Python argparse helper section [duplicate] - python

This question already has answers here:
How to modify the metavar for a positional argument in pythons argparse?
(2 answers)
Closed 7 years ago.
Just started using argparse for parsing commands.
I have a command arg that is -l. This argument takes 2 args from user.
-l ONE_ARG TWO_ARG
In the help file using argparse, I get the following:
-l L L Some message for this argument
How can I replace the 'L' to give a small temple of what the user needs to put into those arguments like so.
-l "First_Name" "Last_Name" Some message for this argument
Basically something more descriptive than 'L L' which means nothing to the user really.

The best options is to use metavars, https://docs.python.org/2/library/argparse.html#metavar which gives
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-l', nargs=2,
help = "Some message for this argument",
metavar=('"First Name"', '"Second Name"'))
args = vars(parser.parse_args())
A more flexible but less elegant answer may be to manually specify the exact help you want:
import argparse
def print_names():
outstr = "usage: scriptname -l 'First Name' 'Second Name' "
outstr += "Some message for this argument "
print(outstr)
parser = argparse.ArgumentParser()
parser.add_argument('-l', help=print_names(), nargs=2)
args = vars(parser.parse_args())

Related

python argparse default with nargs wont work [duplicate]

This question already has answers here:
Argparse optional argument with different default if specified without a value
(2 answers)
Closed last month.
Here is my code:
from argparse import ArgumentParser, RawTextHelpFormatter
example_text = "test"
parser = ArgumentParser(description='my script.',
epilog=example_text,
formatter_class=RawTextHelpFormatter)
parser.add_argument('host', type=str, default="10.10.10.10",
help="Device IP address or Hostname.")
parser.add_argument('-j','--json_output', type=str, default="s", nargs='?',choices=["s", "l"],
help="Print GET statement in json form.")
#mutally exclusive required settings supplying the key
settingsgroup = parser.add_mutually_exclusive_group(required=True)
settingsgroup.add_argument('-k', '--key', type=str,
help="the api-key to use. WARNING take care when using this, the key specified will be in the user's history.")
settingsgroup.add_argument('--config', type=str,
help="yaml config file. All parameters can be placed in the yaml file. Parameters provided from form command line will take priority.")
args = parser.parse_args()
print(args.json_output)
my output:
None
Everything I am reading online says this should work, but it doesn't. Why?
You could use the const= parameter. const stores its value when the option is present but have no values
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-j', '--json-output', nargs='?', choices=['s', 'l'], const='s')
args = parser.parse_args()
However design wise, it might be better to use the following:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-o', '--output-type', choices=['json-s', 'json-l', 'normal'], default='normal')
args = parser.parse_args()

How to execute with optional argument in Spyder? [duplicate]

This question already has answers here:
How to use argv with Spyder
(4 answers)
Closed 4 years ago.
I don't know how to execute a program with optional arguments on Spyder. I know how to pass variables to it, but my program uses argparse, and I want to execute it with the "-h" or "--help" option, the code is the following one
import argparse
parser = argparse.ArgumentParser()
parser.parse_args()
For now, it only has the default optional argument of "-h"/"--help", I tried putting it on "Command line options" but it doesn't work.
You would have to define the arguments in order for them to be used. It looks like it is just using the default argparse method which only defines the help method in the constructor.
Check the docs here: https://docs.python.org/3/library/argparse.html
Here is an example method for parsing the args I have used before:
import argparse
def process_args(source=None):
parser = argparse.ArgumentParser(prog='my-awesome-program')
parser.add_argument('--value1', dest='value1', type=str)
parser.add_argument('--value2', dest='value2', type=str)
args = parser.parse_args(source)
return args
def main():
args = process_args()
args = vars(args)
my_value_1 = args['value1']
my_value_2 = args['value2']
print('%s, %s' % (my_value_1, my_value_2))
if __name__ == '__main__':
main()

Python getopt/optparse optional command line parameter handling [duplicate]

