Pandas Dataframe: Lack of Memory- What's the better way here? - python

f = pd.read_hdf('Sensor_Data.h5','f')
pieces = [f[x: x + 360] for x in xrange(504649)]
df = pd.concat(pieces)
Morning all. I have a file with 500,000+ rows of data. I want to take 360 row slices from this, and move it down by 1 row each time. (So I will end up with a LOT of data. )
As expected, I tried the above code and got a memory error. I'm assuming there's a better way of doing this?
EDIT: To add some context, this is a .h5 file, and I'm using pandas dataframe to try and slice it this way. I'm trying to create an array of data to feed into a deep neural network using caffenet, though the format it will be in at this point will be unclear...
The code works for small amounts of data. Just not for larger ones. To be clearer of what I'm trying to do:import pandas as pd
df = pd.DataFrame(np.random.randn(10,6)); df
[displays a 6 x 10 table of random numbers]
Now:
pieces = [df[x: x + 4] for x in xrange(7)]
f = pd.concat(pieces)
f
Diplays a new table similar to the previous one, but expanded. It now has rows 0,1,2,3,1,2,3,4,2,3,4,5,3,4,5,6...
Now "pieces" is not a dataframe object itself, but a 'list' for some reason. Is there also a simple way to turn all of these separate datasets (0,1,2,3),(1,2,3,4) and so on, into dataframe object themselves? (Instead of concatenating them together into one dataframe?
I hope this makes sense.

Consider using h5py. From the website: "For example, you can slice into multi-terabyte datasets stored on disk, as if they were real NumPy arrays".

So you have a couple of questions there. First the easiest: pieces is a list because you've created it using a list comprehension, it should be a list of dataframe objects. If you want to use them as separate data frame objects you could just index into the list (i.e. pieces[0] etc).
But you still have this problem that you are trying to create a huge data frame. Without seeing the rest of how you would use the code I'd suggest not create half a million slices of your df but instead looping over you original data frame and calling whatever function you need on a single slice of the data frame:
for x in xrange(504649):
result = my_func(df[x:x+360])
that way each slice is released after its used. And hopefully the result is much smaller than the frame.
You could also similarly as above write all our slices to separate cvs files and read them in as you need.

Related

Understanding a complex one line code - Big Mart Sales Data Set Analysis

I have been trying to learn to analyze Big Mart Sales Data Set from this website. I am unable to decode a line of code which is little bit complex. I tried to understand demystify it but I wasn't able to. Kindly help me understand this line at
In [26]
df['Item_Visibility_MeanRatio'] = df.apply(lambda x: x['Item_Visibility']/visibility_item_avg['Item_Visibility'][visibility_item_avg.index == x['Item_Identifier']][0],axis=1).astype(float)
Thankyou very much in advance. Happy coding
df['Item_Visibility_MeanRatio']
This is the new column name
= df.apply(lambda x:
applying a function to the dataframe
x['Item_Visibility']
take the Item_Visibility column from the original dataframe
/visibility_item_avg['Item_Visibility'][visibility_item_avg.index == x['Item_Identifier']][0]
divide where the Item_Visibility column in the new pivot table where the Item_Identifier is equal to the Item_Identifier in the original dataframe
,axis=1)
apply along the columns (horizontally)
.astype(float)
convert to float type
Also, it looks like .apply is used a lot on the link you attached. It should be noted that apply is generally the slow way to do things, and there are usually alternatives to avoid using apply.
Lets go thorough it step by step:
df['Item_Visibility_MeanRatio']
This part is creating a column in the data frame and its name is Item_Visibility_MeanRatio.
df.apply(lambda...)
Apply a function along an axis of the Data frame.
x['Item_Visibility']
It is getting the data from Item_Visibility column in the data frame.
visibility_item_avg['Item_Visibility'][visibility_item_avg.index == x['Item_Identifier']][0]
This part finds the indexes that visibility_item_avg index is equal to df['Item_Identifier'].This will lead to a list. Then it will get the elements in visibility_item_avg['Item_Visibility'] that its index is equal to what was found in the previous part. [0] at the end is to find the first element of the outcome array.
axis=1
1 : apply function to each row.
astype(float)
This is for changing the value types to float.
To make the code easy to grab, you can always split it to separate parts and digest it little by little.
To make the code faster you can do Vectorization instead of applying lambda.
Refer to the link here.

Save Pandas dataframe with numeric column as text in Excel

I am trying to export a Pandas dataframe to Excel where all columns are of text format. By default, the pandas.to_excel() function lets Excel decide the data type. Exporting a column with [1,2,'w'] results in the cells containing 1 and 2 to be numeric, and the cell containing 'w' to be text. I'd like all rows in the column to be text (i.e. ['1','2','w']).
I was able to solve the problem by assigning the column I need to be text using the .astype(str). However, if the data is large, I am concerned that I will run into performance issues. If I understand correctly, df[col] = df[col].astype(str) makes a copy of the data, which is not efficient.
import pandas as pd
df = pd.DataFrame({'a':[1,2,'w'], 'b':['x','y','z']})
df['a'] = df['a'].astype(str)
df.to_excel(r'c:\tmp\test.xlsx')
Is there a more efficient way to do this?
I searched SO several times and didn't see anything on this. Forgive me if this has been answered before. This is my first post, and I'm really happy to participate in this cool forum.
Edit: Thanks to the comments I've received, I see that Converting a series of ints to strings - Why is apply much faster than astype? gives me other options to astype(str). This is really useful. I also wanted to know if astype(str) was inefficient because it made a copy of the data, which I now see that it does not.
I don't think that you'll not have performance issues with that approach since data is not copied but replaced. You may also convert the whole dataframe into string type using
df = df.astype(str)

