I try to make a simple game, give a sum random number and input to answer it, I try to limit the time for input, but I can stop the input processing when timeout.
score=0
from threading import Timer
while score<=3:
import random
a=random.randint(0,100)
b=random.randint(0,100)
sum=a+b
d=str(sum)
while True:
print(a,"+",b,"=")
timeout = 3
t = Timer(timeout, print, ['Sorry, times up'])
t.start()
prompt = "you have %d s to input your answer\n" % timeout
c = input(prompt)
t.cancel()
#i want to stop input c and make other code like 'do you want to play again'
if c.isdigit():
break
else:
print('invalid input')
continue
result=c
if result==d:
score=score+1
print('your score',score)
else:
score=score-1
print('your score',score)
else:
print('you win')
Similar question has been answered before here.
I have tested it before and the following codes work in my Ubuntu. I'm not sure if this works in Windows too.
import sys
from select import select
timeout = 5
print "What is your name?"
# Assignment to three different variables based on select() paramenters
# rlist: wait until ready for reading
# wlist: wait until ready for writing
# xlist: wait for an "exceptional condition"
rlist, _, _ = select([sys.stdin], [], [], timeout)
if rlist:
s = sys.stdin.readline()
print "Your name is: %s" %(s)
else:
print "Timeout!! Try again."
Hope this helps.
This works also for me (Debian)
import sys, termios, signal
from _thread import interrupt_main
while True:
timeout = 3
signal.signal(signal.SIGALRM, lambda x,y: interrupt_main())
signal.alarm(3)
try:
c = input("Number? ")
except:
termios.tcflush(sys.stdin, termios.TCIOFLUSH)
answer = input('\nContinue? ')
if (len(answer) == 0) or (answer.lower()[0] != 'y'):
break
signal.alarm(0)
If you are using Windows you could try using interrupt_main as handler for Timer
t = Timer(timeout, interrupt_main)
This approach does not fully work for me. In my linux box the signal handler is able to interrupt the input() call but the timer handler, however, not. Only if you press Enter, the program flow follows to the "Continue" question
Related
in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?
The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.
I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.
The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')
from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!
A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)
under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0
This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")
I tried:
from time import sleep
while sleep(3):
input("Press enter to continue.")
But it doesn't seem to work. I want the program to await user input, but if there's no user input after 10 minutes, continue with the program anyway.
This is with python 3.
Why does the code not work?
time.sleep returns nothing; the value of the time.sleep(..) become None; while loop body is not executed.
How to solve it
If you're on Unix, you can use select.select.
import select
import sys
print('Press enter to continue.', end='', flush=True)
r, w, x = select.select([sys.stdin], [], [], 600)
Otherwise, you should use thread.
Windows specific solution that use msvcrt:
import msvcrt
import time
t0 = time.time()
while time.time() - t0 < 600:
if msvcrt.kbhit():
if msvcrt.getch() == '\r': # not '\n'
break
time.sleep(0.1)
Here is a simple way using an alarm. When the time expires, the lambda function is called, which would raise a ZeroDivisionError.
from signal import signal, alarm, SIGALRM
signal(SIGALRM, lambda x, y: 1/0)
try:
alarm(600)
input("Press enter to continue.")
except ZeroDivisionError:
print("timed out")
Another way to do it is this:
from time import sleep
print("I'm executing")
try:
print("Wake up Ctrl-C!")
sleep(600)
except KeyboardInterrupt:
print("I woke up!")
else:
print("I'm executing again.")
Not the greatest of answers and it definitely feels like an abuse of exceptions, but it works.
I am currently generating a python-script with the fabric framwork that is supposed to collect a backup from a remote server and store it locally on the client running fabric.
Now, since the backup file is >400MB, it takes quite some time to transfer it. And here is where my question bumps in:
Is there any kind of progressbars for the fabric get()-function? Or rather, is it possible to add a progressbar somehow?
