Develop Reference

How do I extract the entire sentence from a job description which consists the number of years of experience in it?

I've been working on a job description parser and I have been trying to extract the entire sentence which consists of the number of years of experience required.
I have tried to use regex which provides me the number of years but not the entire sentence.
def extract_years(self,resume_text):
resume_text = str(resume_text.split('.'))
exp=[]
rx = re.compile(r"(\d+(?:-\d+)?\+?)\s*(years?)",re.I)
for word in resume_text:
exp_temp = rx.search(resume_text)
if exp_temp:
exp.append(exp_temp[0])
exp = list(set(exp))
return exp
Output:
['5-7 years']
Desired Output:
['5-7 years of experience in journalism, communications, or content creation preferred']

Try: (\d+(?:-\d+)?+?)\s*(years?).*
Though I'm somewhat new to Regex, I believe you can get what you desire using a combination of ".*" to end of your match terms and possibly the beginning if "5-7 years" comes after some characters like "needs 5-7 years of experience".
just adding the group ".*" at the end would mean to add any combination of characters, 0 or more after your initial match stopping at a line break, to match the entire sentence.
Hope this helps.

Regex not specific enough

So I wrote a program for my Kindle e-reader that searches my highlights and deletes repetitive text (it's usually information about the book title, author, page number, etc.). I thought it was functional but sometimes there would random be periods (.) on certain lines of the output. At first I thought the program was just buggy but then I realized that the regex I'm using to match the books title and author was also matching any sentence that ended in brackets.
This is the code for the regex that I'm using to detect the books title and author
titleRegex = re.compile('(.+)\((.+)\)')
Example
Desired book title and author match: Book title (Author name)
What would also get matched: *I like apples because they are green (they are sometimes red as well). *
In this case it would delete everything and leave just the period at the end of the sentence. This is obviously not ideal because it deletes the text I highlighted
Here is the unformatted text file that goes into my program
The program works by finding all of the matches for the regexes I wrote, looping through those matches and one by one replacing them with empty strings.
Would there be any ways to make my title regex more specific so that it only picks up author titles and not full sentences that end in brackets? If not, what steps would I have to take to restructure this program?
I've attached my code to the bottom of this post. I would greatly appreciate any help as I'm a total coding newbie. Thanks :)
import re
titleRegex = re.compile('(.+)\((.+)\)')
titleRegex2 = re.compile(r'\ufeff (.+)\((.+)\)')
infoRegex = re.compile(r'(.) ([a-zA-Z]+) (Highlight|Bookmark|Note) ([a-zA-Z]+) ([a-zA-Z]+) ([0-9]+) (\|)')
locationRegex = re.compile(r' Location (\d+)(-\d+)? (\|)')
dateRegex = re.compile(r'([a-zA-Z]+) ([a-zA-Z]+) ([a-zA-Z]+), ([a-zA-Z]+) ([0-9]+), ([0-9]+)')
timeRegex = re.compile(r'([0-9]+):([0-9]+):([0-9]+) (AM|PM)')
newlineRegex = re.compile(r'\n')
sepRegex = re.compile('==========')
regexList = [titleRegex, titleRegex2, infoRegex, locationRegex, dateRegex, timeRegex, sepRegex, newlineRegex]
string = open("/Users/devinnagami/myclippings.txt").read()
for x in range(len(regexList)):
newString = re.sub(regexList[x], ' ', string)
string = newString
finalText = newString.split(' ')
with open('booknotes.txt', 'w') as f:
for item in finalText:
f.write('%s\n' % item)

There isn't enough information to tell if "Book title (Book Author)" is different than something like "I like Books (Good Ones)" without context. Thankfully, the text you showed has plenty of context. Instead of creating several different regular expressions, you can combine them into one expression to encode that context.
For instance:
quoteInfoRegex = re.compile(
r"^=+\n(?P<title>.*?) \((?P<author>.*?)\)\n" +
r"- Your Highlight on page (?P<page>[\d]+) \| Location (?P<location>[\d-]+) \| Added on (?P<added>.*?)\n" +
r"\n" +
r"(?P<quote>.*?)\n", flags=re.MULTILINE)
for m in quoteInfoRegex.finditer(data):
print(m.groupdict())
This will pull out each line of the text, and parse it, knowing that the book title is the first line after the equals, and the quote itself is below that.

How to find required word in novel in python?