This question already has answers here:
How to read/process command line arguments?
(22 answers)
Closed 6 years ago.
I finished writing a script in python, and now stuck in the interface, which requires getting few options from user but not sure what is the best way to get optional arguments..
The code for that is as below...
def getOptions(argv):
try:
opts,args = getopt.getopt(argv, "hi:c:d:m", ["ifile=", "add=", "delete"])
except getopt.GetoptError:
printUsage()
sys.exit(2)
for opt, arg in opts:
if opt in ("-h", "--help"):
print ("test -m <make> [src] [dst]\n")
print ("test -i <install>[filename] \n")
.....
sys.exit()
if opt in ( "-m", "--make"):
make(arg)
sys.exit()
if opt in ("-i","--install"):
install(arg)
sys.exit()
... # few more options
else:
assert False, "unhandled option"
My question is that how can i leave out the argument (like use a default optional path for arg) and if that is not provided, get from user ??
Currently i've to provide
./test -i
how can i leave out file name and call like
./test -i
I'm stuck with same issue one more time, My development environment is python 2.6 and because of the limitations, now using optparse but with same issue, i've to support an optional argument and couldn't find way how to do that other than parsing sys.argv manually, i've almost 10 different options and if i can handle one optional argument, my script would be much more convenient for end users.
From:
https://docs.python.org/2/library/getopt.html
Getopts does not support optional arguments.
Can you trying writing your code using argparse? Following is an example:
import argparse
parser = argparse.ArgumentParser(description='python cli')
parser.add_argument("-m", "--make", help="execute make", required=True)
parser.add_argument("-i", "--install", help="execute install", required=True)
# parse input arguments
args = parser.parse_args()
makeVal = args.make
shouldInstall = args.install
if makeVal :
make(makeVal)
...
Reference:
https://docs.python.org/2.7/library/argparse.html

argparse coding issue

write a script that takes two optional boolean arguments,"--verbose‚" and ‚"--live", and two required string arguments, "base"and "pattern". Please set up the command line processing using argparse.
This is the code I have so far for the question, I know I am getting close but something is not quite right. Any help is much appreciated.Thanks for all the quick useful feedback.
def main():
import argparse
parser = argparse.ArgumentParser(description='')
parser.add_argument('base', type=str)
parser.add_arguemnt('--verbose', action='store_true')
parser.add_argument('pattern', type=str)
parser.add_arguemnt('--live', action='store_true')
args = parser.parse_args()
print(args.base(args.pattern))
The string arguments are not required by default, so you need to state that. Also the print statement that uses the arguments is incorrect.
#!/usr/bin/python
import argparse
if __name__=="__main__":
parser = argparse.ArgumentParser(description='eg $python myargs.py --base arg1 --pattern arg2 [--verbose] [--live]')
parser.add_argument('--base', required=True, type=str)
parser.add_argument('--pattern', required=True, type=str)
parser.add_argument('--verbose', action='store_true')
parser.add_argument('--live', action='store_true')
args = parser.parse_args()
print "args.base=" + str(args.base)
print "args.pattern=" + str(args.pattern)
print "args.verbose=" + str(args.verbose)
print "args.live=" + str(args.live)
the #!/usr/bin/python at the top enables the script to be called directly, though python must be located there (to confirm, type $which python), and you must set the file to have execute permission ($chmod +x myargs.py)

