When I press a button using selenium, it redirects me to a new page. I want my selenium to redirect to same link also. How can I do it?
driver.find_element_by_xpath('//span[contains(text(),"Secure Login")]').click()
is a button I am clicking. It is redirecting me to a new page. I want selenium to get the same link and point to new page.
WebDriver creates and interface between selenium and your web browser. You don't need to handle anything separately in selenium if everything is happening in the same tab and it's just a navigation to a different link.
Though if your link is opening to a different tab, you will need to switch tabs. Before communicating with the elements over the new page.
Why don't you switch to new window, not sure about python but in java its like:
String currentState = driver.getWindowHandle().toString();
for (String handles : driver.getWindowHandles())
{
if (!handles.equalsIgnoreCase(currentState))
{
driver.switchTo().window(handles);
}
}
You can do same in python.
Related
I am trying to automate a process with Selenium, and am having troubles figuring out how to switch between open windows while the program is running.
After clicking on the button, it opens another website that has a separate url, which is unique each time it is opened. I need to switch Selenium from interacting with the original website to this new popup within the browser, caused by the original website. The new window shows that it is also controlled by Chromedriver with the bit at the top that says "Chrome is being controlled by automated test software." Additionally, the actual website opened will be the same, just the fine print after the '.com/' is different.
How would I go about doing this? Also, how would I switch back? (If this is even possible)
For example:
driver=webdriver.Chrome(service=s)
driver.get("https://originalwebsite.com/")
driver.find_element(By.XPATH, 'buttons-xpath').click()
# (popup opens up now)
# *switch to popup website here*
driver.find_element(By.XPATH, 'button-on-new-website-xpath').click()
driver.find_element(By.XPATH, 'second-button-on-new-website-xpath').click()
# *popup website closes*
# switch back to original website / window
Thanks!
I have tried to use driver.navigate in a variety of ways but generally have no clue what I am doing. Thanks again!
The comment from ALex Break led to the answer.
All I had to do was:
handles = driver.window_handles
driver.switch_to.window(handles[x])
#handles[x] is the index of the list handles that has the handle I want to switch
#to stored in it
selenium/chromedriver
When clicking a button, a new tab is opened when I do it through a GUI browser.
Python Selenium seems to have no problem clicking the button, as it gives me no errors. The errors come in the next step, when I need to find an element in the clicked page. I had selenium take a screenshot and it still shows the first page.
Presumably it clicked the button, created a new tab, and didn't switch over?
How do I switch to the new tab, or even verify the new tab exists in the first place?
Thank you!
When you open a browser with selenium, it stores a handle for each tab/window it is controlling in a list called window_handles, for example:
from selenium import webdriver
driver = webdriver.Firefox()
print(driver.window_handles)
...should give you something like ['6b7af9bb-f299-462e-a79a-2b8fda63f388']
When you open a new tab, a new handle for that window/tab should be added to that list. To then switch to the tab you want, use driver.switch_to.window(), for example (continuing above example):
driver.switch_to.window(driver.window_handles[1])
Note: you could also use driver.switch_to_window, but this is deprecated in favor of the above example.
Also, just a tip for debugging, it can be helpful to use the python repl so you can follow what the browser is doing in real time.
I'm using Selenium with Python API and Chrome to do the followings:
Collect the Performance Log;
Click some <a, target='_blank'> tags to get into other pages;
For example, I click a href in Page 'A', which commands the browser opens a new window to load another URL 'B'.
But when I use driver.get_log('performance') to get the performance log, I can only get the log of Page 'A'. Even though I switch to the window of 'B' as soon as I click the href, some log entries of the page 'B' will be lost.
So how can I get the whole performance log of another page without setting the target of <a> to '_top'?
I had the same problem and I think it is because the driver does not immediately switch to a new window.
I switched to page "B" and reloaded this page, then uses get_log and it worked.
I am trying to scrape information off websites like this:
https://www.glassdoor.com/Overview/Working-at-7-Eleven-EI_IE3581.11,19.htm
using python + beautifulsoup + mechanize.
Accessing anything on the main-site is no problem. However, I also need the information that appears in a overlay-window that appears when one clicks on the "Rating Trends" button next to the bar with stars.
This overlay-window can also be accessed directly by using the url:
https://www.glassdoor.com/Reviews/7-Eleven-Reviews-E3581.htm#trends-overallRating
The html associated with this page is a modification of the original site's html.
However, regardless of what element I try to find (via findAll ) on that overlay-window website, beautifulsoup returns zero hits.
How can I fix this? I tried adding a sleep time between accessing the website and reading anything in, to no avail.
Thanks!
If you're using the Chrome browser select the background of that page (without the additional information displayed) and select 'Inspect' from the context menu (for Windows anyway), then the 'Network' tab, so that you can see network traffic. Now click on 'Rating trends'. The entry marked 'xhr' will be https://www.glassdoor.ca/api/employer/3581-rating.htm?locationStr=&jobTitleStr=&filterCurrentEmployee=false&filterEmploymentStatus=REGULAR&filterEmploymentStatus=PART_TIME (I much hope!) and its contents will be the following.
{"employerId":3581,"ratings":[{"hasRating":true,"type":"overallRating","value":2.9},{"hasRating":true,"type":"ceoRating","value":0.54},{"hasRating":true,"type":"bizOutlook","value":0.35},{"hasRating":true,"type":"recommend","value":0.4},{"hasRating":true,"type":"compAndBenefits","value":2.4},{"hasRating":true,"type":"cultureAndValues","value":2.5},{"hasRating":true,"type":"careerOpportunities","value":2.5},{"hasRating":true,"type":"workLife","value":2.4},{"hasRating":true,"type":"seniorManagement","value":2.3}],"week":0,"year":0}
Whether this URL can be altered for use in obtaining information for other employers, I regret, I cannot tell you.
I want to use selenium with Python to open multi-tabs in one browser and scraping the real-time betting odds simultaneously with multi-tabs.
The website home page generate a list of games. However, there is no way to get the link of game unless you find the game element and use click()(the website is ajax heavy), which open the game in the same tab. My solution to open multi-tabs is to get the list of game then manually open new tab with home-page first loaded and then click on the game with different index in the list. However, I find the driver.window_handles array always include only one item, which is the current tab instead of all the tabs I opened manually in the browser.
Can anybody tell me what goes wrong or if you can give a better solution to this issue?
The problem is simplified as the code in following:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
# create a new Firefox session
driver_temp = webdriver.Firefox()
driver_temp.implicitly_wait(30)
driver_temp.get("https://www.google.com")
body = driver_temp.find_element_by_tag_name('body')
# manually open second tab
body.send_keys(Keys.CONTROL + 't')
driver_temp.get("https://www.google.com")
body = driver_temp.find_element_by_tag_name('body')
# manually open third tab
body.send_keys(Keys.CONTROL + 't')
driver_temp.get("https://www.google.com")
body = driver_temp.find_element_by_tag_name('body')
#print the number of window_handles
print len(driver_temp.window_handles)
I have opened 3 tabs, however the len(driver_temp.window_handles) is always 1
Selenium does not provide an API to manipulate browser tabs. You've probably noticed that applying the CTRL/COMMAND+T "hack" to open a new tab.
See more at:
Controlling firefox tabs in selenium
Opening a new tab in the same window session of the browser through selenium web driver command?
Instead, open up new browser windows.
Well, to be fair, it is important to mention that the behavior is quite different in Firefox and in Chrome - if you open new tabs in Chrome, selenium would see each tab as a window with it's own handle and you'll switch between them using switch_to.window() easily.