I have a text and I have got a task in python with reading module:
Find the names of people who are referred to as Mr. XXX. Save the result in a dictionary with the name as key and number of times it is used as value. For example:
If Mr. Churchill is in the novel, then include {'Churchill' : 2}
If Mr. Frank Churchill is in the novel, then include {'Frank Churchill' : 4}
The file is .txt and it contains around 10-15 paragraphs.
Do you have ideas about how can it be improved? (It gives me error after some words, I guess error happens due to the reason that one of the Mr. is at the end of the line.)
orig_text= open('emma.txt', encoding = 'UTF-8')
lines= orig_text.readlines()[32:16267]
counts = dict()
for line in lines:
wordsdirty = line.split()
try:
print (wordsdirty[wordsdirty.index('Mr.') + 1])
except ValueError:
continue

Try this:
text = "When did Mr. Churchill told Mr. James Brown about the fish"
m = [x[0] for x in re.findall('(Mr\.( [A-Z][a-z]*)+)', text)]
You get:
['Mr. Churchill', 'Mr. James Brown']
To solve the line issue simply read the entire file:
text = file.read()
Then, to count the occurrences, simply run:
Counter(m)
Finally, if you'd like to drop 'Mr. ' from all your dictionary entries, use x[0][4:] instead of x[0].

This can be easily done using regex and capturing group.
Take a look here for reference, in this scenario you might want to do something like
# retrieve a list of strings that match your regex
matches = re.findall("Mr\. ([a-zA-Z]+)", your_entire_file) # not sure about the regex
# then create a dictionary and count the occurrences of each match
# if you are allowed to use modules, this can be done using Counter
Counter(matches)
To access the entire file like that, you might want to map it to memory, take a look at this question

Create a list of alphabetically sorted UNIQUE words and display the first N words in python

I am new to Python, apologize for a simple question. My task is the following:
Create a list of alphabetically sorted unique words and display the first 5 words
I have text variable, which contains a lot of text information
I did
test = text.split()
sorted(test)
As a result, I receive a list, which starts from symbols like $ and numbers.
How to get to words and print N number of them.

I'm assuming by "word", you mean strings that consist of only alphabetical characters. In such a case, you can use .filter to first get rid of the unwanted strings, turn it into a set, sort it and then print your stuff.
text = "$1523-the king of the 521236 mountain rests atop the king mountain's peak $#"
# Extract only the words that consist of alphabets
words = filter(lambda x: x.isalpha(), text.split(' '))
# Print the first 5 words
sorted(set(words))[:5]
Output-
['atop', 'king', 'mountain', 'of', 'peak']
But the problem with this is that it will still ignore words like mountain's, because of that pesky '. A regex solution might actually be far better in such a case-
For now, we'll be going for this regex - ^[A-Za-z']+$, which means the string must only contain alphabets and ', you may add more to this regex according to what you deem as "words". Read more on regexes here.
We'll be using re.match instead of .isalpha this time.
WORD_PATTERN = re.compile(r"^[A-Za-z']+$")
text = "$1523-the king of the 521236 mountain rests atop the king mountain's peak $#"
# Extract only the words that consist of alphabets
words = filter(lambda x: bool(WORD_PATTERN.match(x)), text.split(' '))
# Print the first 5 words
sorted(set(words))[:5]
Output-
['atop', 'king', 'mountain', "mountain's", 'of']
Keep in mind however, this gets tricky when you have a string like hi! What's your name?. hi!, name? are all words except they are not fully alphabetic. The trick to this is to split them in such a way that you get hi instead of hi!, name instead of name? in the first place.
Unfortunately, a true word split is far outside the scope of this question. I suggest taking a look at this question

I am newbie here, apologies for mistakes. Thank you.
test = '''The coronavirus outbreak has hit hard the cattle farmers in Pabna and Sirajganj as they are now getting hardly any customer for the animals they prepared for the last year targeting the Eid-ul-Azha this year.
Normally, cattle traders flock in large numbers to the belt -- one of the biggest cattle producing areas of the country -- one month ahead of the festival, when Muslims slaughter animals as part of their efforts to honour Prophet Ibrahim's spirit of sacrifice.
But the scene is different this year.'''
test = test.lower().split()
test2 = sorted([j for j in test if j.isalpha()])
print(test2[:5])

You can slice the sorted return list until the 5 position
sorted(test)[:5]
or if looking only for words
sorted([i for i in test if i.isalpha()])[:5]
or by regex
sorted([i for i in test if re.search(r"[a-zA-Z]")])
by using the slice of a list you will be able to get all list elements until a specific index in this case 5.