Simple argparse example wanted: 1 argument, 3 results

The documentation for the argparse python module, while excellent I'm sure, is too much for my tiny beginner brain to grasp right now. I don't need to do math on the command line or meddle with formatting lines on the screen or change option characters. All I want to do is "If arg is A, do this, if B do that, if none of the above show help and quit".
Here's the way I do it with argparse (with multiple args):
parser = argparse.ArgumentParser(description='Description of your program')
parser.add_argument('-f','--foo', help='Description for foo argument', required=True)
parser.add_argument('-b','--bar', help='Description for bar argument', required=True)
args = vars(parser.parse_args())
args will be a dictionary containing the arguments:
if args['foo'] == 'Hello':
# code here
if args['bar'] == 'World':
# code here
In your case simply add only one argument.
My understanding of the original question is two-fold. First, in terms of the simplest possible argparse example, I'm surprised that I haven't seen it here. Of course, to be dead-simple, it's also all overhead with little power, but it might get you started.
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("a")
args = parser.parse_args()
if args.a == 'magic.name':
print 'You nailed it!'
But this positional argument is now required. If you leave it out when invoking this program, you'll get an error about missing arguments. This leads me to the second part of the original question. Matt Wilkie seems to want a single optional argument without a named label (the --option labels). My suggestion would be to modify the code above as follows:
...
parser.add_argument("a", nargs='?', default="check_string_for_empty")
...
if args.a == 'check_string_for_empty':
print 'I can tell that no argument was given and I can deal with that here.'
elif args.a == 'magic.name':
print 'You nailed it!'
else:
print args.a
There may well be a more elegant solution, but this works and is minimalist.
The argparse documentation is reasonably good but leaves out a few useful details which might not be obvious. (#Diego Navarro already mentioned some of this but I'll try to expand on his answer slightly.) Basic usage is as follows:
parser = argparse.ArgumentParser()
parser.add_argument('-f', '--my-foo', default='foobar')
parser.add_argument('-b', '--bar-value', default=3.14)
args = parser.parse_args()
The object you get back from parse_args() is a 'Namespace' object: An object whose member variables are named after your command-line arguments. The Namespace object is how you access your arguments and the values associated with them:
args = parser.parse_args()
print (args.my_foo)
print (args.bar_value)
(Note that argparse replaces '-' in your argument names with underscores when naming the variables.)
In many situations you may wish to use arguments simply as flags which take no value. You can add those in argparse like this:
parser.add_argument('--foo', action='store_true')
parser.add_argument('--no-foo', action='store_false')
The above will create variables named 'foo' with value True, and 'no_foo' with value False, respectively:
if (args.foo):
print ("foo is true")
if (args.no_foo is False):
print ("nofoo is false")
Note also that you can use the "required" option when adding an argument:
parser.add_argument('-o', '--output', required=True)
That way if you omit this argument at the command line argparse will tell you it's missing and stop execution of your script.
Finally, note that it's possible to create a dict structure of your arguments using the vars function, if that makes life easier for you.
args = parser.parse_args()
argsdict = vars(args)
print (argsdict['my_foo'])
print (argsdict['bar_value'])
As you can see, vars returns a dict with your argument names as keys and their values as, er, values.
There are lots of other options and things you can do, but this should cover the most essential, common usage scenarios.
Matt is asking about positional parameters in argparse, and I agree that the Python documentation is lacking on this aspect. There's not a single, complete example in the ~20 odd pages that shows both parsing and using positional parameters.
None of the other answers here show a complete example of positional parameters, either, so here's a complete example:
# tested with python 2.7.1
import argparse
parser = argparse.ArgumentParser(description="An argparse example")
parser.add_argument('action', help='The action to take (e.g. install, remove, etc.)')
parser.add_argument('foo-bar', help='Hyphens are cumbersome in positional arguments')
args = parser.parse_args()
if args.action == "install":
print("You asked for installation")
else:
print("You asked for something other than installation")
# The following do not work:
# print(args.foo-bar)
# print(args.foo_bar)
# But this works:
print(getattr(args, 'foo-bar'))
The thing that threw me off is that argparse will convert the named argument "--foo-bar" into "foo_bar", but a positional parameter named "foo-bar" stays as "foo-bar", making it less obvious how to use it in your program.
