Develop Reference

How do I use the Python keyboard module to detect a key press?

I am working on a self challenge of making a cash register in Python, and I'm looking to use the keyboard module for inputting values instead of typing them into the console. However, I think the keyboard module command I'm using to detect key presses is not becoming false after pressing the key, meaning the number I just typed is being inserted again and again. What is the proper command to use? Here is the code to test out the input before incorporating it into my main code:
import keyboard
running =True
price=""
while running:
if keyboard.is_pressed("1"):
price+="1"
if keyboard.is_pressed("2"):
price+="2"
if keyboard.is_pressed("3"):
price+="3"
if keyboard.is_pressed("4"):
price+="4"
if keyboard.is_pressed("5"):
price+="5"
if keyboard.is_pressed("6"):
price+="6"
if keyboard.is_pressed("7"):
price+="7"
if keyboard.is_pressed("8"):
price+="8"
if keyboard.is_pressed("9"):
price+="9"
if keyboard.is_pressed("0"):
price+="0"
if keyboard.is_pressed("Enter"):
running=False
subtotal=int(price)
print(subtotal)
subtotal=float(subtotal)/100
print("Subtotal: {}".format(subtotal))

There are usually many different ways to code something. Some are better than others. In a problem that is based on keyboard input, like your cash register/adding machine project, I would go with an event-driven approach. Your sample code represents a polling approach. It can work, but it may not be as efficient.
I've never used the keyboard module before, but I did some quick research and came up with the below program, which may give you guidance. Every time a key in the keyboard is pressed, the key_pressed() routine is triggered. Digits are stored, and the Enter key causes an addition and then clearing of the stored digits.
import keyboard
sin = ""
val = 0.0
def key_pressed(e, *a, **kw):
global sin, val
# print(e, a, kw)
k = e.name
if k in "0123456789":
sin += k
elif k == 'enter':
val += float(sin)/100.0
print("Entered: " + sin)
print('Value: ', val)
sin = ""
keyboard.on_press(key_pressed)

I took a look at the documentation located here https://github.com/boppreh/keyboard.
I ran and tested this code on python 3.9
import keyboard
from functools import partial
num = ""
def add(i):
global num
num += str(i)
print(num, end='\r')
for i in range(10): # numbers 0...9
keyboard.add_hotkey(str(i), partial(add, i)) # add hotkeys
keyboard.wait('enter') # block process until "ENTER" is pressed
print("\nNum:{}".format(num))
You could additionally unhook the hotkeys by calling keyboard.unhook_all_hotkeys() after grabbing the number. I imagine you could wait on "+" and "-" if you wanted to implement addition and subtraction of numbers.

I like the last example from this snippet from the Github docs that I ended up using:
import keyboard
# Don't do this! This will call `print('space')` immediately then fail when the key is actually pressed.
#keyboard.add_hotkey('space', print('space was pressed'))
# Do this instead
keyboard.add_hotkey('space', lambda: print('space was pressed'))
# or this
def on_space():
print('space was pressed')
keyboard.add_hotkey('space', on_space)
# or this
while True:
# Wait for the next event.
event = keyboard.read_event()
if event.event_type == keyboard.KEY_DOWN and event.name == 'space':
print('space was pressed')

Change value while program is runing

I need a program on raspberry pi, in which I can change the value of a variable delay while the program is running and is not interrupted by any input(). I came up with only one solution: read a value from a text file and change it using another program. But my solution doesn't work very well... When I overwrite a value in a text file, sometimes it happens that the program can't convert it to a float... sometimes it works well and sometimes it prints this error:
ValueError: could not convert string to float: ''
But the value in the text file seems to be fine...
So, this is main program:
def pause():
file = open('delay.txt', 'r')
pause = file.readline()
return pause
delay = float(pause())
while True:
GPIO.output(STEP, GPIO.HIGH)
delay = float(pause())
sleep(delay)
GPIO.output(STEP, GPIO.LOW)
delay = float(pause())
sleep(delay)
And this is the program, which is changing value in the text file:
while True:
rpm = float(input('RPM: '))
delay = (1/(rpm*60))/800
file = open('delay.txt', 'w')
file.write(str(delay))
file.close()
I really can't move with this... I'll be grateful for any advice and help in solving it.
You don't have to stick to my idea with a text file, maybe there is a better solution, but I couldn't think of anything better.

