write a script that takes two optional boolean arguments,"--verbose‚" and ‚"--live", and two required string arguments, "base"and "pattern". Please set up the command line processing using argparse.
This is the code I have so far for the question, I know I am getting close but something is not quite right. Any help is much appreciated.Thanks for all the quick useful feedback.
def main():
import argparse
parser = argparse.ArgumentParser(description='')
parser.add_argument('base', type=str)
parser.add_arguemnt('--verbose', action='store_true')
parser.add_argument('pattern', type=str)
parser.add_arguemnt('--live', action='store_true')
args = parser.parse_args()
print(args.base(args.pattern))
The string arguments are not required by default, so you need to state that. Also the print statement that uses the arguments is incorrect.
#!/usr/bin/python
import argparse
if __name__=="__main__":
parser = argparse.ArgumentParser(description='eg $python myargs.py --base arg1 --pattern arg2 [--verbose] [--live]')
parser.add_argument('--base', required=True, type=str)
parser.add_argument('--pattern', required=True, type=str)
parser.add_argument('--verbose', action='store_true')
parser.add_argument('--live', action='store_true')
args = parser.parse_args()
print "args.base=" + str(args.base)
print "args.pattern=" + str(args.pattern)
print "args.verbose=" + str(args.verbose)
print "args.live=" + str(args.live)
the #!/usr/bin/python at the top enables the script to be called directly, though python must be located there (to confirm, type $which python), and you must set the file to have execute permission ($chmod +x myargs.py)
Related
def main(argv):
parser = argparse.ArgumentParser()
parser.add_argument('p', 'projectType', type=str, help = 'c or c++ project type', choices=['c', 'c++'])
parser.add_argument('i', 'inputfile', type=pathlib.Path, help = 'the input file path')
parser.add_argument('o',"outputfile",type=pathlib.Path, help= 'the output file path')
parser.add_argument
args = parser.parse_args()
when i run this code on command prompt, and enter the inputfile first for example.. it gives me an error. does Argparse have an option like getopt (where i call something with a letter before inputting it so no mix up ex, '-i ...input...'). Here this option is just for optional arguments.
Is there a way for positional arguments to do that?
As per the argparse documentation you would define it as an "optional" argument but with the required flag set to true, e.g.:
parser.add_argument('-i', '--inputfile', required=True, type=pathlib.Path, help='the input file path')
I have a python script that requires the user to enter two arguments to run it, the arguments could be named anything.
I have also used argparse to allow the users to use a switch '-h' to get instructions of what is required to run the script.
The problem is that now I have used argparse I am getting an error when I pass my two randomly named arguments with the script.
import argparse
parser = argparse.ArgumentParser(add_help=False)
parser.add_argument('-h', '--help', action='help',
help='To run this script please provide two arguments')
parser.parse_args()
currently when I run python test.py arg1 arg2 the error is
error: unrecognized arguments: arg1 arg2
I would like the code to allow the user to run test.py with a -h if required to see the instructions but also allow them to run the script with any two arguments as well.
Resolution with help tag to provide the user with context regarding the arguments required.
parser = argparse.ArgumentParser(add_help=False)
parser.add_argument('-h', '--help', action='help', help='To run this script please provide two arguments: first argument should be your scorm package name, second argument should be your html file name. Note: Any current zipped folder in the run directory with the same scorm package name will be overwritten.')
parser.add_argument('package_name', action="store", help='Please provide your scorm package name as the first argument')
parser.add_argument('html_file_name', action="store", help='Please provide your html file name as the second argument')
parser.parse_args()
Try the following code :-
import argparse
parser = argparse.ArgumentParser(add_help=False)
parser.add_argument('-h', '--help', action='help',
help='To run this script please provide two arguments')
parser.add_argument('arg1')
parser.add_argument('arg2')
args, unknown = parser.parse_known_args()
All your unknown arguments will be parsed in unknown and all known in args.
import argparse
parser = argparse.ArgumentParser(description='sample')
# Add mandatory arguments
parser.add_argument('arg1', action="store")
parser.add_argument('arg2', action="store")
# Parse the arguments
args = parser.parse_args()
# sample usage of args
print (float(args.arg1) + float(args.arg2))
You need to add those arguments to the parser:
parser.add_argument("--arg1", "-a1", dest='arg1', type=str)
parser.add_argument("--arg2","-a2", dest='arg2', type=str)
If those arguments don't have the param required=true, you will be able to call the program without this arguments, so you can run the program with only the -h flag. To run the program with the arguments:
python test.py --arg1 "Argument" --arg2 "Argument"
Then, to have the arguments in variables you have to read them:
args = parser.parse_args()
argument1=args.arg1
argument2=args.arg2
I am in the bit of a weird situation where I need a Python function to run from within a script, with the script then called from my main code.