Notice the two lines near the end of my example -- neither of those will work to get the value of the foo-bar positional param. The first one is obviously wrong (it's an arithmetic expression args.foo minus bar), but the second one doesn't work either:
AttributeError: 'Namespace' object has no attribute 'foo_bar'
If you want to use the foo-bar attribute, you must use getattr, as seen in the last line of my example. What's crazy is that if you tried to use dest=foo_bar to change the property name to something that's easier to access, you'd get a really bizarre error message:
ValueError: dest supplied twice for positional argument
Here's how the example above runs:
$ python test.py
usage: test.py [-h] action foo-bar
test.py: error: too few arguments
$ python test.py -h
usage: test.py [-h] action foo-bar
An argparse example
positional arguments:
action The action to take (e.g. install, remove, etc.)
foo-bar Hyphens are cumbersome in positional arguments
optional arguments:
-h, --help show this help message and exit
$ python test.py install foo
You asked for installation
foo
Yet another summary introduction, inspired by this post.
import argparse
# define functions, classes, etc.
# executes when your script is called from the command-line
if __name__ == "__main__":
parser = argparse.ArgumentParser()
#
# define each option with: parser.add_argument
#
args = parser.parse_args() # automatically looks at sys.argv
#
# access results with: args.argumentName
#
Arguments are defined with combinations of the following:
parser.add_argument( 'name', options... ) # positional argument
parser.add_argument( '-x', options... ) # single-char flag
parser.add_argument( '-x', '--long-name', options... ) # flag with long name
Common options are:
help: description for this arg when --help is used.
default: default value if the arg is omitted.
type: if you expect a float or int (otherwise is str).
dest: give a different name to a flag (e.g. '-x', '--long-name', dest='longName'). Note: by default --long-name is accessed with args.long_name
action: for special handling of certain arguments
store_true, store_false: for boolean args '--foo', action='store_true' => args.foo == True
store_const: to be used with option const '--foo', action='store_const', const=42 => args.foo == 42
count: for repeated options, as in ./myscript.py -vv '-v', action='count' => args.v == 2
append: for repeated options, as in ./myscript.py --foo 1 --foo 2 '--foo', action='append' => args.foo == ['1', '2']
required: if a flag is required, or a positional argument is not.
nargs: for a flag to capture N args ./myscript.py --foo a b => args.foo = ['a', 'b']
choices: to restrict possible inputs (specify as list of strings, or ints if type=int).
Note the Argparse Tutorial in Python HOWTOs. It starts from most basic examples, like this one:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("square", type=int,
help="display a square of a given number")
args = parser.parse_args()
print(args.square**2)
and progresses to less basic ones.
There is an example with predefined choice for an option, like what is asked:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("square", type=int,
help="display a square of a given number")
parser.add_argument("-v", "--verbosity", type=int, choices=[0, 1, 2],
help="increase output verbosity")
args = parser.parse_args()
answer = args.square**2
if args.verbosity == 2:
print("the square of {} equals {}".format(args.square, answer))
elif args.verbosity == 1:
print("{}^2 == {}".format(args.square, answer))
else:
print(answer)
Here's what I came up with in my learning project thanks mainly to #DMH...
Demo code:
import argparse
def main():
parser = argparse.ArgumentParser()
parser.add_argument('-f', '--flag', action='store_true', default=False) # can 'store_false' for no-xxx flags
parser.add_argument('-r', '--reqd', required=True)
parser.add_argument('-o', '--opt', default='fallback')
parser.add_argument('arg', nargs='*') # use '+' for 1 or more args (instead of 0 or more)
parsed = parser.parse_args()
# NOTE: args with '-' have it replaced with '_'
print('Result:', vars(parsed))
print('parsed.reqd:', parsed.reqd)
if __name__ == "__main__":
main()
This may have evolved and is available online: command-line.py
Script to give this code a workout: command-line-demo.sh
code file: argparseDemo.py
Simple: common case
name(abbr, full), with help
import argparse
argParser = argparse.ArgumentParser()
argParser.add_argument("-n", "--name", help="your name")
args = argParser.parse_args()
print("args=%s" % args)
print("args.name=%s" % args.name)
call
python argparseDemo.py -n Crifan
python argparseDemo.py --name Crifan
output: args=Namespace(name='Crifan') and args.name=Crifan
type
argParser.add_argument("-a", "--age", type=int, help="your current age")
print("type(args.age)=%s" % type(args.age))
call: python argparseDemo.py --age 30
output: type(args.age)=<class 'int'> and args.age=30
required
argParser.add_argument("-a", "--age", required=True, type=int, help="your current age")
call: python argparseDemo.py
output: error argparseDemo.py: error: the following arguments are required: -a/--age
default
argParser.add_argument("-a", "--age", type=int, default=20, help="your current age. Default is 20")
call: python argparseDemo.py
output: args.age=20
choices