I'd suggest you use threading for this. I've made a small code example for you to get you started:
import threading
from time import sleep
import logging
logging.basicConfig(level=logging.DEBUG, filename="thread_output.txt", format='%(asctime)s %(levelname)-8s [%(filename)s:%(lineno)d] %(message)s')
running = True
delay = 1
def worker(delay, running):
while running():
logging.debug(1)
sleep(delay())
logging.debug(0)
sleep(delay())
x = threading.Thread(target=worker, args=(lambda: delay, lambda: running))
x.start()
while running:
code = input("""
Make a choice:
1) Set delay
2) quit
""")
code = int(code)
if code == 1:
try:
val = input("Give up the desired delay between 0 and 10 seconds:")
val = int(val)
assert val >= 0 and val <= 10
delay = val
except ValueError:
print("Invalid input! Returning to home menu")
continue
elif code == 2:
running = False
else:
print("invalid option! Returning to home menu")
continue
print("quiting...")
x.join()
The part that helps you here is the fact that you pass the value of delay (and in the example also of running) as a lambda function. This means that every time the value is used, the value refetched. If you then were to change the value of the variable, it would get passed on :)
Hit me up if you have more questions!

how do i interup input in processing in python

I try to make a simple game, give a sum random number and input to answer it, I try to limit the time for input, but I can stop the input processing when timeout.
score=0
from threading import Timer
while score<=3:
import random
a=random.randint(0,100)
b=random.randint(0,100)
sum=a+b
d=str(sum)
while True:
print(a,"+",b,"=")
timeout = 3
t = Timer(timeout, print, ['Sorry, times up'])
t.start()
prompt = "you have %d s to input your answer\n" % timeout
c = input(prompt)
t.cancel()
#i want to stop input c and make other code like 'do you want to play again'
if c.isdigit():
break
else:
print('invalid input')
continue
result=c
if result==d:
score=score+1
print('your score',score)
else:
score=score-1
print('your score',score)
else:
print('you win')

Similar question has been answered before here.
I have tested it before and the following codes work in my Ubuntu. I'm not sure if this works in Windows too.
import sys
from select import select
timeout = 5
print "What is your name?"
# Assignment to three different variables based on select() paramenters
# rlist: wait until ready for reading
# wlist: wait until ready for writing
# xlist: wait for an "exceptional condition"
rlist, _, _ = select([sys.stdin], [], [], timeout)
if rlist:
s = sys.stdin.readline()
print "Your name is: %s" %(s)
else:
print "Timeout!! Try again."
Hope this helps.

This works also for me (Debian)
import sys, termios, signal
from _thread import interrupt_main
while True:
timeout = 3
signal.signal(signal.SIGALRM, lambda x,y: interrupt_main())
signal.alarm(3)
try:
c = input("Number? ")
except:
termios.tcflush(sys.stdin, termios.TCIOFLUSH)
answer = input('\nContinue? ')
if (len(answer) == 0) or (answer.lower()[0] != 'y'):
break
signal.alarm(0)
If you are using Windows you could try using interrupt_main as handler for Timer
t = Timer(timeout, interrupt_main)
This approach does not fully work for me. In my linux box the signal handler is able to interrupt the input() call but the timer handler, however, not. Only if you press Enter, the program flow follows to the "Continue" question

math quiz with a time limit (simultaneous functions) - advanced python

So I would like to run two programs, a timer and a math question. But always the input seems to be stopping the timer funtion or not even run at all. Is there any ways for it to get around that?
I'll keep the example simple.
import time
start_time = time.time()
timer=0
correct = answer
answer = input("9 + 9 = ")
#technically a math question here
#so here until i enter the input prevents computer reading the code
while True:
timer = time.time() - start_time
if timer > 3:
#3 seconds is the limit
print('Wrong!')
quit()
So recap i would like the player to answer the question in less than 3 seconds.
after the 3 seconds the game will print wrong and exit
if the player answer within three seconds the timer would be 'terminated' or stopped before it triggers 'wrong' and quit
hope you understand, and really appreciate your help

