForeignKey(Course.id))
course = db.relationship(Course, backref="course",cascade='all,
delete')
group = db.relationship(Group, backref="group", cascade='all,
delete`)
there are another examples where they are including a relationship field in both tables like that:
class Group(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
courses = db.relationship("Course", secondary=course_groups,
back_populates="courses")
class Course(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String)
groups = db.relationship("Group", secondary=course_groups,
back_populates="groups")
So i'm confused, which one is the most correct ?
I'm running a query and filtering results on 3 tables.
I wrote the function below to perform this query, it looked like this:
def bookshelf():
your_user = db.session.query(User).filter_by(email=session['email']).first().uid
your_books = db.session.query(user_book).filter_by(uid=your_user).all()
name_books = db.session.query(Book).filter_by(bid=your_books.bid).all()
return name_books
The variable your_user gets from the table user the id of the user who is logged in;
The variable your_books gets from the table user_books all the books added by the logged in user;
The variable name_books should get from the table books all the data of the books filtered by the id of the books (bid).
The problem occurs when I try to filter using your_books.bid, the console returns:
AttributeError: 'list' object has no attribute 'bid'
These are the tables cited above:
user_book = db.Table('user_book',
db.Column('uid', db.Integer, db.ForeignKey('user.uid'), primary_key=True),
db.Column('bid', db.Text, db.ForeignKey('book.bid'), primary_key=True),
db.Column('date_added', db.DateTime(timezone=True), server_default=db.func.now())
)
class User(db.Model):
__tablename__ = 'user'
uid = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(25), nullable=False)
hash = db.Column(db.String(), nullable=False)
first_name = db.Column(db.String(30), nullable=True)
last_name = db.Column(db.String(80), nullable=True)
books = db.relationship('Book', secondary=user_book)
class Book(db.Model):
__tablename__ = 'book'
bid = db.Column(db.Text, primary_key=True)
title = db.Column(db.Text, nullable=False)
authors = db.Column(db.Text, nullable=False)
thumbnail = db.Column(db.Text, nullable=True)
users = db.relationship('User', secondary=user_book)
I also tried to do something like your_books = db.session.query(user_book.bid) but I got the same error message.
I also found this answer: Sqlalchemy single query for multiple rows from one column in one table, but I couldn't apply it.
What am I missing?
As I understand it, and following some of the logic, you want to show the books, right? So instead of query(User), use query(Book). Then you can do the .join()as instructed in the comments.
def bookshelf():
your_user = db.session.query(User).filter_by(email=session['email']).first().uid
your_books = db.session.query(Book).join(user_book).filter_by(uid=your_user).all()
return your_books
If you have any questions, let me know and I'll clarify.
I am trying to use sqlalchemy to run queries for one to many relationship. I am having trouble getting my queries to run.
class Quote(db.Model):
id = db.Column(db.Integer, primary_key=True)
description = db.Column(db.String(1000))
category = db.Column(db.String(100))
user_id = db.Column(db.Integer, db.ForeignKey('user.id'))
date_added = db.Column(db.DateTime, nullable=False, default=datetime.utcnow)
class Category(db.Model):
id = db.Column(db.Integer, primary_key=True)
quote_cat = db.relationship("Quote", backref='category', lazy=True)
quote_id_ = db.Column(db.Integer, db.ForeignKey('quote.id'))
sqlalchemy.exc.ArgumentError: Mapper mapped class Category->category
could not assemble any primary key columns for mapped table 'category'
Your quote_cat backref references a property that already exists on the Quote class. Either remove this or change the backref value.
Here are the backref docs:
backref –
indicates the string name of a property to be placed on the related mapper’s class that will handle this relationship in the other direction
I am making a wishlist app and I want to have db schema like bellow, but I can't figure out how to make the joins in sqlalchemy (this is the first time I am using sqlalchemy).
DB schema
(user : wish = 1 : N)
When I select a user, I want to get a list of wishes and each wish may contain a different user (an arranger of the wish)
So I could do something like this
first_user = User.query.get(1)
user_wishes = first_user.wishes.all()
for wish in user_wishes:
if wish.arranger is not None:
print(wish.id, wish.owner.id, wish.arranger.id)
else:
print(wish.id, wish.owner.id)
I have looked up some tutorials, but I only found simple relations.
I need a relation from User to Wish and in the Wish, back to both the UserWishOwner (the user from which I got here) a UserWishArranger (if there is any).
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
wishes = db.Column(db.relationship('Wish', backref='owner', lazy='dynamic'))
class Wish(db.Model):
id = db.Column(db.Integer, primary_key=True)
owner_id = db.Column(db.Integer, db.ForeignKey('user.id'), index=True)
arranger_id = db.Column(db.Integer, db.ForeignKey('user.id'), index=True)
arranger = relationship("User", foreign_keys=[arranger_id])
I have come up with some code, but am a bit confused, because owner_id and arranger_id are the same...
What do I need to do, to make this work?
