Below is my code, the problem that I'm working on is to have the output of my program "written to a file whose name is obtained by appending the string _output to the input file name".
What is the correct way of going about doing this?
fileName = raw_input('Enter the HTML file name:') + '.html'
f = open(fileName, 'r')
myList = f.readlines()
for i in range(0, len(myList)):
toString = ''.join(myList)
newString = toString.replace('<span>', '')
newString = newString.replace('</span>', '')
print newString #testing the output
f.close()
Here is revised code. Something like this?
fileName = raw_input('Enter the HTML file name:') + '.html'
f = open(fileName, 'r')
fnew = open(fileName, 'w')
myList = f.readlines()
for i in range(0, len(myList)):
toString = ''.join(myList)
newString = toString.replace('<span>', '')
newString = newString.replace('</span>', '')
fnew.write(newString)
f.close()
Try;
fileName = raw_input('Enter the HTML file name:') + '.html'
f = open(fileName, 'r+')
toString = f.read()
newString = toString.replace('<span>', '')
newString = newString.replace('</span>', '')
print newString #testing the output
f.truncate() #clean all content from the file
f.write(newString) #write to the file
f.close()
Please refer this post : In Python, is read() , or readlines() faster?
If you want to print the output to a new file then;
new_file = open(new_file_path, 'w') #If the file does not exist, creates a new file for writing
new_file.write(newString)
new_file.close()
Now no need to open the first html file read/write use
f = open(fileName, 'r')
Related
line_row = -1
file = open(file_path, 'r')
for number_of_lines in file:
line_row = line_row + 1
if '1234' in number_of_lines:
lines = file.readlines()
line = lines[line_row]
print(lines)
lines[line_row] = 'hello'
file = open(file_path, "w")
file.writelines(lines)
file.close()
When I run this, it will delete everything that is before the nth line. I want it to replace only the nth line. can you help me?
try this, using enumerate
with open(file_path, 'r') as f:
lines = f.readlines()
for i, line in enumerate(lines):
if "some text" in line:
lines[i] = "updated text"
with open(file_path, "w") as f:
f.writelines(lines)
f = open("text.txt", "rb")
s = f.readlines()
f.close()
f = open("newtext.txt", "wb")
f.writelines(s[::-1])
f.close()
my orignal text file is
Hi ashmi
it show output
Hi ashmi
but i want output
ashmi Hi
This works there is probably a better way but regardless here it is.
f = open("text.txt", "r")
s = f.readlines()
f.close()
f = open("newtext.txt", "w+")
for i in s:
word_list = i.split()
for i in word_list.__reversed__():
f.writelines(i+' ')
f.close()
what i have done is split the words in the text file into a new list then used the reversed function to reverse the list then save the words to a new text file.
I hope this helps.
Now this reverse order of words in a sentence and not letters in a word
f = open("text.txt", "rb")
s = f.read()
f.close()
s = s.split()[::-1]
f = open("newtext.txt", "wb")
f.writelines([b" ".join(s)])
f.close()
here is an alternative
f = open("text.txt", "rb")
s = f.read()
f.close()
s = s.split()[::-1]
f = open("newtext.txt", "wb")
f.write(b" ".join(s))
f.close()
I'm trying to replace a value in a specific line in a text file.
My text file contains count of the searchterm, searchterm & date and time
Text file:
MemTotal,5,2016-07-30 12:02:33,781
model name,3,2016-07-30 13:37:59,074
model,3,2016-07-30 15:39:59,075
How can I replace for example the count of the searchterm for line 2 (model name,3,2016-07-30 13:37:59,074)?
This is what I have already:
f = open('file.log','r')
filedata = f.read()
f.close()
newdata = filedata.replace("2", "3")
f = open('file.log', 'w')
f.write(newdata)
f.close()
It replace all values 2.
You have to change three things in your code to get the job done:
Read the file using readlines.
filedata = f.readlines()
Modify the line you want to change (keep in mind that Python indices start at 0 and don't forget to add a newline character \n at the end of the string):
filedata[1] = 'new count,new search term,new date and time\n'
Save the file using a for loop:
for line in filedata:
f.write(line)
Here is the full code (notice I used the with context manager to open/close the file):
with open('file.log', 'r') as f:
filedata = f.readlines()
filedata[1] = 'new count,new search term,new date and time\n'
with open('file.log', 'w') as f:
for line in filedata:
f.write(line)
My solution:
count = 0
line_number = 0
replace = ""
f = open('examen.log','r')
term = "MemTotal"
for line in f.read().split('\n'):
if term in line:
replace= line.replace("5", "25", 1)
line_number = count
count = count + 1
print line_number
f.close()
f = open('examen.log','r')
filedata = f.readlines()
f.close()
filedata[line_number]=replace+'\n'
print filedata[line_number]
print filedata
f = open('examen.log','w')
for line in filedata:
f.write(line)
f.close()
You only need to define the searchterm & the replace value
output_filename = r"C:\Users\guage\Output.txt"
RRA:
GREQ-299684_6j
GREQ-299684_6k
CZM:
V-GREQ-299684_6k
V-GREQ-299524_9
F_65624_1
R-GREQ-299680_5
DUN:
FB_71125_1
FR:
VQ-299659_18
VR-GREQ-299659_19
VEQ-299659_28
VR-GREQ-299659_31
VR-GREQ-299659_32
VEQ-299576_1
GED:
VEQ-299622_2
VR-GREQ-299618_13
VR-GREQ-299559_1
VR-GREQ-299524_14
FB_65624_1
VR-GREQ-299645_1
MNT:
FB_71125_1
FB_71125_2
VR-534_4
The above is the content of the the .txt file. how can I read it separately the content of it. for example -
RRA:VR-GREQ-299684_6j VR-GREQ-299684_6k VR-GREQ-299606_3 VR-GREQ-299606_4 VR-GREQ-299606_5 VR-GREQ-299606_7
and save it in a variable or something similar to it. Later I want to read CZM separately and so on. I did as below.
with open(output_filename, 'r') as f:
excel = f.read()
But how to read it separately ? can someone tell me how to do it ?