On Windows you can use the msvcrt module's kbhit and getch functions (I modernized this code example a little bit):
import sys
import time
import msvcrt
def read_input(caption, timeout=5):
start_time = time.time()
print(caption)
inpt = ''
while True:
if msvcrt.kbhit(): # Check if a key press is waiting.
# Check which key was pressed and turn it into a unicode string.
char = msvcrt.getche().decode(encoding='utf-8')
# If enter was pressed, return the inpt.
if char in ('\n', '\r'): # enter key
return inpt
# If another key was pressed, concatenate with previous chars.
elif char >= ' ': # Keys greater or equal to space key.
inpt += char
# If time is up, return the inpt.
if time.time()-start_time > timeout:
print('\nTime is up.')
return inpt
# and some examples of usage
ans = read_input('Please type a name', timeout=4)
print('The name is {}'.format(ans))
ans = read_input('Please enter a number', timeout=3)
print('The number is {}'.format(ans))
I'm not sure what exactly you have to do on other operating systems (research termios, tty, select).
Another possibility would be the curses module which has a getch function as well and you can set it to nodelay(1) (non-blocking), but for Windows you first have to download curses from Christopher Gohlke's website.
import time
import curses
def main(stdscr):
curses.noecho() # Now curses doesn't display the pressed key anymore.
stdscr.nodelay(1) # Makes the `getch` method non-blocking.
stdscr.scrollok(True) # When bottom of screen is reached scroll the window.
# We use `addstr` instead of `print`.
stdscr.addstr('Press "q" to exit...\n')
# Tuples of question and answer.
question_list = [('4 + 5 = ', '9'), ('7 - 4 = ', '3')]
question_index = 0
# Unpack the first question-answer tuple.
question, correct_answer = question_list[question_index]
stdscr.addstr(question) # Display the question.
answer = '' # Here we store the current answer of the user.
# A set of numbers to check if the user has entered a number.
# We have to convert the number strings to ordinals, because
# that's what `getch` returns.
numbers = {ord(str(n)) for n in range(10)}
start_time = time.time() # Start the timer.
while True:
timer = time.time() - start_time
inpt = stdscr.getch() # Here we get the pressed key.
if inpt == ord('q'): # 'q' quits the game.
break
if inpt in numbers:
answer += chr(inpt)
stdscr.addstr(chr(inpt), curses.A_BOLD)
if inpt in (ord('\n'), ord('\r')): # Enter pressed.
if answer == correct_answer:
stdscr.addstr('\nCorrect\n', curses.A_BOLD)
else:
stdscr.addstr('\nWrong\n', curses.A_BOLD)
if timer > 3:
stdscr.addstr('\nToo late. Next question.\n')
if timer > 3 or inpt in (ord('\n'), ord('\r')):
# Time is up or enter was pressed; reset and show next question.
answer = ''
start_time = time.time() # Reset the timer.
question_index += 1
# Keep question index in the correct range.
question_index %= len(question_list)
question, correct_answer = question_list[question_index]
stdscr.addstr(question)
# We use wrapper to start the program.
# It handles exceptions and resets the terminal after the game.
curses.wrapper(main)

Use time.time(), it returns the epoch time (that is, the number of seconds since January 1, 1970 UNIX Time). You can compare it to a start time to get the number of seconds:
start = time.time()
while time.time() - start < 60:
# stuff
You can have a timer pull you out of your code at any point (even if the user is inputting info) with signals but it is a little more complicated. One way is to use the signal library:
import signal
def timeout_handler(signal, frame):
raise Exception('Time is up!')
signal.signal(signal.SIGALRM, timeout_handler)
This defines a function that raises an exception and is called when the timeout occurs. Now you can put your while loop in a try catch block and set the timer:
signal.alarm.timeout(60)
try:
while lives > 0
# stuff
except:
# print score

time out and proceed if no input() provided [duplicate]

in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?

The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.

I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.

The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')

from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!

A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)

under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0

This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")