Get subset of rows where any column contains a particular value

I have a very large data file (foo.sas7bdat) that I would like to filter rows from without loading the whole data file into memory. For example, I can print the first 20 rows of the dataset without loading the entire file into memory by doing the following:
import pandas
import itertools
with pandas.read_sas('foo.sas7bdat') as f:
for row in itertools.islice(f,20):
print(row)
However, I am unclear on how to only print (or preferably place in a new file) only rows that have any column that contain the number 123.1. How can I do this?
Pandas has the ability to pull dataframes one chunk at a time. Following the trail of read_sas() documentation to "chunksize" I came across this:
http://pandas.pydata.org/pandas-docs/stable/io.html#iterating-through-files-chunk-by-chunk
for chunk in pd.read_sas('foo.sas7bdat', interator=True, chunksize=100000):
print(chunk)
This would get chunks of 100,000 lines.
As for the other problem you would need a query. However I don't know the constraints of the problem. If you make a Dataframe with all the columns then you still might overflow your memory space so an efficient way would be to collect the indexes and put those in a set, then sort those and use .iloc to get those entries if you wanted to put those into a Dataframe.
You may need to use tools that take this into account. Dask is a good alternative for use on clusters.

HDFStore get column names

I have some problems with pandas' HDFStore being far to slow and unfortunately I'm unable to put together a satisfying solution from other questions here.
Situation
I have a big DataFrame, containing mostly floats and sometimes integer columns which goes through multiple processing steps (renaming, removing bad entries, aggregating by 30min). Each row has a timestamp associated to it. I would like to save some middle steps to a HDF file, so that the user can do a single step iteratively without starting from scratch each time.
Additionally the user should be able to plot certain column from these saves in order to select bad data. Therefore I would like to retrieve only the column names without reading the data in the HDFStore.
Concretely the user should get a list of all columns of all dataframes stored in the HDF then they should select which columns they would like to see whereafter I use matplotlib to present them the corresponding data.
Data
shape == (5730000, 339) does not seem large at all, that's why I'm confused... (Might get far more rows over time, columns should stay fixed)
In the first step I append iteratively rows and columns (that runs okay), but once that's done I always process the entire DataFrame at once, only grouping or removing data.
My approach
I do all manipulations in memory since pandas seems to be rather fast and I/O is slower (HDF is on different physical server, I think)
I use datetime index and automatically selected float or integer columns
I save the steps with hdf.put('/name', df, format='fixed') since hdf.put('/name'.format(grp), df, format='table', data_columns=True) seemed to be far too slow.
I use e.g. df.groupby(df.index).first() and df.groupby(pd.Grouper(freq='30Min')).agg(agg_dict) to process the data, where agg_dict is a dictonary with one function per column. This is incredibly slow as well.
For plotting, I have to read-in the entire dataframe and then get the columns: hdfstore.get('/name').columns
Question
How can I retrieve all columns without reading any data from the HDFStore?
What would be the most efficient way of storing my data? Is HDF the right option? Table or fixed?
Does it matter in term of efficiency if the index is a datetime index? Does there exists a more efficient format in general (e.g. all columns the same, fixed dtype?)
Is there a faster way to aggregate instead of groupby (df.groupby(pd.Grouper(freq='30Min')).agg(agg_dict))
similar questions
How to access single columns using .select
I see that I can use this to retrieve only certain columns but only after I know the column names, I think.
Thank you for any advice!
You may simply load 0 rows of the DataFrame by specifying same start and stop attributes. And leave all internal index/column processing for pandas itself:
idx = pd.MultiIndex.from_product([('A', 'B'), range(2)], names=('Alpha', 'Int'))
df = pd.DataFrame(np.random.randn(len(idx), 3), index=idx, columns=('I', 'II', 'III'))
df
>>> I II III
>>> Alpha Int
>>> A 0 -0.472412 0.436486 0.354592
>>> 1 -0.095776 -0.598585 -0.847514
>>> B 0 0.107897 1.236039 -0.196927
>>> 1 -0.154014 0.821511 0.092220
Following works both for fixed an table formats:
with pd.HDFStore('test.h5') as store:
store.put('df', df, format='f')
meta = store.select('df', start=1, stop=1)
meta
meta.index
meta.columns
>>> I II III
>>> Alpha Int
>>>
>>> MultiIndex(levels=[[], []],
>>> codes=[[], []],
>>> names=['Alpha', 'Int'])
>>>
>>> Index(['I', 'II', 'III'], dtype='object')
As for others question:
As long as your data is mostly homogeneous (almost float columns as you mentioned) and you are able to store it in single file without need to distribute data across machines - HDF is the first thing to try.
If you need to append/delete/query data - you must use table format. If you only need to write once and read many - fixed will improve performance.
As for datetime index, i think here we may use same idea as in 1 clause. If u are able to convert all data into single type it should increase your performance.
Nothing else that proposed in comment to your question comes to mind.
For a HDFStore hdf and a key (from hdf.keys()) you can get the column names with:
# Table stored with hdf.put(..., format='table')
columns = hdf.get_node('{}/table'.format(key)).description._v_names
# Table stored with hdf.put(..., format='fixed')
columns = list(hdf.get_node('{}/axis0'.format(key)).read().astype(str))
note that hdf.get(key).columns works as well, but it reads all the data into memory, while the approach above only reads the column names.
Full working example:
#!/usr/bin/env python
import pandas as pd
data = pd.DataFrame({'a': [1,1,1,2,3,4,5], 'b': [2,3,4,1,3,2,1]})
with pd.HDFStore(path='store.h5', mode='a') as hdf:
hdf.put('/DATA/fixed_store', data, format='fixed')
hdf.put('/DATA/table_store', data, format='table', data_columns=True)
for key in hdf.keys():
try:
# column names of table store
print(hdf.get_node('{}/table'.format(key)).description._v_names)
except AttributeError:
try:
# column names of fixed store
print(list(hdf.get_node('{}/axis0'.format(key)).read().astype(str)))
except AttributeError:
# e.g. a dataset created by h5py instead of pandas.
print('unknown node in HDF.')
Columns without reading any data:
store.get_storer('df').ncols # substitute 'df' with your key
# you can also access nrows and other useful fields
From the docs (fixed format, table format): (important points in bold)
[fixed] These types of stores are not appendable once written (though you can simply remove them and rewrite). Nor are they queryable; they must be retrieved in their entirety. They also do not support dataframes with non-unique column names. The fixed format stores offer very fast writing and slightly faster reading than table stores.
[table] Conceptually a table is shaped very much like a DataFrame, with rows and columns. A table may be appended to in the same or other sessions. In addition, delete and query type operations are supported.
You may try to use epochms (or epochns) (milliseconds or nanoseconds since epoch) in place of datetimes. This way, you are just dealing with integer indices.
You may have a look at this answer if what you need is grouping by on large data.
An advice: if you have 4 questions to ask, it may be better to ask 4 separate questions on SO. This way, you'll get a higher number of (higher quality) answers, since each one is easier to tackle. And each will deal with a specific topic, making it easier to search for people that are looking for specific answers.

