Develop Reference

How to read line in text file and replace the whole line in Python?

I want to replace a whole line in a text document, if there is a line that begins with "truck_placement"
Can I remove the whole line when it contains "truck_placement" and then write the new text?
I tried it but it only inserts the new text und doesn't replace the whole line.
Thats the current code:
cordget = coordinatesentry.get()
fin = open(save_file,"r")
filedata = fin.read()
fin.close
newdata = filedata.replace("truck_placement: " , "truck_placement: " + cordget)
fin = open(save_file, "w")
fin.write(newdata)
fin.close

Your best bet is to append all the lines without "truck_placement" to a new file. This can be done with the following code:
original = open("truck.txt","r")
new = open("new_truck.txt","a")
for line in original:
if "truck_placement" not in line:
new.write(line)
original.close()
new.close()

You can either read the whole file into one string and replace the line using regular expression:
import re
cordget = "(value, one) (value, two)"
save_file = "sample.txt"
with open(save_file, "r") as f:
data = f.read()
# Catch the line from "truck_placement: " until the newline character ('\n')
# and replace it with the second argument, where '\1' the catched group
# "truck_placement: " is.
data = re.sub(r'(truck_placement: ).*\n', r'\1%s\n' % cordget, data)
with open(save_file, "w") as f:
f.writelines(data)
Or you could read the file as a list of all lines and overwrite the specific line:
cordget = "(value, one) (value, two)"
save_file = "sample.txt"
with open(save_file, "r") as f:
data = f.readlines()
for index, line in enumerate(data):
if "truck_placement" in line:
data[index] = f"truck_placement: {cordget}\n"
with open(save_file, "w") as f:
f.writelines(data)

Python replace value in text file

I'm trying to replace a value in a specific line in a text file.
My text file contains count of the searchterm, searchterm & date and time
Text file:
MemTotal,5,2016-07-30 12:02:33,781
model name,3,2016-07-30 13:37:59,074
model,3,2016-07-30 15:39:59,075
How can I replace for example the count of the searchterm for line 2 (model name,3,2016-07-30 13:37:59,074)?
This is what I have already:
f = open('file.log','r')
filedata = f.read()
f.close()
newdata = filedata.replace("2", "3")
f = open('file.log', 'w')
f.write(newdata)
f.close()
It replace all values 2.

You have to change three things in your code to get the job done:
Read the file using readlines.
filedata = f.readlines()
Modify the line you want to change (keep in mind that Python indices start at 0 and don't forget to add a newline character \n at the end of the string):
filedata[1] = 'new count,new search term,new date and time\n'
Save the file using a for loop:
for line in filedata:
f.write(line)
Here is the full code (notice I used the with context manager to open/close the file):
with open('file.log', 'r') as f:
filedata = f.readlines()
filedata[1] = 'new count,new search term,new date and time\n'
with open('file.log', 'w') as f:
for line in filedata:
f.write(line)

My solution:
count = 0
line_number = 0
replace = ""
f = open('examen.log','r')
term = "MemTotal"
for line in f.read().split('\n'):
if term in line:
replace= line.replace("5", "25", 1)
line_number = count
count = count + 1
print line_number
f.close()
f = open('examen.log','r')
filedata = f.readlines()
f.close()
filedata[line_number]=replace+'\n'
print filedata[line_number]
print filedata
f = open('examen.log','w')
for line in filedata:
f.write(line)
f.close()
You only need to define the searchterm & the replace value