I wanted to use the subprocess module, and know how to use it to pass arguments to a pure script, but the thing is, I need to pass the arguments to the nested Python function within, most of which are optional and have default values.
I thought arparse would help me do this somehow.
Here is an example of what I am trying:
## Some Argparse, which will hopefully help
import argparse
parser = argparse.ArgumentParser()
## All arguments, with only "follow" being required
parser.add_argument('file_name', help='Name of resulting csv file')
parser.add_argument('sub_name', help='Sub-name of resulting csv file')
parser.add_argument('follow', help='Account(s) to follow', required=True)
parser.add_argument('locations', help='Locations')
parser.add_argument('languages', help='Languages')
parser.add_argument('time_limit', help='How long to keep stream open')
args = parser.parse_args()
## Actual Function
def twitter_stream_listener(file_name=None,
sub_name='stream_',
auth = api.auth,
filter_track=None,
follow=None,
locations=None,
languages=None,
time_limit=20):
... function code ...
... more function code ...
...
...
## End of script
If you are passing arguments to functions all you need to do is feed them into the function when you're executing them:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("-o", "--output_file_name", help="Name of resulting csv file")
parser.add_argument("-s", "--sub_name", default="stream_", help="Sub-name of resulting csv file")
parser.add_argument("-f", "--follow", help="Account(s) to follow", required=True)
parser.add_argument("-loc", "--locations", default=None, help="Locations")
parser.add_argument("-lan", "--languages", default=None, help="Languages")
parser.add_argument("-t", "--time_limit", default=20, help="How long to keep stream open")
options = parser.parse_args()
# then just pass in the arguments when you run the function
twitter_stream_listener(file_name=options.output_file_name,
sub_name=options.sub_name,
auth=api.auth,
filter_track=None,
follow=options.follow,
locations=options.locations,
languages=options.languages,
time_limit=options.time_limit)
# or, pass the arguments into the functions when defining your function
def twitter_stream_listener_with_args(file_name=options.output_file_name,
sub_name=options.sub_name,
auth=api.auth,
filter_track=None,
follow=options.follow,
locations=options.locations,
languages=options.languages,
time_limit=options.time_limit):
# does something
pass
# then run with default parameters
twitter_stream_listener_with_args()
You can specify defaults in the argparse section (if that is what you are trying to achieve):
#!/usr/bin/python
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('--argument', default = 'something', type = str, help = 'not helpful')
parser.add_argument('--arg2', default = None, type = str, help = 'not helpful')
args = parser.parse_args()
def foo(arg , arg2 ):
print(arg)
if not arg2 is None:
print(arg2)
foo(args.argument, args.arg2)
Then calling:
$ ./test.py
something
$ ./test.py --argument='somethingelse'
somethingelse
$ ./test.py --arg2=123
something
123
$ ./test.py --arg2='ipsum' --argument='lorem'
lorem
ipsum
Is this helpful?
You can do it like that:
import argparse
## Actual Function
def twitter_stream_listener(file_name=None,
sub_name='stream_',
auth=api.auth,
filter_track=None,
follow=None,
locations=None,
languages=None,
time_limit=20):
# Your content here
if __name__ == '__main__':
parser = argparse.ArgumentParser()
## All arguments, with only "follow" being required
parser.add_argument('follow', help='Account(s) to follow')
parser.add_argument('--file_name', help='Name of resulting csv file')
parser.add_argument('--sub_name', help='Sub-name of resulting csv file')
parser.add_argument('--locations', help='Locations')
parser.add_argument('--languages', help='Languages')
parser.add_argument('--time_limit', help='How long to keep stream open')
args = parser.parse_args()
twitter_stream_listener(file_name=args.file_name, sub_name=args.sub_name, follow=args.follow,
locations=args.locations, languages=args.languages, time_limit=args.time_limit)
follow will be the only required argument and the rest optional. Optional ones have to be provided with -- at the beginning. You can easily use the module with subprocess if you need it.
