I have a UI file that I created using Qt Creator. When I execute the application through PyCharm, the main window opens briefly, then closes. I assume it is being garbage collected, but I'm not sure how to get this to work. Any ideas?
Calculator.py
from PyQt5.QtWidgets import QApplication
import MainWindow
import sys
class Calculator(QApplication):
def __init__(self):
args = sys.argv
QApplication.__init__(self, args)
self.initializeApplication()
def initializeApplication(self):
app = MainWindow.MainWindow()
app.show()
if __name__ == '__main__':
app = Calculator()
sys.exit(app.exec_())
MainWindow.py
from PyQt5 import uic
from PyQt5.QtWidgets import QMainWindow
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self, None)
uic.loadUi(r'interface/MainWindow.ui', self)
self.initializeUI()
def initializeUI(self):
self.setWindowTitle('Calculator')
I'm new to Python so please bear with me. I have looked at a few different examples, but nothing that really covers when your application spans multiple source files. Thanks.
The comment that the garbage collector is deleting it is correct since the variables created in a function only exist while the function is called. Also to be able to execute a GUI, you must call exec_() to generate the main loop that is needed.
class Calculator(QApplication):
def __init__(self):
args = sys.argv
QApplication.__init__(self, args)
self.initializeApplication()
self.exec_()
def initializeApplication(self):
self.app = MainWindow.MainWindow()
self.app.show()
if __name__ == '__main__':
app = Calculator()
Related
Before writing the Python code, I already made a ui file to made QT designer. The UI file has one Qlabel containing the values. To output an external value, I've tried, but I never could never make it. This is the My QtCode
import sys
from PyQt5.QtWidgets import *
from PyQt5 import uic
form_class = uic.loadUiType("untitled.ui")[0]
class WindowClass(QMainWindow, form_class) :
def __init__(self) :
super().__init__()
self.setupUi(self)
self.InitUI()
def InitUI(self, name):
self.hello.setText("Hello. %s"%name)
if __name__ == "__main__" :
app = QApplication(sys.argv)
myWindow = WindowClass()
myWindow.show()
app.exec_()
I want to accept the name value in if__name__=="main_" and hand it over to the part that outputs the label of the Qt class. I am not that good at English.
I have multiple windows in a Python GUI application using PyQt5.
I need to hide current window when a button is clicked and show the next window.
This works fine from WindowA to WindowB but I get an error while going from WindowB to WindowC.
I know there is some problem in initialization as the initialization code in WindowB is unreachable, but being a beginner with PyQt, i can't figure out the solution.
WindowA code:
from PyQt5 import QtCore, QtGui, QtWidgets
from WindowB import Ui_forWindowB
class Ui_forWindowA(object):
def setupUi(self, WindowA):
# GUI specifications statements here
self.someButton = QtWidgets.QPushButton(self.centralwidget)
self.someButton.clicked.connect(self.OpenWindowB)
# More GUI specifications statements here
def retranslateUi(self, WindowA):
# More statements here
def OpenWindowB(self):
self.window = QtWidgets.QMainWindow()
self.ui = Ui_forWindowB()
self.ui.setupUi(self.window)
WindowA.hide()
self.window.show()
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
WindowA = QtWidgets.QMainWindow()
ui = Ui_forWindowA()
ui.setupUi(WindowA)
MainWindow.show()
sys.exit(app.exec_())
WindowB code:
from PyQt5 import QtCore, QtGui, QtWidgets
from WindowB import Ui_forWindowB
class Ui_forWindowB(object):
def setupUi(self, WindowB):
# GUI specifications statements here
self.someButton = QtWidgets.QPushButton(self.centralwidget)
self.someButton.clicked.connect(self.OpenWindowC)
# More GUI specifications statements here
def retranslateUi(self, WindowB):
# More statements here
def OpenWindowB(self):
self.window = QtWidgets.QMainWindow()
self.ui = Ui_forWindowC()
self.ui.setupUi(self.window)
WindowB.hide() # Error here
self.window.show()
# The below code doesn't get executed when Ui_forWindowB is called from A
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
WindowB = QtWidgets.QMainWindow()
ui = Ui_forWindowB()
ui.setupUi(WindowB)
MainWindow.show()
sys.exit(app.exec_())
It works fine from A to B where
WindowA.hide() # Works Properly
While calling WindowC from WindowB
WindowB.hide() # Shows error: name 'WindowB' is not defined
I understand that the initialization isn't done as the "if" statement doesn't get executed.
How to get this working?
I have many more windows to connect in this flow
When you run a Python script, the first file executed will be assigned the name __main__, therefore, if you first execute WindowA the code inside the block if __name__ == "__main__" gets executed and the application is started using WindowA as the main window, similarly if you execute your WindowB script first, the application will be started usingWindowB as the main window.
You cannot start two applications within the same process so you have to choose which one you want to be the main window, all the others will be secondary windows (even if they inherit from QMainWindow).