Here's a piece of my code:
def collect_backup():
env.warn_only=True
run('uptime')
print "Copying scrips to be run..."
filename, remotepath = _getlatest()
print "Copy complete."
print "Collecting backup..."
localpath = _collect(filename, remotepath)
def _collect(filename, remotepath):
a=remotepath + filename
localpath="/home/bcns/backups/"
####Here's the get() I was talking about
get(a, localpath)
return(localpath)
The "filename" and "remotepath" variables are set in another function.
There is a lot of great info at the following site:
http://thelivingpearl.com/2012/12/31/creating-progress-bars-with-python/
Here is their solution for a console prog bar with threading:
import sys
import time
import threading
class progress_bar_loading(threading.Thread):
def run(self):
global stop
global kill
print 'Loading.... ',
sys.stdout.flush()
i = 0
while stop != True:
if (i%4) == 0:
sys.stdout.write('\b/')
elif (i%4) == 1:
sys.stdout.write('\b-')
elif (i%4) == 2:
sys.stdout.write('\b\\')
elif (i%4) == 3:
sys.stdout.write('\b|')
sys.stdout.flush()
time.sleep(0.2)
i+=1
if kill == True:
print '\b\b\b\b ABORT!',
else:
print '\b\b done!',
kill = False
stop = False
p = progress_bar_loading()
p.start()
try:
#anything you want to run.
time.sleep(1)
stop = True
except KeyboardInterrupt or EOFError:
kill = True
stop = True
Hope that helps or at least gets you started.
in python, is there a way to, while waiting for a user input, count time so that after, say 30 seconds, the raw_input() function is automatically skipped?
The signal.alarm function, on which #jer's recommended solution is based, is unfortunately Unix-only. If you need a cross-platform or Windows-specific solution, you can base it on threading.Timer instead, using thread.interrupt_main to send a KeyboardInterrupt to the main thread from the timer thread. I.e.:
import thread
import threading
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
timer = threading.Timer(timeout, thread.interrupt_main)
astring = None
try:
timer.start()
astring = input(prompt)
except KeyboardInterrupt:
pass
timer.cancel()
return astring
this will return None whether the 30 seconds time out or the user explicitly decides to hit control-C to give up on inputting anything, but it seems OK to treat the two cases in the same way (if you need to distinguish, you could use for the timer a function of your own that, before interrupting the main thread, records somewhere the fact that a timeout has happened, and in your handler for KeyboardInterrupt access that "somewhere" to discriminate which of the two cases occurred).
Edit: I could have sworn this was working but I must have been wrong -- the code above omits the obviously-needed timer.start(), and even with it I can't make it work any more. select.select would be the obvious other thing to try but it won't work on a "normal file" (including stdin) in Windows -- in Unix it works on all files, in Windows, only on sockets.
So I don't know how to do a cross-platform "raw input with timeout". A windows-specific one can be constructed with a tight loop polling msvcrt.kbhit, performing a msvcrt.getche (and checking if it's a return to indicate the output's done, in which case it breaks out of the loop, otherwise accumulates and keeps waiting) and checking the time to time out if needed. I cannot test because I have no Windows machine (they're all Macs and Linux ones), but here the untested code I would suggest:
import msvcrt
import time
def raw_input_with_timeout(prompt, timeout=30.0):
print(prompt, end=' ')
finishat = time.time() + timeout
result = []
while True:
if msvcrt.kbhit():
result.append(msvcrt.getche())
if result[-1] == '\r': # or \n, whatever Win returns;-)
return ''.join(result)
time.sleep(0.1) # just to yield to other processes/threads
else:
if time.time() > finishat:
return None
The OP in a comment says he does not want to return None upon timeout, but what's the alternative? Raising an exception? Returning a different default value? Whatever alternative he wants he can clearly put it in place of my return None;-).
If you don't want to time out just because the user is typing slowly (as opposed to, not typing at all!-), you could recompute finishat after every successful character input.
