How does class Application(frame): works? - python

I have a question. I thought that a class can be based on an object or previously define class. When I change it into class Application(object): it doesn't work. Can you tell me why it didn't work and why did the code below works or why did class Application(Frame) works? Frame is not a previously define object and not object. Sorry for my English. Here is my code:
# Lazy Buttons
# Demonstrates using a class with tkinter
from tkinter import *
class Application(Frame): #
""" A GUI application with three buttons. """
def __init__(self, master):
super(Application, self).__init__(master)
self.grid()
self.create_widgets()
def create_widgets(self):
""" Create three buttons that do nothing. """
# create the first Button
self.bttn1 = Button(self, text= "I do nothing.")
self.bttn1.grid()
# create second button
self.bttn2 = Button(self)
self.bttn2.grid()
self.bttn2.configure(text="Me too!")
# create third button
self.bttn3 = Button(self)
self.bttn3.grid()
self.bttn3["text"] = "Same here!"
# main
root= Tk()
root.title("Lazy Buttons")
root.geometry("200x85")
app = Application(root)
root.mainloop()

Frame is a previously defined class. It's part of tkinter, which you imported on your first line.
Your Application class extends Frame, which means that it gets methods from Frame and can do everything that a Tk Frame can do, like show widgets. If you don't extend Frame, and only extend object instead, this will not work.
It might be clearer to replace...
from tkinter import *
with...
import tkinter as tk
and fix your references to Tk's classes (they would become tk.Button, tk.Frame and tk.Tk).

Related

External window is empty with "tk.Toplevel" and "parent"

When I click on a label to open an external window (tertiary.py), the window opens normally but is empty inside. I don't get errors, but I don't see Tkinter widgets and miscellaneous items.
This is the secondary window where there is the label on which I click in order to open an external window. I add, for information purposes only, that this window is called secondary because it is displayed in a frame (with a vertical menu on the left) where the main window is called home = tk.Tk(). The secondary window opens and displays correctly in the frame.
Inside the secondary window there is the label thanks to which I want to open an external window (not in the frame) called tertiary
How can I solve?
secondary.py
import tkinter as tk
from tkinter import *
from tkinter import ttk
import other_options
from other_options import form_other_options
class Page2(tk.Frame):
def __init__(self, master, **kw):
super().__init__(master, **kw)
self.configure(bg='white')
bar1=Frame(self, width=2200, height=35, background="#960000", highlightbackground="#b40909", highlightthickness=0) #grigio chiaro #b40909
bar1.place(x=0, y=0)
other_options = Label(self, text="Other Options", bg="#960000", foreground='white', font='Ubuntu 10')
other_options.place(x=1025, y=7)
other_options.bind("<Button-1>", lambda event: other_options.form_other_options(self))
tertiary.py
from tkinter import *
from tkinter import ttk
import tkinter as tk
def form_other_options(parent):
other_options = tk.Toplevel(parent)
other_options.title("Other options")
other_options.geometry("1000x800")
other_options.config(bg="white")
other_options.state("normal")
other_options.transient(parent)
class checkbox():
def __init__(self, master, **kw):
super().__init__(master, **kw)
labelframe1 = LabelFrame(self, text="checkbox", width=600,height=190, bg="white", foreground='#e10a0a')
labelframe1.place(x=10, y=13)
Checkbutton1 = IntVar()
Button1 = Checkbutton(self, text = "option1",
variable = Checkbutton1,
onvalue = 1,
offvalue = 0,
height = 2,
width = 10)
Button1.pack()
other_options.mainloop()
The first reason why the window is empty is that you never create an instance of the class checkbox, so the code that creates the widgets never runs.
So, the first step is to make sure you create an instance of that class:
other_options = tk.Toplevel(parent)
...
cb = checkbox(other_options)
When you do that, you will discover other bugs in your code. The first positional argument when creating a tkinter widget must be another widget. If you want the widget to be inside a Toplevel, the parent needs to be the toplevel or a descendant. You're using self which isn't a widget at all.
A simple fix is to use master instead of self, since you're passing the toplevel window as the master parameter:
labelframe1 = LabelFrame(master, ...)
Button1 = Checkbutton(master, ...)
You also need to remove the call to other_options.mainloop(). Unless there is a very compelling reason to do otherwise, an entire application should only call mainloop() exactly once.
There are other problems in the code that, strictly speaking, aren't related to the question being asked. For example, you're importing tkinter twice: once as import tkinter as tk and once as from tkinter import *. You only need to import tkinter once, and PEP8 recommends to use the first form:
import tkinter as tk
You'll need to add the prefix tk. to every place where you call a tkinter function. This will help make your code easier to understand and helps prevent pollution of the global namespace.
You also should use PEP8 naming standards. Specifically, class names should begin with an uppercase character. This will also make your code easier to understand.
There's also no reason why your checkbox class should be indented. You should move it out of the function.
Also, instead of checkbox not inheriting from anything, and then creating a LabelFrame, you should just inherit from LabelFrame. That way you can use your class more like a real widget, and would enable you to use self rather than master when creating the other widgets.
class Checkbox(tk.LabelFrame):
def __init__(self, master, **kw):
super().__init__(master, **kw)
...
button1 = tk.Checkbutton(self, ...)
...
There are probably other problems, but those are the most obvious.

