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Hello I have an error with the code below. I am trying to print "Bus num: "busnum. busnum is data taken from a excel sheet. Can someone explain to me why this invalid syntax as well as ways to improve to that part of the code?
for busnum,change in busses_in_year[location]:
print('Bus #: 'busnum)
I believe you wanted to use string formatting. See below:
for busnum,change in busses_in_year[location]:
print('Bus #: %d' % busnum)
Or you could simply do print("Bus #:" + str(busnum))"
Either way you can't just stick it onto the end there. You have to add it or format it in.
Or you can just use 'comma'.
print('Bus #: ', busnum)
Instead of
print('Bus #: 'busnum)
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import math
import random
possibility_1=0
possibility_2=0
while True:
list = [0, 1]
number_1=random.choice(list)
number_2=random.choice(list)
number_3=random.choice(list)
number_total=str(number_1)+","+str(number_2)+","+str(number_3)
if number_total==(1,1,0) or number_total==(0,0,1):
possibility_1 +=1
if number_total==(1,1,1) or number_total==(0,0,0):
possibility_2 +=1
print(str(number_total)+" possibility_11= "+ str(possibility_1)+" possibility_12= "+ str(possibility_2))
guys the possibility_1 and possibility_2 doesn!t changing. Please help me I want to make a heads or tails code and simulate it then check the possibilities.
Looks like number_total is a string so the output would be "1,1,0" you are comparing with a tuple. This means the if statements will not be invoked.
if number_total=="1,1,0" or number_total=="0,0,1":
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I am currently trying to create team selection code for my python video game.
Unfortunately, it keeps highliting the ":" of my if statement and saying that it is invalid syntax, even if i change the if statement for another. I tried everything, but after all, it IS an if statement, and i can't do much.
Heres my minimal recreation of the problem. The structure is important as there is netwroking code there;
team1=[]
team2=[]
if (len(team1)+len(team2)):
if team1==team2:
rand = (random.choice([team1, team2])
if rand == "team1":
team1.append(username)
else:
team2.append(username)
else:
if team1>=team2:
team1.append(username)
else:
team2.append(username)
else:
team1.append(username)
The problem is the stray '(' you have before random.choice([team1, team2]). Delete it so it becomes:
rand = random.choice([team1, team2])
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Closed 7 years ago.
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I'm trying to make a simple console game in Python 2.7, where the user gets a dilemma and makes a decision by typing the number correlating to the option he wants to choose. This question is the main menu.
s = raw_input("Enter a number in the range 1 to %s\n> " % v
if (is_number(s) and s in q):
return s
I'm getting a "SyntaxError: Invalid syntax" from the if (is_number(s) and s in q) statemet when trying to run the program. It was working fine before i added the question.
This is my first real program.
You're missing a parentheses on the previous line:
s = raw_input("Enter a number in the range 1 to %s\n> " % v
# here--^
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On codacy it detects an issue where I dont have enough arguments for format string. Help please.
code:
self.notify.error("An item we don't have: track %s level %s was selected." % [track, level])
pass a tuple, not a list
self.notify.error("An item we don't have: track %s level %s was selected." % (track, level))
this is how i fixed it
"An item we don't have: track {} level {} was selected.".format(track, level)
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Closed 9 years ago.
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I am new to this and am receiving an error that says print (line 5) is an invalid syntax
from random import randint
r=randint
while True:
s=int(input('How many sides would you like on your die')
print (r(1,s))
The problem is not actually on line 5, but on line 4. You have two ( brackets but only one ). In search of the final ) the Python interpreter checks the following line, and only at that point does it raise the error.
s=int(input('How many sides would you like on your die')
^
There is a closing parenthesis missing.