argParser.add_argument("-f", "--love-fruit", choices=['apple', 'orange', 'banana'], help="your love fruits")
call: python argparseDemo.py -f apple
output: args=Namespace(love_fruit='apple') and args.love_fruit=apple
multi args
argParser.add_argument("-f", "--love-fruit", nargs=2, help="your love fruits")
call: python argparseDemo.py -f apple orange
output: args.love_fruit=['apple', 'orange']
Detail
most simple: -x
code:
import argparse
argParser = argparse.ArgumentParser()
argParser.add_argument("-a") # most simple -> got args.a, type is `str`
args = argParser.parse_args()
print("args.a=%s" % args.a)
usage = run in command line
python argparseDemo.py -a 30
or: ./argparseDemo.py -a 30
makesure argparseDemo.py is executable
if not, add it: chmod +x argparseDemo.py
output
args.a=30
Note
default type is str
argParser.add_argument("-a") == argParser.add_argument("-a", type=str)
print("type(args.a)=%s" % type(args.a)) -> type(args.a)=<class 'str'>
args type is Namespace
print("type(args)=%s" % type(args)) -> type(args)=<class 'argparse.Namespace'>
args value is Namespace(a='30')
print("args=%s" % args) -> args=Namespace(a='30')
so we can call/use args.a
parameter name
full parameter name: --xxx
code
argParser.add_argument("-a", "--age")
usage
python argparseDemo.py -a 30
or: python argparseDemo.py --age 30
get parsed value: args.age
Note: NOT args.a, and NOT exist args.a
full parameter name with multiple words: --xxx-yyy
code
argParser.add_argument("-a", "--current-age")
get parsed value: args.current_age
add help description: help
code
argParser.add_argument("-a", help="your age") # with help
output
use --help can see description
 python argparseDemo.py --help
usage: argparseDemo.py [-h] [-a A]
optional arguments:
-h, --help show this help message and exit
-a A your age
designate parameter type: type
code
argParser.add_argument("-a", type=int) # parsed arg is `int`, not default `str`
output
print("type(args.a)=%s" % type(args.a)) -> type(args.a)=<class 'int'>
print("args=%s" % args) -> args=Namespace(a=30)
add default value: default
code
argParser.add_argument("-a", type=int, default=20) # if not pass a, a use default value: 20
effect
usage: python argparseDemo.py
output: print("args.age=%s" % args.age) -> args=Namespace(a=20)
You could also use plac (a wrapper around argparse).
As a bonus it generates neat help instructions - see below.
Example script:
#!/usr/bin/env python3
def main(
arg: ('Argument with two possible values', 'positional', None, None, ['A', 'B'])
):
"""General help for application"""
if arg == 'A':
print("Argument has value A")
elif arg == 'B':
print("Argument has value B")
if __name__ == '__main__':
import plac
plac.call(main)
Example output:
No arguments supplied - example.py:
usage: example.py [-h] {A,B}
example.py: error: the following arguments are required: arg
Unexpected argument supplied - example.py C:
usage: example.py [-h] {A,B}
example.py: error: argument arg: invalid choice: 'C' (choose from 'A', 'B')
Correct argument supplied - example.py A :
Argument has value A
Full help menu (generated automatically) - example.py -h:
usage: example.py [-h] {A,B}
General help for application
positional arguments:
{A,B} Argument with two possible values
optional arguments:
-h, --help show this help message and exit
Short explanation:
The name of the argument usually equals the parameter name (arg).
The tuple annotation after arg parameter has the following meaning:
Description (Argument with two possible values)
Type of argument - one of 'flag', 'option' or 'positional' (positional)
Abbreviation (None)
Type of argument value - eg. float, string (None)
Restricted set of choices (['A', 'B'])
Documentation:
To learn more about using plac check out its great documentation:
Plac: Parsing the Command Line the Easy Way
To add to what others have stated:
I usually like to use the 'dest' parameter to specify a variable name and then use 'globals().update()' to put those variables in the global namespace.
Usage:
$ python script.py -i "Hello, World!"
Code:
...
parser.add_argument('-i', '--input', ..., dest='inputted_variable',...)
globals().update(vars(parser.parse_args()))
...
print(inputted_variable) # Prints "Hello, World!"
New to this, but combining Python with Powershell and using this template, being inspired by an in-depth and great Python Command Line Arguments – Real Python
There is a lot you can do within the init_argparse() and I am covering just the most simple scenario here.
import argparse
use if __name__ == "__main__": main() pattern to execute from terminal
parse arguments within the main() function that has no parameters as all
define a init_argparse() function
create a parser object by calling argparse.ArgumentParser()
declare one or more argumnent with parser.add_argument("--<long_param_name>")
return parser
parse args by creating an args object by calling parser.parse_args()
define a function proper with param1, param2, ...
call function_proper with params being assigned as attributes of an args object
e.g. function_proper(param1=args.param1, param2=args.param2)
within a shell call the module with named arguments:
e.g. python foobar.py --param1="foo" --param2=="bar"
#file: foobar.py
import argparse
def function_proper(param1, param2):
#CODE...