I found a solution to this problem in a blog post. Here's the code from that blog post:
import signal
class AlarmException(Exception):
pass
def alarmHandler(signum, frame):
raise AlarmException
def nonBlockingRawInput(prompt='', timeout=20):
signal.signal(signal.SIGALRM, alarmHandler)
signal.alarm(timeout)
try:
text = raw_input(prompt)
signal.alarm(0)
return text
except AlarmException:
print '\nPrompt timeout. Continuing...'
signal.signal(signal.SIGALRM, signal.SIG_IGN)
return ''
Please note: this code will only work on *nix OSs.
The input() function is designed to wait for the user to enter something (at least the [Enter] key).
If you are not dead set to use input(), below is a much lighter solution using tkinter. In tkinter, dialog boxes (and any widget) can be destroyed after a given time.
Here is an example :
import tkinter as tk
def W_Input (label='Input dialog box', timeout=5000):
w = tk.Tk()
w.title(label)
W_Input.data=''
wFrame = tk.Frame(w, background="light yellow", padx=20, pady=20)
wFrame.pack()
wEntryBox = tk.Entry(wFrame, background="white", width=100)
wEntryBox.focus_force()
wEntryBox.pack()
def fin():
W_Input.data = str(wEntryBox.get())
w.destroy()
wSubmitButton = tk.Button(w, text='OK', command=fin, default='active')
wSubmitButton.pack()
# --- optionnal extra code in order to have a stroke on "Return" equivalent to a mouse click on the OK button
def fin_R(event): fin()
w.bind("<Return>", fin_R)
# --- END extra code ---
w.after(timeout, w.destroy) # This is the KEY INSTRUCTION that destroys the dialog box after the given timeout in millisecondsd
w.mainloop()
W_Input() # can be called with 2 parameter, the window title (string), and the timeout duration in miliseconds
if W_Input.data : print('\nYou entered this : ', W_Input.data, end=2*'\n')
else : print('\nNothing was entered \n')
from threading import Timer
def input_with_timeout(x):
def time_up():
answer= None
print('time up...')
t = Timer(x,time_up) # x is amount of time in seconds
t.start()
try:
answer = input("enter answer : ")
except Exception:
print('pass\n')
answer = None
if answer != True: # it means if variable have somthing
t.cancel() # time_up will not execute(so, no skip)
input_with_timeout(5) # try this for five seconds
As it is self defined... run it in command line prompt , I hope you will get the answer
read this python doc you will be crystal clear what just happened in this code!!
A curses example which takes for a timed math test
#!/usr/bin/env python3
import curses
import curses.ascii
import time
#stdscr = curses.initscr() - Using curses.wrapper instead
def main(stdscr):
hd = 100 #Timeout in tenths of a second
answer = ''
stdscr.addstr('5+3=') #Your prompt text
s = time.time() #Timing function to show that solution is working properly
while True:
#curses.echo(False)
curses.halfdelay(hd)
start = time.time()
c = stdscr.getch()
if c == curses.ascii.NL: #Enter Press
break
elif c == -1: #Return on timer complete
break
elif c == curses.ascii.DEL: #Backspace key for corrections. Could add additional hooks for cursor movement
answer = answer[:-1]
y, x = curses.getsyx()
stdscr.delch(y, x-1)
elif curses.ascii.isdigit(c): #Filter because I only wanted digits accepted
answer += chr(c)
stdscr.addstr(chr(c))
hd -= int((time.time() - start) * 10) #Sets the new time on getch based on the time already used
stdscr.addstr('\n')
stdscr.addstr('Elapsed Time: %i\n'%(time.time() - s))
stdscr.addstr('This is the answer: %s\n'%answer)
#stdscr.refresh() ##implied with the call to getch
stdscr.addstr('Press any key to exit...')
curses.wrapper(main)
under linux one could use curses and getch function, its non blocking.
see getch()
https://docs.python.org/2/library/curses.html
function that waits for keyboard input for x seconds (you have to initialize a curses window (win1) first!