Nevertheless, you should be able to instantiate new windows from a method in your main window.
As a good practice, you could create a main script to handle the initialization of your application and start an empty main window that will then handle your workflow, also, you may want to wrap your UI classes, specially if they are generated using Qt creator, here is an example:
main.py
import PyQt5
from PyQt5 import QtCore, QtWidgets
from PyQt5.QtWidgets import QApplication
from views.main_window import MainWindow
class App(QApplication):
"""Main application wrapper, loads and shows the main window"""
def __init__(self, sys_argv):
super().__init__(sys_argv)
# Show main window
self.main_window = MainWindow()
self.main_window.show()
if __name__ == '__main__':
app = App(sys.argv)
sys.exit(app.exec_())
main_window.py
This is the main window, it doesn't do anything, just control the workflow of the application, i.e. load WindowA, then WindowB etc., notice that I inherit from Ui_MainWindow, by doing so, you can separate the look and feel from the logic and use Qt Creator to generate your UI:
from PyQt5.QtWidgets import QWidget, QMainWindow
from views.window_a import WindowA
from views.window_b import WindowB
from widgets.main_window import Ui_MainWindow
class MainWindow(Ui_MainWindow, QMainWindow):
"""Main application window, handles the workflow of secondary windows"""
def __init__(self):
Ui_MainWindow.__init__(self)
QMainWindow.__init__(self)
self.setupUi(self)
# start hidden
self.hide()
# show window A
self.window_a = WindowA()
self.window_a.actionExit.triggered.connect(self.window_a_closed)
self.window_a.show()
def window_a_closed(self):
# Show window B
self.window_b = WindowB()
self.window_b.actionExit.triggered.connect(self.window_b_closed)
self.window_b.show()
def window_b_closed(self):
#Close the application if window B is closed
self.close()
window_a.py
from PyQt5.QtWidgets import QWidget, QMainWindow
from widgets.main_window import Ui_forWindowA
class WindowA(Ui_forWindowA, QMainWindow):
"""Window A"""
def __init__(self):
Ui_forWindowA.__init__(self)
QMainWindow.__init__(self)
self.setupUi(self)
# Do some stuff
window_b.py
from PyQt5.QtWidgets import QWidget, QMainWindow
from widgets.main_window import Ui_forWindowB
class WindowA(Ui_forWindowB, QMainWindow):
"""Window B"""
def __init__(self):
Ui_forWindowB.__init__(self)
QMainWindow.__init__(self)
self.setupUi(self)
# Do some stuff
Hopefully should give you an idea to get you going.
I am creating a small GUI program using PySide. I am having difficulty creating another object of same class. What exactly I am trying to do is that when clicked on a button on MainWindow it should create another independent window of same class.
import sys
from PySide import QtCore, QtGui
class Sticky(QtGui.QMainWindow):
def __init__(self,parent = None):
QtGui.QMainWindow.__init__(self,parent)
self.initUI()
def initUI(self):
....
self.addToolBarElements()
....
self.show()
def addToolBarElements(self):
....
self.newwindow = QtGui.QAction(QtGui.QIcon(os.path.join(os.path.dirname(__file__),'icons/new.png')),"New Note",self)
self.newwindow.setStatusTip("New")
self.newwindow.triggered.connect(newwindow)
self.toolBar.addAction(self.newwindow)
def newwindow(self):
#how to create new object of same class
def run():
app = QtGui.QApplication(sys.argv)
notes = Sticky()
sys.exit(app.exec_())
Here is what I have tried:
I have tried multiprocessing but I didn't understand much. I tried calling run() method again but it gives error.
Do not call with the same name 2 different elements, in your case self.newwindow refers to the QAction as the method of the class, avoid it, that is a type of error easy to commit but difficult to find.
going to the point, you just have to create a new object of the class, but the problem is that the garbage collector will eliminate it, to avoid it there are 2 possible options, the first is to make the new window member of the class, or second store it in a list, that's the one I choose because I think you want to have several windows.
import sys
import os
from PySide import QtCore, QtGui
class Sticky(QtGui.QMainWindow):
def __init__(self,parent = None):
QtGui.QMainWindow.__init__(self,parent)
self.others_windows = []
self.initUI()
def initUI(self):
self.addToolBarElements()
self.show()
def addToolBarElements(self):
self.toolBar = self.addToolBar("toolBar")
self.newwindow = QtGui.QAction(QtGui.QIcon(os.path.join(os.path.dirname(__file__),'icons/new.png')), "New Note",self)
self.newwindow.setStatusTip("New")
self.newwindow.triggered.connect(self.on_newwindow)
self.toolBar.addAction(self.newwindow)
def on_newwindow(self):
w = Sticky()
w.show()
self.others_windows.append(w)
def run():
app = QtGui.QApplication(sys.argv)
notes = Sticky()
sys.exit(app.exec_())
run()
I use Qt Designer to build my GUI's and convert them to py files using pyuic5. My end goal here is to interrupt the user from closing the program when a variable == 1 and present them with an 'are you sure you want to close?' type dialog. If said variable == 0 then just close the program normally.