Just like this
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
wishes = db.relationship('Wish', backref='owner', lazy='dynamic', foreign_keys="[Wish.owner_id]")
class Wish(db.Model):
id = db.Column(db.Integer, primary_key=True)
owner_id = db.Column(db.Integer, db.ForeignKey('user.id'), index=True)
arranger_id = db.Column(db.Integer, db.ForeignKey('user.id'), index=True)
arranger = db.relationship("User", foreign_keys=[arranger_id])
I'm trying to create one-to-one and one-to-many relationship at the same time in Flask-SQLAlchemy. I want to achieve this:
"A group has many members and one administrator."
Here is what I did:
class Group(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(140), index=True, unique=True)
description = db.Column(db.Text)
created_at = db.Column(db.DateTime, server_default=db.func.now())
members = db.relationship('User', backref='group')
admin = db.relationship('User', backref='admin_group', uselist=False)
def __repr__(self):
return '<Group %r>' % (self.name)
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
group_id = db.Column(db.Integer, db.ForeignKey('group.id'))
admin_group_id = db.Column(db.Integer, db.ForeignKey('group.id'))
created_at = db.Column(db.DateTime, server_default=db.func.now())
However I got an error:
sqlalchemy.exc.AmbiguousForeignKeysError: Could not determine join
condition between parent/child tables on relationship Group.members -
there are multiple foreign key paths linking the tables. Specify the
'foreign_keys' argument, providing a list of those columns which
should be counted as containing a foreign key reference to the parent
table.
Does anyone know how to do that properly?
The solution is to specify the foreign_keys argument on all relationships:
class User(Base):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
group_id = Column(Integer, ForeignKey('groups.id'))
admin_group_id = Column(Integer, ForeignKey('groups.id'))
class Group(Base):
__tablename__ = 'groups'
id = Column(Integer, primary_key=True)
members = relationship('User', backref='group', foreign_keys=[User.group_id])
admin = relationship('User', backref='admin_group', uselist=False, foreign_keys=[User.admin_group_id])
Perhaps consider the admin relation in the other direction to implement "a group has many members and one admin":
class User(Base):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
group_id = Column(Integer, ForeignKey('groups.id'))
group = relationship('Group', foreign_keys=[group_id], back_populates='members')
class Group(Base):
__tablename__ = 'groups'
id = Column(Integer, primary_key=True)
members = relationship('User', foreign_keys=[User.group_id], back_populates='group')
admin_user_id = Column(Integer, ForeignKey('users.id'))
admin = relationship('User', foreign_keys=[admin_user_id], post_update=True)
See note on post_update in the documentation. It is necessary when two models are mutually dependent, referencing each other.
The problem you're getting comes from the fact that you've defined two links between your classes - a User has a group_id (which is a Foreign Key), and a Group has an admin (which is also defined by a Foreign Key). If you remove the Foreign Key from the admin field the connection is no longer ambiguous and the relationship works. This is my solution to your problem (making the link one-to-one):
from app import db,app
class Group(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(140), index=True, unique=True)
description = db.Column(db.Text)
created_at = db.Column(db.DateTime, server_default=db.func.now())
admin_id = db.Column(db.Integer) #, db.ForeignKey('user.id'))
members = db.relationship('User', backref='group')
def admin(self):
return User.query.filter_by(id=self.admin_id).first()
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(80), unique=True)
group_id = db.Column(db.Integer, db.ForeignKey('group.id'))
created_at = db.Column(db.DateTime, server_default=db.func.now())
The one drawback to this is that the group object doesn't have a neat admin member object you can just use - you have to call the function group.admin() to retrieve the administrator. However, the group can have many members, but only one of them can be the administrator. Obviously there is no DB-level checking to ensure that the administrator is actually a member of the group, but you could add that check into a setter function - perhaps something like:
# setter method
def admin(self, user):
if user.group_id == self.id:
self.admin_id = user.id
# getter method
def admin(self):
return User.query.filter_by(id=self.admin_id).first()
Ok, I found a workaround for this problem finally. The many-to-many relationship can coexist with one-to-many relationship between the same two tables at the same time.
Here is the code:
groups_admins = db.Table('groups_admins',
db.Column('user_id', db.Integer, db.ForeignKey('user.id')),
db.Column('group_id', db.Integer, db.ForeignKey('group.id'))
)
class Group(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(140), index=True, unique=True)
description = db.Column(db.Text)
created_at = db.Column(db.DateTime, server_default=db.func.now())
members = db.relationship('User', backref='group')
admins = db.relationship('User',
secondary=groups_admins,
backref=db.backref('mod_groups', lazy='dynamic'),
lazy='dynamic')
def __repr__(self):
return '<Group %r>' % (self.name)
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
group_id = db.Column(db.Integer, db.ForeignKey('group.id'))
created_at = db.Column(db.DateTime, server_default=db.func.now())
I still want someone to tell me how to set one-to-many and one-to-one relationship at the same time, so I leave my answer here and won't accept it forever.
This link solved it for me
most important thing is to specify foreign_keys value in the relation as well as the primary join