Is there a way to make a label show in every window for tkinter without having to write out every single line of code over and over

I am wondering if there is a way, in tkinter or using any other python module, to make it so you keep a label or any other element in every window made by just using something like a function that makes the label within the window? I've tried this:
#Modules
import tkinter as tkin
#The initializer window
class Test:
def __init__(self):
#Initializes the main window
self.start = tkin.Tk()
self.start.title('Test')
self.label_thing()
#Makes a label
def label_thing(self):
self.label1 = tkin.Label(text='Not Button')
self.label1.pack()
I don't know if I made any errors or if this isn't a thing you can do but I'd also like to refrain from having the label localized to this window and having to remake the code for every window.
Let us assume you have a button that creates windows, you would pass this window as an argument to the function that creates the label, so like:
import tkinter as tk # Fixed weird import naming
class Test:
def __init__(self):
self.start = tk.Tk()
self.start.title('Test')
self.label_thing(self.start) # Label on the main window
tk.Button(self.start,text='Click me',command=self.create_win).pack()
self.start.mainloop()
def label_thing(self, master):
self.label1 = tk.Label(master, text='Not Button')
self.label1.pack()
def create_win(self):
new = tk.Toplevel()
self.label_thing(new) # Label on the new window
if __name__ == '__main__':
Test()
As you can see, as long as you press the button, new windows are created, and all those windows have the label on them, dynamically.

Python, accessing widget items from outside of a class

I have an auto generated code which generates a GUI that has various widgets in it. One of the widget is a ScrolledListBox. A part of the code is shown below:
class New_Toplevel_1:
def __init__(self, top=None):
self.Scrolledlistbox4.configure(background="white")
self.Scrolledlistbox4.configure(font="TkFixedFont")
self.Scrolledlistbox4.configure(highlightcolor="#d9d9d9")
self.Scrolledlistbox4.configure(selectbackground="#c4c4c4")
self.Scrolledlistbox4.configure(width=10)
I want to access the Scrolledlistbox4 from outside this class. So for example, I would like to write to write a function that updates the ScrolledListBox whenever I call it. I am relatively new to python and would like to know how can I accomplish this.
You need to first create a Scrolledlistbox4 object as an attribute:
self.scrolled_listbox = Scrolledlistbox4(...)
then you can do all configures in outermost scope like:
a = New_Toplevel_1()
a.scrolled_listbox.configure(background='white')
...
In below example "Outside Button" changes the text option of a class' button from the outside:
import tkinter as tk
class FrameWithButton(tk.Frame):
def __init__(self, master):
super().__init__(master)
self.btn = tk.Button(root, text="Button")
self.btn.pack()
root = tk.Tk()
an_instance = FrameWithButton(root)
an_instance.pack()
def update_button():
global an_instance
an_instance.btn['text'] = "Button Text Updated!"
tk.Button(root, text="Outside Button", command=update_button).pack()
root.mainloop()

Python Tkinter class structure practice

#game class
import Tkinter as tk
class Game(tk.Canvas):
def __init__(self, master):
canvas = tk.Canvas(master)
canvas.pack()
button = tk.Button(canvas, text='Quit', command=self.quit_game)
button.pack()
def quit_game(self):
root.destroy()#Should i put something else here?
root = tk.Tk()
game = Game(root)
root.mainloop()
Is it good practice, or, in other words, is there a problem with inheriting from canvas directly instead of frame, if for example I am not going to add any widgets except the canvas?
Another question I have is regarding the root.destroy(). I don't understand why I can't say master.destroy() or something to that effect.
There is nothing wrong with inheriting from Canvas or any other Tkinter widget.
re master.destroy() vs root.destroy(): you can call it however you want. You simply need a reference to the root window. If you call it root, to destroy it you would call root.destroy().
In general you should avoid the use of global variables. Given that you're passing in the root widget to your class, you can save a reference and use that instead:
class Game(tk.Canvas):
def __init__(self, master):
self.master = master
...
def quit_game(self):
self.master.destroy()