I have seen lots of examples on how to do this, but all of them require editing the code in the GUI module. I import my gui.py file created by pyuic5 into my main script where I do all my connections to buttons, line edits, etc.. I do this so that at anytime I can update the GUI with Qt Designer and not affect the programs functionality.
Is there a way to do this from my main script that has the GUI module from Qt Designer imported?
Example of how my main script is structured:
import philipsControlGui
import sys
def main():
MainWindow.show()
sys.exit(app.exec_())
def test():
print('test')
# Main window setup
app = philipsControlGui.QtWidgets.QApplication(sys.argv)
MainWindow = philipsControlGui.QtWidgets.QMainWindow()
ui = philipsControlGui.Ui_MainWindow()
ui.setupUi(MainWindow)
# Main window bindings
ui.onButton.clicked.connect(test)
### Can I insert something here to do: if user closes the window... do something else instead?
if __name__ == "__main__":
main()
You should create a subclass from your imported gui so you can reimplement the closeEvent method:
import sys
from PyQt5 import QtCore, QtGui, QtWidgets
from philipsControlGui import Ui_MainWindow
class MainWindow(QtWidgets.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
self.ui = Ui_MainWindow()
self.ui.setUpUi(self)
self.ui.onButton.clicked.connect(self.test)
self._check_close = True
def test(self):
print('test')
self._check_close = not self._check_close
def closeEvent(self, event):
if self._check_close:
result = QtWidgets.QMessageBox.question(
self, 'Confirm Close', 'Are you sure you want to close?',
QtWidgets.QMessageBox.Yes | QtWidgets.QMessageBox.No)
if result == QtWidgets.QMessageBox.Yes:
event.accept()
else:
event.ignore()
def main():
app = QtWidgets.QApplication(sys.argv)
window = MainWindow()
window.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
If there's a specific 'ExitButton' in your design, you should be able to connect it in the main code and create a pop up dialog. You would have to import the QtCore/QtGui components. I always write my GUI directly (QtDesigner is pain when it comes to these things) so I'm assuming something like this:
from PyQt4.QtGui import *
from PyQt4.QtCore import *
[YOUR CODE]
ui.ExitButton.clicked.connect(Exit)
def Exit():
msg = QMessageBox()
msg.setIcon(QMessageBox.Information)
msg.setText("Are you sure you want to close this window?")
msg.setWindowTitle("MessageBox demo")
msg.setStandardButtons(QMessageBox.Ok | QMessageBox.Cancel)
msg.buttonClicked.connect(msgbtn)
retval = msg.exec_()
print "value of pressed message box button:", retval
I have created gui form using qtdesigner and converted in to python code using pyuic4. Sample of my main script is as follows:
#!/usr/bin/env python
from PyQt4 import QtGui
from multibootusb_ui import Ui_Dialog
import sys
import os
import another_file_function
class AppGui(QtGui.QDialog,Ui_Dialog):
def __init__(self):
QtGui.QDialog.__init__(self)
self.ui = Ui_Dialog()
self.ui.setupUi(self)
self.ui.close.clicked.connect(self.close)
another_file_function.function2()
def function1():
self.ui.text_label.setText("some text")
function1()
app = QtGui.QApplication(sys.argv)
window = AppGui()
ui = Ui_Dialog()
window.show()
sys.exit(app.exec_())
To make it easy i have created different function in different file. So that it can be accessed at any time by any scrips.
Here is the sample of function from another_file_function:
#!/usr/bin/env python
def function2():
#code here
self.ui.text_label.setText("some text")
The function1 from main script and function2 from another_file_function are same. Also I am calling function2 from main class. The problem is that when i use function1() from main script it updates the GUI text without an issue. However, if i use the same function in different file and call that function from main script it fails to update and i get global name 'self' is not defined error.
Where am I getting wrong? Any help is appriciated.
Thank you.
I am unclear why function1 works either, I am going to assume it has a self in it's definition that you dropped.
To get function2 to work you need to do something like:
other file:
def function2(input):
#code here
input.ui.text_label.setText("some text")
main file:
#!/usr/bin/env python
from PyQt4 import QtGui
from multibootusb_ui import Ui_Dialog
import sys
import os
import another_file_function
class AppGui(QtGui.QDialog,Ui_Dialog):
def __init__(self):
QtGui.QDialog.__init__(self)
self.ui = Ui_Dialog()
self.ui.setupUi(self)
self.ui.close.clicked.connect(self.close)
another_file_function.function2()
def function1(self):
self.ui.text_label.setText("some text")
function1()
app = QtGui.QApplication(sys.argv)
window = AppGui()
another_file_function.function2(window)
window.function1()
window.show()
sys.exit(app.exec_())