How to loop through a list of strings in Python

I'm a bit new to Python and I am trying to simplify my existing code.
Right now, I have the code repeated 5 times with different strings. I'd like to have the code one time and have it run through a list of strings.
Currently what I have:
def wiScanFormat():
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
MAC = data.replace("Address:", "\nAddress, ")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(MAC)
File.close()
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
SSID = data.replace("ESSID:", "\nESSID, ")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(SSID)
File.close()
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
FREQ = data.replace("Frequency:", "\nFrequency, ")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(FREQ)
File.close()
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
QUAL = data.replace("Quality", "\nQuality, ")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(QUAL)
File.close()
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
SIG = data.replace("Signal level", "\nSignal Level, ")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(SIG)
File.close()
What I'd like to have:
ORG = ['Address:', 'ESSID:'...etc]
NEW = ['\nAddress, ' , '\nESSID, ' , ... etc]
and run that through:
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
ID = data.replace("ORG", "NEW")
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(ID)
File.close()
I've tried running exactly what I put up, but it does not seem to format it the way I need to.
The output from above looks like:
Cell 46 - Address: xx:xx:xx:xx:xx:xx ESSID:"MySSID" Frequency:2.412 GHz (Channel 1) Quality=47/100 Signal level=48/100 Quality=47/100 Signal level=48/100
But it is supposed to look like this (And it does when I run that same block over the strings separately):
xx:xx:xx:xx:xx:xx MySSID 5.18 GHz (Channel 36) 0.81 0.99
How should I go about looping this block of code through my list of strings?
There two strings that I would need for the find and replace, old and new, so they would have to work together. These lists will be the same size, obviously, and I need them to be in the correct order. Address with address, ESSID with ESSID, etc.
Thanks in advance!

Try something like this:
ORG = ['Address:', 'ESSID:'...etc]
NEW = ['\nAddress, ' , '\nESSID, ' , ... etc]
File = open("/home/pi/gpsMaster/WiScan.txt", "r")
data = File.read()
File.close()
for org, new in zip(ORG, NEW):
data = data.replace(org, new)
File = open("/home/pi/gpsMaster/WiScan.txt", "w")
File.write(data)
File.close()
(Note the way zip works: https://docs.python.org/2/library/functions.html#zip)

If I am reading your question right, you are opening the same file, making a small alteration, saving it, and then closing it again, five times. You could just open it once, make all the alterations, and then save it. For instance, like this:
filename = "/home/pi/gpsMaster/WiScan.txt"
with open(filename, 'r') as fin:
data = fin.read()
data = data.replace("Address:", "\nAddress, ")
data = data.replace("ESSID:", "\nESSID, ")
data = data.replace("Frequency:", "\nFrequency, ")
data = data.replace("Quality", "\nQuality, ")
data = data.replace("Signal level", "\nSignal Level, ")
with open(filename, 'w') as fout:
fout.write(data)
If you want to use lists (ORG and NEW) for your replacements, you could do this:
with open(filename, 'r') as fin:
data = fin.read()
for o,n in zip(ORG, NEW):
data = data.replace(o,n)
with open(filename, 'w') as fout:
fout.write(data)

Given your ORG and NEW, the simplest way to do this would be something like:
# Open once for both read and write; use with statement for guaranteed close at end of block
with open("/home/pi/gpsMaster/WiScan.txt", "r+") as f:
data = f.read() # Slurp file
f.seek(0) # Seek back to beginning of file
# Perform all replacements
for orig, repl in zip(ORG, NEW):
data = data.replace(orig, repl)
f.write(data) # Write new data over old
f.truncate() # If replacement shrunk file, truncate extra

You could just do this:
def wiScanFormat(path = "/home/pi/gpsMaster/WiScan.txt"):
# List of tuples with strings to find and strings to replace with
replacestr = [
("Address:", "\nAddress, "),
("ESSID:", "\nESSID, "),
("Frequency:", "\nFrequency, "),
("Quality", "\nQuality, "),
("Signal level", "\nSignal Level, ")
]
with open(path, "r") as file: # Open a file
data = file.read()
formated = data
for i in replacestr: # Loop over each element (tuple) in the list
formated = formated.replace(i[0], i[1]) # Replace the data
with open(path, "w") as file:
written = file.write(formated) # Write the data
return written

Match the last word and delete the entire line

Input.txt File
12626232 : Bookmarks
1321121:
126262
Here 126262: can be anything text or digit, so basically will search for last word is : (colon) and delete the entire line
Output.txt File
12626232 : Bookmarks
My Code:
def function_example():
fn = 'input.txt'
f = open(fn)
output = []
for line in f:
if not ":" in line:
output.append(line)
f.close()
f = open(fn, 'w')
f.writelines(output)
f.close()
Problem: When I match with : it remove the entire line, but I just want to check if it is exist in the end of line and if it is end of the line then only remove the entire line.
Any suggestion will be appreciated. Thanks.
I saw as following but not sure how to use it in here
a = "abc here we go:"
print a[:-1]

I believe with this you should be able to achieve what you want.
with open(fname) as f:
lines = f.readlines()
for line in lines:
if not line.strip().endswith(':'):
print line
Here fname is the variable pointing to the file location.