import time
def tastaturabfrage():
inittime = int(time.time()) # time now
waitingtime = 2.00 # time to wait in seconds
while inittime+waitingtime>int(time.time()):
key = win1.getch() #check if keyboard entry or screen resize
if key == curses.KEY_RESIZE:
empty()
resize()
key=0
if key == 118:
p(4,'KEY V Pressed')
yourfunction();
if key == 107:
p(4,'KEY K Pressed')
yourfunction();
if key == 99:
p(4,'KEY c Pressed')
yourfunction();
if key == 120:
p(4,'KEY x Pressed')
yourfunction();
else:
yourfunction
key=0
This is for newer python versions, but I believe it will still answer the question. What this does is it creates a message to the user that the time is up, then ends the code. I'm sure there's a way to make it skip the input rather than completely end the code, but either way, this should at least help...
import sys
import time
from threading import Thread
import pyautogui as pag
#imports the needed modules
xyz = 1 #for a reference call
choice1 = None #sets the starting status
def check():
time.sleep(15)#the time limit set on the message
global xyz
if choice1 != None: # if choice1 has input in it, than the time will not expire
return
if xyz == 1: # if no input has been made within the time limit, then this message
# will display
pag.confirm(text = 'Time is up!', title = 'Time is up!!!!!!!!!')
sys.exit()
Thread(target = check).start()#starts the timer
choice1 = input("Please Enter your choice: ")
I'm creating part of a program right now for a personal project and I need some help on one aspect of it.
Here is how the program works:
User enters the amount of time to run
User enters the text - Files are modified
Timer is started
optional User can enter "password" to interrupt the timer
Actions are reversed
I have all of the steps coded except the Timer because I'm trying to figure out the best way to do this. Ideally, I'd like the timer to be displaying a countdown, and if the user enters a certain "password" the timer is interrupted and it skips to step number 5.
Would the best way to do this be with a thread? I haven't worked much with threads in the past. I just need someway for the timer to be displayed while also giving control back to the user in case they want to enter that password.
Thanks for any help you provide.
Here's the code:
import time
import urllib
import sys
def restore():
backup = open(r'...backupfile.txt','r')
text = open(r'...file.txt', 'w+')
text.seek(0)
for line in backup:
text.write(line)
backup.close()
text.close()
text = open(r'...file.txt', 'a+')
backup = open(r'...backupfile.txt','w+')
text.seek(0)
for line in text:
backup.write(line)
backup.close()
while True:
url = raw_input('Please enter a URL: ')
try:
if url[:7] != 'http://':
urllib.urlopen('http://' + url)
else:
urllib.urlopen(url)
except IOError:
print "Not a real URL"
continue
text.write(url)
while True:
choice = raw_input('Would you like to enter another url? (y/n): ')
try:
if choice == 'y' or choice == 'n':
break
except:
continue
if choice == 'y':
text.seek(2)
continue
elif choice == 'n':
while True:
choice = raw_input('Would you to restore your file to the original backup (y/n): ')
try:
if choice == 'y' or choice == 'n':
break
except:
continue
if choice == 'y':
text.close()
restore()
sys.exit('Your file has been restored')
else:
text.close()
sys.exit('Your file has been modified')
As you can see, I haven't added the timing part yet. It's pretty straight forward, just adding urls to a text file and then closing them. If the user wants the original file, reverse() is called.
Under Windows you can use msvcrt to ask for a key. Asking for a password is actually more complex, because you have to track several keys. This program stops with F1.
import time
import msvcrt
from threading import Thread
import threading
class worker(Thread):
def __init__(self,maxsec):
self._maxsec = maxsec
Thread.__init__(self)
self._stop = threading.Event()
def run(self):
i = 1
start = time.time()
while not self.stopped():
t = time.time()
dif = t-start
time.sleep(1) # you want to take this out later (implement progressbar)
# print something once in a while
if i%2==0: print '.',
#check key pressed
if msvcrt.kbhit():
if ord(msvcrt.getch()) == 59:
self.stop()
#do stuff
# timeout
if dif > self._maxsec:
break
i+=1
def stop(self):
print 'thread stopped'
self._stop.set()
def stopped(self):
return self._stop.isSet()
print 'number of seconds to run '
timeToRun = raw_input()
#input files
#not implemented
#run
w = worker(timeToRun)
w.run()
#reverse actions