def init_argparse() -> argparse.ArgumentParser:
parser = argparse.ArgumentParser()
parser.add_argument("--param1")
parser.add_argument("--param2")
return parser
def main() -> None:
parser = init_argparse()
args = parser.parse_args()
function_proper(param1=args.param1, param2=args.param2)
if __name__ == "__main__":
main()
>>> python .\foobar.py --param1="foo" --param2=="bar"
I went through all the examples and answers and in a way or another they didn't address my need. So I will list her a scenario that I need more help and I hope this can explain the idea more.
Initial Problem
I need to develop a tool which is getting a file to process it and it needs some optional configuration file to be used to configure the tool.
so what I need is something like the following
mytool.py file.text -config config-file.json
The solution
Here is the solution code
import argparse
def main():
parser = argparse.ArgumentParser(description='This example for a tool to process a file and configure the tool using a config file.')
parser.add_argument('filename', help="Input file either text, image or video")
# parser.add_argument('config_file', help="a JSON file to load the initial configuration ")
# parser.add_argument('-c', '--config_file', help="a JSON file to load the initial configuration ", default='configFile.json', required=False)
parser.add_argument('-c', '--config', default='configFile.json', dest='config_file', help="a JSON file to load the initial configuration " )
parser.add_argument('-d', '--debug', action="store_true", help="Enable the debug mode for logging debug statements." )
args = parser.parse_args()
filename = args.filename
configfile = args.config_file
print("The file to be processed is", filename)
print("The config file is", configfile)
if args.debug:
print("Debug mode enabled")
else:
print("Debug mode disabled")
print("and all arguments are: ", args)
if __name__ == '__main__':
main()
I will show the solution in multiple enhancements to show the idea
First Round: List the arguments
List all input as mandatory inputs so second argument will be
parser.add_argument('config_file', help="a JSON file to load the initial configuration ")
When we get the help command for this tool we find the following outcome
(base) > python .\argparser_example.py -h
usage: argparser_example.py [-h] filename config_file
This example for a tool to process a file and configure the tool using a config file.
positional arguments:
filename Input file either text, image or video
config_file a JSON file to load the initial configuration
optional arguments:
-h, --help show this help message and exit
and when I execute it as the following
(base) > python .\argparser_example.py filename.txt configfile.json
the outcome will be
The file to be processed is filename.txt
The config file is configfile.json
and all arguments are: Namespace(config_file='configfile.json', filename='filename.txt')
But the config file should be optional, I removed it from the arguments
(base) > python .\argparser_example.py filename.txt
The outcome will be is:
usage: argparser_example.py [-h] filename config_file
argparser_example.py: error: the following arguments are required: c
Which means we have a problem in the tool
Second Round : Make it optimal
So to make it optional I modified the program as follows
parser.add_argument('-c', '--config', help="a JSON file to load the initial configuration ", default='configFile.json', required=False)
The help outcome should be
usage: argparser_example.py [-h] [-c CONFIG] filename
This example for a tool to process a file and configure the tool using a config file.
positional arguments:
filename Input file either text, image or video
optional arguments:
-h, --help show this help message and exit
-c CONFIG, --config CONFIG
a JSON file to load the initial configuration
so when I execute the program
(base) > python .\argparser_example.py filename.txt
the outcome will be
The file to be processed is filename.txt
The config file is configFile.json
and all arguments are: Namespace(config_file='configFile.json', filename='filename.txt')
with arguments like
(base) > python .\argparser_example.py filename.txt --config_file anotherConfig.json
The outcome will be
The file to be processed is filename.txt
The config file is anotherConfig.json
and all arguments are: Namespace(config_file='anotherConfig.json', filename='filename.txt')
Round 3: Enhancements
to change the flag name from --config_file to --config while we keep the variable name as is we modify the code to include dest='config_file' as the following:
parser.add_argument('-c', '--config', help="a JSON file to load the initial configuration ", default='configFile.json', dest='config_file')
and the command will be
(base) > python .\argparser_example.py filename.txt --config anotherConfig.json
To add the support for having a debug mode flag, we need to add a flag in the arguments to support a boolean debug flag. To implement it i added the following:
parser.add_argument('-d', '--debug', action="store_true", help="Enable the debug mode for logging debug statements." )
the tool command will be:
(carnd-term1-38) > python .\argparser_example.py image.jpg -c imageConfig,json --debug
the outcome will be
The file to be processed is image.jpg
