I use peewee orm in python.
I have a query that :
userOrganizations = (UserOrganization
.select(UserOrganization,Organization)
.join(Organization)
.where(UserOrganization.user==user.user_id)
.aggregate_rows()
)
I want to get length of userOrganizations variable. Is there any method like userOrganizations.length() ?
According to the peewee documentation you can use the count() function, i.e.:
userOrganizations.count()
If you're worried about maybe running extra DB queries, you can convert your result to a list and get the length, like:
len(list(userOrganizations))
Source for second technique: this question.
Related
I have a dictionary that is being used to query the database for a match. I have one single query line that isn't working for me. If i have a list like this:
user['names']= [Alice, Bob, John]
Since this is a list I tried to use something like this:
q.filter(UserTable.firstname in user['firstnames'])
But for whatever reason this doesn't work. However, I know that Bob is in the database. When I manually pull down all the queries I can see the name is there in one of the rows. If I do this instead:
q.filter(UserTable.firstname == user['firstnames'][1]) #Only does Bob
It works. And when I pull all the queries manually, convert each row to a dictionary, and then do a
row[#row_that_matches].firstname in user['names']
that also works. But for some reason using the "in" keyword in sqlalchemy doesn't work as expected. Does anyone know an alternative that can make an sqlalchemy query for something in a list of values?
Use the in_() column method to test a column against a sequence:
q.filter(UserTable.firstname.in_(user['firstnames'])
See the Common Filter Operations section of the Object Relational tutorial:
IN:
query.filter(User.name.in_(['ed', 'wendy', 'jack']))
# works with query objects too:
query.filter(User.name.in_(
session.query(User.name).filter(User.name.like('%ed%'))
))
I am trying to use Django's ORM to generate a query using both extra and filter methods. Something like this:
Model.objects.filter(clauseA).extra(clauseB).all()
This generates a query, but the issue is that everything in the filter clause is AND'd with everything in the extra clause, so the sql looks like:
SELECT * FROM model WHERE clauseA AND clauseB.
My question is, is there a way to change the default combination operator for a query in Django such that the query generated will be:
SELECT * FROM model WHERE clauseA OR clauseB.
Try Q object
Model.objects.filter(Q(clauseA) | ~Q(clauseB))
EDIT
try this
Model.objects.filter(clauseA) | Model.objects.extra(clauseB)
It might be easier if you just get rid of the filter clause, and include that filter directly into extra OR'd with your Postgres specific function. I think it is already a limitation of the Django ORM.
You can attempt to create your own Func expression though. Once you have created one for your Postgres specific function, you might be able to use a combination of Func(), F(), and Q() objects to get rid of that nasty .extra() function and chain them nicely.
I have this query:
mps = (
session.query(mps) .filter_by(idc = int(c.idc))
.filter_by(idmp = int(m.idmp))
.group_by(func.day(mps.tschecked))
).all()
My problem is, that I don't know how to extract (with sqlalchemy) the max/min/avg value from a table...
I find this: Database-Independent MAX() Function in SQLAlchemy
But I don't know where to use this func.max/min/avg...
Can someone tell me how to do this? Can you give me an example?
The following functions are available with from sqlalchemy import func:
func.min
func.max
func.avg
Documentation is available here.
You can use them i.e. in the query() method.
Example:
session.query(self.stats.c.ID, func.max(self.stats.c.STA_DATE))
(just like you use aggregate functions in plain SQL)
Or just use an order_by() and select the first or last element. . .
I'm trying to get some query performance improved, but the generated query does not look the way I expect it to.
The results are retrieved using:
query = session.query(SomeModel).
options(joinedload_all('foo.bar')).
options(joinedload_all('foo.baz')).
options(joinedload('quux.other'))
What I want to do is filter on the table joined via 'first', but this way doesn't work:
query = query.filter(FooModel.address == '1.2.3.4')
It results in a clause like this attached to the query:
WHERE foos.address = '1.2.3.4'
Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to:
WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4'
It works fine. The question is of course - how can I achieve this with sqlalchemy itself?
If you want to filter on joins, you use join():
session.query(SomeModel).join(SomeModel.foos).filter(Foo.something=='bar')
joinedload() and joinedload_all() are used only as a means to load related collections in one pass, not used for filtering/ordering!. Please read:
http://docs.sqlalchemy.org/en/latest/orm/tutorial.html#joined-load - the note on "joinedload() is not a replacement for join()", as well as :
http://docs.sqlalchemy.org/en/latest/orm/loading.html#the-zen-of-eager-loading
I have this query:
mps = (
session.query(mps) .filter_by(idc = int(c.idc))
.filter_by(idmp = int(m.idmp))
.group_by(func.day(mps.tschecked))
).all()
My problem is, that I don't know how to extract (with sqlalchemy) the max/min/avg value from a table...
I find this: Database-Independent MAX() Function in SQLAlchemy
But I don't know where to use this func.max/min/avg...
Can someone tell me how to do this? Can you give me an example?
The following functions are available with from sqlalchemy import func:
func.min
func.max
func.avg
Documentation is available here.
You can use them i.e. in the query() method.
Example:
session.query(self.stats.c.ID, func.max(self.stats.c.STA_DATE))
(just like you use aggregate functions in plain SQL)
Or just use an order_by() and select the first or last element. . .