This question already has answers here:
Limiting floats to two decimal points
(35 answers)
Closed 7 years ago.
I need to print double with precision equal exactly to 6, I found function round:
print(str(round(result, 6))
But in case result itself has less precision, the print function skips zeros at the end.
Gor example, the output of such code,
print(str(round(4.0, 6)))
is
4.0
But what I need is
4.000000
How can I reach this?
Try using a format string:
print("%.6f"%4.0) # 4.000000
Or alternatively:
print("{:.6f}".format(4.0))
See the Python documentation for details on format strings and more examples.
Related
This question already has answers here:
Print a float number in normal form, not exponential form / scientific notation [duplicate]
(2 answers)
How to suppress scientific notation when printing float values?
(16 answers)
Closed 2 years ago.
I want to print the whole number instead of 1e-06
number = 1
result = number/1000000
print(result)
Please help whats the best way to do it?
Try out the following by using format:
number = 1
result = number/1000000
print('{0:.6f}'.format(result))
Output:
0.000001
output = f"{num:.9f}"
you can replace 9 with the amount of numbers you have after the decimal point in your number.
and also you will need to define your variable to float to order it will work.
This question already has answers here:
Why does integer division yield a float instead of another integer?
(4 answers)
Closed 3 years ago.
Pretty new to python, facing a problem that requires basically the opposite of the remainder "%" function. For example, if I wanted to divide 81.5 by 20, my output would be 4. My best attempt is as follows:
amount = 81.504
round(amount, 2)
num20s = amount / 20
int(num20s)
I've tried several different combinations of the above code, but nothing has worked so far. This is the closest I've gotten to what I want, but it won't work in edge cases, and for some reason still represents the number with a ".0" at the end, so that last line must not be doing anything.
Integer division operator in python is "//".
>>> amount = 81.504
>>> amount // 20
Out[3]: 4.0
>>> int(amount // 20)
Out[4]: 4
This question already has answers here:
Truncate to three decimals in Python
(21 answers)
Closed 3 years ago.
I would like to truncate a floating point number at the third decimal place. However, I don't want to round the number.
float("{0:.3f}".format(132.32579))
The code above produces 132.326 but I want it to produce 132.325. Any help is appreciated
You can round to 1 digit more, slice the string for ignoring the last digit and convert back to float:
print( float("{0:.4f}".format(132.32579) [:-1]))
You can avoid the string conversion/rounding by multiplying by 1000, converting to int and dividing by 1000.0 again:
print( float(int(132.32579*1000)/1000.0))
Output (both):
132.325
This question already has answers here:
Formatting floats without trailing zeros
(21 answers)
Closed 6 years ago.
I have a long list of floating point numbers to be formatted as follows:
Examples:
case 1) 6.0 -> 6.0 (No trailing zeros)
case 2) 1.23456789 -> 1.234567 (or 1.234568) (Max precision of 6)
case 3) 0.000004 -> 0.000004 (No exponent)
I can use
'{}'.format(round(x, 6))
for cases 1 & 2 but 3 gives 4e-06
If I use
'{:6f}'.format(6.0)
I get 6.000000 for case 1)
Is there a clean way to get the formatting I want?
Perhaps you can consider this solution.
Your case:
print ('%.6f' % data).rstrip('0').rstrip('.')
Use %.6f%(data)
Hope it works !
This question already has answers here:
binary numbers?
(8 answers)
Closed 8 years ago.
I wonder why adding one or multiple leading zeros to an integer in Python leads to different results when using the bitshift-operators:
In: 10<<1
Out: 20
Adding a "0" in front of the integer:
In: 010<<1
Out: 16
Meanwhile, I found the answer is quite simple - but maybe it's worth sharing it:
According to this answer, adding a leading zero to an integer will cause Python to interpret it as an octal/base 8.
In: int("010",8)
Out: 8
Thus, left-shifting the octal (or decimal 8), i.e. multipicaton by 2**1, leads to 16
In: 8<<1
Out: 16