Using Tkinter in python to edit the title bar

I am trying to add a custom title to a window but I am having troubles with it. I know my code isn't right but when I run it, it creates 2 windows instead, one with just the title tk and another bigger window with "Simple Prog". How do I make it so that the tk window has the title "Simple Prog" instead of having a new additional window. I dont think I'm suppose to have the Tk() part because when i have that in my complete code, there's an error
from tkinter import Tk, Button, Frame, Entry, END
class ABC(Frame):
def __init__(self,parent=None):
Frame.__init__(self,parent)
self.parent = parent
self.pack()
ABC.make_widgets(self)
def make_widgets(self):
self.root = Tk()
self.root.title("Simple Prog")
If you don't create a root window, Tkinter will create one for you when you try to create any other widget. Thus, in your __init__, because you haven't yet created a root window when you initialize the frame, Tkinter will create one for you. Then, you call make_widgets which creates a second root window. That is why you are seeing two windows.
A well-written Tkinter program should always explicitly create a root window before creating any other widgets.
When you modify your code to explicitly create the root window, you'll end up with one window with the expected title.
Example:
from tkinter import Tk, Button, Frame, Entry, END
class ABC(Frame):
def __init__(self,parent=None):
Frame.__init__(self,parent)
self.parent = parent
self.pack()
self.make_widgets()
def make_widgets(self):
# don't assume that self.parent is a root window.
# instead, call `winfo_toplevel to get the root window
self.winfo_toplevel().title("Simple Prog")
# this adds something to the frame, otherwise the default
# size of the window will be very small
label = Entry(self)
label.pack(side="top", fill="x")
root = Tk()
abc = ABC(root)
root.mainloop()
Also note the use of self.make_widgets() rather than ABC.make_widgets(self). While both end up doing the same thing, the former is the proper way to call the function.
Here it is nice and simple.
root = tkinter.Tk()
root.title('My Title')
root is the window you create and root.title() sets the title of that window.
Try something like:
from tkinter import Tk, Button, Frame, Entry, END
class ABC(Frame):
def __init__(self, master=None):
Frame.__init__(self, master)
self.pack()
root = Tk()
app = ABC(master=root)
app.master.title("Simple Prog")
app.mainloop()
root.destroy()
Now you should have a frame with a title, then afterwards you can add windows for
different widgets if you like.
One point that must be stressed out is:
The .title() method must go before the .mainloop()
Example:
from tkinter import *
# Instantiating/Creating the object
main_menu = Tk()
# Set title
main_menu.title("Hello World")
# Infinite loop
main_menu.mainloop()
Otherwise, this error might occur:
File "/Library/Frameworks/Python.framework/Versions/3.8/lib/python3.8/tkinter/__init__.py", line 2217, in wm_title
return self.tk.call('wm', 'title', self._w, string)
_tkinter.TclError: can't invoke "wm" command: application has been destroyed
And the title won't show up on the top frame.
Example of python GUI
Here is an example:
from tkinter import *;
screen = Tk();
screen.geometry("370x420"); //size of screen
Change the name of window
screen.title('Title Name')
Run it:
screen.mainloop();
I found this works:
window = Tk()
window.title('Window')
Maybe this helps?
Easy method:
root = Tk()
root.title('Hello World')
Having just done this myself you can do it this way:
from tkinter import Tk, Button, Frame, Entry, END
class ABC(Frame):
def __init__(self, parent=None):
Frame.__init__(self, parent)
self.parent = parent
self.pack()
ABC.make_widgets(self)
def make_widgets(self):
self.parent.title("Simple Prog")
You will see the title change, and you won't get two windows. I've left my parent as master as in the Tkinter reference stuff in the python library documentation.
For anybody who runs into the issue of having two windows open and runs across this question, here is how I stumbled upon a solution:
The reason the code in this question is producing two windows is because
Frame.__init__(self, parent)
is being run before
self.root = Tk()
The simple fix is to run Tk() before running Frame.__init__():
self.root = Tk()
Frame.__init__(self, parent)
Why that is the case, I'm not entirely sure.
self.parent is a reference to the actual window, so self.root.title should be self.parent.title, and self.root shouldn't exist.
widget.winfo_toplevel().title("My_Title")
changes the title of either Tk or Toplevel instance that the widget is a child of.
I found a solution that should help you:
from tkinter import Tk, Button, Frame, Entry, END
class ABC(Frame):
def __init__(self,master=None):
super().__init__(master)
self.pack()
self.master.title("Simple Prog")
self.make_widgets()
def make_widgets(self):
pass
root = Tk()
app = ABC(master=root)
app.mainloop()
Found at: docs.python.org

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