Python parsing

I'm trying to parse the title tag in an RSS 2.0 feed into three different variables for each entry in that feed. Using ElementTree I've already parsed the RSS so that I can print each title [minus the trailing )] with the code below:
feed = getfeed("http://www.tourfilter.com/dallas/rss/by_concert_date")
for item in feed:
print repr(item.title[0:-1])
I include that because, as you can see, the item.title is a repr() data type, which I don't know much about.
A particular repr(item.title[0:-1]) printed in the interactive window looks like this:
'randy travis (Billy Bobs 3/21'
'Michael Schenker Group (House of Blues Dallas 3/26'
The user selects a band and I hope to, after parsing each item.title into 3 variables (one each for band, venue, and date... or possibly an array or I don't know...) select only those related to the band selected. Then they are sent to Google for geocoding, but that's another story.
I've seen some examples of regex and I'm reading about them, but it seems very complicated. Is it? I thought maybe someone here would have some insight as to exactly how to do this in an intelligent way. Should I use the re module? Does it matter that the output is currently is repr()s? Is there a better way? I was thinking I'd use a loop like (and this is my pseudoPython, just kind of notes I'm writing):
list = bandRaw,venue,date,latLong
for item in feed:
parse item.title for bandRaw, venue, date
if bandRaw == str(band)
send venue name + ", Dallas, TX" to google for geocoding
return lat,long
list = list + return character + bandRaw + "," + venue + "," + date + "," + lat + "," + long
else
In the end, I need to have the chosen entries in a .csv (comma-delimited) file looking like this:
band,venue,date,lat,long
randy travis,Billy Bobs,3/21,1234.5678,1234.5678
Michael Schenker Group,House of Blues Dallas,3/26,4321.8765,4321.8765
I hope this isn't too much to ask. I'll be looking into it on my own, just thought I should post here to make sure it got answered.
So, the question is, how do I best parse each repr(item.title[0:-1]) in the feed into the 3 separate values that I can then concatenate into a .csv file?

Don't let regex scare you off... it's well worth learning.
Given the examples above, you might try putting the trailing parenthesis back in, and then using this pattern:
import re
pat = re.compile('([\w\s]+)\(([\w\s]+)(\d+/\d+)\)')
info = pat.match(s)
print info.groups()
('Michael Schenker Group ', 'House of Blues Dallas ', '3/26')
To get at each group individual, just call them on the info object:
print info.group(1) # or info.groups()[0]
print '"%s","%s","%s"' % (info.group(1), info.group(2), info.group(3))
"Michael Schenker Group","House of Blues Dallas","3/26"
The hard thing about regex in this case is making sure you know all the known possible characters in the title. If there are non-alpha chars in the 'Michael Schenker Group' part, you'll have to adjust the regex for that part to allow them.
The pattern above breaks down as follows, which is parsed left to right:
([\w\s]+) : Match any word or space characters (the plus symbol indicates that there should be one or more such characters). The parentheses mean that the match will be captured as a group. This is the "Michael Schenker Group " part. If there can be numbers and dashes here, you'll want to modify the pieces between the square brackets, which are the possible characters for the set.
\( : A literal parenthesis. The backslash escapes the parenthesis, since otherwise it counts as a regex command. This is the "(" part of the string.
([\w\s]+) : Same as the one above, but this time matches the "House of Blues Dallas " part. In parentheses so they will be captured as the second group.
(\d+/\d+) : Matches the digits 3 and 26 with a slash in the middle. In parentheses so they will be captured as the third group.
\) : Closing parenthesis for the above.
The python intro to regex is quite good, and you might want to spend an evening going over it http://docs.python.org/library/re.html#module-re. Also, check Dive Into Python, which has a friendly introduction: http://diveintopython3.ep.io/regular-expressions.html.
EDIT: See zacherates below, who has some nice edits. Two heads are better than one!

Regular expressions are a great solution to this problem:
>>> import re
>>> s = 'Michael Schenker Group (House of Blues Dallas 3/26'
>>> re.match(r'(.*) \((.*) (\d+/\d+)', s).groups()
('Michael Schenker Group', 'House of Blues Dallas', '3/26')
As a side note, you might want to look at the Universal Feed Parser for handling the RSS parsing as feeds have a bad habit of being malformed.
Edit
In regards to your comment... The strings occasionally being wrapped in "s rather than 's has to do with the fact that you're using repr. The repr of a string is usually delimited with 's, unless that string contains one or more 's, where instead it uses "s so that the 's don't have to be escaped:
>>> "Hello there"
'Hello there'
>>> "it's not its"
"it's not its"
Notice the different quote styles.

Regarding the repr(item.title[0:-1]) part, not sure where you got that from but I'm pretty sure you can simply use item.title. All you're doing is removing the last char from the string and then calling repr() on it, which does nothing.
Your code should look something like this:
import geocoders # from GeoPy
us = geocoders.GeocoderDotUS()
import feedparser # from www.feedparser.org
feedurl = "http://www.tourfilter.com/dallas/rss/by_concert_date"
feed = feedparser.parse(feedurl)
lines = []
for entry in feed.entries:
m = re.search(r'(.*) \((.*) (\d+/\d+)\)', entry.title)
if m:
bandRaw, venue, date = m.groups()
if band == bandRaw:
place, (lat, lng) = us.geocode(venue + ", Dallas, TX")
lines.append(",".join([band, venue, date, lat, lng]))
result = "\n".join(lines)
EDIT: replaced list with lines as the var name. list is a builtin and should not be used as a variable name. Sorry.