You were almost there with your function. You were checking if : appears anywhere in the line, when you need to check if the line ends with it:
def function_example():
fn = 'input.txt'
f = open(fn)
output = []
for line in f:
if not line.strip().endswith(":"): # This is what you were missing
output.append(line)
f.close()
f = open(fn, 'w')
f.writelines(output)
f.close()
You could have also done if not line.strip()[:-1] == ':':, but endswith() is better suited for your use case.
Here is a compact way to do what you are doing above:
def function_example(infile, outfile, limiter=':'):
''' Filters all lines in :infile: that end in :limiter:
and writes the remaining lines to :outfile: '''
with open(infile) as in, open(outfile,'w') as out:
for line in in:
if not line.strip().endswith(limiter):
out.write(line)
The with statement creates a context and automatically closes files when the block ends.

To search if the last letter is : Do following
if line.strip().endswith(':'):
...Do Something...

You can use a regular expression
import re
#Something end with ':'
regex = re.compile('.(:+)')
new_lines = []
file_name = "path_to_file"
with open(file_name) as _file:
lines = _file.readlines()
new_lines = [line for line in lines if regex.search(line.strip())]
with open(file_name, "w") as _file:
_file.writelines(new_lines)

Problems with Python's file.write() method and string handling

The problem I am having at this point in time (being new to Python) is writing strings to a text file. The issue I'm experiencing is one where either the strings don't have linebreaks inbetween them or there is a linebreak after every character. Code to follow:
import string, io
FileName = input("Arb file name (.txt): ")
MyFile = open(FileName, 'r')
TempFile = open('TempFile.txt', 'w', encoding='UTF-8')
for m_line in MyFile:
m_line = m_line.strip()
m_line = m_line.split(": ", 1)
if len(m_line) > 1:
del m_line[0]
#print(m_line)
MyString = str(m_line)
MyString = MyString.strip("'[]")
TempFile.write(MyString)
MyFile.close()
TempFile.close()
My input looks like this:
1 Jargon
2 Python
3 Yada Yada
4 Stuck
My output when I do this is:
JargonPythonYada YadaStuck
I then modify the source code to this:
import string, io
FileName = input("Arb File Name (.txt): ")
MyFile = open(FileName, 'r')
TempFile = open('TempFile.txt', 'w', encoding='UTF-8')
for m_line in MyFile:
m_line = m_line.strip()
m_line = m_line.split(": ", 1)
if len(m_line) > 1:
del m_line[0]
#print(m_line)
MyString = str(m_line)
MyString = MyString.strip("'[]")
#print(MyString)
TempFile.write('\n'.join(MyString))
MyFile.close()
TempFile.close()
Same input and my output looks like this:
J
a
r
g
o
nP
y
t
h
o
nY
a
d
a
Y
a
d
aS
t
u
c
k
Ideally, I would like each of the words to appear on a seperate line without the numbers in front of them.
Thanks,
MarleyH

You have to write the '\n' after each line, since you're stripping the original '\n';
Your idea of using '\n'.join() doesn't work because it will use\n to join the string, inserting it between each char of the string. You need a single \n after each name, instead.
import string, io
FileName = input("Arb file name (.txt): ")
with open(FileName, 'r') as MyFile:
with open('TempFile.txt', 'w', encoding='UTF-8') as TempFile:
for line in MyFile:
line = line.strip().split(": ", 1)
TempFile.write(line[1] + '\n')

fileName = input("Arb file name (.txt): ")
tempName = 'TempFile.txt'
with open(fileName) as inf, open(tempName, 'w', encoding='UTF-8') as outf:
for line in inf:
line = line.strip().split(": ", 1)[-1]
#print(line)
outf.write(line + '\n')
Problems:
the result of str.split() is a list (this is why, when you cast it to str, you get ['my item']).
write does not add a newline; if you want one, you have to add it explicitly.