The config file is imageConfig,json
Debug mode enabled
and all arguments are: Namespace(config_file='imageConfig,json', debug=True, filename='image.jpg')
A really simple way to use argparse and amend the '-h'/ '--help' switches to display your own personal code help instructions is to set the default help to False, you can also add as many additional .add_arguments as you like:
import argparse
parser = argparse.ArgumentParser(add_help=False)
parser.add_argument('-h', '--help', action='help',
help='To run this script please provide two arguments')
parser.parse_args()
Run: python test.py -h
Output:
usage: test.py [-h]
optional arguments:
-h, --help To run this script please provide two arguments
As an addition to existing answers, if you are lazy enough, it is possible to use code generation tool called protoargs. It generates arguments parser from the configuration. For python it uses argparse.
Configuration with optional A and B:
syntax = "proto2";
message protoargs
{
optional string A = 1; // A param description
optional string B = 2; // B param description
}//protoargs
Configuration with required A and B:
syntax = "proto2";
message protoargs
{
required string A = 1; // A param description
required string B = 2; // B param description
}//protoargs
Configuration with positional A and B:
syntax = "proto2";
message protoargs
{
required string A = 1; // A param description
required string B = 2; // B param description
}//protoargs
message protoargs_links
{
}//protoargs_links
Now all you should run is:
python ./protoargs.py -i test.proto -o . --py
And use it (it is possible to take other examples here):
import sys
import test_pa
class ArgsParser:
program = "test"
description = "Simple A and B parser test."
def parse(self, argv):
self.config = test_pa.parse(self.program, self.description, argv)
def usage(self):
return test_pa.usage(self.program, self.description)
if __name__ == "__main__":
parser = ArgsParser()
if len(sys.argv) == 1:
print(parser.usage())
else:
parser.parse(sys.argv[1:])
if parser.config.A:
print(parser.config.A)
if parser.config.B:
print(parser.config.B)
If you want more - change configuration, regenerate parser, use an updated parser.config.
UPD: As mentioned in rules, I must specify that this is my own project
code:
import argparse
parser=argparse.ArgumentParser()
parser.add_argument('-A', default=False, action='store_true')
parser.add_argument('-B', default=False, action='store_true')
args=parser.parse_args()
if args.A:
print('do this')
elif args.B:
print('do that')
else:
print('help')
running result:
$ python3 test.py
help
$ python3 test.py -A
do this
$ python3 test.py -B
do that
$ python3 test.py -C
usage: test.py [-h] [-A] [-B]
test.py: error: unrecognized arguments: -C
As for the original request (if A ....), I would use argv to solve it, not using argparse at all:
import sys
if len(sys.argv)==2:
if sys.argv[1] == 'A':
print('do this')
elif sys.argv[1] == 'B':
print('do that')
else:
print('help')
else:
print('help')
Since you have not clarified wheather the arguments 'A' and 'B' are positional or optional, I'll make a mix of both.
Positional arguments are required by default. If not giving one will throw 'Few arguments given' which is not the case for the optional arguments going by their name. This program will take a number and return its square by default, if the cube option is used it shall return its cube.
import argparse
parser = argparse.ArgumentParser('number-game')
parser.add_argument(
"number",
type=int,
help="enter a number"
)
parser.add_argument(
"-c", "--choice",
choices=['square','cube'],
help="choose what you need to do with the number"
)
# all the results will be parsed by the parser and stored in args
args = parser.parse_args()
# if square is selected return the square, same for cube
if args.c == 'square':
print("{} is the result".format(args.number**2))
elif args.c == 'cube':
print("{} is the result".format(args.number**3))
else:
print("{} is not changed".format(args.number))
usage
$python3 script.py 4 -c square
16
Here the optional arguments are taking value, if you just wanted to use it like a flag you can too. So by using -s for square and -c for cube we change the behaviour, by adding action = "store_true". It is changed to true only when used.
parser.add_argument(
"-s", "--square",
help="returns the square of number",
action="store_true"
)
parser.add_argument(
"-c", "--cube",
help="returns the cube of number",
action="store_true"
)
so the conditional block can be changed to,
if args.s:
print("{} is the result".format(args.number**2))
elif args.c:
print("{} is the result".format(args.number**3))
else:
print("{} is not changed".format(args.number))
usage
$python3 script.py 4 -c
64
The simplest answer!
P.S. the one who wrote the document of argparse is foolish
python code:
import argparse
parser = argparse.ArgumentParser(description='')
parser.add_argument('--o_dct_fname',type=str)
parser.add_argument('--tp',type=str)
parser.add_argument('--new_res_set',type=int)
args = parser.parse_args()
o_dct_fname = args.o_dct_fname
tp = args.tp
new_res_set = args.new_res_set
running code
python produce_result.py --o_dct_fname o_dct --tp father_child --new_res_set 1

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