Is .loc the best way to build a pandas DataFrame?

I have a fairly large csv file (700mb) which is assembled as follows:
qCode Date Value
A_EVENTS 11/17/2014 202901
A_EVENTS 11/4/2014 801
A_EVENTS 11/3/2014 2.02E+14
A_EVENTS 10/17/2014 203901
etc.
I am parsing this file to get specific values, and then using DF.loc to populate a pre-existing DataFrame, i.e. the code:
for line in fileParse:
code=line[0]
for point in fields:
if(point==code[code.find('_')+1:len(code)]):
date=line[1]
year,quarter=quarter_map(date)
value=float(line[2])
pos=line[0].find('_')
ticker=line[0][0:pos]
i=ticker+str(int(float(year)))+str(int(float(quarter)))
df.loc[i,point]=value
else:
pass
the question I have is .loc the most efficient way to add values to a existing DataFrame? As this operation seems to take over 10 hours...
fyi fields are the col that are in the DF (values i'm interested in) and the index (i) is a string...
thanks
No, you should never build a dataframe row-by-row. Each time you do this the entire dataframe has to be copied (it's not extended inplace) so you are using n + (n - 1) + (n - 2) + ... + 1, O(n^2), memory (which has to be garbage collected)... which is terrible, hence it's taking hours!
You want to use read_csv, and you have a few options:
read in the entire file in one go (this should be fine with 700mb even with just a few gig of ram).
pd.read_csv('your_file.csv')
read in the csv in chunks and then glue them together (in memory)... tbh I don't think this will actually use less memory than the above, but is often useful if you are doing some munging at this step.
pd.concat(pd.read_csv('foo.csv', chunksize=100000))  # not sure what optimum value is for chunksize
read the csv in chunks and save them into pytables (rather than in memory), if you have more data than memory (and you've already bought more memory) then use pytables/hdf5!
store = pd.HDFStore('store.h5')
for df in pd.read_csv('foo.csv', chunksize=100000):
store.append('df', df)
If I understand correctly, I think it would be much faster to:
Import the whole csv into a dataframe using pandas.read_csv.
Select the rows of interest from the dataframe.
Append the rows to your other dataframe using df.append(other_df).
If you provide more information about what criteria you are using in step 2 I can provide code there as well.
A couple of options that come to mind
1) Parse the file as you are currently doing, but build a dict intend of appending to your dataframe. After you're done with that convert that dict to a Dataframe and then use concat() to combine it with the existing Dataframe
2) Bring that csv into pandas using read_csv() and then filter/parse on what you want then do a concat() with the existing dataframe

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