This question already has answers here:
Print a float number in normal form, not exponential form / scientific notation [duplicate]
(2 answers)
How to suppress scientific notation when printing float values?
(16 answers)
Closed 2 years ago.
I want to print the whole number instead of 1e-06
number = 1
result = number/1000000
print(result)
Please help whats the best way to do it?
Try out the following by using format:
number = 1
result = number/1000000
print('{0:.6f}'.format(result))
Output:
0.000001
output = f"{num:.9f}"
you can replace 9 with the amount of numbers you have after the decimal point in your number.
and also you will need to define your variable to float to order it will work.
Related
This question already has answers here:
Is floating point arbitrary precision available?
(5 answers)
Is floating point math broken?
(31 answers)
Closed 1 year ago.
I am trying to divide floats by each other but am having a hard time getting accurate results. I understand that computers store floats in a way where the value stored is not exact to the given number. I am simply looking for a way where I can get specific results when working with floats.
input:
x = 2.4
y = 0.2
print(x/y)
Output:
11.999999998
I highly recommend to use decimals
Example
from decimal import Decimal
x = Decimal("2.4")
y = Decimal("0.2")
print(x / y) # 12
Notice we passing number as string, as passing float numbers would have the same problem you pointed out.
But care with comparison, as 12 == x / y evaluates to False
This question already has answers here:
Python round up integer to next hundred
(10 answers)
Closed 2 years ago.
This is my code so far:
number = 201234
print(f'number is {number:,.0f}')
This prints: number is 201,234
However I want it to print: number is 200,000
I've tried using print(f'number is {number:,.1g}') but this prints in scientific notation like so: number is 2e+05
Is there a simple way to format this to get the desired outcome?
Use the round() function with a negative argument.
number = 201234
print(f'number is {round(number, -5):,.0f}')
Prints
number is 200,000
This question already has answers here:
Truncate to three decimals in Python
(21 answers)
Closed 3 years ago.
I would like to truncate a floating point number at the third decimal place. However, I don't want to round the number.
float("{0:.3f}".format(132.32579))
The code above produces 132.326 but I want it to produce 132.325. Any help is appreciated
You can round to 1 digit more, slice the string for ignoring the last digit and convert back to float:
print( float("{0:.4f}".format(132.32579) [:-1]))
You can avoid the string conversion/rounding by multiplying by 1000, converting to int and dividing by 1000.0 again:
print( float(int(132.32579*1000)/1000.0))
Output (both):
132.325
This question already has answers here:
Print pi to a number of decimal places
(8 answers)
Closed 4 years ago.
I'm writing a program that estimates the value of pi. I want to implement that you in the command line can specify when the result have the specified number of correct decimals.
Example:
python est_pi.py 3
should end the script when the estimation is 3.141...
Is it possible to have a variable real_pi = 3.14159... and then index into the number of decimals or is there any other solution to this problem?
If You can round your result using:
round(0.333333, N)
Where N is the parameter in input of your script
all the details are there: Round float to x decimals?
When you reached the needed precision, you can format the display through:
format(66.66666666666, '.'+str(N)+'f')
That will display your 66.666... with N digits.
In python 3.6 you have the f-string:
value = 2.34558
precision = N
width = 4
print(f'result: {value:{width}.{precision}f}')
Everything is detailed there: Limiting floats to two decimal points
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
Closed 7 years ago.
I need to print double with precision equal exactly to 6, I found function round:
print(str(round(result, 6))
But in case result itself has less precision, the print function skips zeros at the end.
Gor example, the output of such code,
print(str(round(4.0, 6)))
is
4.0
But what I need is
4.000000
How can I reach this?
Try using a format string:
print("%.6f"%4.0) # 4.000000
Or alternatively:
print("{:.6f}".format(4.0))
See the Python documentation for details on format strings and more examples.