Something like this:
def read_file_with_custom_record_separator(file_path, delimiter='\n'):
fh = open(file_path)
data = ""
for line in fh:
if line.strip().endswith(delimiter) and data != "":
print "VARIABLE:\n<", data, ">\n"
data = line
else:
data += line
print "LAST VARIABLE:\n<", data, ">\n"
And then:
read_file_with_custom_record_separator("input.txt", ":")
You can make use of the file text : as indicator to create a new file like this:
savefilename = ""
with open(filename, 'r') as f:
for line in f:
line = line.strip() # get rid of the unnecessary white chars
lastchar = line[-1:] # get the last char
if lastchar == ":": # if the last char is ":"
savefilename = line[0:-1] # get file name from line (except the ":")
sf = open(savefilename + ".txt", 'w') # create a new file
else:
sf.write(line + "\n") # write the data to the opened file
Then you should get collection of files:
RRA.txt
CZM.txt
DUN.txt
# etc
which contains all the appropriate data:
RRA.txt
VR-GREQ-299684_6j
VR-GREQ-299684_6k
VR-GREQ-299606_3
VR-GREQ-299606_4
VR-GREQ-299606_5
VR-GREQ-299606_7
CZM.txt
VR-GREQ-299684_6k
VR-GREQ-299606_6
VR-GREQ-299606_8
VR-GREQ-299640_1
VR-GREQ-299640_5
VR-GREQ-299524_9
FB_65624_1
VR-GREQ-299680_5
DUN.txt
FB_71125_1
# and so on
You can replace the sf = open and the sf.write which whatever way you feel best to separate the data. Here, I use files...
You can iterate over the file and use the lines and indices to your advantage; something like this:
with open(output_filename, 'r') as f:
for index, line in enumerate(f):
# here you have access to each line and its index
# so you can save any number of lines you wish
What about reading it into a list, then process its element as you prefer
>>> f = open('myfile.txt', 'r').readlines()
>>> len(f)
46
>>> f[0]
RRA:
>>> f[-1]
VR-GREQ-299534_4
>>> f[:3]
['RRA:\n', 'VR-GREQ-299684_6j \n', 'VR-GREQ-299684_6k \n']
>>>
>>> [l for l in f if l.startswith('FB_')]
['FB_65624_1 \n', 'FB_71125_1 \n', 'FB_69228_1 \n', 'FB_65624_1 \n', 'FB_71125_1 \n', 'FB_71125_2 \n']
>>>
The problem I am having at this point in time (being new to Python) is writing strings to a text file. The issue I'm experiencing is one where either the strings don't have linebreaks inbetween them or there is a linebreak after every character. Code to follow:
import string, io
FileName = input("Arb file name (.txt): ")
MyFile = open(FileName, 'r')
TempFile = open('TempFile.txt', 'w', encoding='UTF-8')
for m_line in MyFile:
m_line = m_line.strip()
m_line = m_line.split(": ", 1)
if len(m_line) > 1:
del m_line[0]
#print(m_line)
MyString = str(m_line)
MyString = MyString.strip("'[]")
TempFile.write(MyString)
MyFile.close()
TempFile.close()
My input looks like this:
1 Jargon
2 Python
3 Yada Yada
4 Stuck
My output when I do this is:
JargonPythonYada YadaStuck
I then modify the source code to this:
import string, io
FileName = input("Arb File Name (.txt): ")
MyFile = open(FileName, 'r')
TempFile = open('TempFile.txt', 'w', encoding='UTF-8')
for m_line in MyFile:
m_line = m_line.strip()
m_line = m_line.split(": ", 1)
if len(m_line) > 1:
del m_line[0]
#print(m_line)
MyString = str(m_line)
MyString = MyString.strip("'[]")
#print(MyString)
TempFile.write('\n'.join(MyString))
MyFile.close()
TempFile.close()
Same input and my output looks like this:
J
a
r
g
o
nP
y
t
h
o
nY
a
d
a
Y
a
d
aS
t
u
c
k
Ideally, I would like each of the words to appear on a seperate line without the numbers in front of them.
Thanks,
MarleyH
You have to write the '\n' after each line, since you're stripping the original '\n';
Your idea of using '\n'.join() doesn't work because it will use\n to join the string, inserting it between each char of the string. You need a single \n after each name, instead.
import string, io
FileName = input("Arb file name (.txt): ")
with open(FileName, 'r') as MyFile:
with open('TempFile.txt', 'w', encoding='UTF-8') as TempFile:
for line in MyFile:
line = line.strip().split(": ", 1)
TempFile.write(line[1] + '\n')
fileName = input("Arb file name (.txt): ")
tempName = 'TempFile.txt'
with open(fileName) as inf, open(tempName, 'w', encoding='UTF-8') as outf:
for line in inf:
line = line.strip().split(": ", 1)[-1]
#print(line)
outf.write(line + '\n')
Problems:
the result of str.split() is a list (this is why, when you cast it to str, you get ['my item']).
write does not add a newline; if you want one, you have to add it explicitly.