Example call using command line:
python -m your_module_name follow_val --file_name sth1 --locations sth2
This is probably a silly question, but I have a python script that current takes in a bunch of arguments using argparser and I would like to load this script as a module in another python script, which is fine. But I am not sure how to call the module as no function is defined; can I still call it the same way I do if I was just invoking it from cmd?
Here is the child script:
import argparse as ap
from subprocess import Popen, PIPE
parser = ap.ArgumentParser(
description='Gathers parameters.')
parser.add_argument('-f', metavar='--file', type=ap.FileType('r'), action='store', dest='file',
required=True, help='Path to json parameter file')
parser.add_argument('-t', metavar='--type', type=str, action='store', dest='type',
required=True, help='Type of parameter file.')
parser.add_argument('-g', metavar='--group', type=str, action='store', dest='group',
required=False, help='Group to apply parameters to')
# Gather the provided arguments as an array.
args = parser.parse_args()
... Do stuff in the script
and here is the parent script that I want to invoke the child script from; it also uses arg parser and does some other logic
from configuration import parameterscript as paramscript
# Can I do something like this?
paramscript('parameters/test.params.json', test)
Inside the configuration directory, I also created an init.py file that is empty.
The first argument to parse_args is a list of arguments. By default it's None which means use sys.argv. So you can arrange your script like this:
import argparse as ap
def main(raw_args=None):
parser = ap.ArgumentParser(
description='Gathers parameters.')
parser.add_argument('-f', metavar='--file', type=ap.FileType('r'), action='store', dest='file',
required=True, help='Path to json parameter file')
parser.add_argument('-t', metavar='--type', type=str, action='store', dest='type',
required=True, help='Type of parameter file.')
parser.add_argument('-g', metavar='--group', type=str, action='store', dest='group',
required=False, help='Group to apply parameters to')
# Gather the provided arguments as an array.
args = parser.parse_args(raw_args)
print(vars(args))
# Run with command line arguments precisely when called directly
# (rather than when imported)
if __name__ == '__main__':
main()
And then elsewhere:
from first_module import main
main(['-f', '/etc/hosts', '-t', 'json'])
Output:
{'group': None, 'file': <_io.TextIOWrapper name='/etc/hosts' mode='r' encoding='UTF-8'>, 'type': 'json'}
There may be a simpler and more pythonic way to do this, but here is one possibility using the subprocess module:
Example:
child_script.py
import argparse
parser = argparse.ArgumentParser()
parser.add_argument("-n", "--name", help="your name")
args = parser.parse_args()
print("hello there {}").format(args.name)
Then another Python script can call that script like so:
calling_script.py:
import subprocess
# using Popen may suit better here depending on how you want to deal
# with the output of the child_script.
subprocess.call(["python", "child_script.py", "-n", "Donny"])
Executing the above script would give the following output:
"hello there Donny"
One of the option is to call it as subprocess call like below:
import subprocess
childproc = subprocess.Popen('python childscript.py -file yourjsonfile')
op, oe = childproc.communicate()
print op
I am using Python argparse to take in parameters through the CLI. I have tried using the following but when I don't give any one of the arguments, it gives the output as None. I want then default ones to be the ones provided in const=. Please take a look.
parser = argparse.ArgumentParser()
parser.add_argument('--input', nargs='?', const='testInput')
parser.add_argument('--target', nargs='?', const='testTarget')
parser.add_argument('--msg', nargs='?', const='helloFromTheOtherSide')
args = parser.parse_args()
print args.input
If I don't give input, it prints it as None as I said. I want it to print TestInput instead..
Use the default argument:
parser = argparse.ArgumentParser()
parser.add_argument('--input', nargs='?', default='testInput')
parser.add_argument('--target', nargs='?', default='testTarget')
parser.add_argument('--msg', nargs='?', default='helloFromTheOtherSide')
args = parser.parse_args()
print args.input
With
parser.add_argument('--input', nargs='?', default='testInput', const='aConst')
you have a 3 way choice
prog # input='testInput'
prog --input # input='aConst'
prog --input myfile # input='myfile'
If you don't need that aConst option, omit the nargs='?'. Since it is a flagged argument it is already optional. It doesn't need the `?'.
parser.add_argument('--input', default='testInput')